XII

5714AirForce-X Group-2019

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SHRIRAM COMPETITION CLASSES PVT. LTD. SIKAR Help Line No. 9414015200

OMR SHEET CODE

Read the following passage carefully and answer thequestions given below it- Vacations were once the prerogative of the privilegedfew, even as late as the nineteenth century. Now they areconsidered the right of all, except for such unfortunatemasses an in China, for whom life, except for sleep andbrief periods of rest, is uninterrupted toil.They are more necessary now than before because theaverage life is well rounded and has become increasinglydepartmentalized. The idea of vacations, as we conceiveit, must be incomprehesible to primititive peoples. Rest ofsome kind has of course always been a part of the rhythmof human life, but earlier ages did not find it necessary toorganise it in the way that modern man has done. Holidays,feast days, were sufficient.With modern man’s increasing tensions, with the uselessquality of so much of his work, this break in the year’sroutine became steadily more necessary. Vacationsbecame necessary for the purpose of renewal repair.The author’s main purpose in this passage is to:-

explore the history of vacationstell why vacations have become more commoncontrast holiday and festive occasions with vactiondemonstrate that vacations are not really necessary

According to the passage, we need vacations now morethan ever because we have:-

a more carefree nature much more free timelittle diversity in our worka higher standard of living

It is implied in the passage that our lives are very:-habitual patrioticvaried independent

As used in the passage the word ‘prerogative’ most nearmeans:-

habit privilege request hopeThe contemporary attitude vacations is best expressedby which the following proverbs:-

A penny saved is a penny earnedThe devil finds work for idle handAll work and no play makes Jack a dull boyMany hands make light work

Direction:- Find out which part of the sentence has an error.If there is no mistake, the answer is ‘No error’.I saw him/a couple of times/since May./No error Tea/which I am drinking/is hot/No error

All though the police officer sympathized with the poor/

he refused to/take an action against the rich man/No error

Direction:- Choose the word opposite in meaning to thegiven word.PAROCHIAL

Narrow International Global Worldwide

FALLIBLEUnerring ReliableFalsehood Trustful

IMPERTINENTArrogance AppropriateRespectful Modest

Direction:- Choose the one which best expresses the meaningof the given word.BEAUTIFUL

Handsome AlluringAppealing Attractive

MOMENTOUSImportant TemporaryFleeting Monumental

INFATUATIONEmotion PassionImagination Compassion

Direction:- Choose the one which best expresses the samesentence in Passive voice.The smugglers did not realize that their conversation wasbeing recorded.

The smugglers did not realize that someone wasrecording their conversation

Someone did not realise that the smugglers wererecording their conversation

It was not realised by the smugglers that theirconversation was being recorded.

The smugglers recorded their conversation withoutrealisingThe principal kept the staff members waiting.

The staff members are kept waiting for the principalThe staff members were kept waiting by the principalThe staff members were waiting for the principalThe staff members were being kept waiting by the

principalWho taught you grammar?

By whom you were taught grammarBy whom were you taught grammarBy whom was grammar you taughtBy whom were grammar taught to you

Direction:- Fill in the blank with appropriate word.The lame boy tried to climb up the staircase without....................help.

little any some manyEach school has its own set of rules ............all good pu-pils should follow them.

but or so andPoint out the incorrect statement:

Leaving out of the sound of a part of a word inpronounciation is called Elision.

Change is a speech sound a called Elision.A sound may be affected by the sounds that precede

and or succeed it.none

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OMR SHEET CODE

Q.21 Self inductance has dimensions -[A] M1L2T–2A–2 [B] M1L1T–2A2

[C] M2L–1T–2A–1 [D] MLT–2

Q.22 Capacitance has dimensions -[A] M–1L–2T4A2 [B] M–1L2T4A2

[C] M–1L2T–4A–2 [D] M–1L2T–1A2

Q.23 E.M.F has dimensions of -[A] M1L2T–3A–1 [B] M2L2T–3A–1

[C] M2L2T3A–1 [D] M2L–2A–1

Q.24 ‘Z’ the impedance has dimensions -[A] M0L2T–2 [B] M1L2T–3A–2

[C] M1L2T–2A–1 [D] M1L1T–3A2

Q.25 The dimensions of 1/CR are -[A] M0L0T2 [B] M1L2T–1A–1

[C] M0L0T–1 [D] M0L1T–1

Q.26 Periodic time of a simple pendulum is 2 secondand it can travel to and fro from equilibrium positionupto maximum 5cm. At the starting of motion pen-dulum is at maximum displacement in right sidefrom equilibrium position.(A) y = 5 sin �t (B) y = 5 cos �t(C) y = 5 cos 2�t (D) y = 5 sin 2�t

Q.27 Amplitude of harmonic oscillator is a, when velocityof particle is half of maximum velocity, then posi-tion of particle will be

(A) a23

(B) a2

3

(C) a/2 (D) aQ.28 A particle executing S.H.M. having amplitude 0.01m

& frequency 60Hz. Maximum acceleration of par-ticle is(A) 14.4 �2 m/s2

(B) 144 �2 m/s2

(C) 1.44 �2 m/s2

(D) .144 �2 m/s2

Q.29 Two objects A and B of equal mass are suspendedfrom two springs of spring constants k

A and k

B if the

objects oscillte vertically in such a manner that theirmaximum kinetic energies are equal, then the ratioof their amplitudes is

(A) A

B

KK

(B) A

B

KK

(C) B

A

KK

(D) B

A

KK

Q.21

[A] M1L2T–2A–2 [B] M1L1T–2A2

[C] M2L–1T–2A–1 [D] MLT–2

Q.22

[A] M–1L–2T4A2 [B] M–1L2T4A2

[C] M–1L2T–4A–2 [D] M–1L2T–1A2

Q.23

[A] M1L2T–3A–1 [B] M2L2T–3A–1

[C] M2L2T3A–1 [D] M2L–2A–1

Q.24 ‘Z’

[A] M0L2T–2 [B] M1L2T–3A–2

[C] M1L2T–2A–1 [D] M1L1T–3A2

Q.25 1/CR

[A] M0L0T2 [B] M1L2T–1A–1

[C] M0L0T–1 [D] M0L1T–1

Q.26 2 sec

5cm

(A) y = 5 sin �t (B) y = 5 cos �t(C) y = 5 cos 2�t (D) y = 5 sin 2�t

Q.27 a

(A) a23

(B) a2

3

(C) a/2 (D) aQ.28 0.01m

60Hz (A) 14.4 �2 m/s2 (B) 144 �2 m/s2

(C) 1.44 �2 m/s2 (D) .144 �2 m/s2

Q.29 A B kA k

B

(A) A

B

KK

(B) A

B

KK

(C) B

A

KK

(D) B

A

KK

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OMR SHEET CODE

Q.30 A horizontal spring block system of mass M ex-ecutes simple harmonic motion. When the blockis passing through its equilibrium position an, ob-ject of mass m is put on it and the two move to-gether. Find the new amplitude.

(A) AmM

M�

(B) AM

mM �

(C) AmM

m�

(D) Am

mM �

Q.31 If Length of simple pendulum is increased by 6%then percentage change in time-period will be(A) 3 % (B) 9 %(C) 6 % (D) 1/9 %

Q.32 A rod with retangular cross section oscillates abouta horizontal axis passing through one of its endsand it behaves like a second pendulum its lengthwill be(A) 1.5 m (B) 1 m(C) 3m (D) 2m

Q.33 Infinite spring with force constant k, 2k 4k, 8k,..........respectively are connected in series. Theeffective force constant of the spring will be(A) 2k (B) k(C) k/2 (D) 2048

Q.34 One body is suspended from a spring of lenght � &spring constant k then time period is T. Now ifspring is divided in two equal parts & joined in par-allel and same body is suspended then new timeperiod will be(A) Double (B) Half(C) Same (D) None

Q.34 A tunnel has been dug through the centre of theearth and a ball is released in it. It executes S.H.M.with time period(A) 42 minutes (B) 1 day(C) 1 hour (D) 84.6 minutes

Q.36 A simple spring has length � and force constant ' K'. It is cut into two parts of lengths �

1 and �

2 such

that �1 + n�

2 (n = an Integer.) The force constant of

spring of length �1 is

(A) K(1 + n) (B) )n1(nK

�

(C) K (D) 1n

K�

Q.30 M

m

(A) AmM

M�

(B) AM

mM �

(C) AmM

m�

(D) Am

mM �

Q.31

6% (A) 3 % (B) 9 % (C) 6 % (D) 1/9 %

Q.32

(A) 1.5 m (B) 1 m(C) 3m (D) 2m

Q.33 k, 2k 4k, 8k, ............

(A) 2k (B) k(C) k/2 (D) 2048

Q.34 � ( k)

T

(A) (B)

(C) (D)

Q.35

(A) 42 minutes(B) 1 day(C) 1 hour(D) 84.6 minutes

Q.36 � '

K ' �1

�2 �

1 = n�

2 ( n = )

�1

(A) K(1 + n) (B) )n1(nK

�

(C) K (D) 1n

K�

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OMR SHEET CODE

Q.37 A spring of force constant k is out into two peaceswhose lengths are in the ratio 1 : 2. What is the.force constant of the longer peace

(A) 2k

(B) 2k3

(C) 2k (D) 3kQ.38 A spring-mass system oscillates with a frequency

' f '. If it is taken in an elevator slowly acceleratingupwards, the frequency will(A) increase(B) decrease(C) remain same(D) become zero

Q.39 The work done by a compound pendulum in onecomplete oscillation is equal to(A) the total energy of the pendulum(B) kinetic energy of the pendulum(C) potential energy of the pendulum(D) always zero

Q.40 Two pendulums of lengths 1.44 and 1 metre lengthstart swinging together. After how many vibrationsthey will again start swing together.(A) 3 (B) 4(C) 5 (D) 6

Q.41 Two pendulums have time-period T and 5T/4. Theystart S.H.M. at the same time from the mean posi-tion. What will be the phase difference betweenthem after the bigger pendulum has completed oneoscillation(A) 45° (B) 90°(C) 60° (D) 30°

Q.42 If a simple pendulum oscillates in water instead ofair then the time period will(A) decrease slightly(B) increase slightly(C) remain the same(D) decrease considerably

Q.43 A hollow metal sphere is filled with water and hungpy a long thread. A small hole is drilled at the bot-tom through which water slowly flows out. Now thesphere is made to oscillate, the period of oscilla-tion of the pendulum(A) remains constant(B) continuously decreases(C) continuously increases(D) first increases and then decreases

Q.37 (k)

1 : 2

(A) 2k

(B) 2k3

(C) 2k (D) 3kQ.38

' f '

(A)

(B)

(C)

(D)

Q.39

(A)

(B)

(C)

(D)

Q.40 1.44 1

(A) 3 (B) 4(C) 5 (D) 6

Q.41 T 5T/4

(A) 45° (B) 90°(C) 60° (D) 30°

Q.42

(A)

(B)

(C)

(D)

Q.43

(A)

(B)

(C)

(D)

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SHRIRAM COMPETITION CLASSES PVT. LTD. SIKAR Help Line No. 9414015200

OMR SHEET CODE

Q.44 A simple pendulum has some time period T. Whatwill be the % change in its time-period if its ampli-tude is decreased by 6%(A) 6%(B) 3%(C) 1.5%(D) It will remain unchanged

Q.45 A simple pendulum has T = 2 sec at a place whereg = 9.81 m/s2. Its time-period T' will be how muchat another place where g' = 4.36 m/s2 ?(A) 3 sec(B) 1.5 sec(C) 4/3 sec(D) 2/3 sec

Q.46 A simple pendulum of period T has a metal bobwhich is negatively charged. If its is allowed to os-cillate above a large positively charged metallicplate, its period(A) remains the same(B) decreases(C) increases(D) nothing can be said definitely

Q.47 The length of a simple pendulum is equal to theradius of the earth (R). Its time-period will be

(A) gR

2� (B) g2R

2�

(C) gR2

2� (D) indeterminate

Q.48 The equation of S.H.M. of a particle is

0kydt

yd2

2

�� , where ��is a positive constant. The

time period of motion is given by

(A) k

2�(B)

k2�

(C) 2�k (D) 2 �� kQ.49 A particle executing S.H.M. has maximum veloc-

ity 'a' and maximum acceleration �, the period ofoscillation shall be(A) 2�(�/�)(B) 2�(�/�)(C) 2�(�/�)1/2

(D) 2�(�/�)1/2

Q.44 T

6%

(A) 6%(B) 3%(C) 1.5%(D)

Q.45 T = 2 sec

g = 9.81 m/s2

g' = 4.36 m/s2 T

(A) 3 sec (B) 1.5 sec(C) 4/3 sec (D) 2/3 sec

Q.46 (T)

(A)

(B)

(C)

(D)

Q.47 (R)

(A) gR

2�

(B) g2R

2�

(C) gR2

2�

(D)

Q.48

0kydt

yd2

2

�� K

(A) k

2�(B)

k2�

(C) 2�k (D) 2 �� k

Q.49 '�'

'�'(A) 2�(�/�) (B) 2�(�/�)(C) 2�(�/�)1/2 (D) 2�(�/�)1/2

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SHRIRAM COMPETITION CLASSES PVT. LTD. SIKAR Help Line No. 9414015200

OMR SHEET CODE

Q.50 The equation of motion of a particle executing SHMis (k is a positive constant)

(A) 0xmk

dt

xd2

2

�� (B) 0xmk

dtdx

��

(C) 0xmk

dtdx

2

����

���

�(D) 0x

mk

dt

xd2

2

��

Q.51 The Young’s modulus of a wire of length L andradius r is = Y N/m2. If the length and radiusare reduced to L/2 and r/2, then its Young’smodulus will be :(A) Y/2 (B) Y(C) 2 Y (D) 4 Y

Q.52 To break a wire, a force of 106 N/m2 is required.If the density of the material is 3 × 103 kg/m3,then the length of the wire which will break byits own weight will be :(A) 34 m (B) 30 m(C) 300 m (D) 3 m

Q.53 A rod (Young’s modulus = 7 × 109 N/m2) has abreaking strain of 0.2%. The minimum crosssectional area of the rod in order to support aload of 104 newtons is :(A) 1 × 10–2 m2 (B) 1.4 × 10–3 m2

(C) 3.5 × 10–3 m2 (D) 7.1 × 10–4 m2

Q.54 In steel, the Young’s modulus and the strainat the breaking point are 2 × 1011 Nm–2 and0.15 respectively. The stress at the breakingpoint for steel is therefore(A) 1.33 × 1011 Nm–2 (B) 1.33 × 1012 Nm–2

(C) 7.5 × 10–13 Nm–2 (D) 3 × 1010 Nm–2

Q.55 Which of the following statements is correct :(A) Hooke’s law is applicable only within elasticlimit(B) The adiabatic and isothermal elastic constants(Bulk Modulus) of a gas are equal at same pressure(C) Young’s modulus is dimensionless(D) Stress multiplied by strain is equal to the storedenergy

Q.56 The force required to stretch a steel wire of 1cm2 cross-section to 1.1 times its length wouldbe(Y = 2 × 1011 Nm–2)(A) 2 × 106 N (B) 2 × 103 N(C) 2 × 10–6 N (D) 2 × 10–7 N

Q.50

( k )

(A) 0xmk

dt

xd2

2

�� (B) 0xmk

dtdx

��

(C) 0xmk

dtdx

2

����

���

�(D) 0x

mk

dt

xd2

2

��

Q.51 L r Y N/m2 L/2 r/2

(A) Y/2 (B) Y(C) 2 Y (D) 4 Y

Q.52 106 N/m2 3 × 103 kg/m3

(A) 34 m (B) 30 m(C) 300 m (D) 3 m

Q.53 = 7 ×109 N/m2 0.2%

104

(A) 1 × 10–2 m2 (B) 1.4 × 10–3 m2

(C) 3.5 × 10–3 m2 (D) 7.1 × 10–4 m2

Q.542 × 1011 Nm–2 0.15

(A) 1.33 × 1011 Nm–2

(B) 1.33 × 1012 Nm–2

(C) 7.5 × 10–13 Nm–2

(D) 3 × 1010 Nm–2

Q.55(A)

(B)

(C) (D)

Q.56 1.1 1 cm2

2 × 1011 Nm–2

(A) 2 × 106 N (B) 2 × 103 N(C) 2 × 10–6 N (D) 2 × 10–7 N

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OMR SHEET CODE

Q.57 Which one of the fol lowing substancespossesses the highest elasticity :(A) Rubber (B) Glass(C) Steel (D) Copper

Q.58 Which one of the following quantities does nothave the unit of force per unit area :(A) Stress(B) Strain(C) Young’s modulus of elasticity(D) Pressure

Q.59 A copper wire and a steel wire of the samediameter and length are connected end to endand a force is applied, which stretches theircombined length by 1 cm. The two wires willhave :(A) Different stresses and strains(B) The same stress and strain(C) The same strain but different stresses(D) The same stress but different strains

Q.60 A copper wire and a steel wire of the same diam-eter and length 1m and 2m respectively are con-nected end to end and a force is applied whichstretches their combined length by 1cm. Howmuch each wire is elongated respectively. Y ofcopper =1.2×1010 Nm–2 and Y of steel = 2.0 × 1010

Nm–2.(A) 0.45 cm, 0.55 cm(B) 0.55 cm, 0.45 cm(C) 0.045 cm, 0.55 cm(D) 0.45 cm, 0.055 cm

Q.61 Four wires of the same material are stretched bythe same load. The dimension of the wires are asgiven below. The one which has the maximumelongation is of -(A) diameter 1 mm and length 1 m(B) diameter 2 mm and length 2 m(C) diameter 0.5 mm and length 0.5 m(D) diameter 3 mm and length 3 m

Q.62 Four wires of different material but the same areaof cross-section are loaded by the same force.Their lengths and elongations are as follows. Theone whose material’s Young’s modulus is the larg-est is -(A) L = 2m, ��= 1 mm(B) L = 1 m,�� = 0.25 mm(C) L = 1.5 m, �� = 0.5 mm(D) L = 2.5 m, �� = 1.5 mm

Q.57

(A) (B) (C) (D)

Q.58

(A) (B) (C) (D)

Q.59

1

(A) (B) (C) (D)

Q.60 1m 2m

1cm

Y =1.2×1010 Nm–2 Y = 2.0 × 1010 Nm–2.(A) 0.45 cm, 0.55 cm(B) 0.55 cm, 0.45 cm(C) 0.045 cm, 0.55 cm(D) 0.45 cm, 0.055 cm

Q.61

(A) 1 mm 1 m(B) 2 mm 2 m(C) 0.5 mm 0.5 m(D) 3 mm 3 m

Q.62

(A) L = 2m, ��= 1 mm(B) L = 1 m,�� = 0.25 mm(C) L = 1.5 m, �� = 0.5 mm(D) L = 2.5 m, �� = 1.5 mm

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OMR SHEET CODE

Q.63 When a wire is stretched to double its length(A) strain is unity(B) stress is equal to Young’s modulus ofelasticity(C)Young’s modulus is equal to twice the elasticpotential energy per unit volume(D) All of these

Q.64 Let Yg and Y

r represent Young's modulus for glass

and rubber respectively. It is said that glass ismore elastic than rubber. Therefore, it follows(A) Y

g = Y

r(B) Y

g < Y

r

(C) Yg > Y

r(D) Y

g / Y

r = 0

Q.65 A cube of aluminium of sides 0.1 m issubjected to a shearing force of 100 N. Thetop face of the cube is displaced through 0.02cm with respect to the bottom face. Theshearing strain would be :(A) 0.02 (B) 0.1(C)0.005 (D) 0.002

Q.66 A square lead slab of side 50 cm and thickness5.0 cm is subjected to a shearing force (on itsnarrow face) of magnitude 9.0 × 104 N. The loweredge is riveted to the floor. The upper edge dis-placement if the shear modulus of lead is 5.6 x109 Pa will be (Pa means Pascal = Nm–2).(A) 3.2 × 10–3 m (B) 3.2 × 10–6 m(C) 3.2 × 10–5 m (D) 3.2 × 10–4 m

Q.67 A cube is subjected to a uniform volume com-pression. If the side of the cube decreases by2%, the bulk strain is -(A) 0.02 (B) 0.03(C) 0.04 (D) 0.06

Q.68 The isothermal elasticity of a gas is equal to :(A) Density (B) Volume(C) Pressure (D) Specific heat

Q.69 The adiabatic elasticity of a gas is equal to(A) � × density(B) � × volume(C) � × pressure(D) � × specific heat

Q.70 The only elastic modulus that applies to fluidsis :(A) Young’s modulus(B) Shear modulus(C) Modulus of rigidity(D) Bulk Modulus

Q.63

(A) (B) (C)

(D)

Q.64 Yg Y

r

(A) Yg = Y

r(B) Y

g < Y

r

(C) Yg > Y

r(D) Y

g / Y

r = 0

Q.65 0.1 m 100 N

0.02 cm :

(A) 0.02 (B) 0.1(C)0.005 (D) 0.002

Q.66 50 cm 5.0 cm 9.0 × 104 N

5.6 x 109 Pa(Pa = Nm–2)

(A) 3.2 × 10–3 m (B) 3.2 × 10–6 m(C) 3.2 × 10–5 m (D) 3.2 × 10–4 m

Q.67 2% –

(A) 0.02 (B) 0.03(C) 0.04 (D) 0.06

Q.68(A) (B) (C) (D)

Q.69(A) � × (B) � × (C) � × (D) � ×

Q.70(A) (B) (C) (D)