5_5_the_mole
TRANSCRIPT
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Chapter 5Chemical Reactions and Quantities5.5
The Mole
Copyright 2005 by Pearson Education, Inc.Publishing as Benja in Cu ings
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Collection Terms
! collection term statesa speci"ic nu ber o" ite s.
# 1 do$en donuts% 12 donuts
# 1 rea o" paper% 500 sheets
#1 case % 2& cans
Copyright 2005 by Pearson Education, Inc.Publishing as Benja in Cu ings
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! mole is a collection that contains
# the sa e nu ber o" particles as there are carbonato s in 12.0 g o" carbon.
# (.02 ) 10 2' ato s o" an ele ent *!+ogadro s nu ber-.
1 mole element Number of Atoms1 ole C % (.02 ) 10 2' C ato s1 ole a % (.02 ) 10 2' a ato s1 ole !u % (.02 ) 10 2' !u ato s
A Mole of Atoms
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! ole# o" a co+alent co pound has !+ogadro s nu ber o"
olecules.1 mole CO 2 = .!2 " 1! 2# CO 2 molecules1 mole $ 2 O = .!2 " 1! 2# $ 2 O molecules
# o" an ionic co pound contains !+ogadro s nu ber o""or ula units.
1 mole NaCl = .!2 " 1! 2# NaCl formula units1 mole % 2 &O' = .!2 " 1! 2# %2 &O ' formula units
A Mole of a Compound
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&les of One Mole Quantities
1 ole C % (.02 ) 10 2' C ato s
1 ole !l % (.02 ) 10 2' !l ato s
1 ole / % (.02 ) 10 2' / ato s
1 ole 2 % (.02 ) 10 2' 2 olecules
1 ole CCl & % (.02 ) 10 2' CCl & olecules
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!+ogadro s nu ber .!2 " 1! 2# can be ritten as ane3uality and t o con+ersion "actors.
()ualit*+1 mole = .!2 " 1! 2# particles
Con,ersion -actors+.!2 " 1! 2# particles and 1 mole
1 mole .!2 " 1!2#
particles
A,o adro/s Number
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0sin A,o adro/s Number
!+ogadro s nu ber is used to con+ertmoles of a substance to particles.
o any Cu ato s are in 0.50 ole Cu0.50 ole Cu ) (.02 ) 10 2' Cu ato s
1 ole Cu
% '.0 ) 10 2' Cu ato s
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0sin A,o adro/s Number
!+ogadro s nu ber is used to con+ertparticles of a substance to moles.
o any oles o" C 2 are in2.50 ) 10 2& olecules C 2
2.50 ) 10 2& olecules C 2 ) 1 ole C 2
(.02 ) 10 2' olecules C 2
% &.15 ole C 2
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1. 8he nu ber o" ato s in 2.0 ole !l is !. 2.0 !l ato s.
B. '.0 ) 10 2' !l ato s.
C. 1.2 ) 102&
!l ato s.
2. 8he nu ber o" oles o" / in 1.6 ) 10 2& ato s / is !. 1.0 ole / ato s.
B. '.0 ole / ato s. C. 1.1 ) 10 &6 ole / ato s.
earnin Chec
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&olution
!. 8he nu ber o" ato s in 2.0 ole !l is 2.0 ole !l ) (.02)10 2' !l ato s % 1.2 ) 10 2& !l ato s 1 ole !l
A,o adro/s
Number
B. 8he nu ber o" oles o" / in 1.6 ) 10 2& ato s / is1.6 ) 10 2& ato s / ) 1 ole /
(.02 ) 10 2' / ato sA,o adro/s
Number % '.0 oles o" / ato s
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&ubscripts and Moles
8he subscripts in a formula sho# the relationship o" ato s in the "or ula.# the oles o" each ele ent in 1 ole o" co pound.
9lucoseC 12
In 1 olecule: ( ato s C 12 ato s ( ato s 3n 1 mole+ mole C 12 mole $ mole O
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&ubscripts &tate Atoms and Moles
7 ole C 6 ole & ole
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-actors from &ubscripts
8he subscripts are used to rite con+ersion "actors "or oles o" each ele ent in 1 ole co pound. ;or aspirin
C 7 6 &, the "ollo ing "actors can be ritten:
7 ole C 6 ole & ole 1 mole C4$ O' 1 mole C4$ O' 1 mole C4$ O'and1 mole C4$ O' 1 mole C4$ O' 1 mole
C4$ O'7 ole C 6 ole & ole
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1&
earnin Chec
!. o any ole are in 0.150 oleaspirin C 7 6 &
B. o any ato s are in 0.150 oleaspirin C 7 6 &
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&olution
!. o any ole are in 0.150 ole aspirin C 7 6 &0.150 ole C 7 6 & ) ' mole O % 0.(00 ole 1 mole C 4 $ 5 O ' subscript factor
B. o any ato s are in 0.150 ole aspirin C 7 6 &0.150 ole C 7 6 & ) ' mole O ) (.02 ) 10 2' ato s
1 mole C 4 $ 5 O ' 1 ole subscript A,o adro/s
factor Number % '.(1 ) 10 2' ato s