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TRANSCRIPT
Acids & Bases
They are everywhere..
In your food
In your house
EVEN IN YOU!!!!!
What is an acid?• An acid is a solution that has an excess of
H+ ions. It comes from the Latin word
acidus that means "sharp" or "sour".
• The more H + ions, the more acidic the
solution.
Properties of an Acid
• Tastes Sour
• Conduct Electricity
• Corrosive, which means they
break down certain substances.
Many acids can corrode fabric,
skin,and paper
• Some acids react strongly with
metals
• Turns blue litmus paper red
Picture from BBC Revision Bites
http://www.bbc.co.uk/schools/ks3bitesize/science/chemistry/acids_b
ases_1.shtml
Uses of Acids
• Acetic Acid = Vinegar
• Citric Acid = lemons, limes, & oranges. It is in many sour candies such as lemonhead & sour patch.
• Ascorbic acid = Vitamin C which your body needs to function.
• Sulfuric acid is used in the production of fertilizers, steel, paints, and plastics.
• Car batteries
What is a base?
• A base is a solution that
has an excess of OH-
ions.
• Another word for base
is alkali.
• Bases are substances
that can accept
hydrogen ions
Properties of a Base
• Feel Slippery
• Taste Bitter
• Corrosive
• Can conduct electricity.
(Think alkaline batteries.)
• Do not react with metals.
• Turns red litmus paper blue.
Uses of Bases• Bases give soaps, ammonia,
and many other cleaning products some of their useful properties.
• The OH- ions interact strongly with certain substances, such as dirt and grease.
• Chalk and oven cleaner are examples of familiar products that contain bases.
• Your blood is a basic solution.
pH Scale
• pH is a measure of how acidic or basic a
solution is.
• The pH scale ranges from 0 to 14.
• Acidic solutions have pH values below 7
• A solution with a pH of 0 is very acidic.
• A solution with a pH of 7 is neutral.
• Pure water has a pH of 7.
• Basic solutions have pH values above 7.
pH Scale
• A change of 1 pH unit represents a tenfold change in the acidity of the solution.
• For example, if one solution has a pH of 1 and a second solution has a pH of 2, the first solution is not twice as acidic as the second—it is ten times more acidic.
Acid – Base Reactions
• A reaction between an
acid and a base is called
neutralization. An acid-
base mixture is not as
acidic or basic as the
individual starting
solutions.
Molarity
• Molar concentration (M) defines the
number of moles of a species per
litre of solution (mol.L-1)
• One mole is the formula weight of a
substance expressed in grams.
Molarity Example
• Na2SO4 has a formula weight (molar
mass) of 142 g
• A one litre solution containing 14.2 g
of Na2SO4 has a molarity of 0.1 M
(mol.L-1)
• Na2SO4 dissociates in water:
Na2SO4 = 2Na+ + SO42-
• The molar concentrations of Na+ and
SO 2- are 0.2 M and 0.1 M
Definitions of Acids and Bases:
• Arrhenious Acids and Bases
• Bronstead Lowry Acids and Bases
• Acid: a substance that produces H3O+
when dissolved in water.
• Base: a substance that produces OH-
when dissolved in water.
• Arrhenius acids and bases are limited to
water solutions.
Arrhenius Acids and Bases
** This definition is not
very flexible**
• Acid: proton donor.
• Base: proton acceptor.
• Bronsted-Lowry acid base
reaction: proton transfer from acid
to base.
Bronsted-Lowry Acids and Bases style
• Conjugate Acid-Base Pairs: two
species that differ by a proton.
• Acid : the species that contains the
proton that is transferred.
• Conjugate base: the species formed by
loss of the proton.
HF(aq) + H2O(l) ⇌ F-(aq) + H3O+(aq)
• HF and F- make up an acid-base
conjugate pair. F- is the conjugate base
of HF.
Conjugate Acid-Base Pairs
Acid Base
HCl Cl -
H2SO4 HSO4-
HSO4- SO4
2-
NH4+ NH3
H3O+ H2O
H2O OH-
H2O is amphoteric - it acts as both
an acid and a base.
Acid-Base Conjugate Pairs
acid + base⇌ conj. base + conj. acid
HF + NH3 ⇌ F- + NH4+
HCl + H2O ⇌ Cl- + H3O+
H2O + NH2- ⇌ OH- + NH3
Bronsted-Lowry Acid-Base Reactions
Identify the acid-base conjugate pairs
HNO2(aq) + H2O(l) ⇌ H3O+(aq) + NO2
-(aq)
CH3NH2(aq) + H2O(l) ⇌ CH3NH3+(aq) + OH-(aq)
Test Your Skill
H2O(l) + H2O(l) ⇌ H3O+(aq) + OH-(aq)
• H3O+ and H2O are a conjugate acid-
base pair.
• H3O+ and OH - are a conjugate acid-
base pair.
Autoionization of Water
H2O(l) + H2O(l) ⇌ H3O+(aq) + OH-(aq)
• The equilibrium constant for this
reaction is called Kw.
• Kw = [H3O+][OH -]
• Kw changes with temperature and is
equal to 1.0 × 10-14 at 25o C.
Autoionization of Water
H2O(l) + H2O(l) ⇌ H3O+(aq) + OH-(aq)
• In pure water, [H3O+] = [OH -].
Kw = [H3O+][OH -] = 1.0 × 10-14
Kw = [H3O+]2 = 1.0 × 10-14
• [H3O+] = [OH -] = 1.0 × 10-7 M
Calculating Hydrogen and Hydroxide Ion
Concentrations
• Adding an acid or a base to water
causes the H3O+ and OH-
concentrations to change.
• Calculate the hydroxide ion
concentration of a solution in which
the hydrogen ion concentration is
3.6 × 10-3 M.
Acidic or Basic Solutions
• Calculate the hydrogen ion
concentration in a solution in which
the hydroxide ion concentration is
0.025 M.
Test Your Skill
Calculating pH:
Identifying Acids and Bases
• Acids have a ph from 0-7
• Lower pH value indicates
a stronger acid.
• Bases have a pH from
7-14
• Higher pH value indicates
a stronger base.
• Calculate the hydrogen ion concentration
in a solution that has a pH of 3.52.
Calculating Hydrogen Ion Concentration from
pH
[H3O+][OH-] = Kw = 1.0 × 10-14
log([H3O+][OH-]) = log Kw
log[H3O+] + log[OH-] = log Kw
-log[H3O+] - log[OH-] = -log Kw
pH + pOH = pKw
pH + pOH = 14.00
Relating pH and pOH
• HA(aq) + H2O(l) H3O+(aq) +A-(aq)
• Strong acids ionize completely in
solution.
• Memorize the six common strong acids:
HCl, HBr, HI, HNO3, HClO4, and H2SO4.
100%
Strong Acids and Bases
• Calculate the pOH of a 0.050 M HCl
solution.
pH of a Strong Acid Solution
• Strong bases quantitatively produce
hydroxide ions in water.
• The most common strong bases are the
group IA and soluble IIA oxides and
hydroxides.
Strong Bases
• Calculate the pH of a 0.035 M Ba(OH)2
solution.
pH of a Strong Base Solution
What is the concentration of a solution of
HCl if the pH is 3.75?
What is the concentration of a solution of
KOH if the pH is 11.60?
Test Your Skill
Titration Equipment
• Stand
• Buret
• Buret clamp
• Erlenmeyer Flask (diagram shows a beaker)
• Analyte (unknown molarity)
• Titrant (standard solution of known molarity)
• Indicator
• pH meter (optional, but highly recommended)
• Stirrer (optional, recommended)
Around the Endpoint
• You have reached the
endpoint when the
indicator first
permanently changes
color.
• There will be a very
large jump in pH as all
of the analyte is
reacted, and there is
now excess titrant. Example of a solution using
phenolphthalein as a indicator.
The reaction has just reached
the equivalence point, because
the solution has just
permanently turned pale pink.
37
Molarity
Let’s start our discussion of solution concentration
Measurement with
Molarity: the most common solution concentration
measurement is defined as follows:
M = moles of solute
LITERS of solution
Which means Molarity = # of moles per liter of solution
MOLARITY
Capital M
38
Molarity
Let’s Consider the following Problem:
What is the molarity of a solution in which 50g of
CuSO4 is dissolved in water to make a 2 liter solution.
Step 1. What’s the formula for MOLARITY?
M = moles of solute
liters of solution
39
Molarity
Step 2. We need to determine how many moles we have
in 50g of CuSO4 .
How do we do that? Remember the mole Hole?
- 1. Determine the molar mass of CuSO4
(159.5g/mol)
- 2. Calculate the # of moles of CuSO4
Since we’re going into the mole hole we need
to DIVIDE # of grams by molar mass
(50/159.5) = 0.31 moles
40
Molarity
Step 3. Calculate the Molarity of the solution using
the formula for MOLARITY
M = moles of Solute
liters of solution
How many moles do we have?
How many liters do we have?
So M = 0.31 moles
2 liters M = 0.155 mol/liter
0.31 mol
2 L
41
Molarity by dilution
In a titration the endpoint is reached when the
moles of each substance are equalt.
However, the moles are not provided only volume and
concentration. Therefore,
M1 x V1 = M2 x V2
If we know three values we can calculate the 4th.
Let’s see how we use this relationship
42
Dilution Problem
What is the concentration of Nitric acid if 12ml of
the acid reaches an equivalence point when 30ml
of 1.6M sodium hydroxide is added to it.
M1 x V1 = M2 x V2
[acid] x 12ml = [1.6M] x 30ml
[acid] x Volume acid = [base] x Volume base