5 elevators
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Viet nam August 2005
ALTIVAR71Lift Training
Lift Training Vietnam Augu
Load detai ls Vector drive required
Constant torque (torque load dependant)
Lift regenerative on raising empty car
Dynamic brake or Network Braking required
Calculations Gearbox & Pulley system efficiencies
Maximum mass of car & counter weight mass
Lifting and lowering speed
Acceleration & Deceleration rate
Lif t Char act er ist ics
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Lift Training Vietnam Augu
Car
Counterweight
Supply
Dyna
micBrake
Gener al Ar r angement
Encoder
Lift Training Vietnam Augu
ua r an on r o -Mot or ing
Car
with
full
load
+
Torqu
e
-
Torqu
e
+
Speed
-
Speed
C
ar
Coun
ter
weig
ht
Motoring
Motoring
Car
with
no
load
Count
er
weight
Ca
r
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Lift Training Vietnam Augu
ua r an on r o -Regenerat ing
+
Torqu
e
-
Torqu
e
+
Speed
-
Speed
Count
er
weight
Ca
r
Car
with
no
load
Car
with
full
load
Regenerating
Regenerating
Car
Co
unt
er
wei
ght
Brake
Brake
Lift Training Vietnam Augu
4 Quadr ant Cont r ol
Car
with
full
load
+
Torqu
e
-
Torqu
e
+
Speed
-
Speed
C
ar
Coun
ter
weig
ht
Motoring
Motoring
Car
with
no
load
Count
er
weight
Ca
r
Count
er
weight
Ca
r
Car
with
no
load
Car
with
full
load
Regenerating
Regenerating
Car
Co
unt
er
wei
ght
Brake
Brake
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Lift Training Vietnam Augu
Motor and gear box
efficiency 90%
Example Calculat ion
Empty CarMass 1270kg
Counter weightmass (car + maximum load)1560kg
Maximum loadMass 580kg
Vertical
Speed1.6m/s
Cable
mass100kg
Motor & gear box Inertia
0.034kg/m2
Idler pulley Inertia
0.006kg/m2
Acceleration0.8 m/s2
System efficiencyincludes friction of carand counterweightagainst guides, cableand pulleys etc. 95%
Lift Training Vietnam Augu
m.
))((
.
(ravelocityAngular
(m/velocityLinearradiusEquivalent
01020
2601500
61
2
2
36520
010010015601850
m/kg.
.)(radiequivalentMassInertia
qu va en a us oGyr at ion
Car
Counterweight
1) Calculate the equivalent rotating
inertia of the car, counterweight& rope
Car full load1850 kg
Counter weight1560 kg
Vertical speed 1.6m/sAcceleration 0.8
m/s2
Motor 1500 RPM
11kW
Motor & G/Box Inertia0.034kg/m2
Motor gearbox efficiency90%
System efficiency
95%
Use equivalent radius to simplify calculations.
Do not need to know gearbox ratios, pulley orrope sizes. Uses inertia of a cylinder whereall weight is effectively distributed around anarc scribed by the equivalent radius.
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Lift Training Vietnam Augu
watts
Efficiency
oAcceleVelocityInertiaP MotorACC
465
9.0
2
157157034.0
AngularAngular
2) Calculate the power to accelerate t he motor
and gearbox
Acceler at ing Power
Car
Counter
weight
3) Calculate the power to accelerate the car,
counterweight, cables and load
watts
Efficiency
oAcceleVelocityInertiaP
systemACC
737,4
95.0
2
1571573652.0
AngularAngular
4) Total Accelerating power required
wa
,PTotalACC
5202
47374
Car full load1850 kg
Counter weight1560 kg
Vertical speed 1.6
m/sAcceleration 0.8
m/s2
Motor 1500 RPM
11kW
Motor & G/Box Inertia0.034kg/m2
Motor gearbox efficiency90%
System efficiency
95%
Lift Training Vietnam Augu
5) Calculate t he worst case lifting or loweringpower requirement.
watts
..
..
Efficiency
GraVelocity)W/CloadCar(PLift
5416
90950
8196115601850
Tot al Power Requir ement
Car
Counterweight
6) Calculate the total power
required.
kWatts
k
PPP LiftonAcceleratiTotal
618.10
)416.5202.5(
The 11kW motor is just adequate but it does notallow a safety factor for possible overloadsituations
Car full load1850 kg
Counter weight1560 kg
Vertical speed 1.6m/sAcceleration 0.8
m/s2
Motor 1500 RPM
11kW
Motor & G/Box Inertia0.034kg/m2
Motor gearbox efficiency90%
System efficiency
95%
This power isrequired from
the motor
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Lift Training Vietnam Augu
watts
EfficiGravityVelocityEmptyCarghtCounterWeiPgen
3891
9.095.081.96.112701560
)(Re
8) Calculate the decelerating regenerative power for
system and motor gearbox.
097,8
3891206,4
Regen
LowerDEC PPP
Regener at ive Power
Car
Counter
weight
7) Calculate the worst case lowering or
lifting regenerative power.
Car full load1850 kg
Counter weight
1560 kg
Vertical speed 1.6
m/sAcceleration 0.8m/s2
Motor 1500 RPM
11kWMotor & G/Box Inertia
0.034kg/m2
Motor gearbox efficiency
90%
System efficiency95%
watts
Efficiency
oAcceleVelocityInertiaP
MotorsystemDEC
206,4
95.09.02
1571573652.0034.0
AngularAngular&
9) Calculate the total regenerative power.
This energy
must bedissipated
Lift Training Vietnam Augu
10) Calculate maximum Brake Reis tance
Po
VsistorRe
2
76
8097
785Re
2
sistor
ynam c ra e es s orSizing
Car
Counterweight
Car full load1850 kg
Counter weight1560 kg
Vertical speed 1.6m/sAcceleration 0.8
m/s2
Motor 1500 RPM
11kW
Motor & G/Box Inertia0.034kg/m2
Motor gearbox efficiency90%
System efficiency
95%
Points:
1) This is a maximum resistor resistance. Anyincrease in resistor resistance means that thepeak power of 8.097kW can not be dissipatedcausing the Drive to fault on over voltage etc.
2) Peak regeneration occurs at maximum speedwhen accelerating or decelerating when underregeneration. At half speed under the sameoperating conditions power dissipation by theresistor will only be 4kW.
3) No allowance has been made for a car that couldbe overloaded!!
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Lift Training Vietnam Augu
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SchindlerElevators in New Zealand and Australia
Project : Elevator c ontrol
-
retrofit applications.
ec r on csExper iance
Lift Training Vietnam Augu
Linear speed display in m/s.
4 adjustable S curves
Smooth transitions
Adaptive speed gains
Speed dependant response
Pre-torque star ting
No roll back
Schindler Requier ment s
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Lift Training Vietnam Augu
a n equ r emenCurves
Lift Training Vietnam Augu
7 63 8 92 2/ 8 98 7 2 2/ 09 / 93 S C H IN DL ER L I FT S V AR IO US / W AI KA TO P OL Y TE CH U D3 C US TO M SO FT WA RE D E VE LO PM EN T
7 64 9 04 2 2 2/ 08 /95 S C HI ND LE R L IF TS D IG IT AL H OU SE BU IL DI NG M V3 CU ST OM S OF TW AR E D EV EL OP ME NT
7 66 9 04 5 0 4/ 07 /95 S C HI ND LE R L IF TS M OU NT S MA RT S TA DI UM 1 *U D3 -6 0/ 1 *D B- 30 0/ 1 * SO FT WA RE / 1* CU ST OM R ESI ST
7 67 9 08 6 2 0/ 04 /95 S C HI ND LE R L IF TS W AI KA TO P O LY TE CH NI C 1 *U D3 -4 6/ 1 *D B- 30 0/ 1 *S OF TW AR E/ 1* CU ST OM R ESI ST
683 9009 5131150 29/04 /94SCHINDLER LIFTSLTD ENDEANSBUILDINGAUCKLAND DYNAMICBRAKE RESISTOR
6 84 9 01 3 5 22 74 0 1 7/ 09 / 94 S C H IN DL ER L I FT S LT D G RE E NL AN E HO SP I TA L D YN AM IC B RA KE R ES I ST OR S
768 9060 18/01 /95SCHINDLER L IFTSLTD TARANAKI SAVINGS BANKCENTR2*UD3-31 /2*SOFTWARE/ 2*DB300/ 2*CUSTOMRESIST
765 9104 07/06 /95SCHINDLER L IFTSNF LTD LEARNIING RESOURCE CENTRE 1*UD3-46/1*DB-300/ 1*SOFTWARE/ 1*CUSTOMRESIST
I I E VISTA FOR ELEVATOR, SIMILAR T I I I
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A RGYLE DIAMONDS 2 X ME10.0 WITH ENCLOSURE AND
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I LIA Inquiry 90209 3% CHOKES FITTED TO A UE420
I TION 2 X UE-620D 18 PULSE
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I TION (USA) THROUGH WALL MOUNTING FLAN
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FALCON ELECTRICAL RVSX-22 CONFORMAL COATING
CL IV E WIL SO N INV ERCA RGILL FIT EDNI MODULES
ome o s omp e e yNapier
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Lift Training Vietnam Augu
Control System
OEM PCB Based Logic Standard Start Forward Start Reverse and Jog
Control of the VSD
Output Contactor
Used Schneider PLC or Use Controller Inside
Implement S Curve Functionality within the Drive
Use Drive Position on Limit Switch Functionality
Use ATV71 Power Removal Function (No MoreOutput Contactor?)
Output Contactor Control for Safety Requirements
Performance Requirements
Needs to be Smooth
Needs to be Fast
Use Pretorque Functionality within Drive
Speed PID Loop
High Speed Hoisting
External Poition Sensors
OEM Visit s
Lift Training Vietnam Augu
Elecrical Equipment
Do not used 1 supplier
Use Schneider.
Single Point of Contact.
Schneider can Supply VSD, Contactors,Overloads, Brake Reistors, Network Brakingand Full Expertise with ConsiderableExperience.
OEM Visit s
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Thank You
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