acceleration: a change in velocity!. an object traveling at the same rate in the same direction, is...
DESCRIPTION
Any speeding up, slowing down, or change in the direction of motion means that velocity is changing. Any of this is acceleration. a = v t v = 6 m/s [S] v = 6 m/s [W]TRANSCRIPT
![Page 1: Acceleration: a change in Velocity!. An object traveling at the same rate in the same direction, is in uniform motion. NON uniform motion - there must](https://reader036.vdocuments.us/reader036/viewer/2022082419/5a4d1b717f8b9ab0599b564c/html5/thumbnails/1.jpg)
Acceleration:a change in Velocity!
![Page 2: Acceleration: a change in Velocity!. An object traveling at the same rate in the same direction, is in uniform motion. NON uniform motion - there must](https://reader036.vdocuments.us/reader036/viewer/2022082419/5a4d1b717f8b9ab0599b564c/html5/thumbnails/2.jpg)
An object traveling at the same rate in the same direction, is in uniform motion.
NON uniform motion - there must be an increase or decrease in Velocity.
Acceleration is a vector quantity. It is the rate at which velocity CHANGES with time.
a
![Page 3: Acceleration: a change in Velocity!. An object traveling at the same rate in the same direction, is in uniform motion. NON uniform motion - there must](https://reader036.vdocuments.us/reader036/viewer/2022082419/5a4d1b717f8b9ab0599b564c/html5/thumbnails/3.jpg)
Any speeding up, slowing down, or change in the direction of motion means that velocity is changing.
Any of this is acceleration.
a = v t
v = 6 m/s [S]
v = 6 m/s [W]
![Page 4: Acceleration: a change in Velocity!. An object traveling at the same rate in the same direction, is in uniform motion. NON uniform motion - there must](https://reader036.vdocuments.us/reader036/viewer/2022082419/5a4d1b717f8b9ab0599b564c/html5/thumbnails/4.jpg)
=
∆t∆va
= vfinal - vinitial
tfinal - tinitial
![Page 5: Acceleration: a change in Velocity!. An object traveling at the same rate in the same direction, is in uniform motion. NON uniform motion - there must](https://reader036.vdocuments.us/reader036/viewer/2022082419/5a4d1b717f8b9ab0599b564c/html5/thumbnails/5.jpg)
If a cheetah reaches a speed of 19 m/s in 2.0 s from a standing start, what is the cheetah's acceleration?
= + 9.5 m/s2
v1 = 0 m/s
= ∆t∆v
vfinal - vinitial
tfinal - tinitial
v2 = +19 m/s
a
= 2+19 - 0a
![Page 6: Acceleration: a change in Velocity!. An object traveling at the same rate in the same direction, is in uniform motion. NON uniform motion - there must](https://reader036.vdocuments.us/reader036/viewer/2022082419/5a4d1b717f8b9ab0599b564c/html5/thumbnails/6.jpg)
Find the acceleration of a bike as it from +13.9 m/s to +8.3 m/s in 3.5 s.
= - 1.6 m/s2
v1 = +13.9 m/s
= ∆t∆v vfinal - vinitial
tfinal - tinitial
v2 = +8.3 m/s
a
= 3.5+8.3 – (+13.9)a
slows down
![Page 7: Acceleration: a change in Velocity!. An object traveling at the same rate in the same direction, is in uniform motion. NON uniform motion - there must](https://reader036.vdocuments.us/reader036/viewer/2022082419/5a4d1b717f8b9ab0599b564c/html5/thumbnails/7.jpg)
A speed skater at the start line accelerates at +4.1 m/s2, and reaches a top speed in 3.2 seconds. What is the change in velocity?
∆v = ?
= ∆t∆v
∆t = 3.2 s
a
a = + 4.1 m/s2
= 3.2∆v4.1 (3.2) = ∆v 4.1 (3.2)+ 13 m/s
![Page 8: Acceleration: a change in Velocity!. An object traveling at the same rate in the same direction, is in uniform motion. NON uniform motion - there must](https://reader036.vdocuments.us/reader036/viewer/2022082419/5a4d1b717f8b9ab0599b564c/html5/thumbnails/8.jpg)
a = v t
d = d2 - d1
v = d t
t = t2 - t1
![Page 9: Acceleration: a change in Velocity!. An object traveling at the same rate in the same direction, is in uniform motion. NON uniform motion - there must](https://reader036.vdocuments.us/reader036/viewer/2022082419/5a4d1b717f8b9ab0599b564c/html5/thumbnails/9.jpg)
P-T Graph P-T Graph