5.4 – apply the remainder and factor theorems divide 247 / 3 8829 / 8
TRANSCRIPT
5.4 – Apply the Remainder and Factor Theorems
Divide
247 / 3
8829 / 8
5.4 – Apply the Remainder and Factor Theorems
When you divide a polynomial f(x) by a divsor d(x), you get a quotient polynomial q(x) and a
remainder polynomial r(x).
f(x) / d(x) = q(x) + r(x)/d(x)
The degree of the remainder must be less than the degree of the divisor. One way to divide
polynomials is called polynomial long division.
5.4 – Apply the Remainder and Factor Theorems
Example 1:
Divide f(x) = 3x4 – 5x3 + 4x – 6 by x2 – 3x + 5
5.4 – Apply the Remainder and Factor Theorems
Example 1b:
Divide f(x) = x3 +3x2 – 7 by x2 – x – 2
5.4 – Apply the Remainder and Factor Theorems
Example 2:
Divide f(x) = x3 +5x2 – 7x + 2 by x – 2
5.4 – Apply the Remainder and Factor Theorems
Example 2b:
Divide f(x) = 3x3 + 17x2 + 21x – 11 by x + 3
5.4 – Apply the Remainder and Factor Theorems
Synthetic division can be used to divide any polynomial by a divisor of the form x – k.
5.4 – Apply the Remainder and Factor Theorems
Example 3:
Divide f(x) = 2x3 + x2 – 8x + 5 by x + 3 using synthetic division
5.4 – Apply the Remainder and Factor Theorems
Example 3b:
Divide f(x) = 2x3 + 9x2 + 14x + 5 by x – 3 using synthetic division
5.4 – Apply the Remainder and Factor Theorems
5.4 – Apply the Remainder and Factor Theorems
Example 4:
Factor f(x) = 3x3 – 4x2 – 28x – 16 completely given that x + 2 is a factor.
5.4 – Apply the Remainder and Factor Theorems
Example 4b:
Factor f(x) = 2x3 – 11x2 + 3x + 36 completely given that x – 3 is a factor.
5.4 – Apply the Remainder and Factor Theorems
Example 5:
One zero of f(x) = x3 – 2x2 – 23x + 60 is x = 3. What is another zero of f?