5 source of magnetic field
Post on 14-Jun-2015
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Source of Magnetic Field
Long, Straight Current-carrying Wire
Long, Straight Current-carrying Wire
µ0
permeability is the measure of the ability of a material to support the formation of
a magnetic field within itself.
Long, Straight Current-carrying Wire
Long, Straight Current-carrying Wire
Sample Problem:
A long, straight wire allows 3.50 A through it, What is
the magnitude of the magnetic field 25.0cm from
the wire?
Answer
B=2.80x10-6 T
Center of a Circular Current-carrying Loop
Center of a Circular Current-carrying Loop
r=radius of the loopB=magnetic field strengthI=currentµ0=permeability of free space (4Π x 10-7 m/A)
Center of a Circular Current-carrying Loop
r=radius of the loopB=magnetic field strengthI=currentµ0=permeability of free space (4Π x 10-7 m/A)
B=µ0I / 2r
Center of a Circular Current-carrying Loop
Sample Problem:A circular loop with a diameter of 15.0cm lies
on a horizontal plane as viewed from above. Through it is a 3.80A of current moving clockwise. What is the magnitude and direction of magnetic field at its center?
Answer
B=3.18x10-5 T
Current carrying Solenoid
Current carrying Solenoid
N=no. of loopsL=length of coilB=magnetic field strengthI=currentµ0=permeability of free space (4Π x 10-7 m/A)
Current carrying Solenoid
N=no. of loopsL=length of coilB=magnetic field strengthI=currentµ0=permeability of free space (4Π x 10-7 m/A)
B=µ0NI / L
Sample Problem
A solenoid 150.0cm long with 1.550 turns has a
central magnetic field of 1.50mT. Find the current
through the coil.
Answer
B= 1.16 T
Exercises:
1. A long, straight wire allows 6.20 A through it, What is the magnitude of the magnetic field 17.0cm from the wire?
2. A solenoid 15.0 m long with 2.50 turns has a central magnetic field of 7.80 T. Find the current through the coil.
3. A circular loop with a diameter of 20.0 m lies on a horizontal plane as viewed from above. Through it is a 4.80A of current moving clockwise. What is the magnitude of magnetic field at its center?
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