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Best & effective Solution of Structural Technology. BeST Ver 2.6

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175

350

11

7

x

y

Unit : cm

As = 63.14Ix = 13600 Iy = 984Zx = 868 Zy = 174J = 19 Cw = 283000

Design ConditionsDesign Code : AISC-2005(LRFD)

Section Size : ㅐ-350x175x7x11

Steel Material Fy = 345 N/mm2 (A992)

Unbraced Lengths Lx = 3.16, Ly = 3.16 m

Lb = 3.16 m

EffectiveLengthFact. Kx = 1.00, Ky = 1.00

Modification Factor Cb = 1.00

Design Force and Moment Pu = 0.0 kN

Mux = 28.2, Muy = 0.0 kN·m

Vux = 0.0, Vuy = 4.4 kN

Check Thickness Ratios for Flexure

Check Flange -. λp = 0.38 E/Fy = 9.15

-. λr = 1.0 E/Fy = 24.09

-. bf/2tf = 7.95 < λp ---> Compact Section

Check Web -. λp = 3.76 E/Fy = 90.56

-. λr = 5.70 E/Fy = 137.29

-. h/tw = 42.86 < λp ---> Compact Section

Check Flexural Strength about Major Axis

Compute Yielding Strength -. Mp = Fy*Zx = 299.24 kN·m

Compute Lateral-Torsional Buckling -. Lp = 1.76ry E/Fy = 1.67 m

-. Lr = 1.95rts E0.7Fy

JcSxho

... = 4.72 m

-. Mn,LTB = Cb[Mp-(Mp-0.7FySx)( Lb-Lp

Lr-Lp )] = 244.45 kN·m

Compute Flexural Strength about Major Axis -. Mnx = Min[Mp, Mn,LTB] = 244.45 kN·m

-. ΦMnx = Φ*Mnx = 220.01 kN·m

Check Interaction of Combined Strength -. Pu/ΦPn < 0.20

-. Ratio = Pu

2ΦPn+[ Mux

ΦMnx+ Muy

ΦMny ] = 0.128 < 1.000 ---> O.K.

Check Shear Strength

Check Shear Strength in Local-y Direction -. λr = 2.24* E/Fy = 53.95

-. h/t = 42.86 < λr

-. Cv = 1.00

-. Vn = 0.6*Fy*Aw*Cv = 506.77 kN

-. ΦVny = Φ*Vn = 506.77 kN

Designer :Project Name :

Best & effective Solution of Structural Technology. BeST Ver 2.6

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Date : Page :

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-. Vuy/ΦVny = 0.009 < 1.000 ---> O.K.