a4.1 gt geometry. simplify each expression. 1. 90 – (x + 20) 2. 180 – (3x – 10) write an...

A4.1GT Geometry

Simplify each expression.

1. 90 – (x + 20)

2. 180 – (3x – 10)

Write an algebraic expression for each of the following.

3. 4 more than twice a number

4. 6 less than half a number

70 – x

190 – 3x

2n + 4

Drill: Thurs, 9/16

OBJ: SWBAT identify adjacent, vertical, complementary, and supplementary angles in order to find angle measures.

MOTIVATION

WHAT ARE ADJACENT ANGLES?

Holt McDougal Geometry

1-4 Pairs of Angles

Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent.

Example 1A: Identifying Angle Pairs

AEB and BED

AEB and BED have a common vertex, E, a common side, EB, and no common interior points. Their noncommon sides, EA and ED, are opposite rays. Therefore, AEB and BED are adjacent angles and form a linear pair.

Holt McDougal Geometry

1-4 Pairs of Angles

Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent.

Example 1B: Identifying Angle Pairs

AEB and BEC

AEB and BEC have a common vertex, E, a common side, EB, and no common interior points. Therefore, AEB and BEC are only adjacent angles.

Holt McDougal Geometry

1-4 Pairs of Angles

DEC and AEB

DEC and AEB share E but do not have a common side, so DEC and AEB are not adjacent angles.

Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent.

Example 1C: Identifying Angle Pairs

Holt McDougal Geometry

1-4 Pairs of Angles

Check It Out! Example 1a

5 and 6

Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent.

5 and 6 are adjacent angles. Their noncommon sides, EA and ED, are opposite rays, so 5 and 6 also form a linear pair.

Holt McDougal Geometry

1-4 Pairs of Angles

Check It Out! Example 1b

7 and SPU

Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent.

7 and SPU have a common vertex, P, but do not have a common side. So 7 and SPU are not adjacent angles.

Holt McDougal Geometry

1-4 Pairs of Angles

Check It Out! Example 1c

7 and 8

Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent.

7 and 8 have a common vertex, P, but do not have a common side. So 7 and 8 are not adjacent angles.

COMPLEMENTARY & SUPPLEMENTARY ANGLE MATCH-UP

GEO SKETCH FOR VERTICAL ANGLES

Another angle pair relationship exists between two angles whose sides form two pairs of opposite rays. Vertical angles are two nonadjacent angles formed by two intersecting lines. 1 and 3 are vertical angles, as are 2 and 4.

ALGEBRA AND ANGLES (RS A4D)

3x + 8( )°

4x + 5( )°

H K

I J

ALGEBRA AND ANGLES (RS A4D)

3x + 45( )°12x - 15( )°

L N

O

M

ALGEBRA AND ANGLES (RS A4D)

5x - 16( )°

3x + 20( )°

Light passing through a fiber optic cable reflects off the walls of the cable in such a way that 1 ≅ 2, 1 and 3 are complementary, and 2 and 4 are complementary.

If m1 = 47°, find m2, m3, and m4.

Example 4: Problem-Solving Application

1 Understand the Problem

The answers are the measures of 2, 3, and 4.

List the important information:

• 1 2• 1 and 3 are complementary, and 2 and 4 are complementary.• m1 = 47°

2 Make a Plan

If 1 2, then m 1 = m 2.

If 3 and 1 are complementary, then m3 = (90 – 47)°.

If 4 and 2 are complementary, then m4 = (90 – 47)°.

Solve3

By the Transitive Property of Equality, if m1 = 47° and m1 = m2, then m2 = 47°.

Since 3 and 1 are complementary, m3 = 43°. Similarly, since 2 and 4 are complementary, m4 = 43°.

Look Back4

The answer makes sense because 47° + 43° = 90°, so 1 and 3 are complementary, and 2 and 4 are complementary.

Thus m2 = 47°, m3 = 43°, and m4 =43°.

What if...? Suppose m3 = 27.6°. Find m1, m2, and m4.

Check It Out! Example 4

1 Understand the Problem

The answers are the measures of 1, 2, and 4.

List the important information:

• 1 2• 1 and 3 are complementary, and 2 and 4 are complementary.• m3 = 27.6°

2 Make a Plan

If 1 2, then m1 = m2.

If 3 and 1 are complementary, then m1 = (90 – 27.6)°.

If 4 and 2 are complementary, then m4 = (90 – 27.6)°.

Solve3

By the Transitive Property of Equality, if m1 = 62.4° and m1 = m2, thenm2 = 62.4°.

Since 3 and 1 are complementary, m3 = 27.6°. Similarly, since 2 and 4 are complementary, m4 = 27.6°.

Look Back4

The answer makes sense because 27.6° + 62.4° = 90°, so 1 and 3 are complementary, and 2 and 4 are complementary.

Thus m1 = m2 = 62.4°; m4 = 27.6°.