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  • 8/10/2019 4th Session PPT

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    Risks and uncertainity

    Insurable risks

    Non-insurable risks

    Investment decisions under risk:

    Strategies and state of nature. Outcome and pay-off matrix.

    Risk-Return evaluation.

    Risk preference.

    risk seekerrisk averter

    risk indifferent

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    Adjustments for risk and criteria for decisions:

    1. Finite-horizon method

    2. Risk discounting model.

    3. The shackle approach.

    4. The probability theory approach.

    5. Sensitivity analysis.

    6. Simulation.7. Hedging.

    8. Decision tree.

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    Investment decisions under

    uncertainity

    The maximin criteria.

    The minimax regret criteria.

    The hurwicz alpha index. The maximax criteria.

    The laplace criterion.

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    Treatments of Risks and Uncertainty in

    Projects

    The availability ofpartialor imperfect

    information about a problem leads to two

    new category of decision-making techniques

    Decisions under risk (In terms of a probability function)

    Decisions under Uncertainty (No probability function is

    secure)

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    Decisions under risk

    Decisions under risk are usually based on one

    of the following criteria

    Expected Value

    Combined Expected value and variance

    Known Aspiration level

    Most likely occurrence of a future state

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    Expected Value Criterion

    Expressed in terms of either actual money or its utility

    Decision Makers attitude towards the worth or utility of

    money is important

    The final decision should ultimately be made by consideringall pertinent factors that affect the decision makersattitude

    towards the utility of money

    The drawback of this is that use of expected value criterion

    may be misleading fro the decisions that are applied only a

    few number of times i.e small sample sizes

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    Example 1

    A preventive maintenance policy requires making decisions about when a

    machine (or a piece of equipment) should be serviced on a regular basis in

    order to minimize the cost of sudden breakdown

    The decision situation is summarized as follows. A machine in a group of nmachines is serviced when it breaks down. At the end of T periods,

    preventive maintenance is performed by servicing all n machines. The

    decision problem is to determine the optimum T that minimizes the total

    cost per period of servicing broken machines and applying preventive

    maintenance

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    Let ptbe the probability that machine would break down in period t

    Let ntbe the random variable representing the number of broken machines in

    the same period.

    C1is the cost of repairing a broken machine C2 the preventive maintenance of the machine

    The expected cost per period can be written as

    Where E{nt}is the expected number of broken machines in period t.

    nt is a binominal random variable with parameter (n,pt), E{nt}=npt

    The necessary condition for T*to minimize EC(T) are

    EC(T*-1)>= EC(T*) and EC(T*+1)>= EC(T*)

    T

    ncnEcTEC

    T

    tt

    1

    121

    )(

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    To illustrate the above formulation, suppose

    c1=Rs.100, c2=Rs.10 and n=50

    The values of pt and EC(T) are tabulated below

    T*

    T pt Cumulative pt EC(T)

    1 0.05 0 500

    2 0.07 0.05 375

    3 0.10 0.12 366.7

    4 0.13 0.22 400

    5 0.18 0.35 450

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    Expected Value-Variance Criterion

    We indicated that the expected value criterion is suitable formaking long-run decisions

    To make it work for the short-run decision problems Expected

    Value-Variancecriterion is used

    A possible criterion reflecting this objective is Max E[Z]-k*var[z]

    Where z is a random variable for profit and k is a constant

    referred to as risk aversion factor

    Risk aversion factor k is an indicator of the decision makersattitude towards excessive deviation from the expected

    values.

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    Applying this criteria to example 1 we get

    Ct is the variance of EC(T) This criteria has resulted in a more conservative decision that applies

    preventive maintenance every period compared with every third period

    previously

    T pT pT2 Cum. pT Cum. pT2 EC(T)+varcT

    1 0.05 0.0025 0 0 500

    2 0.07 0.0049 0.05 0.0025 6312

    3 0.10 0.0100 0.12 0.0074 6622

    4 0.13 0.0169 0.22 0.0174 6731

    5 0.18 0.0324 0.35 0.0343 6764

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    Aspiration Level Criterion

    This method does not yield an optimal decision in the sense

    of maximizing profit or minimizing cost

    It is a means of determining acceptable courses of action

    Most Likely Future Criterion

    Converting the probabilistic situation into deterministic

    situation by replacing the random variable with the singlevalue that has the highest probability of occurrence

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    Decisions under uncertainty

    They assume that there is no probability distributionsavailable to the random variable.

    The methods under this are

    The Laplace Criterion The Minimax criterion

    The Savage criterion

    The Hurwicz criterion

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    Laplace Criterion

    This Criterion is based on what is known as theprinciple of

    insufficiency

    ai is the selection yielding the largest expected gain

    Selection of the action ai

    *corresponding

    where 1/n is the probability that

    ia

    n

    j

    jiavn

    1

    ,1

    max

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    Example 2

    A recreational facility must decide on the level of supply it must stock to meet the needsof its customers during one of the holiday. The exact number of customers is not known,but it is expected to be of four categories:200,250,300 or 350 customers. Four levels ofsupplies are thus suggested with level i being ideal (from the view point of the costs) if thenumber of customer falls in category i. Deviation from these levels results in additionalcosts either because extra supplies are stocked needlessly or because demand cannot besatisfied. The table below provides the costs in thousands of dollars

    a1, a2, a3 and a4 are the supplies level

    Customer Category

    3 4

    a1 5 10 18 25

    a2 8 7 8 23

    a3 21 18 12 21

    a4 30 22 19 15

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    Solution by Laplace Criterion

    E{a1} = (1/4)(5+10+18+25) = 14.5

    E{a2} = (1/4)(8+7+8+23) = 11.5

    E{a3} = (1/4)(21+18+12+21) = 18.0

    E{a4} = (1/4)(30+22+19+15) = 21.5

    Thus the best level of inventory according to

    Laplace criterion is specified by a2.

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    Minimax (Maxmini) Criterion

    This is the most conservative criterion since it is based on

    making the best out of the worst possible conditions

    If the outcome v(ai,j)represents loss for the decision maker,

    then, for, aithe worst loss regardless of what jmay be is max

    j [v(ai,j)]

    The minimax criterion then selects the action ai associated

    with min ai max j [v(ai,j)]

    Similarly if v(ai,j)] represents gain, the criterion selects the

    action aiassociated with max ai min j [v(ai,j)]

    This is called themaxmini criterion

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    Applying this criterion to the Example 2

    Thus the best level of inventory according to this criterion isspecified by a3

    Customer Category

    MaxSupply 3 4

    a1 5 10 18 25 25

    a2 8 7 8 23 23

    a3 21 18 12 21 21

    a4 30 22 19 15 30

    Minimax value

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    Savage Minimax Regret criterion

    This is an extremely conservative method

    The Savage Criterion introduces what is called as regret matrix

    which is defined as

    r(ai,j)={jijk

    aavav

    k

    ,,max

    jkaji avav k ,min,

    if v is profit

    if vis loss

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    Applying this criteria to Example 2

    The regret matrix is shown below

    Thus the best level of inventory according to this criterion is specified by a2

    Customer Category

    MaxSupply 1 2 3 4

    a1 0 3 10 10 10

    a2 3 0 0 8 8

    a3 16 11 4 6 16

    a4 25 15 11 0 25

    minimax

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    Hurwicz Criterion

    This Criterion represents a range of attitudes from the most optimistic to the most

    pessimistic

    The Hurwicz criterion strikes a balance between extreme pessimism and extreme

    optimism by weighing the above two conditions by the respective weights and

    1- , where 0

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    Applying this criterion to Example 2 Set =0.5

    Resolving with =0.75 for selecting between a1 and

    a2

    min max min+(1-)max

    5 25 15

    7 23 15

    12 21 16.5

    15 30 22.5

    minimum