4th order runge-kutta method
DESCRIPTION
runge-kutta methodTRANSCRIPT
yi+1 = yi + 1/6(k1 +2k2 + 2k3 + k4) F(xi, yi) = 2xyk1 = hF(xi,yi)k2 = hF(xi + h/2, yi + k1/2)k3 = hF(xi + h/2, yi + k2/2)k4 = hF(xi + h, yi + k3)
i h xi yi k1 k2 k3 k4 yi+10 0.1 0 1 0 0.01 0.01005 0.020201 1.010051 0.1 0.1 1.01005 0.020201 0.030605 0.030761 0.041632 1.0408112 0.1 0.2 1.040811 0.041632 0.053081 0.053368 0.065651 1.0941743 0.1 0.3 1.094174 0.06565 0.07889 0.079353 0.093882 1.1735114 0.1 0.4 1.173511 0.093881 0.109841 0.110559 0.128407 1.2840255 0.1 0.5 1.284025 0.128403 0.148305 0.1494 0.172011 1.4333296 0.1 0.6 1.433329 0.171999 0.197513 0.199171 0.22855 1.6323157 0.1 0.7 1.632315 0.228524 0.261987 0.264496 0.30349 1.8964788 0.1 0.8 1.896478 0.303437 0.348193 0.351998 0.404726 2.2479039 0.1 0.9 2.247903 0.404622 0.465541 0.471328 0.543846 2.71827
10 0.1 1 2.71827 0.543654 0.62792 0.636768 0.738108 3.35346 0 0.2 0.4 0.6 0.8 1 1.20
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0 0.2 0.4 0.6 0.8 1 1.20
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