4.3 recursive definitions and structural induction sometimes it is difficult to define an object...

4.3 Recursive Definitions and Structural Induction• Sometimes it is difficult to define an object explicitly.

However, it may be easy to define this object in terms of itself. This process is called recursion.

FIGURE 1

A Recursively Defined Picture.

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Recursively Defined Functions We use two steps to define a function with the set of

nonnegative integers as its domain:• Basis step: specify the value of the function at zero.• Recursive step: give a rule for finding its value at an

integer from its values at smaller integers.• Such a definition is called a recursive or inductive

definition.• Example 1: suppose that f is defined recursively by f(0)=3, f(n+1)=2*f(n) +3. find f(1) , f(2), f(3), f(4).

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• Example 2: give an inductive definition of the factorial function F(n)=n! .

• Example 3: Give a recursive definition of an, where a is a nonzero real number and n is a nonnegative integer.

• Example 4: Give a recursive definition of

n

kka

0

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Recursively Defined Functions

• Definition 1: The Fibonacci numbers, f0, f1,f2

,. . ., are defined by the equations:f0=0, f1=1, and fn = fn-1 + fn-2 for n = 2, 3, 4,. . .

• Example 5: Find the Fibonacci numbers f2, f3, f4,

f5, and f6.

• Example 6: Show that whenever n ≥ 3, fn > αn-2,

where 2/)51(

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Recursively Defined Functions

Recursively Defined Sets and Structures

• Example 7: consider the subset S of the set of integers defined by

• Basis step: 3 S.• Recursive step: if x S, y S, then x+y S.

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• Definition 2: The set * of strings over the alphabet can be defined recursively by

• Basis step: * (where λ is the empty string containing no symbols)

• Recursive step: if w* and x, then wx*

• Example 8: if ={0, 1}, the strings found to be in *, the set of all bit strings, are

1. λ specified to be in the basis step, 2. 0 and 1 formed during the first application of the

recursive step,3. 00, 01, 10, and 11 formed during the second

application for the recursive step, and so on.

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• Definition 3: two strings can be combined via the operation of concatenation.

• Let be a set of symbols and • * the set of strings formed form symbols in . • We can define the concatenation of two strings,

denoted by ∙ , recursively as follows. • Basis step: if w*, then w ∙ λ=w, where λ is the

empty string. • Recursive step: if w1* and w2* and x, then w1 ∙(w2x)=(w1 ∙ w2)x• Example 9: length of a string Give a recursive definition of l(w), the length of the

string w. 7


• Definition 4: The set of rooted trees, where a rooted tree consists of a set of vertices containing a distinguished vertex called the root, and edges connecting these vertices, can be defined recursively by these steps:

• Basis step: A single vertex r is a rooted tree.• Recursive step: Suppose that T1, T2, . . . ,Tn are

disjoint rooted trees with roots r1, r2, . . ., rn, respectively.

• Then the graph formed by staring with a root r, which is not in any of the rooted trees T1, T2, . . . ,Tn , and adding an edge from r to each of the vertices r1, r2, . . ., rn, is also a rooted tree.

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FIGURE 2 Building Up Rooted Trees.

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• Definition 5: The set of extended binary trees can be defined recursively by these step:

• Basis step: The empty set is an extended binary tree.

• Recursive step: if T1 and T2 are disjoint extended binary trees, there is an extended binary tree, denoted by T1 T∙ 2 , consisting of a root r together with edges connecting the root to each of the roots of the left subtree T1 and the right subtree T2 when these trees are nonempty.

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FIGURE 3 Building Up Extended Binary Trees. 11


• Definition 6: The set of full binary trees can be defined recursively by these steps:

• Basis step: There is a full binary tree consisting only of a single vertex r.

• Recursive step: if T1 and T2 are disjoint full binary trees, there is a full binary tree, denoted by T1 T∙ 2 , consisting of a root r together with edges connecting the root to each of the roots of the left subtree T1 and the right subtree T2 .

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FIGURE 4 Building Up Full Binary Trees.

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Structural Induction• To prove results about recursively defined sets

we generally use some form of mathematical induction.

• Example 12: show that the set S defined in example 7 by specifying that 3 S and that if x S and y S , then x+y S, is the set of all positive integers that are multiples of 3.

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Structural Induction• Definition 7: We define the height and number of

vertex, h(T) and n(T), of a full binary tree T recursively, .

• Basis step: The height of the full binary tree T consisting of only a root r is h(T)=0

• Recursive step: If T1 and T2 are full binary trees, then the full binary tree T= T1 T∙ 2 has height h(T) = 1+ max(h(T1) , h(T2 )), n(T) = 1+n(T1)+n(T2.

• Theorem 2: If T is a full binary tree T, then n(T) ≤ 2h(T) +1 -1

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Generalized Induction• As an example, note that we can define an ordering

on N x N, the ordered pairs of nonnegative integers, by specifying that (x1, y1) is less than or equal to (x2, y2) if either x1< x2, or x1=x2 and y1 < y2; this is called the lexicographic ordering.

• The set N x N with this ordering has the property that every subset of N x N has a least element (see Supplementary exercise 53 in section 8.6). This implies that we can recursively define the terms am,n , with mN, nN, and prove results about them using a variant of mathematical induction, as illustrated in example 15.

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Generalized Induction• Example 15: Suppose that am,n is defined

recursively for (m, n) N x N by a0,0 =0 and

Show that am,n =m+n(n+1)/2 for all (m, n) NxN

that is, for all pairs of nonnegative integers.

0 if

0 and 0 if 1

1,

,1, nna

mnaa

nm

nmnm

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4.3 recursive definitions and structural induction sometimes it is difficult to define an object...

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