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4/19/2012 1 B T BOILERS AND THERMAL SYSTEMS; BOILER EFFICIENCY IMPROVEMENT SECTION P BOILER TYPES FIRE TUBE As the name implies, the As the name implies, the fire is in the tubes and the water outside. Most of the small “packaged” boilers in buildings and industry today are fire tube boilers and thus are likely the ones we will encounter. Section P - 2 Source: Illustration recreated for web by Technologists Inc. using graphic supplied by The Boiler Efficiency Institute, Auburn, Alabama to PNL, for use with FEMP O&M Best Practices, as a model.

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Page 1: 6-1 Steam Systems P SI CEMFastTrack 03 26 12 [Read-Only]

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B TBOILERS AND THERMALSYSTEMS;

BOILER EFFICIENCYIMPROVEMENTSECTION P

BOILER TYPES

FIRE TUBEAs the name implies, the As the name implies, the fire is in the tubes and thewater outside. Most of thesmall “packaged” boilers

inbuildings and industry today are fire tube boilersand thus are likely the

ones we will encounter.

Section P - 2

Source: Illustration recreated for web by Technologists Inc. using graphic supplied by The Boiler Efficiency Institute, Auburn, Alabama to PNL, for use with FEMP O&M Best Practices, as a model.

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WATER TUBEAgain, as the name implies, now the water is in the tubeand the fire outside. Most of the larger boiler systems

todayare constructed water tube boilers. There are smallerpackaged water tube boilers also. We will see water tubep gboilers but most of the larger ones are well designed andcontrolled. Thus, we will not spend much time on watertube boilers.

Section P - 3

PROPERTIES AND USE OF STEAM

Steam is water in a vapor state Steam temperature is in °C or K

K = C + 273 Steam pressure is in kPa, MPa or bar

1 bar = 100 KPa = 0.1 Mpa Steam conditions are either:

saturated - temperature or pressure specifies its properties

superheated must know temperature and superheated - must know temperature and pressure to find its properties

Section P - 4

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HEAT CONTENT OF STEAM

The heat content of steam is called its enthalpy (h or H) measured in kJ/Kg

By definition h = H = 0 at 0°C

Enthalpy is the sum of the sensible plus latent heat. Sensible heat - heat absorbed or removed during a

change in temperature without a change in state of phase

Latent heat - heat absorbed or removed during a change of state or phase at constant temperature

Section P - 5

STEAM DISTRIBUTION SYSTEM

The steam distribution system on the next page shows a “typical” distribution system.

The major components include The steam manifold and piping, heat exchangers, steam traps at each use point and at various

locations throughout the system, pressure reducing valves, condensate return piping, condensate return piping, condensate return tank(s), and various pumps.

Section P - 6

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STEAM SYSTEM

170 C 8 BAR (800 KPA) 150 C & 450 KPA

Section P - 7

Not shown in the previous diagram are:

make up water, water treatment for the make up water, and f d t t k hi h i t i ll b t a feedwater tank which is typically between

the condensate return tank and the boiler.

The feedwater tank will also normally have feedwater preheating and removal of oxygen (deaeration).(deaeration).

Section P - 8

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STEAM TRAPS

Purposes1 Reject (Return) Condensate1. Reject (Return) Condensate2. Reject Air3. Hold Back Steam

Section P - 9

MONITORING

In a poorly maintained or non-maintained system, 20% to 30% of the steam traps are likely stuck open wasting significant amounts of expensive steam. To locate failed steam traps, use:

1. Sight (Watch the Discharge)2. Sound (Listen to the Operation Possibly Ultrasonically)3. Temperature (Watch the Delta T)

Note: Real Time MMS Available

Other indications that a steam trap may be malfunctioning: the system has trouble holding pressure, the condensate return tank is unpressurized and

significant flash steam is formed

Section P - 10

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COMBUSTION EFFICIENCY Combustion is an exothermic (heat producing) chemical

reaction. The chemistry for the combustion of methane (natural

) gas is about 96% methane) is shown below.

CH4 + 2O2 CO2 + 2H2O+ _O2 + _ O2

+ _N2 + _ N2

+ _ NOx

Section P - 11

CONTROLLING COMBUSTION

In any closed combustion system such as a boiler or a furnace without secondary air, we can measure precisely what occurred at the can measure precisely what occurred at the burner by carefully measuring the exhaust.

The goal is to be able to carefully control the fuel and airflow to ensure complete and efficient combustion.

We will see why excess air is important and We will see why excess air is important and why too much excess air is expensive.

Section P - 12

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NATURAL GAS

FLUE GAS ANALYSIS VS. % COMBUSTION AIR

Section P - 13

Section P - 14

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ALL TEMPERATURES ARE STR IN °C (STACK TEMPERATURE RISE)

efficiency New

efficiency Old-efficiency NewsavingsPercent

nconsumptio Fuel savingsPercent Savings

Section P - 15

SCALE AND SOOTWhether fire tube or water tube, it is important that the tubes remain clean.On the waterside, scaling can lead to a dramatic loss in efficiency. Scale isa good insulator, thus as scale forms the temperature of the fireside mustincrease to do the work on the waterside. Water treatment is essential tomaintain this condensate return never have a scaling problem. Most of us

ill fi d i i di ll h h b il d d lwill find it necessary to periodically shut the boiler down and remove scale.The Figure on the next page demonstrates the expected amount of lossdue to scaling. Reverse osmosis water treatment will almost eliminatescaling problems.

Soot on the fireside has a similar effect. Running good combustion systems slightly on the excess airside ensures complete combustion and

Section P - 16

andminimizes soot. However, soot blowers may be required, especially forcertain fuels, and periodic brushing gas fired system, this brushing is likely required about once a year.

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Section P - 17

LOAD BALANCINGThe boiler room is an interesting place. If the boiler room

operator keeps the boiler working with adequate pressure everywhere in the plant, no one complains. Normally, there is an extra boiler or two for back up and load variation reasons Therefore there is a natural load variation reasons. Therefore, there is a natural tendency for the operator to fire all the available boilers and run them at part load. If one goes down, the others quickly move up and the pressure is maintained.

Boilers don't run well at low loads and each boiler has about 3-5% “skin losses”, so there is a significant energy penalty for this philosophy. Instead, profiling the efficiency of each boiler for varying loads will yield data h b d d i h i fi i fil

y y g ythat can be used to determine the optimum firing profile for any load.

Section P - 18

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BOILER BLOWDOWN

Section P - 19

Additional details on Blowdown in Appendix

FLASH STEAM

When a hot pressurized liquid is placed in a tank with lower pressure, some “flash steam” will form as the enthalpy of thesaturated liquid is reduced.

This phenomenon is sometimes a major loss to the steam system (700 kPa blowdown going to an unpressurized vessel will produce significant

h h h atmospheric pressure steam which is worthless and thus is a loss). It is easy to calculate how much as shown in the example following.

Section P - 20

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FLASH STEAM

Alternatively, the high-pressure liquid can be taken to a low pressure tank. The flash t h h t d steam now has enough pressure to use, and

inexpensive low-pressure steam is the result.

The next example shows how to calculate that.

Continuous top blowdown is an excellent source for this purpose and sometimes enough pressureis left in the condensate return to accomplish the same thing.

Section P - 21

BOILER LOG SHEETSAs with any other operating equipment, log sheets areextremely important.

Th ill t ll h t i h i h t i i They will tell you what is happening, what is going wrong, and usually what is causing that. It isvitally important to keep good log sheets for all boilersystems.

The numbers are usually taken or observedanyway. The log sheet is simply an organized method ofkeeping those numbers.

Log sheets should be developed for individual sites,boilers, and operators.

Section P - 22

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BOILER AND STEAM PLANT ECM’SINCREASE BOILER EFFICIENCY1. Reduce Excess Air to Boiler(s)2. Provide Sufficient Air to Boiler(s) for Complete Combustion3. Install Low Excess Air Burner (s)( )4. Repair/Replace Faulty Burner (s)5. Repair Natural Draft Burner(s) with Forced Draft Burner(s)6. Install Turbulators in Firetube Boiler(s)7. Replace Existing Boiler(s) with New More Efficient Boiler(s)8. Install a Condensing Boiler/Water Heater9. Install a Pulse Combustion Boiler/Water Heater10. Install a Small Boiler for Summer Operation11. Clean Boiler(s) to Eliminate Fouling and Scale12. Improve Feedwater Chemical Treatment to Reduce Scaling13. Optimize Boiler Loading When Using Multiple Boilers

Section P - 23

INSULATION14. Install Insulation on Steam Line(s)15. Install Insulation Jacket on Steam Fitting(s)16. Install Insulation on Feedwater Line(s)17. Install Insulation on Condensate Return Line(s)18. Install Insulation on Condensate/Feedwater/Deaerator Tank(s)19. Install Insulation on (Domestic) Hot Water Line(s)20. Install Insulation on (Domestic) Hot Water Tank21. Install Insulation Jacket on Boiler Shell22. Install Insulation to Reduce Heat Loss

REDUCE BOILER LOAD23. Repair Steam Leak(s)

R i F il d St T ( )24. Repair Failed Steam Trap(s)25. Reduce Boiler Blowdown26. Return Condensate to Boiler(s)

Section P - 24

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27. Shut Off Steam Tracer(s) During Summer28. Shut Off or Turn Back Boiler During Long Periods of No Use29. Change Boiler Steam Pressure30. Replace Continuous Gas Pilot(s) with Electronic Pilot(s)31. Install Stack Damper(s) to Reduce Natural Draft Heat Loss32. Pressurize Condensate Return System33. Reduce or Utilize Flash Steam33. Reduce or Utilize Flash Steam34. Reduce Boiler Load and/or Steam Requirement

WASTE HEAT RECOVERY35. Install an Economizer to Preheat Boiler Feedwater36. Install Heat Exchanger to Preheat Boiler Makeup or Feedwater37. Install Heat Exchanger to Recover Blowdown Heat38. Install Recuperator to Preheat Combustion Air39 Recover Waste Heat to Supplement (Domestic) Hot Water Demand39. Recover Waste Heat to Supplement (Domestic) Hot Water Demand40. Recover Heat from Boiler Flue Gas to Supplement Bldg Heat41. Install Heat Recovery Steam Generator on Incinerator42. Direct Contact Condensation Heat Recovery

Section P - 25

OTHER43. Vary (Domestic or Heating) Hot Water Temp. Based on

Demand44. Eliminate Air Conditioning in Boiler Room45. Install Back Pressure Steam Turbine for Cogeneration46. Switch to an interruptible Natural Gas Source47. Request Change to a Different Utility Rate Schedule48. Switch to a More Economical Fuel Source49. Install Heat Pump to Supplement (Domestic) Hot Water

Demand50. Replace Electric Boiler(s) with Natural Gas Fired Boiler(s)

I t ll S t llit B il51. Install a Satellite Boiler52. Install a Variable Frequency Drive on Pump(s) and Fan(s)53. Replace On/Off Control System with Variable Firing Rate

Section P - 26

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ADDITIONAL PRACTICE EXAMPLES

1. A large facility assumed that it was too costly in distribution piping to return y p p gcondensate to the boiler. Find the savings for utilizing this source of heat for condensate unit heaters to provide space heating for 4,000 hours per year. Assume the temperature leaving the heater is 40°C, the temperature of condensate is125°C there is 9000 kg/hr of condensate is125 C, there is 9000 kg/hr of condensate available, and cost of present fuel to heat the building is $8/GJ. Boiler efficiency is 85%.

Section P - 27

SOLUTION FOR EXAMPLE 1

Analysis:q = m x Cp x deltaT q p

= (9000 kg/hr)(4.2 kJ/kg°C)(125-40)°C= 3.2 x 106 kJ/hr

Savings = (3.2 x 106 kJ/hr) x (1 GJ/1,000,000 kJ) x($8.00/GJ) x(4000 h / )(1/0 85)(4000 hrs/yr)(1/0.85)

= $120,471/year

Section P - 28

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EXAMPLE 2

In operating a boiler with dual fuel capability, comment on the lowest cost of fuel given the comment on the lowest cost of fuel given the following.

Natural Gas $5.80/GJ efficiency = 0.92Residual Fuel Oil $310/ton

(40,000 kJ/kg) efficiency = 0.88

Section P - 29

SOLUTION FOR EXAMPLE 2

Analysis:Convert each fuel source to $/GJ delivered$

Natural Gas = ($5.80/GJ)/0.92 = $6.30/GJ delivered

Residual = ($310/ton)(1/1000 ton/kg) x (1/40000 kg/kJ) x( g )

(106 kJ/GJ)(1/0.88)=$8.81/GJ delivered

Best Choice: Natural Gas

Section P - 30

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EXAMPLE PROBLEM

3. Last year a 20 GJ/hr boiler consumed 19,000 GJ of natural gas at $8/GJ. The boiler operates at 6% O2 and 350 °C STR. What is the savings for correcting that to 3% O2?

Eff1=75% and Eff2=77%

%6.2or026.077

75-77savings %

yr

948,3$

GJ

00.8$

Year

GJ000,19026.0savingsCost

Section P - 31

AEE/ Certified Energy Manager CEM AEE/ Certified Energy Manager CEM ®®

Section P - 32

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4. Now, you can install an economizer that will reduce the stack temperature rise to 200°C. What is the % fuel savings for that change?

%2777-83

savings%

Eff 1 = 77% Eff 2 = 83%

%2.783

savings %

3) What is the % excess air for 3% O2 –Natural Gas?

Approximately 15%

What would the CO2 reading be if we measured it?

Section P - 33

2 g

Approximately 10%

STEAM EXAMPLES

1a. Find the enthalpy of 800 kPa (8 bar) saturated steam.

Using Table H = 2768.7 kJ/kg

for 800 kPa steam

1b. Find the enthalpy of 165 °C steam.

Section P - 34

py

Using Table H = 2762 kJ/kg

for 165°C steam

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2. How much heat is required to raise the temperature of 3000 kg of water from 20°C to 80°C?

For 20°C water from Table H = 83.9For 20 C water from Table H 83.9

For 80°C water from Table H = 334.9

( )

kJ000,753xkg

kJ9.839.334kg3000kJx

=

=

GJ753.0x ≈

Section P - 35

3. Find the amount of heat required to convert 3000 kg of boiler feedwater at 90°C to saturated steam at 800 kPa (8 bar).

For 90°C water H = 376.9 (Table)For 90 C water H 376.9 (Table)

For 800 kPa steam H = 2768.7 (Table)

( )

kJ4001757kg

kJ9.3767.2768kg3000kJx =

GJ18.7xkJ400,175,7x

=

Section P - 36

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APPENDIX

Section P - 37

TYPES OF STEAM TRAPS

Section P - 38

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INVERTED BUCKET STEAM TRAP

1) Steam enters trap under bottom of bucket, where it rises and collects at top, imparting buoyancy imparting buoyancy. Bucket then rises and lifts valve towards its seat until valve is snapped tightly shut. Air and carbon dioxide continually pass through bucket vent and collect at top of trap Any collect at top of trap. Any steam passing through vent is condensed by radiation from trap.

Section P - 39

INVERTED BUCKET STEAM TRAP

2) As the entering condensate starts to fill the bucket, the bucket begins

to exert a pull on the lever. As the condensate continues to rise, more force is exerted until there is enough to open the valve against the differential pressure pressure.

Section P - 40

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F&T STEAM TRAP

1) When steam reaches the trap, the thermostatic air vent closes in response to higher temperature. Condensate continues to flow through the main valve which is positioned by the float to discharge

d t t th

Section P - 41

condensate at the same rate that it flows to the trap.

F&T STEAM TRAP

2) As air accumulates in the trap, the temperature drops below that of saturated steam. The balanced pressure thermostatic air vent opens and discharges air.

Section P - 42

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THERMOSTATIC STEAM TRAP

As the temperature inside the trap increases, it quickly heats the charged bellows element, increasing the vapor pressure inside. When pressure inside the element becomes balanced with system pressure in the trap body, the spring effect of the bellows causes the element to expand, closing the valve. When temperature in the trap drops a few degrees below drops a few degrees below saturated steam temperature, imbalanced pressure contracts the bellows, opening the valve.

Section P - 43

BOILER BLOWDOWN

Condensate is distilled water and thus is very clean. If it Condensate is distilled water and thus is very clean. If it is

not all returned, make up water is needed and this water is

not as clean. Thus, solids (mud) will build up in the boiler.

Some of that mud will float at the top and some will sink Some of that mud will float at the top and some will sink to the bottom. The mud on the bottom would eventually plug the boiler. As the boiler is firing, these residual solids are formed at the steam water interface where some sink and some float.

Section P - 44

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To cure these problems, boilers will have to be “blown down” in some fashion.

There is usually a top blowdown (skimming) that is often continuous or could easily be automated by blowing down when the conductivity of the water reaches a down when the conductivity of the water reaches a certain level. This top blowdown is relatively clean and usually a small volume flow.

If the boiler is producing 700 kPa steam, then this blowdown is saturated water at 165 C.

Section P - 45

Thus, TOP BLOWDOWN IS AN EXCELLENT OPPORTUNITY FOR WASTE HEAT RECOVERY.

The bottom or mud blowdown is usually donell b ti t ti ll T bmanually, by timers, or automatically. To be

sure the mud is adequately removed, thisblowdown is usually drawn off in a large linewith agitation. Mud blowdown is usually not agood candidate for heat recovery.

Section P - 46

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An excellent system takes the high pressure blowdown,develops low pressure steam in the tank described andthen runs the liquid left in the low pressure tank then runs the liquid left in the low pressure tank

through ashell and tube heat exchanger to preheat the make upwater. These systems are available commercially.

Section P - 47

BOILER BLOWDOWN(SEE FIGURE)

Purpose: Avoid “mud” build up in boilerProblem: Very hot liquid at boiler drum pressure Problem: Very hot liquid at boiler drum pressure

is rejected

Management:Maintain proper BD rateRecover heat from blowdown with a shell &

t b h t h ( ti t tube heat exchanger (continuous or top blowdown)

Recover flash steam (see heat recovery Q-8)

Section P - 48

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CALCULATING BOILER BLOWDOWN

% BD = A x 100% BD A x 100(B – A)

A = ppm impurities in feedwater

B = ppm allowed in boiler

Section P - 49

BOILER BLOWDOWN EXAMPLE

Calculate the percentage of blowdown for a boiler that has an allowable limit of 500 ppm of impurities and uses feedwater with 10 ppm of impuritiesfeedwater with 10 ppm of impurities.

A = 10 ppmB = 500 ppm

%BD = 10 x 100 = 2%500 - 10

Section P - 50

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BLOWDOWN CALCULATION EXAMPLE

Calculate the % of flash steam generated by expanding saturated liquid from 10 bar to 2 barbar.

From steam tables: Hf1 = 762.5 kJ/kg ( 10 bar liquid)Hf2 = 504.7 kJ/kg ( 2 bar liquid)Hfg2 = 2201.5 kJ/kg (2 bar liquid to vapor)

% FLASH = 762.5 – 504.7 x100 = 11.7%2201.5

Section P - 51

SI STEAM TABLES

Section P - 52

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Section P - 54

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Section P - 58

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Section P - 63

END OF SECTION P

Section P - 64