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Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

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Page 1: Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

Aim: Rational Inequalities Course: Adv. Alg. & Trig.

Aim: How do we solve various inequality problems?

Do Now:

Graph the solution set of

3x + 5 > 14

Page 2: Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

Aim: Rational Inequalities Course: Adv. Alg. & Trig.

Rational Inequalities

34

x

x

34

x

x

What values of x makes this statement true?

3 4x x

12 3x x

4 12x

3x

cross-multiply?

distribute

isolate variable

divide

check:2

3 1 3 true4 2

53 5 3

4 5

x = 5

also true!

Page 3: Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

Aim: Rational Inequalities Course: Adv. Alg. & Trig.

Rational Inequalities

34

x

x

34

x

x

What values of x makes this statement true?

3 04

x

x

standard form to

find zeros

3 40

4 4

xx

x x

subtract -

LCD

3 40

4

x x

x

Combine & Simplify

12 3 4 120

4 4

x x x

x x

Find zeros of Numerator & Denominator

4x – 12 = 0

4 – x = 0

x = 3

x = 4

critical values

Page 4: Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

Aim: Rational Inequalities Course: Adv. Alg. & Trig.

Rational Inequalities - Algebraically

Test Interval

Representative x-value

Value of Polynomial

(-, 3) x = 0 y = -3

(3, 4) x = 3.5(4, ) x = 10

y = 4

y = -4 2/3

Find zeros of Numerator & Denominator

4x – 12 = 0

4 – x = 0

x = 3

x = 4

critical values

34

x

x

3 0

4

x

x

4 12

04

x

x

-10 -5 5 100

34

x

x

( ,3) (4, )

()

Page 5: Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

Aim: Rational Inequalities Course: Adv. Alg. & Trig.

Rational Inequalities - Algebraically

2x 7

x 53

Algebraically, find the zeros, the critical numbers and test intervals of

2x 7

x 5 3 0 Standard form

to find zeroes

2x 7 3x 15

x 50 Add fractions

x 8

x 50 Simplify

to find zeroes

critical numbers: x = 8; x = 5

Note: rational expressions change sign at its zeros and its undefined values.

=

Page 6: Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

Aim: Rational Inequalities Course: Adv. Alg. & Trig.

Rational Inequalities - Algebraically

2x 7

x 53

Algebraically find the zeros, the critical numbers and test intervals of

x 8

x 50 critical numbers: x = 8

x = 5

Test Interval

Representative x-value

Value of Polynomial

(-, 5) x = 0 y = -8/5

(5, 8] x = 6[8, ) x = 10

y = 2

y = -2/5

2x 7

x 53

( ,5) [8, )

Page 7: Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

Aim: Rational Inequalities Course: Adv. Alg. & Trig.

2

-2

-4

5 10

h x = 2x-7

x-5-3

Rational Inequalities

2x 7

x 53Solve

2x 7

x 5 3 0

Standard form

Graphically:

y is negative from(-, 5) and [8, )

2x 7

x 5 3 y

(8, 0)

< 0

Page 8: Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

Aim: Rational Inequalities Course: Adv. Alg. & Trig.

Using the Graphing Calculator

2x 7

x 53

x 8

x 50

x 8

x 5Y1

= (-x + 8)/(x – 5) Y1

2nd MATH 6 GRAPH0

≤ 0

Page 9: Aim: Rational Inequalities Course: Adv. Alg. & Trig. Aim: How do we solve various inequality problems? Do Now: Graph the solution set of 3x + 5 > 14

Aim: Rational Inequalities Course: Adv. Alg. & Trig.

Model Problem

1 31

2 4t t Solve

Test Interval

Representative t-value

Value of Polynomial

(-, 0)(0, 1.25]

[1.25, )

t = -1t = 1

t = 10

f(t) = -9/4f(t) = 1/4

f(t) = -36/40

Note: rational expressions change sign

at its zeros and its undefined values.

1 31 0

2 4t t

1 34 1 0

2 4t

t t

5 4 0

1 25.

t

t

==

1 31 0

2 4t t

critical numbers: t = 0; t = 1.25

2

-2

(1.25, 0)(0, 0)