5_5_the_mole

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    Chapter 5Chemical Reactions and Quantities5.5

    The Mole

    Copyright 2005 by Pearson Education, Inc.Publishing as Benja in Cu ings

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    Collection Terms

    ! collection term statesa speci"ic nu ber o" ite s.

    # 1 do$en donuts% 12 donuts

    # 1 rea o" paper% 500 sheets

    #1 case % 2& cans

    Copyright 2005 by Pearson Education, Inc.Publishing as Benja in Cu ings

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    ! mole is a collection that contains

    # the sa e nu ber o" particles as there are carbonato s in 12.0 g o" carbon.

    # (.02 ) 10 2' ato s o" an ele ent *!+ogadro s nu ber-.

    1 mole element Number of Atoms1 ole C % (.02 ) 10 2' C ato s1 ole a % (.02 ) 10 2' a ato s1 ole !u % (.02 ) 10 2' !u ato s

    A Mole of Atoms

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    ! ole# o" a co+alent co pound has !+ogadro s nu ber o"

    olecules.1 mole CO 2 = .!2 " 1! 2# CO 2 molecules1 mole $ 2 O = .!2 " 1! 2# $ 2 O molecules

    # o" an ionic co pound contains !+ogadro s nu ber o""or ula units.

    1 mole NaCl = .!2 " 1! 2# NaCl formula units1 mole % 2 &O' = .!2 " 1! 2# %2 &O ' formula units

    A Mole of a Compound

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    &amples of One Mole Quantities

    1 ole C % (.02 ) 10 2' C ato s

    1 ole !l % (.02 ) 10 2' !l ato s

    1 ole / % (.02 ) 10 2' / ato s

    1 ole 2 % (.02 ) 10 2' 2 olecules

    1 ole CCl & % (.02 ) 10 2' CCl & olecules

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    !+ogadro s nu ber .!2 " 1! 2# can be ritten as ane3uality and t o con+ersion "actors.

    ()ualit*+1 mole = .!2 " 1! 2# particles

    Con,ersion -actors+.!2 " 1! 2# particles and 1 mole

    1 mole .!2 " 1!2#

    particles

    A,o adro/s Number

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    0sin A,o adro/s Number

    !+ogadro s nu ber is used to con+ertmoles of a substance to particles.

    o any Cu ato s are in 0.50 ole Cu0.50 ole Cu ) (.02 ) 10 2' Cu ato s

    1 ole Cu

    % '.0 ) 10 2' Cu ato s

    Copyright 2005 by Pearson Education, Inc.Publishing as Benja in Cu ings

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    0sin A,o adro/s Number

    !+ogadro s nu ber is used to con+ertparticles of a substance to moles.

    o any oles o" C 2 are in2.50 ) 10 2& olecules C 2

    2.50 ) 10 2& olecules C 2 ) 1 ole C 2

    (.02 ) 10 2' olecules C 2

    % &.15 ole C 2

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    1. 8he nu ber o" ato s in 2.0 ole !l is !. 2.0 !l ato s.

    B. '.0 ) 10 2' !l ato s.

    C. 1.2 ) 102&

    !l ato s.

    2. 8he nu ber o" oles o" / in 1.6 ) 10 2& ato s / is !. 1.0 ole / ato s.

    B. '.0 ole / ato s. C. 1.1 ) 10 &6 ole / ato s.

    earnin Chec

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    &olution

    !. 8he nu ber o" ato s in 2.0 ole !l is 2.0 ole !l ) (.02)10 2' !l ato s % 1.2 ) 10 2& !l ato s 1 ole !l

    A,o adro/s

    Number

    B. 8he nu ber o" oles o" / in 1.6 ) 10 2& ato s / is1.6 ) 10 2& ato s / ) 1 ole /

    (.02 ) 10 2' / ato sA,o adro/s

    Number % '.0 oles o" / ato s

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    &ubscripts and Moles

    8he subscripts in a formula sho# the relationship o" ato s in the "or ula.# the oles o" each ele ent in 1 ole o" co pound.

    9lucoseC 12

    In 1 olecule: ( ato s C 12 ato s ( ato s 3n 1 mole+ mole C 12 mole $ mole O

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    &ubscripts &tate Atoms and Moles

    7 ole C 6 ole & ole

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    1'

    -actors from &ubscripts

    8he subscripts are used to rite con+ersion "actors "or oles o" each ele ent in 1 ole co pound. ;or aspirin

    C 7 6 &, the "ollo ing "actors can be ritten:

    7 ole C 6 ole & ole 1 mole C4$ O' 1 mole C4$ O' 1 mole C4$ O'and1 mole C4$ O' 1 mole C4$ O' 1 mole

    C4$ O'7 ole C 6 ole & ole

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    1&

    earnin Chec

    !. o any ole are in 0.150 oleaspirin C 7 6 &

    B. o any ato s are in 0.150 oleaspirin C 7 6 &

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    &olution

    !. o any ole are in 0.150 ole aspirin C 7 6 &0.150 ole C 7 6 & ) ' mole O % 0.(00 ole 1 mole C 4 $ 5 O ' subscript factor

    B. o any ato s are in 0.150 ole aspirin C 7 6 &0.150 ole C 7 6 & ) ' mole O ) (.02 ) 10 2' ato s

    1 mole C 4 $ 5 O ' 1 ole subscript A,o adro/s

    factor Number % '.(1 ) 10 2' ato s