a new analytical solution solved by triple series equations method

12
A new analytical solution solved by triple series equations method for constant-head tests in conned aquifers Ya-Chi Chang, Hund-Der Yeh Institute of Environmental Engineering, National Chiao-Tung University, Hsinchu, Taiwan abstract article info Article history: Received 21 May 2009 Received in revised form 18 March 2010 Accepted 18 March 2010 Available online 25 March 2010 Keywords: Constant-head test Aquifer Mixed boundary value problem Partially penetrating well The constant-head pumping tests are usually employed to determine the aquifer parameters and they can be performed in fully or partially penetrating wells. Generally, the Dirichlet condition is prescribed along the well screen and the Neumann type no-ow condition is specied over the unscreened part of the test well. The mathematical model describing the aquifer response to a constant-head test performed in a fully penetrating well can be easily solved by the conventional integral transform technique under the uniform Dirichlet-type condition along the rim of wellbore. However, the boundary condition for a test well with partial penetration should be considered as a mixed-type condition. This mixed boundary value problem in a conned aquifer system of innite radial extent and nite vertical extent is solved by the Laplace and nite Fourier transforms in conjunction with the triple series equations method. This approach provides analytical results for the drawdown in a partially penetrating well for arbitrary location of the well screen in a nite thickness aquifer. The semi-analytical solutions are particularly useful for the practical applications from the computational point of view. © 2010 Elsevier Ltd. All rights reserved. 1. Introduction Hydraulic parameters such as hydraulic conductivity, specic storage and leakage factor are important for quantifying groundwater resources. To determine these parameters, the constant-head pumping test is generally employed if the aquifer has low permeability. During the test, the hydraulic head at the well is kept constant throughout the test period and the transient ow rate across the wellbore is measured at the same time. A pumping test performed in a fully or partially penetrating borehole is inuenced by the well skin effect. The fully penetrating well can be simulated as a Dirichlet (also called the rst type) boundary condition, and the relative models can be solved by the conventional integral transform techniques [11]. If the well skin effect is negligible in the model, the Dirichlet and Neumann (second type) boundary conditions are appropriate for describing the drawdown along the well screen and casing, respectively. Thus, the boundary condition along the well face in the partially penetrating well is a mixed- type condition. The term mixed-typeboundary condition is used to distinguish this boundary condition from the uniformDirichlet and Neumann boundary condition or a combination of Dirichlet and Neumann boundary conditions (which is usually dened as third type or Robin type boundary condition). If the well skin effect is considered in the model, a more appropriate description for such an aquifer system is to treat the skin zone as a different formation zone instead of using a skin factor. Thus, the aquifer system naturally becomes a two-zone formation (see, e.g., [26,27,34,35]). Mixed boundary conditions are widely used to describe many boundary value problems of mathematical physics. Such problems arise in potential theory and its numerous applications to engineering, fracture mechanics, heat conduction, and many others. Only limited analytical solutions to mixed boundary problems (MBPs) in the eld of well hydraulics have been found so far by special solution techniques including the dual integral/series equation [8,22], WeinerHopf technique [18], and Green's function [12]. Most of the solutions to MBPs have been obtained numerically [29], or by approximate methods such as asymptotic analysis [2], or perturbation techniques [8,25]. For the mathematical model under the mixed boundary condition in a conned aquifer of semi-innite thickness, Wilkinson and Hammond [25] used a perturbation method to give an approximate solution for drawdown changes at the well. Cassiani and Kabala [4] used the dual integral equation method to develop a Laplace-domain solution that accounts for the effects of wellbore storage, innitesimal skin, and aquifer anisotropy. Cassiani et al. [5] further used the same method to develop the solutions in Laplace domain suited for constant-head pumping tests and double packer tests treated as the MBPs. Selim and Kirkham [21] used the GramSchmidt orthonorma- lization method to develop a steady state solution in a conned aquifer of nite horizontal extent. Similar problems under the mixed boundary conditions also arise in the eld of heat conduction. Among others, Huang [13] used the WeinerHopf technique to develop a solution in a semi-innite slab and Huang and Chang [12] combined Advances in Water Resources 33 (2010) 640651 Corresponding author. 300 Institute of Environmental Engineering, National Chiao Tung University, 1001 University Road, Hsinchu, Taiwan. E-mail address: [email protected] (H.-D. Yeh). 0309-1708/$ see front matter © 2010 Elsevier Ltd. All rights reserved. doi:10.1016/j.advwatres.2010.03.010 Contents lists available at ScienceDirect Advances in Water Resources journal homepage: www.elsevier.com/ locate/advwatres

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Page 1: A new analytical solution solved by triple series equations method

Advances in Water Resources 33 (2010) 640–651

Contents lists available at ScienceDirect

Advances in Water Resources

j ourna l homepage: www.e lsev ie r.com/ locate /advwatres

A new analytical solution solved by triple series equations method for constant-headtests in confined aquifers

Ya-Chi Chang, Hund-Der Yeh ⁎Institute of Environmental Engineering, National Chiao-Tung University, Hsinchu, Taiwan

⁎ Corresponding author. 300 Institute of EnvironmenTung University, 1001 University Road, Hsinchu, Taiwan

E-mail address: [email protected] (H.-D. Yeh

0309-1708/$ – see front matter © 2010 Elsevier Ltd. Aldoi:10.1016/j.advwatres.2010.03.010

a b s t r a c t

a r t i c l e i n f o

Article history:Received 21 May 2009Received in revised form 18 March 2010Accepted 18 March 2010Available online 25 March 2010

Keywords:Constant-head testAquiferMixed boundary value problemPartially penetrating well

The constant-head pumping tests are usually employed to determine the aquifer parameters and they can beperformed in fully or partially penetrating wells. Generally, the Dirichlet condition is prescribed along thewell screen and the Neumann type no-flow condition is specified over the unscreened part of the test well.The mathematical model describing the aquifer response to a constant-head test performed in a fullypenetrating well can be easily solved by the conventional integral transform technique under the uniformDirichlet-type condition along the rim of wellbore. However, the boundary condition for a test well withpartial penetration should be considered as a mixed-type condition. This mixed boundary value problem in aconfined aquifer system of infinite radial extent and finite vertical extent is solved by the Laplace and finiteFourier transforms in conjunction with the triple series equations method. This approach provides analyticalresults for the drawdown in a partially penetrating well for arbitrary location of the well screen in a finitethickness aquifer. The semi-analytical solutions are particularly useful for the practical applications from thecomputational point of view.

tal Engineering, National Chiao.).

l rights reserved.

© 2010 Elsevier Ltd. All rights reserved.

1. Introduction

Hydraulic parameters such as hydraulic conductivity, specificstorage and leakage factor are important for quantifying groundwaterresources. To determine these parameters, the constant-head pumpingtest is generally employed if the aquifer has low permeability. Duringthe test, the hydraulic head at the well is kept constant throughout thetest period and the transient flow rate across the wellbore is measuredat the same time. A pumping test performed in a fully or partiallypenetrating borehole is influenced by the well skin effect. The fullypenetrating well can be simulated as a Dirichlet (also called the firsttype) boundary condition, and the relative models can be solved by theconventional integral transform techniques [11]. If thewell skin effect isnegligible in the model, the Dirichlet and Neumann (second type)boundary conditions are appropriate for describing the drawdownalong the well screen and casing, respectively. Thus, the boundarycondition along thewell face in thepartially penetratingwell is amixed-type condition. The term “mixed-type” boundary condition is used todistinguish this boundary condition from the “uniform” Dirichlet andNeumann boundary condition or a combination of Dirichlet andNeumann boundary conditions (which is usually defined as third typeor Robin type boundary condition). If thewell skin effect is considered inthe model, a more appropriate description for such an aquifer system isto treat the skin zoneasa different formationzone insteadof usinga skin

factor. Thus, theaquifer systemnaturallybecomesa two-zone formation(see, e.g., [26,27,34,35]).

Mixed boundary conditions are widely used to describe manyboundary value problems of mathematical physics. Such problemsarise in potential theory and its numerous applications to engineering,fracture mechanics, heat conduction, and many others. Only limitedanalytical solutions tomixed boundary problems (MBPs) in the field ofwell hydraulics have been found so far by special solution techniquesincluding the dual integral/series equation [8,22], Weiner–Hopftechnique [18], and Green's function [12]. Most of the solutions toMBPs have been obtained numerically [29], or by approximatemethods such as asymptotic analysis [2], or perturbation techniques[8,25].

For the mathematical model under the mixed boundary conditionin a confined aquifer of semi-infinite thickness, Wilkinson andHammond [25] used a perturbation method to give an approximatesolution for drawdown changes at the well. Cassiani and Kabala [4]used the dual integral equation method to develop a Laplace-domainsolution that accounts for the effects of wellbore storage, infinitesimalskin, and aquifer anisotropy. Cassiani et al. [5] further used the samemethod to develop the solutions in Laplace domain suited forconstant-head pumping tests and double packer tests treated as theMBPs. Selim and Kirkham [21] used the Gram–Schmidt orthonorma-lization method to develop a steady state solution in a confinedaquifer of finite horizontal extent. Similar problems under the mixedboundary conditions also arise in the field of heat conduction. Amongothers, Huang [13] used the Weiner–Hopf technique to develop asolution in a semi-infinite slab and Huang and Chang [12] combined

Page 2: A new analytical solution solved by triple series equations method

Fig. 1. Schematic representation of a partially penetrating well in a confined aquifer offinite extent with a finite thickness of b.

641Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

the Green's function with conformal mapping to develop the solutionin an elliptic disk.

In reality, the thickness of aquifer is generally finite. Cassiani et al.[5] have developed the Laplace-domain solutions to MBPs forconstant-head test based on the infinite aquifer thickness assumption.Their solutions are appropriate for the early time condition when thepressure change caused by the constant-head pumping has notreached the bottom of the aquifer or for the special condition, wherethe screen length is significantly shorter than the aquifer thickness.Chang and Chen [6] removed such constraints by assuming finiteaquifer thickness and treated the well skin effect as a skin factor. Theyalso treated the boundary along thewell screen as a Robin (third type)boundary condition and replaced the mixed boundary by homoge-neous Neumann boundary. They considered the wellbore fluxentering through the well screen as unknown and discretized thescreen length into M segments [7]. To avoid discretizing the wellscreen, Chang and Yeh [8] developed an analytical solution for aconstant-head test performed in a partially penetrating well in anaquifer. They used the dual series equations (DSE) method andperturbationmethod to solve theMBP along the well which has a wellscreen extended from the top of the aquifer to any location of the well.According to the image well theory, their solution is applicable to thesituation where the middle of the screen of the partially penetratingwell is located right at the center of the aquifer. However, theirsolution can not apply to the case of a partially penetrating well witharbitrary location of the well screen.

This study aims to develop a new model describing a constant-head test performed in a flowing partially penetrating well forarbitrary location of the well screen in an aquifer of a finite thicknessin depth. The solution of the model is based on the followingassumptions: (1) the aquifer is homogeneous and infinite extent inthe radial direction; (2) thewell has a finite radius; (3) the initial headis constant and uniform throughout the whole aquifer; and (4) thewell loss is not considered in the system. The mixed-type boundarycondition at the well is handled via the triple series equations (TSE)method. This solution contains infinite series involving the summa-tions of multiplication of integrals, trigonometric functions, andthe modified Bessel functions of second kind, where the single anddouble integrals are presented in terms of trigonometric functionsmultiplying the associated Legendre functions. The infinite-seriessolution is difficult to accurately compute due to the oscillatory natureand slow convergence of the multiplied functions. Therefore, Shanks'transform method [19,20] is used to accelerate the evaluation of theLaplace-domain solution and the numerical inversion scheme,Stehfest algorithm [24], is used to find the time domain solution. Tothe best of our knowledge, this is the first paper using the TSE methodto solve the mixed boundary value problems in the area of waterresources.

2. Mathematical model

2.1. Mathematical statement

Fig. 1 shows a schematic representation of a partially penetratingwell in a confined aquifer with a finite thickness of b. The drawdownat the distance r from the well and the distance z from the bottom ofthe aquifer at time t is denoted as s(r, z, t). The well screen whichextends from arbitrary location d1 to d2 is of length l under aprescribed constant drawdown hw. The hydraulic parameters of theaquifer are horizontal hydraulic conductivity Kr [L/T], verticalhydraulic conductivity Kz [L/T], and specific storage Ss [1/L]. Thegoverning equation for the drawdown can be written as

Kr∂2s∂r2

+1r∂s∂r

!+ Kz

∂2s∂z2

= Ss∂s∂t : ð1Þ

The prescribed Dirichlet boundary condition for a constant draw-down along the well screen is:

s rw; z; tð Þ = sw d1≤z≤d2 : ð2aÞ

A Neumann boundary condition of zero flux is specified as:

∂s∂r jr= rw

= 0 0≤z≤d1 and d2≤z≤b: ð2bÞ

In addition, the initial condition and other boundary conditionsare:

s r; z;0ð Þ = 0 ð3Þs ∞; z; tð Þ = 0 ð4Þand

∂s∂z = 0; z = 0; z = b: ð5Þ

The dimensionless parameters used hereafter are defined inTable 1. Eqs. (1)–(5) in dimensionless form are, respectively,

∂2s*∂ρ2

+1ρ∂s*∂ρ + α2 ∂2s*

∂ξ2=

∂s*∂τ ð6Þ

s* ρ; ξ; τ = 0ð Þ = 0 ð7Þ

s* ρ = ∞; ξ; τð Þ = 0 ð8Þ

s* ρ = 1; ξ; τð Þ = 1; ξ1≤ξ≤ξ2 ð9aÞ

∂s*∂ρ jρ=1

= 0; 0≤ξ≤ξ1 and ξ2≤ξ≤β ð9bÞ

∂s*∂ξ jξ=0;ξ=β

= 0: ð10Þ

Note that Eqs. (6)–(10) constitute a MBP.

Page 3: A new analytical solution solved by triple series equations method

Table 1Dimensionless expressions.

Symbol Illustration

s⁎(ρ, ξ, τ) s(r, z, t)/sw, dimensionless drawdowns ⁎(ρ, ξ, τ) Dimensionless drawdown in Laplace domains* ρ; ξ; τð Þ Dimensionless drawdown in Laplace and Fourier domainα

ffiffiffiffiffiffiffiffiffiffiffiffiffiffiKz = Kr

p, anisotropy ratio

β b/rw, dimensionless aquifer thicknessηn nπ/βρ r/rw, dimensionless radial distanceτ Krt/Ssrw2 , dimensionless timeλ l/rw, dimensionless screen lengthλn

ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffinπα=βð Þ2 + p

qξ z/rw, dimensionless vertical distanceξ1 d1/rwξ2 d2/rwω l/b, partial penetration ratio

Table 2Symbol definitions.

Symbol Illustration

f1(x, a)ffiffiffi2

psin x = 2ð Þ

πffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffifficos xð Þ− cos

pað Þ

f2(n, a) [Pn(cos a)+Pn−1(cos a)], n≥1f3(x, a) 1

4 ln 1− cos a + xð Þð Þ− ln 1− cos a−xð Þð Þð ÞHn K1(λn)/K0(λn)In n−λnHn

μ1 ξ1π/βμ2 π−ξ2π/βΩ1(x) ∫

0

xf1(u, x)udu

Ω2(x, k) ∫0

x f1(u, x) sin(ku)du

Ω3(x) ∫0

xf1(u, x)f3(u, x)du

642 Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

2.2. Laplace-domain solution

The detailed derivation for the solution of Eq. (6) with Eqs. (7)–(10) using Laplace transform, finite Fourier cosine transform, and TSEmethod is given in Appendix A. The solution for drawdown in anaquifer involving a partially penetrating well is obtained as:

s* ρ; ξ; pð Þ = 12B 0;pð ÞK0

ffiffiffip

� �K0

ffiffiffip

p� � + ∑∞

n=1B n; pð ÞK0 λnρð Þ

K0 λnð Þ cos ηnξð Þ ð11Þ

where K0 is the modified Bessel functions of the second kind withorder zero, ηn=(nπ)/β and the coefficients B(0, p) and B(n, p) areexpressed as

B 0;pð Þ = C 0; pð Þ + D 0;pð Þ= C0 + D0= B0

ð12Þ

and

B n;pð Þ = C n; pð Þ + D n;pð Þ= Cn + Dn= Bn:

ð13Þ

The coefficients C0, Cn,D0, andDn in Eqs. (12) and (13) are calculatedby the following equations

C0 = 1 +ffiffiffip

pH0Ω1 μ1ð Þ� �−1

4pπ

Ω3 μ1ð Þ+2p

1− μ1π

� �+∑

k=1

2k

IkCk−λkHkDkð ÞΩ2 μ1; kð Þ−D0ffiffiffip

pH0Ω1 μ1ð Þ

� �

ð14Þ

Cn = ∑∞

k=1

1k

IkCk−λkHkDkð Þ Ω2 μ1; kð Þf2 n; μ1ð Þ−∫μ 1

0Ω2 y; kð Þdf2 n; yð Þ

dydy

� �

+12ffiffiffip

pH0 C0 + D0ð Þ ∫μ 1

0Ω1 yð Þdf2 n; yð Þ

dydy−Ω1 μ1ð Þf2 n; μ1ð Þ

� �

+2pπ

Ω3 μ1ð Þf2 n; μ1ð Þ−∫μ 1

0Ω3 yð Þdf2 n; yð Þ

dydy

� �

−2 sin nμ1ð Þpnπ

ð15Þ

D0 = 1 +ffiffiffip

pH0Ω1 μ2ð Þð Þ−1 ∑

k=1

2k

−1ð ÞkΩ2 μ2; kð Þ IkDk−λkHkCkð Þ−C0ffiffiffip

pH0Ω1 μ2ð Þ

� �

ð16Þ

and

Dn = −1ð Þn ∑∞

k=1−1ð Þk 1

kIkDk−λkHkCkð Þ

× Ω2 μ2; kð Þ⋅f2 n; μ2ð Þ−∫μ 2

0Ω2 y; kð Þdf2 n; yð Þ

dydy

� �

+12

ffiffiffip

pH0 D0 + C0ð Þ ∫μ 2

0Ω1 yð Þdf2 n; yð Þ

dydy−Ω1 μ2ð Þf2 n; μ2ð Þ

� � ð17Þ

with

μ1 = ξ1π= β ð18Þ

μ2 = π−ξ2π = βð Þ ð19Þ

Ω1 xð Þ = ∫x

0f1 u; xð Þudu ð20Þ

Ω2 x; kð Þ = ∫x

0f1 u; xð Þ sin kuð Þdu ð21Þ

Ω3 xð Þ = ∫x

0f1 u; xð Þf3 u; xð Þdu ð22Þ

λn =

ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffinπαβ

2+ p

sð23Þ

H n; pð Þ = Hn = K1 λnð Þ= K0 λnð Þ ð24Þ

f1 x; að Þ =ffiffiffi2

psin x = 2ð Þ

πffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffifficos xð Þ− cos

pað Þ ð25Þ

f2 n; að Þ = Pn cosað Þ + Pn−1 cosað Þ½ � ð26Þ

f3 x; að Þ = 14

ln 1− cos a + xð Þð Þ− ln 1− cos a−xð Þð Þð Þ ð27Þ

where Pn(cos(⋅)) is the associated Legendre function ([1], p. 335) andK1 is the modified Bessel functions of the second kind with order one.The definitions of functions or variables used in equations above arealso listed in Table 2.

The determination of the values of C0, Cn, D0, and Dn in Eqs. (14)–(17) from Eqs. (A29) to (A48) is described in detail in Appendix A. Thecoefficients B0 and Bn in the drawdown solution (11) can therefore bedetermined based on Eqs. (12) and (13).

The flux entering the well screen and the total well dischargeobtained using Eq. (11) are respectively given as:

q* 1; ξ; pð Þ = −∂s* ρ; ξ;pð Þ∂ρ j

ρ=1=

12B0

ffiffiffip

p K1ffiffiffip

p� �K0

ffiffiffip

p� �+ ∑

n=1Bnλn

K1 λnð ÞK0 λnð Þ cos n

ξβπ

ð28Þ

Page 4: A new analytical solution solved by triple series equations method

643Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

and

Q pð Þ = 1λ∫ξ2

ξ1

q* 1; ξ;pð Þdξ =12B0

ffiffiffip

p K1ffiffiffip

p� �K0

ffiffiffip

p� �− ∑

n=1ληnð Þ−1BnλnHn sin nμ1ð Þ + −1ð Þn sin nμ2ð Þ� �

ð29Þ

where λ= l/rw is the dimensionless length of the screen.

2.3. Simplified solutions

2.3.1. Partially penetrating well (well screen extends from the top of theaquifer)

When the well screen extends from d1 to the top of the aquifer, thecoefficients in Eqs. (14)–(17) can be found by setting ξ2=β. Thedrawdown can then be determined from solving Eqs. (A17a) and(A17b) which should be identical to the results obtained using

Fig. 2. The drawdown distribution at dimensionless time τ

infinity-order perturbation approach in solving DSE in Chang and Yeh[8].

2.3.2. Fully penetrating wellWhen the well fully penetrates the entire thickness of the

formation, i.e., ξ1 is zero and ξ2 equals β, the drawdown and thewell discharge can be obtained using Eqs. (11) and (29), respectively,as [11]

s* ρ; ξ; pð Þ = 1pK0

ffiffiffip

� �K0

ffiffiffip

p� � ð30Þ

and

Q pð Þ = K1ffiffiffip

p� �ffiffiffip

pK0

ffiffiffip

p� � ð31Þ

Eqs. (30) and (31) are identical to the solutions of drawdown andflow rate in Laplace domain given in Yang and Yeh [28].

=1, 100, 104 and τ=106 for β=100 and various ρ.

Page 5: A new analytical solution solved by triple series equations method

644 Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

3. Results and discussion

Numerical calculations for the aquifer drawdown and well fluxare performed in PC using the FORTRAN code developed based onthe present solutions. The first step in the development of solutionsis to determine the coefficients of Laplace-domain solution inEq. (11) from using Eq. (A50). The single and double integralsinvolved in the elements are then computed using the subroutinesDQDAG and DTWODQ in IMSL [10,15], respectively. Once thecoefficients are known, the second step is to find the infinitesummation in Eq. (11) by Shank's transform method. Then the finalstep is to transform the Laplace-domain solution of Eq. (11) intotime-domain using IMSL subroutine LINV for the Stehfest method[24] with eight weighting factors. The infinite summation in thesolution can be found more efficiently using Shank's transformwhich consists of a family of nonlinear sequence-to-sequencetransformations [20]. Shanks [20] concluded that these transforma-tions are effective when applied to accelerate the convergence ofsome slowly convergent sequences and may also converge to somedivergent sequences.

The solutions can be verified by calculating the values at theboundary along the test well in Eq. (11). Fig. 2 shows thedimensionless drawdown for β=100, ξ1=30, ξ2=80 and various ρat τ=1, 100, 104 and 106. As indicated in the figure, the dimensionlessdrawdown is constant along the well screen and decreases with theincreasing dimensionless radial distance at τ=1. In addition, thedimensionless drawdown increases with dimensionless time alongthe unscreened part of the well. The dimensionless drawdown haslarger value in the screen part and smaller value along the unscreenedpart. Fig. 3 shows the plots of the flux along the well screen forβ=100, ξ1=30 and ξ2=80 at τ=1, 100, 104 and 106. Thedimensionless flux is non-uniformly distributed and large at thescreen edge due to the vertical flow induced by the presence of wellpartial penetration. Fig. 4 exhibits the behavior of dimensionlessdrawdown versus dimensionless time τ and illustrates the effect ofscreen length on the drawdown response, where the dimensionlessradial distance ρ is 10, the vertical distance ξ is 50 and α=1 fordifferent length of the screen. This figure indicates that thedimensionless drawdown increases with the length of the screen.To test the influence of anisotropy of the aquifer, Fig. 5 is plotted forρ=5, ξ=50, ξ1=40, ξ2=60 and various anisotropy α. As can beobserved, the drawdown increases with α. The spatial dimensionlessdrawdown contours at τ=100, 103 and 104 are plotted in Fig. 6. Thedimensionless drawdown increases with dimensionless time at afixed radial distance and flow is horizontal when the dimensionless

Fig. 3. The distribution of flux along the well screen at different dimensionless time forβ=100.

radial distance is large than 80 and the dimensionless time is 104.Fig. 7(a) and (b) shows the spatial dimensionless drawdown contoursfor various α2 with ξ1=200 and ξ2=250 at τ=105 and demonstratesthe influence of anisotropy on the dimensionless drawdown. The flowis almost horizontal at the bottom of the aquifer when thedimensionless radial distance is large than 400 for α2=1; however,the flow is vertical at the bottom of the aquifer for α2=0.5. Fig. 8(a)and (b) plots the spatial dimensionless drawdown contours for thesame length of 50 but different locations of well screen. In Fig. 8(a),the screen is symmetric with ξ1=12.5 and ξ2=37.5 and in Fig. 8(b)the screen extends from the top of the aquifer with ξ1=25 andξ2=50 at τ=105. Since the screen is symmetric about themiddle lineof the aquifer, the drawdown contours are symmetric as shown inFig. 6(a). Fig. 9 illustrates the spatial dimensionless drawdowncontours for β=200, ξ1=100 and ξ2=150 at τ=107. The directionof flow is upward when the radial distance is far from the pumpingwell and it is downward when the radial distance is close to the wellscreen.

4. Concluding remarks

This paper developed a new semi-analytical solution fordescribing the drawdown response for a constant-head testperformed in a partially penetrating well in an aquifer of infiniteradial extent and finite vertical extent, where the well screen isinstalled within any part of the well. The Laplace and finite cosineFourier transforms in conjunction with TSE method are used to solvethe mixed-type boundary and initial values problem for a partiallypenetrating well in an aquifer of a finite thickness. The presentsolutions can be reduced to the solutions given in Yang and Yeh [28]for a fully penetrating well in an aquifer of a finite thickness. Inaddition, they are also equal to the results obtained using infinity-order perturbation approach for a partially penetrating well of awell screen extending from the top of the aquifer presented inChang and Yeh [8]. The flux estimated from the solution is non-uniformly distributed along the screen and with a local peak at theedge, due to the vertical flow induced by the effect of well partialpenetration.

These solutions are particularly useful for practical applicationssince they can be used to evaluate the sensitivities of the inputparameters in a mathematical model (e.g., [14] and [9]), to identifythe hydraulic parameters if coupling with the extended Kalman filter(e.g., [16] and [33]) or an optimization approach such as the nonlinearleast-squares (e.g., [30] and [31] ) or simulated annealing (e.g., [17]and [32] ) in the analysis of aquifer data, and to validate a numericalsolution [36].

Acknowledgements

This study was supported by the Taiwan National Science Councilunder the grant NSC 96-2221-E-009-087-MY3. The authors wouldlike to thank three anonymous reviewers for their valuable andconstructive comments that help improve the clarity of ourpresentation.

Appendix A

The Laplace-domain solution for dimensionless drawdown can beobtained by taking the Laplace transformwith respect to time and thefinite Fourier cosine transform with respect to ξ. The definition ofLaplace transform is:

s* ρ; ξ; pð Þ = Lp s* ρ; ξ;τð Þ;τ→p½ � = ∫∞

0s* ρ; ξ; τð Þe−pτdτ ðA1Þ

where s⁎(ρ, ξ, p) is the dimensionless drawdown in Laplace domain.

Page 6: A new analytical solution solved by triple series equations method

Fig. 4. Type curve for drawdown for ρ=10, ξ=50, α=1, β=100 and various penetration lengths.

Fig. 5. Type curve for drawdown for ρ=5, ξ1=40, ξ2=60, β=100 and various anisotropy α.

645Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

Page 7: A new analytical solution solved by triple series equations method

Fig. 6. The spatial drawdown contours at dimensionless time τ=100, 103 and τ=104 for β=50.

646 Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

Taking the Laplace transform of Eq. (6) and Eqs. (8)–(10) with theinitial condition in Eq. (7), the problem reads:

∂2s*∂ρ2

+1ρ∂s*∂ρ + α2 ∂2s*

∂ξ2−ps* = 0 ðA2Þ

s* ρ = ∞; ξ; pð Þ = 0 ðA3Þ

s* ρ = 1; ξ; pð Þ = 1p; ξ1≤ξ≤ξ2 ðA4aÞ

∂s*∂ρ jρ=1

= 0; 0≤ξ ≤ ξ1 and ξ2≤ξ≤β ðA4bÞ

Page 8: A new analytical solution solved by triple series equations method

Fig. 7. The spatial drawdown contours at dimensionless time τ=105 for β=250 and various α2.

Fig. 8. The spatial drawdown contours at dimensionless time τ=106 for β=50 and various screen locations (ξ1=12.5 and ξ2=37.5; ξ1=25 and ξ2=50).

647Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

Page 9: A new analytical solution solved by triple series equations method

Fig. 9. The spatial drawdown contours as at dimensionless time τ=107 for β=200, ξ1=100 and ξ2=150.

648 Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

∂s*∂ξ jξ=0;ξ=β

= 0 ðA5Þ

The finite cosine Fourier transformwith respect to ξ is then definedas follows [23]:

s* ρ;n; pð Þ = Fc s* ρ; ξ;pð Þ; ξ→n½ � = ∫β

0

s* ρ; ξ;pð Þ cos ηnξð Þdξ ðA6Þ

where s* ρ;n;pð Þ is the dimensionless drawdown after finite cosineFourier transform. Substituting Eq. (A6) into Eqs. (A2), (A3) and (A5)results in the Bessel differential equation as

∂2 s*∂ρ2

+1ρ∂ s*∂ρ −λ2

n s* = 0 ðA7Þ

with the boundary condition

s* ρ = ∞;n;pð Þ = 0: ðA8Þ

The general solution to Eq. (A7) with the boundary condition (A8)is [3]

s* ρ;n; pð Þ = A n;pð ÞK0 λnρð Þ ðA9Þ

where A(n, p) can be found from using the mixed-type boundarycondition (A4a) and (A4b). The inverse of the finite cosine Fouriertransform is

s* ρ; ξ; pð Þ = 1βs* ρ;0;pð Þ + 2

β∑∞

n=1s* ρ;n; pð Þ cos ηnξð Þ: ðA10Þ

Thus, the solution in ξ domain obtained by inserting Eq. (A9) intoEq. (A10) is

s* ρ; ξ; pð Þ = 1βA 0;pð ÞK0

ffiffiffip

pρð Þ + 2

β∑∞

n=1A n;pð ÞK0 λnρð Þ cos ηnξð Þ ðA11Þ

with its derivative with respect to ρ given by

∂s*∂ρ ρ; ξ;pð Þ=− 1

βA 0;pð Þ ffiffiffi

pp

K1ffiffiffip

pρð Þ− 2

β∑∞

n=1A n;pð ÞλnK1 λnρð Þcos ηnξð Þ:

ðA12Þ

Substituting Eq. (A11) into Eqs. (A4a) and (A12) into Eq. (A4b)results in a system of TSE as

1βA 0; pð ÞK0

ffiffiffip

pð Þ + 2β

∑∞

n=1A n;pð ÞK0 λnð Þ cos ηnξð Þ = 1

p; ξ1≤ξ≤ξ2

ðA13aÞ1βA 0; pð Þ ffiffiffi

pp

K1ffiffiffip

pð Þ + 2β

∑∞

n=1A n;pð ÞλnK1 λnð Þ cos ηnξð Þ

= 0; 0≤ξ≤ξ1; ξ2≤ξ≤β:

ðA13bÞ

Introduce

B n;pð Þ = 2A n; pð ÞK0 λnð Þ= β ðA14Þ

and

x = ξπ= β: ðA15Þ

Therefore, ηnξ=nx and the TSE of Eqs. (A13a) and (A13b) can berearranged as [22]:

12B 0; pð Þ ffiffiffi

pp

H 0;pð Þ + ∑∞

n=1B n; pð ÞλnHn cos nxð Þ = 0; 0≤x≤ ξ1

βπ

ðA16aÞ

12B 0; pð Þ + ∑

n=1B n;pð Þ cos nxð Þ = 1

p;

ξ1βπbx≤ ξ2

βπ ðA16bÞ

12B 0; pð Þ ffiffiffi

pp

H 0;pð Þ + ∑∞

n=1B n; pð ÞλnHn cos nxð Þ = 0;

ξ2βπ≤x≤π:

ðA16cÞ

The symbol Hn is defined in Eq. (24) and H0 is from Hn when n=0.Our goal now is to determine the coefficients B(0, p) and B(n, p) inEqs. (A16a)–(A16c). For convenience, the coefficients B(0, p) and B(n, p)are expressed asB0 andBn, respectively, as in Eqs. (12) and (13). To solve

Page 10: A new analytical solution solved by triple series equations method

649Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

the TSE in Eq. (A16a)–(A16c), we further split it into the following twoDSE ([22], p. 192)

12

C0+D0ð Þ ffiffiffip

pH 0;pð Þ+ ∑

n=1Cn+Dnð ÞλnHn cos nxð Þ = 0; 0 ≤ x ≤ μ1

ðA17aÞ

12C0+ ∑

n=1Cn cos nxð Þ = 1

p; μ1bx≤π ðA17bÞ

12D0+ ∑

n=1Dn cos nxð Þ = 0; 0 b x ≤ π− μ2 ðA18aÞ

12

C0+D0ð Þ ffiffiffip

pH 0;pð Þ+∑

n=1Cn+Dnð ÞλnHn cos nxð Þ = 0; π−μ2≤x≤π

ðA18bÞ

where μ1 and μ2 are defined by Eqs. (18) and (19), respectively. WithEqs. (12) and (13), Eqs. (A17a) and (A18b) are equal to Eqs. (A16a)and (A16c), respectively, and the sum of Eqs. (A17b) and (A18a)in the range of μ1bx≤π−μ2 is equal to Eq. (A16b). Eqs. (A17a)–(A17b) and (A18a)–(A18b) are regarded as dual series relationsand by means of them, the coefficients C0, D0, Cn and Dn can bedetermined.

Eqs. (A17a) and (A17b) can be solved by the following proceduregiven in Sneddon ([22], p. 161). Assume that for 0≤x≤μ1

12C0 + ∑

n=1Cn cos nxð Þ = cos

x2

� �∫μ1x

h1 yð Þdyffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffifficosx− cos

py

ðA19Þ

where h1(y) is an unknown function to be determined. UsingEqs. (A17b) and (A19), for the full range 0≤x≤π, the coefficients C0and Cn can then be expressed as ([22], (5.4.56), (5.4.57))

C0 =2π

πffiffiffi2

p ∫μ1

0h1 yð Þdy + ∫

π

μ1

1pdy

� �ðA20Þ

and

Cn =2π

π2ffiffiffi2

p ∫μ10 h1 yð Þ Pn cosyð Þ + Pn−1 cosyð Þ½ �dy + ∫π

μ1

1pcos nyð Þdy

�:

ðA21Þ

The function h1(y) can be determined using Eq. (A17a) for0≤x≤μ1. Integrating Eq. (A17a), one can obtain

12C0

ffiffiffip

pH 0;pð Þx + ∑

n=1Cn sin nxð Þ

= ∫x

0∑∞

n=1CnIn cos nuð Þ−1

2D0

ffiffiffip

pH 0; pð Þ−∑

n=1DnλnHn cos nuð Þ

� �du

= ∫x

0F uð Þdu

ðA22Þ

where F(u) is defined as the integrand on the RHS of Eq. (A22).Substituting Eq. (A21) into Eq. (A22), one can find that h1(y) satisfiesthe following equation: ([22], p. 161, Eq. (5.4.58))

∫μ1

0h1 yð Þ 1ffiffiffi

2p ∑

n=1Pn cosyð Þ + Pn−1 cosyð Þ½ � sinnxdy

= ∫x

0F uð Þdu−1

2ffiffiffip

pH 0;pð ÞC0x−∑

n=1

∫π

μ1

1pcos nuð Þdu sin nxð Þ:

ðA23Þ

The summation term on the left-hand side of Eq. (A23) can beexpressed as ([22], p. 59, Eq. (2.6.31))

1ffiffiffi2

p ∑∞

n=1Pn cosyð Þ + Pn−1 cosyð Þ½ � sinnx =

cosx2

� �Heav x−yð Þffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi

cosy− cosp

xðA24Þ

where Heav(X) is the Heaviside unit step function defined as

Heav Xð Þ =0 Xb0

1 = 2 X = 01 X N 0

:

8<: ðA25Þ

Substituting Eq. (A24) into Eq. (A23) yields

∫μ1

0

h1 yð ÞH x−yð Þffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffifficosy− cos

pxdy

=secx2

∫x

0F uð Þdu−1

2ffiffiffip

pH 0;pð ÞC0x−∑

n=1

∫π

μ1

1pcos nuð Þdu sin nxð Þ

( ):

ðA26Þ

With Eq. (A25), Eq. (A26) can be expressed alternatively as

∫x

0

h1 yð Þffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffifficosy− cos

pxdy =sec

x2

× ∫x

0F uð Þdu−1

2ffiffiffip

pH 0;pð ÞC0x−∑

n=1

2π∫π

μ1

1pcos nuð Þdu sin nxð Þ

( )0 ≤ x b μ1:

ðA27Þ

Then, the function h1(y) found based on Sneddon ([22], p. 162, Eq.(5.4.60)) is

h1 yð Þ = 2π

ddy

∫y

0

sin x= 2ð Þffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffifficosx− cos

py

× ∫x

0F uð Þdu−1

2ffiffiffip

pH 0; pð ÞC0x− ∑

n=1

∫π

μ1

1pcos nuð Þdu sin nxð Þ

( )dx:

ðA28Þ

By integrating Eq. (A28) and substituting it into Eqs. (A20) and(A21), the coefficients C0 and Cn can then be expressed as Eqs. (14)and (15), respectively.

For computational convenience, Eqs. (14) and (15) can be writtenas a vector equation

C = I−Xð Þ�1YD + I−Xð Þ�1

Z ðA29Þ

where I is an (n+1)×(n+1) identity matrix; X=[xi,j] and Y= [yi,j]are (n+1)×(n+1) matrices; CT=[C0, C1,…, Cn], DT=[D0, D1,…, Dn],and ZT=[z1, z2,…, zn+1] are column vectors. The elements in thematrices and vectors are defined as

x1;1 = 0 ðA30Þ

x1;j =2

j−1ð Þ Ij−1Ω2 μ1; j−1ð Þ1 +

ffiffiffip

pH0Ω1 μ1ð Þ ðA31Þ

xij =1

j−1ð Þ Ij−1 Ω2 μ1; j−1ð Þf2 i−1; μ1ð Þ−∫μ1

0Ω2 y; j−1ð Þdf2 i−1; yð Þ

dydy

� �ðA32Þ

xi1 =12ffiffiffip

pH0 ∫

μ2

0Ω1 yð Þdf2 i−1; yð Þ

dydy−Ω1 μ1ð Þf2 i−1; μ1ð Þ

� �ðA33Þ

y11 =− ffiffiffi

pp

H0Ω1 μ1ð Þ1 +

ffiffiffip

pH0Ω1 μ1ð Þ ðA34Þ

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650 Y.-C. Chang, H.-D. Yeh / Advances in Water Resources 33 (2010) 640–651

y1j =−2j−1ð Þλj−1Hj−1Ω2 μ1; j−1ð Þ

1 +ffiffiffip

pH0Ω1 μ1ð Þ ðA35Þ

yi1 =12ffiffiffip

pH0 ∫

μ1

0Ω1 yð Þdf2 i−1; yð Þ

dydy−Ω1 μ1ð Þf2 i−1; μ1ð Þ

� �ðA36Þ

yij=1

j−1ð Þλj−1Hj−1 ∫μ1

0Ω2 y; j−1ð Þdf2 i−1; yð Þ

dydy−Ω2 μ1; j−1ð Þf2 i−1; μ1ð Þ

� �ðA37Þ

z1 =4pπΩ3 μ1ð Þ + 2

p 1− μ1π

� �1 +

ffiffiffip

pH0Ω1 μ1ð Þ ðA38Þ

zi =2pπ

Ω3 μ1ð Þf2 i−1; μ1ð Þ−∫μ1

0Ω3 yð Þdf2 i−1; yð Þ

dydy

� �−2 sin i−1ð Þμ1ð Þ

i−1ð ÞπpðA39Þ

where i and j goes from 2 to n and the functions f1(⋅), f2(⋅) and f3(⋅) aredefined in Eqs. (25)–(27), respectively.

Similarly, Eqs. (A18a)–(A18b) can be solved by setting x′=π−xand Dn′=(−1)nDn. Eqs. (A18a)–(A18b) is rewritten as

12D′0 + ∑

n=1D′n cos nx′ð Þ = 0; μ2bx′≤π ðA40aÞ

12

D′0 + C0

� � ffiffiffip

pH0 + ∑

n=1D′n + −1ð ÞnCn

� �λnHn cos nx′ð Þ = 0; 0≤x′≤μ2

ðA40bÞ

and the vector equation for solving coefficients D0 and Dn is expressedas

D = I−X� �−1

YC ðA41Þ

where X=[x ij] and Ỹ= [ỹij] are (n+1)×(n+1) matrices with theelements

x1;1 = 0 ðA42Þ

x1;j =2 −1ð Þj−1

j−1ð Þ Ij−1Ω2 μ2; j−1ð Þ1 +

ffiffiffip

pH0Ω1 μ2ð Þ ðA43Þ

xi1 =12ffiffiffip

pH0 ∫

μ2

0Ω1 yð Þdf2 i−1; yð Þ

dydy−Ω1 μ1ð Þf2 i−1; μ2ð Þ

� �ðA44Þ

xij =

ffiffiffi2

p

π−1ð Þi−1 −1ð Þj−1

j−1ð Þ Ij−1 Ω2 μ2; j−1ð Þf2 i−1; μ2ð Þ−∫μ20 Ω2 y; j−1ð Þdf2 i−1; yð Þ

dydy

� �

ðA45Þ

y11 =− ffiffiffi

pp

H0Ω1 μ2ð Þ1 +

ffiffiffip

pH0Ω1 μ2ð Þ ðA46Þ

y1j =−2 −1ð Þj−1

j−1ð Þ λj−1Hj−1Ω2 μ2; j−1ð Þ1 +

ffiffiffip

pH0Ω1 μ2ð Þ ðA47Þ

yi1 =−1ð Þi−1

2ffiffiffip

pH0 ∫

μ2

0Ω1 yð Þdf2 i−1; yð Þ

dydy−Ω1 μ2ð Þf2 i−1; μ2ð Þ

� �ðA48Þ

yij =−1ð Þj−1 −1ð Þi−1

j−1ð Þ λj−1Hj−1

× ∫μ2

0Ω2 y; j−1ð Þdf2 i−1; yð Þ

dydy−Ω2 μ2; j−1ð Þf2 i−1; μ2ð Þ

� �: ðA49Þ

If n tends to infinity, Eq. (11) would give the exact solution for thedrawdown. However, it would give a relatively accurate result even a

finite number of n is considered. Let n vary from 1 to N, where N is anarbitrary finite number. Substituting Eq. (A41) into Eq. (A29), theelements in C column vector can be expressed as

cj−1 = ∑N + 1

i=1φi;jzi; j = 1;2;3;…;N + 1 ðA50Þ

with φi,j represents (i, j)th element in the matrix [I−(I−X)−1Y(I−X)−1Ỹ]−1(I−X)−1.

Once the coefficients C0 and Cn are known, the coefficients D0 andDn can then be obtained from Eq. (A41).

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