acids and bases titrations ap chemistry. neutralization reactions and titrations neutralization...
Post on 17-Dec-2015
288 Views
Preview:
TRANSCRIPT
Neutralization Reactions and Titrations
Neutralization ReactionsStrong acid + Strong Base Salt + Water HCl + NaOH NaCl + H2O
(neutral pH = 7)
Neutral solution results only if the acid and base are mixed in the mole ratios specified in the balanced equation.
Titration A lab technique used to determine the unknown
concentration of an acid or base using a neutralization reaction.
Titration Set-up
Titrant- an acid/base with a known concentration
Analyte- a solution being analyzed
Burette- glassware used to deliver the titrant
For example, if you had an acid of unknown concentration, you would add base (with a known concentration) to it until all the acid had been neutralized.
At the very point that all the acid was gone, the amount of base you added would exactly equal the amount of acid you started with.
Moles of Acid = Moles of Base
The equation for titration calculations is
At neutralization, Moles of Acid= Moles of Base
MaVa = MbVb
Ma = Acid Molarity Mb = Base Molarity
Va = Acid volume Vb = Base Volume
Volumes can be any units as long as they are the same on both sides!
Example Titration Problem If 5.00mL of 1.00M NaOH was used to titrate10.0mL of
HNO3, what is the concentration of HNO3?
MaVa = MbVb
Ma=? Va=10.0mL Mb=1.00M Vb= 5.00mL
Ma (10.0mL) = (1.00M)(5.00mL)
Ma = (1.00M)(5.00mL)
(10.00mL)
Ma =0.500M
Titration Vocabulary Equivalence Point – The point in a titration where the moles of acid = moles
of base
Endpoint – Point at which the indicator changes color. The endpoint and the equivalence points are not always
the same. (but they should be!!!)
An indicator is used to determine when the acid has been neutralized in a titration.
Without an indicator it would be impossible to know when the titration should stop, unless you use a pH meter.
Titration of strong acid with a strong base
Such as NaOH and HClEquivalence point occurs at pH = 7Should use an indicator that changes at a
pH of 7, such as bromothymol blue
Strong Acid – Strong Base Titrations You can calculate the volume of base needed to reach the equivalence point using the formula: V·M = V·M.
There are three situations in which you determine pH.
•Initial strong acid concentration (this is simply the –log[H+] which is based on the [Acid].)
•Equivalence point (or endpoint) when moles of OH- = moles of H+. The pH is 7 (due to the auto-ionization of water.)
•Before and after the endpoint (calculate excess moles of H+ or OH-, divide by the total volume, and calculate the pH based on this value.)
Titration of a weak acid with a strong base
Such as CH3COOH and NaOH
Equivalence point occurs at a pH >7 Should use an indicator that changes at a pH
above 7, such as phenolphthalein.
•Notice that starting pH is higher and
•the Equivalence Point pH is higher.
Why is the Equivalence point at a pH >7?
The conjugate base of a weak acid is a strong base.
CH3COOH = Weak acid CH3COO- = Strong Base
Once all of the acid has been converted to CH3COO-, it starts to take the H+ from H2O in solution, creating more OH- ions thus making the pH >7
Weak Acid – Strong Base Titrations
When a weak acid (such as HC2H3O2) is neutralized by a strong base (such as NaOH), the graph varies in two ways:
the equivalence point is not at pH = 7 and a buffer region exists as you approach the
endpoint. You can still calculate the volume of base
needed to reach the equivalence point using the formula: V·M = V·M. Weak acids require the same amount of base for neutralization as strong acids because they dissociate as they are neutralized
There are five situations in which you need to be able to calculate the pH. 1. Initial weak acid concentration (this is an ICE box
calculation.) The shortcut can be used here.
2. Equivalence point (endpoint) is when all of the weak acid has been neutralized and turned into the conjugate base (C2H3O2- in this case.) This is a hydrolysis problem. Calculate the [C2H3O2-] and then do an ICE box problem knowing that Kb = . Calculate the [OH-], the pOH, and then the pH.
3. Halfway to the equivalence point (as in a half-titration) the pH = pKa. This is because at this point, there is a perfect buffer as the [HA] = [A-]. At this point, you can determine the Ka of an unknown weak acid… very useful.
4. Before and after the half-way point, the pH can be calculated using the Henderson-Hasselbach equation (or an ICE box, if you want.) Use stoichiometry to determine the [HA] and [A-]. pH = pKa + log
5. Finally, after the equivalence point, the pH depends on the excess strong base that has been added. As in the strong acid-strong base titration, calculate excess moles of OH-, divide by the total volume, and calculate the pOH and then pH based on this value. The effect on the pH by the A- is negligible compared to the excess OH-.
Weak Base – Strong Acid Titrations•When a sample of a weak base is titrated with a strong acid, the curve resembles an inverted Weak Acid – Strong Base titration curve.Note that the pH at the equivalence point is less than 7.
•An indicator such as phenolphthalein that changes at pH of 9 would change when only 6 mL of acid had been added even though the equivalence point is reached at around 11 mL.
The acid-base indicator must be chosen with a Ka near to the [H+] of the equivalence point; that is the pKa of the indicator must match the pH of the equivalence point.
Weak Diprotic Acid – Strong Base Titrations
When a weak diprotic acid (examples: H2C2O4 or H2CO3) is titrated, there are two equivalence points. •The curve is not as distinct because of the various proton donors and proton acceptors in solution.
top related