9.1.4.9 lab - subnetting network topologies

Lab Subnetting Network TopologiesLab Subnetting Network TopologiesObjectivesParts 1 to 5, for each network topology:Determine the number of subnets.Design an appropriate addressing scheme.Assign addresses and subnet mask pairs to device interfaces.Examine the use of the available network address space and future growth potential.Background / ScenarioWhen given a network topology, it is important to be able to determine the number of subnets required. In this lab, several scenario topologies will be provided, along with a base network address and mask. You will subnet the network address and provide an IP addressing scheme that will accommodate the number of subnets displayed in the topology diagram. You must determine the number of bits to borrow, the number of hosts per subnet, and potential for growth as specified by the instructions.Network Topology AIn Part 1, you have been given the 192.168.10.0/24 network address to subnet, with the following topology. Determine the number of networks needed and then design an appropriate addressing scheme.

Determine the number of subnets in Network Topology A.How many subnets are there? ____3______ How many bits should you borrow to create the required number of subnets? ____2_____ How many usable host addresses per subnet are in this addressing scheme? ______62_____ What is the new subnet mask in dotted decimal format? ________255.255.255.192_________________ How many subnets are available for future use? ____1___________

Record the subnet information.Fill in the following table with the subnet information:Subnet NumberSubnet AddressFirst Usable Host AddressLast Usable Host AddressBroadcast Address

0192.168.10.0/26192.168.10.1192.168.10.62192.168.10.63

1192.168.10.64/26192.168.10.65192.168.10.126192.168.10.127

2192.168.10.128/26192.168.10.129192.168.10.190192.168.10.191

3192.168.10.192/26192.168.10.193192.168.10.254192.168.10.255

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Network Topology BThe network topology from Part 1 has expanded to accommodate the addition of router R3 and its accompanying network, as illustrated in the following topology. Use the 192.168.10.0/24 network address to provide addresses to the network devices, and then design a new addressing scheme to support the additional network requirement.

Determine the number of subnets in Network Topology B.How many subnets are there? ____6_______ How many bits should you borrow to create the required number of subnets? ___3______ How many usable host addresses per subnet are in this addressing scheme? ___30________ What is the new subnet mask in dotted decimal format? ____255.255.255.224__________ How many subnets are available for future use? ____2___________


0192.168.0.0/27192.168.0.1192.168.0.30192.168.0.31

1192.168.0.32/27192.168.0.33192.168.0.62192.168.0.63

2192.168.0.64/27192.168.0.65192.168.0.94192.168.0.95

3192.168.0.96/27192.168.0.97192.168.0.126192.168.0.127

4192.168.0.128/27192.168.0.129192.168.0.158192.168.0.159

5192.168.0.160/27192.168.0.161192.168.0.190192.168.0.191

6192.168.0.192/27192.168.0.193192.168.0.222192.168.0.223

7192.168.0.224/27192.168.0.225192.168.0.254192.168.0.255

Network Topology CThe topology has changed again with a new LAN added to R2 and a redundant link between R1 and R3. Use the 192.168.10.0/24 network address to provide addresses to the network devices. Also provide an IP address scheme that will accommodate these additional devices. For this topology, assign a subnet to each network.

Determine the number of subnets in Network Topology C.How many subnets are there? ___9________ How many bits should you borrow to create the required number of subnets? _4________ How many usable host addresses per subnet are in this addressing scheme? ____14_______ What is the new subnet mask in dotted decimal format? __255.255.255.240________________ How many subnets are available for future use? _7______________ Record the subnet information.Fill in the following table with the subnet information:Subnet NumberSubnet AddressFirst Usable Host AddressLast Usable Host AddressBroadcast Address

0192.168.0.0/28192.168.0.1192.168.0.14192.168.0.15

1192.168.0.16/28192.168.0.17192.168.0.30192.168.0.31

2192.168.0.32/28192.168.0.33192.168.0.46192.168.0.47

3192.168.0.48/28192.168.0.49192.168.0.62192.168.0.63

4192.168.0.64/28192.168.0.65192.168.0.78192.168.0.79

5192.168.0.80/28192.168.0.81192.168.0.94192.168.0.95

6192.168.0.96/28192.168.0.97192.168.0.110192.168.0.111

7192.168.0.112/28192.168.0.113192.168.0.126192.168.0.127

8192.168.0.128/28192.168.0.129192.168.0.142192.168.0.143

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Assign addresses to network devices in the subnets.Fill in the following table with IP addresses and subnet masks for the router interfaces:DeviceInterfaceIP AddressSubnet Mask

R1GigabitEthernet 0/1192.168.0.1255.255.255.240

Serial 0/0/0192.168.0.17255.255.255.240

Serial 0/0/1192.168.0.33255.255.255.240


Serial 0/0/0192.168.0.65255.255.255.240

Serial 0/0/1192.168.0.81255.255.255.240


Serial 0/0/0192.168.0.113255.255.255.240

Serial 0/0/1192.168.0.129255.255.255.240

Fill in the following table with the IP addresses and subnet masks for devices in the LAN as displayed in topology.DeviceInterfaceIP AddressSubnet MaskDefault Gateway

PC-ANIC192.168.0.2255.255.255.240192.168.0.1

PC-BNIC192.168.0.3255.255.255.240192.168.0.1

S1VLAN 1192.168.0.4255.255.255.240192.168.0.1

PC-CNIC192.168.0.50255.255.255.240192.168.0.49

PC-DNIC192.168.0.51255.255.255.240192.168.0.49

S2VLAN 1192.168.0.52255.255.255.240192.168.0.49

PC-ENIC192.168.0.98255.255.255.240192.168.0.97

PC-FNIC192.168.0.99255.255.255.240192.168.0.98

S3VLAN 1192.168.0.100255.255.255.240192.168.0.99

Network Topology DThe network was modified to accommodate changes in the organization. The 192.168.10.0/24 network address is used to provide the addresses in the network.

Determine the number of subnets in Network Topology D.How many subnets are there? __15_________ How many bits should you borrow to create the required number of subnets? ____4_____ How many usable host addresses per subnet are in this addressing scheme? ___14________ What is the new subnet mask in dotted decimal format? ______255.255.255.240___________________ How many subnets are available for future use? __1_____________ Record the subnet information.Fill in the following table with the subnet information.Subnet NumberSubnet AddressFirst Usable Host AddressLast Usable Host AddressBroadcast Address

0192.168.0.0/28192.168.0.1192.168.0.14192.168.0.15

1192.168.0.16/28192.168.0.17192.168.0.30192.168.0.31

2192.168.0.32/28192.168.0.33192.168.0.46192.168.0.47

3192.168.0.48/28192.168.0.49192.168.0.62192.168.0.63

4192.168.0.64/28192.168.0.65192.168.0.78192.168.0.79

5192.168.0.80/28192.168.0.81192.168.0.94192.168.0.95

6192.168.0.96/28192.168.0.97192.168.0.110192.168.0.111

7192.168.0.112/28192.168.0.113192.168.0.126192.168.0.127

8192.168.0.128/28192.168.0.129192.168.0.142192.168.0.143

9192.168.0.144/28192.168.0.145192.168.0.158192.168.0.159

10192.168.0.160/28192.168.0.161192.168.0.174192.168.0.175

11192.168.0.176/28192.168.0.177192.168.0.190192.168.0.191

12192.168.0.192/28192.168.0.193192.168.0.206192.168.0.207

13192.168.0.208/28192.168.0.209192.168.0.222192.168.0.223

14192.168.0.224/28192.168.0.225192.168.0.238192.168.0.239

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Network Topology EThe organization has a network address of 172.16.128.0/17 to be divided as illustrated in the following topology. You must choose an addressing scheme that can accommodate the number of networks and hosts in the topology.

Determine the number of subnets in Network Topology E.How many subnets are there? _____12______ How many bits should you borrow to create the required number of subnets? ___4______ How many usable host addresses per subnet are in this addressing scheme? __2046_________ What is the new subnet mask in dotted decimal format? __255.255.248.0_______________________ How many subnets are available for future use? ___4____________


0172.16.128.0/21172.16.128.1172.16.135.254172.16.135.255

1172.16.136.0/21172.16.136.1172.16.143.254172.16.143.255

2172.16.144.0/21172.16.144.1172.16.151.254172.16.151.255

3172.16.152.0/21172.16.152.1172.16.159.254172.16.159.255

4172.16.160.0/21172.16.160.1172.16.167.254172.16.167.255

5172.16.168.0/21172.16.168.1172.16.175.254172.16.175.255

6172.16.176.0/21172.16.176.1172.16.183.254172.16.183.255

7172.16.184.0/21172.16.184.1172.16.191.254172.16.191.255

8172.16.192.0/21172.16.192.1172.16.199.254172.16.199.255

9172.16.200.0/21172.16.200.1172.16.207.254172.16.207.255

10172.16.208.0/21172.16.208.1172.16.215.254172.16.215.255

11172.16.216.0/21172.16.216.1172.16.223.254172.16.223.255

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Assign addresses to network devices in the subnets.Fill in the following table with IP addresses and subnet masks for the router interfaces:DeviceInterfaceIP AddressSubnet Mask


GigabitEthernet 0/1172.16.136.1255.255.248.0

Serial 0/0/0172.16.144.1255.255.248.0

Serial 0/0/1172.16.152.1255.255.248.0



Serial 0/0/0172.16.176.1255.255.248.0

Serial 0/0/1172.16.184.1255.255.248.0



Serial 0/0/0172.16.208.1255.255.248.0

Serial 0/0/1172.16.216.1255.255.248.0

ReflectionWhat information is needed when determining an appropriate addressing scheme for a network?____The number of networks you are planning on making, and the number of hosts per network._____________________________________________________________________________________________After the subnets are assigned, will all the host addresses be utilized in each subnet?___no, you have to set up each device to their required network, subnet mask and default gateway.________________________________________________________________________________________ 2013 Cisco and/or its affiliates. All rights reserved. This document is Cisco Public.Page 1 of 10 2013 Cisco and/or its affiliates. All rights reserved. This document is Cisco Public.Page 9 of 10

9.1.4.9 lab - subnetting network topologies

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