activity – sets of 3 r th term r+1 th term first few terms

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Activity – sets of 3 Activity – sets of 3 r r th th term term r+1 r+1 th th term term first few terms first few terms

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Activity – sets of 3Activity – sets of 3

rrthth term term

r+1r+1thth term term

first few termsfirst few terms

Sequences and SeriesSequences and Series Use subscript notationUse subscript notation

Generate a sequence using a ruleGenerate a sequence using a rule

Generate a sequence using inductive definitionGenerate a sequence using inductive definition

Describing the behaviour of a sequenceDescribing the behaviour of a sequence

SequencesSequences

Finite Infinite

2 4 3 1 4 1, 4, 7, 10…

A finite sequence has a first and last term

A infinite sequence goes on forever

NotationNotation

If we say un = 3n - 5

u1 = 3(1) - 5

u2 = 3(2) - 5

u3 = 3(3) - 5

u4 = 3(4) - 5

u5 = 3(5) - 5

= -2

= 1

= 4

= 7

= 10

SequencesSequences

For each of the following, work out the first 6 terms, the 50th term and the 100th term. Describe what happens as n gets larger.

un = 3n + 2

cn = 7 – 4n

kn = n2 – 2n + 8

rn = (-2)n

ntn

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Inductive DefinitionInductive Definition

u1 = 3 u2 = 8 u3 = 13 u4 = 18

Write down the terms of the sequence un = 5n - 2

Inductive DefinitionInductive Definition

u1 = 3 u2 = 8 u3 = 13 u4 = 18

Each term is 5 more than the last

u2 = u1 + 5

u3 = u2 + 5

u4 = u3 + 5

We could write this as:

un+1 = un + 5

Next term Current term

Inductive DefinitionInductive Definition

This is called a recurrence relation

un+1 = un + 5

Inductive DefinitionInductive Definition

Write down a sequence using the recurrence relation above.

un+1 = un - 3

What extra information do I need?

Inductive DefinitionInductive Definition

In order to write a sequence when given a recurrence relation, I need to know the first term.

un+1 = un - 3

Inductive DefinitionInductive Definition

Now write the sequence

un+1 = un - 3u1 = 7

u1 = 7 u2 = 4 u3 = 1 u4 = -2 u5 = -5

ProblemProblemA sequence is defined by u1 = 3 un+1 = un + k

If u4 = 7.5, find k

u1 = 3

u2 = 3 + k

u3 = 3 + k + k = 3 + 2k

u4 = 3 + 2k + k = 3 + 3k

3 + 3k = 7.5 k = 1.5

Un+1 = un + 1.5

QuizQuiz