5.2 forces & equilibrium soh cah toa too. normal forces if an object is not accelerating (at...
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5.2 Forces & Equilibrium
SOH CAH TOA too
Normal forces
• If an object is NOT accelerating (at rest or a constant velocity) the net force must be zero.
• This means that all the forces must balance out and cancel.
• The normal force is always perpendicular to the surface (not always up if surface is at an angle).
Hooke’s Law
• A spring always exerts a ‘restoring’ force - the force always acts to move the spring back to its ‘resting’ position. If you pull on the spring, it wants to pull back. If you push on the spring, it wants to push back. The force of the push is proportional to the displacement:
F = -k•xF is force, k is the spring constant and x is the displacementthe “-” means that the force is always opposite the displacement.
• What are the units of k? (click for answer)K = -F/x so units are N/m
Sine, Cosine, and Tangent
SOH CAH TOA• Here is the secret of trigonometry – these are
really just ratios (shh - don’t tell your math teachers) that we use in physics to figure out components of vectors in an easier way.
SOH CAH TOA
• Draw a right triangle on the board using a meter stick.
• Measure the length of each side and the hypotenuse
• Determine the angle
SOH CAH TOA
• We need to find the ratios of the sides• The sides are designated as adjacent to the
angle or opposite the angle that is measured
Adjacent side
Opp
osite
si
de
hypotenuse
angle
SOH CAH TOA
• Find the ratio of opposite/hypotenuse of the angle on the board.
• This is called the “sine” of the angle.• Now determine the sine of the measured
angle (use a protractor to get the angle).
Adjacent side
Opp
osite
si
de
hypotenuse
angle
SOH CAH TOA
• The ratio of opposite/hypotenuse should equal the “sine” of the measured angle.
• SOH: Sine = opposite / hypotenuse• This gives up the y component of a vector
Adjacent side
Opp
osite
si
de
hypotenuse
angle
SOH CAH TOA
• Repeat for adjacent over hypotenuse• This gives the “cosine” of the angle. Check the
cosine of the measured angle• CAH: cosine = adjacent / hypotenuse and is
used to get the x-component.
Adjacent side
Opp
osite
si
de
hypotenuse
angle
SOH CAH TOA
• Repeat for opposite over adjacent• This gives the “tangent” of the angle. Check
the tangent of the measured angle• TOA: tangent = opposite / adjacent and is used
to get the resultant if the x and y components are known.
Adjacent side
Opp
osite
si
de
hypotenuse
angle
SOH CAH TOA
• Do a second example of a different triangle• Make sure you have your calculator in ‘degrees’• Sample problem:– Draw a force vector of 14 n at 40° to scale– Determine the x and y components graphically– Determine the x and y components with trig
(SOH CAH TOA).• Everyone do this and have a volunteer put on
board
• Do p 113, 116, SP p 131 q 5-8• 4 additional problems: Determine x and y
components graphically & with trig for:a) 18 N @ 35°, b) 13 N @ 55°, c) find the resultant of Fx = 13.8 N & Fy = 6.9 N
• If you move a chair, borrow a protractor etc. put it back!! It’s rude