algebra merit. simplify simplify by factorising

Algebra

Merit

Simplify

Simplify by factorising

Simplify by taking out the common factor (2x) out of everything

Make W the subject

Make W the subject

Solve for x and y

Solve for x and y

• A square warehouse is extended by 10 metres at one end. The area of the extended warehouse is 375m2 Find the original area of the warehouse.

Area = 152 =225 m2

• A square warehouse is extended by 10 metres at one end. The area of the extended warehouse is 375m2 Find the original area of the warehouse.

Simplify

Simplify

• Elton has more than twice as many CDs as Robbie. Altogether they have 56 CDs. Write a relevant equation and use it find the least number of CDs that Elton could have.

• Elton has more than twice as many CDs as Robbie. Altogether they have 56 CDs. Write a relevant equation and use it find the least number of CDs that Elton could have.

• Elton purchases some DVDs from the mall. He buys four times as many music DVDs as movie DVDs. The music DVDs are $2.50 each. The movie DVDs are $1.50 each. Altogether he spends $92.Solve the equations to find out how many music DVDs that he purchased.

• Elton purchases some DVDs from the mall. He buys four times as many music DVDs as movie DVDs. The music DVDs are $2.50 each. The movie DVDs are $1.50 each. Altogether he spends $92.Solve the equations to find out how many music DVDs that he purchased.

Simplify

Simplify

One of the solutions of 4x2 + 8x + 3 = 0 is x = -1.5

• Use this solution to find the second solution of the equation.

One of the solutions of 4x2 + 8x + 3 = 0 is x = -1.5

• Use this solution to find the second solution of the equation.

• Must be one of the brackets

One of the solutions of 4x2 + 8x + 3 = 0 is x = -1.5

• Use this solution to find the second solution of the equation.

• We need 2x to make 4x2

• We need +1 to make ‘3’

One of the solutions of 4x2 + 8x + 3 = 0 is x = -1.5

• Use this solution to find the second solution of the equation.

• We need 2x to make 4x2

• We need +1 to make ‘3’

The volume of the box shown is 60 litres. Find the dimensions of the box.

60 litres = 60, 000 cm3

60 litres = 60, 000 cm3

Dimensions are 50cm:30cm:40cm

• The triangle drawn below is equilateral. The perimeter is 30 cm. Write down two equations and solve them simultaneously to find the values of x and y.

• The triangle drawn below is equilateral. The perimeter is 30 cm. Write down two equations and solve them simultaneously to find the values of x and y.

Simplify

Factorise

Express as a single fraction

Express as a single fraction

Solve the equation

Solve the equation

Simplify

Simplify

There are V litres in Claudia’s water tank. There are d “drippers” on the irrigation hose from the tank to the garden. Each dripper

uses x litres of water per day.

• Write an expression to show the total amount of water, T, left in the tank after one day.

There are V litres in Claudia’s water tank. There are d “drippers” on the irrigation hose from the tank to the garden. Each dripper

uses x litres of water per day.

• Write an expression to show the total amount of water, T, left in the tank after one day.

There are V litres in Claudia’s water tank. There are d “drippers” on the irrigation hose from the tank to the garden. Each dripper

uses x litres of water per day.

• At the end of the day on the 1st of April there were 150 litres of water in the tank. The next day, 4 drippers were used to irrigate the garden and at the end of the day there were 60 litres of water left.

• Use the expression you gave above to show how much water each dripper used on that day.

There are V litres in Claudia’s water tank. There are d “drippers” on the irrigation hose from the tank to the garden. Each dripper

uses x litres of water per day.

• At the end of the day on the 1st of April there were 150 litres of water in the tank. The next day, 4 drippers were used to irrigate the garden and at the end of the day there were 60 litres of water left.

• Use the expression you gave above to show how much water each dripper used on that day.

Graeme is designing a path around the front of his garden. His design is shown below.

The width of the path is x metres.

Graeme has sufficient paving to make a path with a total area of 22 m2.

• The area of the path can be written as

• 4x+3x2 +(5-2x)x=22. • Rewrite the equation

and then solve to find the width of the path around the front of the garden.

The width of the path is x metres.

Graeme has sufficient paving to make a path with a total area of 22 m2.

The width of the path is x metres.