a structures form, behavior, and design rch 331 r. a...
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![Page 1: A STRUCTURES FORM, BEHAVIOR, AND DESIGN RCH 331 R. A ...faculty.arch.tamu.edu/media/cms_page_media/4790/lect5.pdf · Rigid Body Equilibrium 1 F2014abn Lecture 5 Architectural Structures](https://reader033.vdocuments.us/reader033/viewer/2022041606/5e33fdc941f0bb2c051ae38e/html5/thumbnails/1.jpg)
F2014abnRigid Body Equilibrium 1Lecture 5
Architectural StructuresARCH 331
five
rigid body equilibrium
lecture
ARCHITECTURAL STRUCTURES:
FORM, BEHAVIOR, AND DESIGN
ARCH 331
DR. ANNE NICHOLS
FALL 2014
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F2014abnArchitectural StructuresARCH 331
Equilibrium
• rigid body
– doesn’t deform
– coplanar force systems
• static:
A
CB
0==∑ xxFR
0==∑ yyFR
0==∑MM
Rigid Body Equilibrium 2Lecture 5
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F2014abnArchitectural StructuresARCH 331
Free Body Diagram
• FBD (sketch)
• tool to see all forces on a body or a
point including
– external forces
– weights
– force reactions
– external moments
– moment reactions
– internal forces
Rigid Body Equilibrium 3Lecture 5
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F2014abnArchitectural StructuresARCH 331
Free Body Diagram
• determine body
• FREE it from:– ground
– supports & connections
• draw all external forcesacting ON the body– reactions
– applied forces
– gravity
m⋅g
+ weight
100 lb
100 lb
Rigid Body Equilibrium 4Lecture 5
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F2014abnArchitectural StructuresARCH 331
Free Body Diagram• sketch FBD with relevant geometry
• resolve each force into components– known & unknown angles – name them
– known & unknown forces – name them
– known & unknown moments – name them
• are any forces related to other forces?
• for the unknowns
• write only as many equilibrium equations as needed
• solve up to 3 equations
Rigid Body Equilibrium 5Lecture 5
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F2014abnArchitectural StructuresARCH 331
Free Body Diagram
• solve equations
– most times 1 unknown easily solved
– plug into other equation(s)
• common to have unknowns of
– force magnitudes
– force angles
– moment magnitudes
Rigid Body Equilibrium 6Lecture 5
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F2014abnArchitectural StructuresARCH 331
Reactions on Rigid Bodies
• result of applying force
• unknown size
• connection or support type
– known direction
– related to motion prevented
no vertical motion no translation
no translationno rotation
Rigid Body Equilibrium 7Lecture 5
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F2014abnArchitectural StructuresARCH 331
Supports and Connections
Rigid Body Equilibrium 8Lecture 5
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F2014abnArchitectural StructuresARCH 331
Supports and Connections
Rigid Body Equilibrium 9Lecture 5
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F2014abnArchitectural StructuresARCH 331
FBD Example
• 500 lb known
• pin – Ax, Ay
• smooth surface –
B at 4:3
• 3 equations
• sum moments at
– A?
– B? (Bx)
Rigid Body Equilibrium 10Lecture 5
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F2014abnRigid Body Equilibrium 11Lecture 5
Architectural StructuresARCH 331
Moment Equations
• sum moments at intersection where the
most forces intersect
• multiple moment equations may not be
useful
• combos:
0Fx =∑0Fy =∑0M
1=∑
0F =∑0M1 =∑0M
2=∑
0M1 =∑0M2 =∑0M
3=∑
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F2014abnArchitectural StructuresARCH 331
Recognizing Reactions
F F
unknowns
3
weight m⋅gunknowns
3
Rigid Body Equilibrium 12Lecture 5
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F2014abnArchitectural StructuresARCH 331
Recognizing Reactions
unknowns
3
unknowns for
2 bodies
6
unknowns
2
m⋅g
weight
F1 F2
weight
F1F2
m⋅g
not independent
Rigid Body Equilibrium 13Lecture 5
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F2014abnArchitectural StructuresARCH 331
Constraints
• completely constrained
– doesn’t move
– may not be statically determinate
• improperly or partially constrained
– has ≤ unknowns
– can’t solve
Rigid Body Equilibrium 14Lecture 5
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F2014abnArchitectural StructuresARCH 331
Constraints
• overconstrained
– won’t move
– can’t be solved with statics
– statically indeterminate to nth degree
A C
B
200 lb-ft
60 lb
55° A
5’ 9’
CB
200 lb-ft
55°
60 lb
Ax
Ay Cy
MRA
Rigid Body Equilibrium 15Lecture 5
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F2014abnArchitectural StructuresARCH 331
Partial Constraints
100 N 1 m
0.75 m
30° A
B
100 N 1 m
0.75 m
30° A
B
A B
W
500 mm
200 mm
B
W
Rigid Body Equilibrium 16Lecture 5
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F2014abnArchitectural StructuresARCH 331
Cable Reactions
• equilibrium:
– more reactions (4) than equations
– but, we have slope relationships
– x component the same everywhere
A
C
45 kN
4 m
2 m
B 6 m
45 kN
Rigid Body Equilibrium 17Lecture 5
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F2014abnArchitectural StructuresARCH 331
Two Force Rigid Bodies
• equilibrium:
– forces in line, equal and opposite
A B C
A
F2
BF1
dAF2
BF1
dA
F2
BF1
α
(no) (no)
Rigid Body Equilibrium 18Lecture 5
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F2014abnArchitectural StructuresARCH 331
Three Force Rigid Bodies
• equilibrium:
– concurrent or parallel forces
A B C
F1
F2
A
B
C
F3
F2
A
F1
B
C
F3
d1
d2
F2
A
F1
B
C
F3
α
(no)
beams!
Rigid Body Equilibrium 19Lecture 5
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F2014abnArchitectural StructuresARCH 331
Concentrated Loads
Rigid Body Equilibrium 20Lecture 5
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F2014abnArchitectural StructuresARCH 331
Distributed Loads
Rigid Body Equilibrium 21Lecture 5
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F2014abnArchitectural StructuresARCH 331
Beam Supports
• statically determinate
• statically indeterminate
L L L
simply supported
(most common)
overhang cantilever
L
continuous
(most common case when L1=L2)
L
L L
Propped Restrained
Rigid Body Equilibrium 22Lecture 5
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F2014abnArchitectural StructuresARCH 331
Equivalent Force Systems
• replace forces by resultant
• place resultant where M = 0
• using calculus and area centroids
dx
w(x)
x
L
loadingloading
L
0AdAwdxW === ∫∫
dx
y
x
elx
Rigid Body Equilibrium 23Lecture 5
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F2014abnArchitectural StructuresARCH 331
Load Areas
• area is width x “height” of load
• w is load per unit length
• W is total load
x
x/2
W
x/2
x
2x/3
W/2
x/3
x
x/2
W
x/6 x/3
W/2
0
Wxw =⋅ w w 22
Wxw=
⋅
w
2w
Rigid Body Equilibrium 24Lecture 5
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F2014abnArchitectural StructuresARCH 331
Method of Sections
• relies on internal forces being in
equilibrium on a section
• cut to expose 3 or less members
• coplanar forces → ∑M = 0 too
A B
C
P
F
E
D
P
.
A
By
AC
AB
Rigid Body Equilibrium 25Lecture 5
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F2014abnArchitectural StructuresARCH 331
Method of Sections
• joints on or off the section are good to
sum moments
• quick for few members
• not always obvious where to cut or sum
A B
C
P
F
E
D
P
.
A
By
AC
AB
B
.
Rigid Body Equilibrium 26Lecture 5