algebra1 adding and subtracting radical expressions

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CONFIDENTIAL 1 Algebra1 Algebra1 Adding and Adding and Subtracting Subtracting Radical Expressions Radical Expressions

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Algebra1 Adding and Subtracting Radical Expressions. Warm Up. Find the domain of each square-root function. 1) y = √(4x – 2) 2) y = -2√(x + 3) 3) y = 1 + √(x + 6). 1) exponential 2) quadratic. Adding and Subtracting Radical Expressions. - PowerPoint PPT Presentation

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Page 1: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 1

Algebra1Algebra1

Adding and Adding and SubtractingSubtracting

Radical ExpressionsRadical Expressions

Page 2: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 2

Warm UpWarm Up

1) exponential 2) quadratic

1) y = √(4x – 2)

2) y = -2√(x + 3)

3) y = 1 + √(x + 6)

Find the domain of each square-root function.

Page 3: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 3

Adding and Subtracting Radical ExpressionsAdding and Subtracting Radical Expressions

Square-root expressions with the same radicand are examples of like radicals .

Like radicals can be combined by adding or subtracting. You can use the Distributive Property to show how this is done:

Notice that you can combine like radicals by adding or subtracting the numbers multiplied by the radical and

keeping the radical the same.

2√4 + 4√5 = √5(2 + 5) = 7√5

6√x - 2√x = √x(6 - 2) = 4√x

Page 4: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 4

Adding and Subtracting Square-Root ExpressionsAdding and Subtracting Square-Root Expressions

A) 3√7 + 8√7 = √7(3 + 8) = 11√7

B) 9√y - √y = √y(9 - 1) = 8√y

C) 12√2 - 4√11 = √x(6 - 2) = 4√x

D) -8√(3d) + 6√(2d) + 10√(3d)= √(3d)(10 - 8) + 6√(2d) = 2√(3d) + 6√(2d)

Add or subtract.

√y = √y. The terms are like radicals.

The terms are like radicals.

The terms are unlike radicals. Do notcombine.

Identify like radicals.

Combine like radicals.

Page 5: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 5

Now you try!

1a) -√71b) 3√31c) 8√n1d) √(2s) + 8√(5s)

Add or subtract.

1a) 5√7 - 6√7

1b) 8√3 - 5√3

1c) 4√n + 4√n

1d) √(2s) - √(5s) + 9 √(5s)

Page 6: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 6

Sometimes radicals do not appear to be like until they are simplified. Simplify allradicals in an expression before trying to

identify like radicals.

Page 7: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 7

Simplifying Before Adding or SubtractingSimplifying Before Adding or Subtracting

A) √(12) + √(27)

= √{(4)(3)} + √{(9)(3)}

= √4√3 + √9√3

= 2√3 + 3√3

= √3(2 + 3)

= 5√3

Add or subtract.

Factor the radicands using perfect squares.

Product Property of Square Roots

Simplify.

Combine like radicals.

Page 8: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 8

B) 3√8 + √(45)

= 3√{(4)(2)} + √{(9)(5)}

= 3√4√2 + √9√5

= 3(2)√2 + 3√5

= 6√2 + 3√5

Factor the radicands using perfect squares.

Product Property of Square Roots

Simplify.

The terms are unlike radicals. Do not combine.

Page 9: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 9

C) 5√(28x) - 8√(7x)

= 5√{(4)(7x)} - 8√(7x)

= 5√4√(7x) - 8√(7x)

= 5(2)√(7x) - 8 √(7x)

= 10√(7x) - 8 √(7x)

= 2√(7x)

Factor 28x using a perfect square.

Product Property of Square Roots

Simplify.

Combine like radicals.

Page 10: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 10

D) √(125b) + 3√(20b) - √(45b)

= √{(25)(5b)} + 3√{(4)(5b)} - √{(9)(5b)}

= √(25)√(5b) + 3√4√(5b) - √9√(5b)

= 5√(5b) + 3(2)√(5b) - 3√(5b)

= 5√(5b) +6√(5b) - 3√(5b)

= 8√(5b)

Factor the radicands using perfect squares.

Product Property of Square Roots

Simplify.

Combine like radicals.

Page 11: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 11

Now you try!

2a) 5√62b) 9√3 2c) 5√(3y)

Add or subtract.

2a) √(54) + √(24)

2b) 4√(27) - √(18)

2c) √(12y) + √(27y)

Page 12: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 12

Geometry ApplicationGeometry Application

A) 12 + 5√7 + √(28)

= 12 + 5√7 + √{(4)(7)}

= 12 + 5√7 + √4√7

= 12 + 5√7 + 2√7

= 12 + 7√7

Write an expression for perimeter.

Product Property of Square Roots

Simplify.

Find the perimeter of the triangle. Give your answer as a radical expression in simplest form.

Combine like radicals.

Factor 28 using a perfect square.

The perimeter is (12 + 7√7) cm.

Page 13: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 13

Now you try!

3 )10√b in.

3) Find the perimeter of a rectangle whose length is 2√b inches and whose width is 3√b inches. Give your answer

as a radical expression in simplest form.

Page 14: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 14

Assessment

1) 14√3 - 6√3

2) 9√5 + √5

3) 6√2 + 5√2 - 15√2

1 )8√32 )10√53- )4√2

Page 15: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 15

Simplify each expression. 4 )2√25 )17√36 )33√3

7( - )√5x)8 )2(√7c+)18√(6c)

9 )8(√2t-)4√(3t)

4) √(32) - √(8)

5) 4√(12) + √(75)

6) 2√3 + 5√(12) - 15√(27)

7) √(20x) - √(45x)

8) √(28c) + 9√(24c)

9) √(50t) - 2√(12t) + 3√(2t)

Page 16: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 16

10) Find the perimeter of the trapezoid shown. Give your answer as a radical expression in simplest form.

10) 12√2 in

Page 17: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 17

Adding and Subtracting Radical ExpressionsAdding and Subtracting Radical Expressions

Square-root expressions with the same radicand are examples of like radicals .

Like radicals can be combined by adding or subtracting. You can use the Distributive Property to show how this is done:

Notice that you can combine like radicals by adding or subtracting the numbers multiplied by the radical and

keeping the radical the same.

2√4 + 4√5 = √5(2 + 5) = 7√5

6√x - 2√x = √x(6 - 2) = 4√x

Let’s review

Page 18: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 18

Adding and Subtracting Square-Root ExpressionsAdding and Subtracting Square-Root Expressions

A) 3√7 + 8√7 = √7(3 + 8) = 11√7

B) 9√y - √y = √y(9 - 1) = 8√y

C) 12√2 - 4√11 = √x(6 - 2) = 4√x

D) -8√(3d) + 6√(2d) + 10√(3d)= √(3d)(10 - 8) + 6√(2d) = 2√(3d) + 6√(2d)

Add or subtract.

√y = √y. The terms are like radicals.

The terms are like radicals.

The terms are unlike radicals. Do notcombine.

Identify like radicals.

Combine like radicals.

Page 19: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 19

Sometimes radicals do not appear to be like until they are simplified. Simplify allradicals in an expression before trying to

identify like radicals.

Page 20: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 20

Simplifying Before Adding or SubtractingSimplifying Before Adding or Subtracting

A) √(12) + √(27)

= √{(4)(3)} + √{(9)(3)}

= √4√3 + √9√3

= 2√3 + 3√3

= √3(2 + 3)

= 5√3

Add or subtract.

Factor the radicands using perfect squares.

Product Property of Square Roots

Simplify.

Combine like radicals.

Page 21: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 21

C) 5√(28x) - 8√(7x)

= 5√{(4)(7x)} - 8√(7x)

= 5√4√(7x) - 8√(7x)

= 5(2)√(7x) - 8 √(7x)

= 10√(7x) - 8 √(7x)

= 2√(7x)

Factor 28x using a perfect square.

Product Property of Square Roots

Simplify.

Combine like radicals.

Page 22: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 22

Geometry ApplicationGeometry Application

A) 12 + 5√7 + √(28)

= 12 + 5√7 + √{(4)(7)}

= 12 + 5√7 + √4√7

= 12 + 5√7 + 2√7

= 12 + 7√7

Write an expression for perimeter.

Product Property of Square Roots

Simplify.

Find the perimeter of the triangle. Give your answer as a radical expression in simplest form.

Combine like radicals.

Factor 28 using a perfect square.

The perimeter is (12 + 7√7) cm.

Page 23: Algebra1 Adding and Subtracting Radical Expressions

CONFIDENTIAL 23

You did a great job You did a great job today!today!