aim: law of cosines course: alg. 2 & trig. aim: what is the law of cosines? do now: if the...
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Aim: Law of Cosines Course: Alg. 2 & Trig.
Aim: What is the Law of Cosines?
Do Now:
If the measures of two sides and theincluded angle of a triangle are known,can the size (area) and shape of the triangle be determine?
Yes
Aim: Law of Cosines Course: Alg. 2 & Trig.
SAS SASSAS SAS
B
A
C
2 sides and included angle:
AB A’B’, BC B’C’, B B’
2 sides and included angle:
AB A’B’, BC B’C’, B B’
B’
A’
C’
B’
A’
C’
Shortcut for proving congruence in triangles:
Measurements showed: ABC A’B’C’ABC A’B’C’
SAS
Aim: Law of Cosines Course: Alg. 2 & Trig.
Area of Triangle
y
x
(b cos A, b sin A)
b
c
a h
A B
C
Area of ABC 1
2ab sinC
1
2ac sinB
1
2bc sin A
The area of a triangle is equal to one-halfthe product of the measures of two sidesand the sine of the angle between them.
A case
Aim: Law of Cosines Course: Alg. 2 & Trig.
Area of Triangle & Law of Cosines
y
x
(b cos A, b sin A)
b
c
a
A B(c,0)
C
Use the distance formula to find length of a
(0,0)
212
212 )()( yyxxd
a (bcos A c)2 (bsinA 0)2
a (bcos A c)2 (bsinA 0)2
a (b2 cos2 A 2bc cos A c 2) (b2 sin2 A)
a2 b2 cos2 A 2bc cos A c2 b2 sin2 A
a2 b2(cos 2 A sin2 A) 2bc cosA c2
a2 b2 2bc cos A c2
a2 b2 c 2 2bc cos A
AB = cAC = bBC = a
Aim: Law of Cosines Course: Alg. 2 & Trig.
Law of Cosines
a2 b2 c 2 2bc cos A
The square of the measure of one side of atriangle is equal to the sum of the squaresof the measures of the other two sides minustwice the product of the measures of thesetwo sides and the cosine of the angle betweenthem.
a2 b2 c 2 2bc cos A
b2 a2 c 2 2ac cosB
c 2 a2 b2 2abcosC
Law of Cosines
Aim: Law of Cosines Course: Alg. 2 & Trig.
What does it all mean?
a2 b2 c 2 2bc cos A
If you do know the measures of two sides and the included angle of a triangle, thenyou can determine the size and shape of the triangle.
a = ?
A B
C
35
b
c
If I know the measuresof A, b, and c, thenI can find the measureof side a.
ex. Find a if mA = 35, b = 16, and c = 7
a2 162 72 2(16)(7)cos35
a2 121.5099421to nearest tenth
16
7
a 11.0
11
Aim: Law of Cosines Course: Alg. 2 & Trig.
Model Problem
b2 a2 c 2 2ac cosB
In ∆ABC, if a = 4, c = 6, and cos B = 1/16,find b.
b2 42 62 2(4)(6)(1/ 16)
Appropriateversion of Lawof Cosines
Substituteand solve:
b2 49
b 7 must be positive
B
A
Ca
bc
Aim: Law of Cosines Course: Alg. 2 & Trig.
Draw:
Model Problem
t 2 r 2 s 2 2rscosT
In ∆RST, if r = 11, s = 12, and mT = 120,find t to the nearest integer.
Appropriateversion of Lawof Cosines interms of r, s &T
Substituteand solve:
t 2 265 264( .5)
S
RT
t
s = 12
r = 11120º
t 2 112 122 2(11)(12) cos120
t2 = 397
t = 19.92485885must be positive
t = 20 to nearestinteger
Aim: Law of Cosines Course: Alg. 2 & Trig.
Finding Angle Measures
In ∆ABC, a = 5, b = 7, and c = 10. Find cos B.
Appropriateversion of Lawof Cosines solvedfor cos B
Substituteand solve:
b2 a2 c 2 2ac cosB
cosB a2 c2 b2
2ac
cosB 52 102 72
2(5)(10)
cosB .76
cosB a2 c2 b2
2ac
cos A b2 c2 a2
2bc
cosC a2 b2 c 2
2ab
Law of Cosinessolved for cosine of angles
Aim: Law of Cosines Course: Alg. 2 & Trig.
Model Problem
In isosceles triangle RED, RE = ED = 5 andRD = 8. Find the measure of the vertex angle,E, to the nearest degree.
cosE r 2 d2 32
2rd
E
DR
t r = 5d = 5
120ºe = 8Draw:
Appropriateversion of Lawof Cosines solvedfor cos E
cosE 52 52 82
2(5)(5)
cosE 52 52 82
2(5)(5)
cos E = -.28
Substitute &solve:
mE ≈ 106
Aim: Law of Cosines Course: Alg. 2 & Trig.
Regents Question
In triangle DEF, side e = 10, f = 8 and mD = 110. Find the length of the third side to the nearest tenth.
1) 218.7 2) 109.3 3) 14.8 4) 10.5
Aim: Law of Cosines Course: Alg. 2 & Trig.
The Product Rule
A surveyor at point P sights two points X and Y that are on opposite sides of a lake. If P is 200 m. from X and 350 m. from Y, and mXPY = 40, find the distance from X to Y to the nearest meter.