6. univesal joints
TRANSCRIPT
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6. UNIVERSAL JOINTS A universal joint is a connection between two intersecting rotating
shafts which are coplanar and are inclined at an angle with respect
to each other. The angle b/n the shafts may vary during operation
Used to transmit rotational motion
For a constant angular velocity of the driver, the velocity of thefollower fluctuates b/n a certain maximum and a certain minimum.
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6.1. Velocity Ratio of Shafts
Consider two shafts A and B which are the driver and follower,respectively.
The axes of the two shafts are inclined at an angle from the planview as shown below.
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If observed from the direction of A, when the shafts rotate,
A-A traces a circle while B-B traces an ellipse
The ellipse is a projection of the circle traced by b-b of the figure
above If shaft A turns through an angle from AA to A1A1, then the
projection of BB will also turn through angle to B1B1.
During this time the angle turned by shaft B is as observed fromthe axis of shaft B.
The projection of B1 andB2 on AA are C1 and C2.
From the geometry of the projections
)2(tan
)1(tan
11
2
22
2
11
1
BC
OC
BC
OCand
BC
OC
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Combining the above two equations we get
From the plan view it can be observed that
The relationship b/n , the angular displacement of shaft A and ,the angular displacement of shaft Bis obtained to be
Differentiating equation (5) with respect to time, the output shaftvelocity can be related to the input shaft velocity.
)3(tan
tan
1
1
2
1
OB
OC
OC
OC
)4(cos1
1 OB
OC
)5(costantan
)6(cossecsec22
dt
d
dt
d
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Where is a constant
The velocity relationship b/n the two shafts is thus obtained to be
From trigonometric relations
Substituting for tan from equation (5)
)8(
)7(
B
A
dt
dand
dt
d
)9(cossecsec 22 BA
22 tan1sec
2
22
2
2
2
cos
tancos
cos
tan1sec
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from equation (9) we obtain the equation that relates the input andoutput velocities.
Upon simplification, the velocity relation is obtained to be
Hence, the ratio of the angular velocities is given by
The ratio B/ A has a maximum value when for which
= 0 or = 180o or any multiple of 180o. For this condition,
)10(sec
1
coscos
tancos22
22
BA
)11(cos
cossin122
BA
)12(
cossin1
cos22
A
B
,1cos
)13(
cos
1
sin1
cos2
max
A
B
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The ratio B/ A has a minimum value when cos = 0, for which = 90o or = 270o, . or any multiple of 90o. For this condition,
6.2. POLAR ANGULAR VELOCITY DIAGRAM
Polar angular velocity diagramshows the velocity of the driver and
follower for a complete revolution of the joint.
)14(cosmin
A
B
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Since the angular velocity of the driver is assumed constant, it isrepresented by a circle.
The angular velocity of the follower is shown as an ellipse, since its
magnitude varies b/n a maximum and a minimum.
The ellipse crosses the circle at four points, in which case, during acycle the angular velocities of the driver and driven shaft are equal.
For this condition
Equation (15) yields
)15(1cossin1
cos22
)16(cos1
1
sincos1cos 2
2
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Upon simplification we obtain
Solving for tan we get
Thus, the driver and follower have the same speed when
)17(tan1cos1sec22
)18(costan
costan
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6.3. COEFFICIENT OF SPEED FLUCTUATION
The difference b/n the maximum and minimum speeds of thefollower expressed as a ratio of the driving shaft speed for constant
angle is defined as the coefficient of speed fluctuation.
Substituting for (B )max and (B )min yields
)19(minmax
A
BBq
)21(
cos
sin
cos
cos1cos
cos
1
)20(
coscos
1
2
2
q
or
qA
AA
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From equation (21) the coefficient of speed fluctuation is obtainedto be
For small angle , sin = , and tan = , hence, the coefficient ofspeed fluctuation is given by
where is in radians.
Having obtained the coefficient of speed fluctuation q, the totalfluctuation of speed is then given by
)22(tansin q
)23(2q
)24(2
Aspeedofnfluctuatiototal
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6.4. ANGULAR ACCELERATION OF DRIVEN SHAFT
Assuming A to be constant, for a constant inclination b/n thedriver and follower, the angular velocity of the follower is
The angular acceleration of the driven shaft is then obtained from
Which yields the angular acceleration of the driven shaft to be
)25(cossin1
cos22 AB
)26(cossin1
cos22
A
B
dt
d
dt
d
)27()cossin1(
2sinsincos222
22
AB
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For maximum angular acceleration, the acceleration term isdifferentiated with respect to time t and set equal to zero to give theposition for which the acceleration is maximum or minimum. i.e.
Upon simplification
For small values of ,
)28(0)cossin1(
2sinsincos222
2
dt
d
dt
d B
)29(
sin2
2cos2sin2cos
2
22
)30(sin2
sin22cos
2
2
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6.5. DOUBLE HOOKS JOINT
In an automobile, if only a single Hooks joint were used, either the
speed of the engine or that of the car would have to vary during
each revolution of the drive shaft. However, the inertia at both ends would resist this occurrence.
High stresses would occur on the transmission shaft and slippage on thetires.
This problem is solved by employing a double Hooks joint
which provides a uniform velocity b/n the input and output ends, Limits the variation of speed to the intermediate shaft.
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If the driver and follower are inclined equally relative to theintermediate shaft,
The fluctuation of speed will be confined to the intermediate shaft.
The intermediate shaft can then be made short and light in order toreduce the inertia in the transmission.
the relation b/n2, speed for the driver, and
4, speed for the
follower, is obtained as follows.
For angle which the driver turns through in a given time,
where is the angle turned by the intermediate shaft during thesame time.
Also
where is the angle turned through by the follower or output shaft.
)31(costantan
)32(costantan
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From these relations we have
i.e. the driving and driven shaft turn through the same angle in thesame time.
If the forks on the intermediate shaft are set at right angles, thespeed of the follower 4 will fluctuate b/n;
)34(
)33(tantan
or
)35(24
22
2
2
cos
1
cos
and