407 class notes
TRANSCRIPT
-
8/2/2019 407 Class Notes
1/114
Classification of Materials
Most materials can be broadly classified into three main groups: metalsceramics and polymers. In addition, modern engineering materials includecomposites, semiconductors, and biomaterials.
Metals-- normally combinations of metallic elements (alloys), e.g. Cu/Zn and
Pb/Sn.-- optically opaque-- strong and ductile
-- good electrical and thermal conductors--
.
Ceramics-- compounds of metallic and non-metallic elements, e.g. oxides and
car es-- can be optically transparent-- hard and brittle-- heat and corrosion resistant-- structural and functional applications
1
-
8/2/2019 407 Class Notes
2/114
Polymers
-- or anic com ounds of carbon h dro en and other non-metallic
elements, e.g. polyethylene and polystyrene-- low density, flexible and formable-- resistant to chemical attack--
Composites-- composed of more than one material type, e.g. glass fiber in a polymer
ma r x.-- combines best characteristics of each of the component materials
-- high specific strength and fracture resistant-- mainl structural a lications
Semiconductors-- electrical properties intermediate between conductors and insulators
-- proper es ex reme y sens ve o m nu e races o mpur y e emen s, e.g.P and B in Si-- vapor processing of thin planar arrays of doped-Si forms the basis of the
integrated circuit industry
-- unc ona app ca ons
2
-
8/2/2019 407 Class Notes
3/114
oma er a s-- materials that are non-toxic when implanted in the human body
-- used for replacement of diseased or damaged body parts, e.g. hip
Current Materials Challenges
-- re uce energy use n ranspor a on sys ems y eve op ng owcost, high performance structural composites for weight reduction,
and (2) ceramic engines for increased operating efficiency.--
,as wind turbines and solar cells.
-- improve quality of the environment by (1) developing cleanermaterials refining and processing technologies, and (2) increasing
recycling efforts.-- develop nanostructured materials and technologies for the next
generation of miniaturized engineered systems.
3
-
8/2/2019 407 Class Notes
4/114
Atomic Bonding in Solids
A.Primary Bonds
Strong bonds (~100 kcal/mol) arising from transfer or sharing ofvalence electrons.
1. Ionic bond
-- transfer of valence electrons-- electron localization (ionic species)-- non-directional bonding
-- NaCl, ZnO, Li2O, etc.-- ex rem es o er o c a e
2. Covalent bond
---- partial electron delocalization (molecular unit)-- hybridization of electron orbitals-- highly directional bonding-- H2, H2O, CH4, graphite, diamond, fullerene, etc.
4
-
8/2/2019 407 Class Notes
5/114
3. Metallic bond
-- complete sharing of valence electrons (free electron gas)-- comp e e e ec ron e oca za on-- non-directional bonding-- no valency restrictions (alloying)-- Fe, Cu, Fe-Ni, Cu-Zn, etc.
B. Secondary BondsWeak bonds (~1 kcal/mol) arising from dipole interactions.
molecules
1. Permanent dipole-- arises when centers of ositive and ne ative char e in amolecule do not coincide
-- directional-- asymmetric polar molecules, such as H2O, H2S, NH3, CF2H2,
etc.
2. Induced dipole-- arises from permanent dipole in one molecular group inducing
a dipole in a neighboring group-- rec ona
5
-
8/2/2019 407 Class Notes
6/114
3. Fluctuating dipole
-- arises from fluctuating charge distribution (no permanent dipole)-- non-directional-- , , 4, 4,
C. Hydrogen BondIntermediate bond (~5 kcal/mol)
-- arises when H atom forms a bridge between two electronegativeatoms
-- highly directional-- n lon cellulose etc.
D. Addition (or Chain) PolymerizationPolymerization consists of joining a large number of molecules together
-- ro en ou e on g ves wo car on or a s or on ng-- directional-- chain-like structure that is called a polymer-- ol eth lene ol st rene etc.
6
-
8/2/2019 407 Class Notes
7/114
Schematics of Secondary Bonds
(a) Electrically symmetric atom(b) Induced atomic dipole
H dro en bondin in h dro enfluoride (HF)
Polar hydrogen chloride (HCl)molecule
7
-
8/2/2019 407 Class Notes
8/114
Ionic Bond
This is easiest to visualize:-- results from strong electrostatic attraction between
oppositely charged ions-- stable ionic aggregates due to ions with filled outer
shells-- non-directional bonding permits close packing-- combination of elements with low ionization energy
(e.g. Na) and high electron affinity (e.g. Cl)
Ionization Energy is the energy required to remove the least tightly bound
Electron affinity is the energy released when an electron is captured byan atom (forms negative ion).
8
-
8/2/2019 407 Class Notes
9/114
Figure 1 An example of an ionic bond showing electron transfer
rom a o o orm a ca on an-
an on pa r.
The ionization energy of Na Na+ is 5.14 eV, whereas the electronaffinit of Cl Cl- is 4.02 eV. Hence the net ener work re uiredto create a pair of isolated Na+ and Cl- ions is 1.12 eV.
9
-
8/2/2019 407 Class Notes
10/114
-
separation distance x0. Note the approximately linear slope of the total force
curve in the vicinity of x0. (b) The bond-energy curve for the ionic compound
NaCl showing the location of the equilibrium separation distance x0.
Interaction Energy
1 2
distance r.
10
-
8/2/2019 407 Class Notes
11/114
The interaction energy E is the sum of two terms: attractive energy EA and repulsive
energy ER
E = EA + ER(attractive) (repulsive)
= (1)
(negative) (positive)
no
21
rr4+
o is permittivity of vacuum, b and n are constants, which depend on iontype; n ~ 8-10.
0dE =dr
rr=
0nbQQ
dr
dE)1n(2
21 ==+
Rearranging terms
b1n
0 *)r(*r4n+=
11
-
8/2/2019 407 Class Notes
12/114
Now from (1)
(3)n
0
21
b*)r(
b
*r4E +
=
Substituting (2) in (3)
=
11
QQE 21b
Cohesive Ener
nr0
Figure 3A unit cell for the rock salt, or
sodium chloride (NaCl) crystal structure.
-
8/2/2019 407 Class Notes
13/114
Na+ ion has 6 first nearest neighbor Cl- ions at r*.
Na+ ion has 12 second nearest neighbor Na+ ions at 2 r*.etc.
By summing the contributions from all ions, it can be shown that theco es ve energy mo s
=
11
*
AQQNE 21
where N is Avogadros number, and A is the Madelung constant, which
depends on structure type.
0
For NaCl, one electronic charge is involved in transfer of valence electron;hence Q1 Q2 = (+e) (-e) = -e2
=n
11
*r4
ANeE
0
2
13
-
8/2/2019 407 Class Notes
14/114
Substance A r*() n Cohesive energy(kcal/mol)
*
a+ -
Zn++O--.
1.64.
1.97 8 964
divalent ions.
Since Q1Q2 = (-2e) (+2e) = - 4e2 for ZnO, the cohesive energy/mol is at least fourmes a o a .
Coordination number is defined as number of nearest neighbors at the bond.
-- NaCl has CN = 6
-- other ionic crystals have different values, e.g. CsCl has CN = 8
-- determined by relative size of anion and cation
14
-
8/2/2019 407 Class Notes
15/114
Ionic Radius is defined as the radius of the hard sphere that represents the
ion.-- radius of anion is usually larger than that of the neutral
atom.
-- radius of cation is usuall smaller than that of the neutralatom.
Element Charge at Ionic radius Atomic
Sodium +1 0.98 1.86or ne
MagnesiumOxygen
-+2-2
.0.781.32
.1.590.60
CN = 6
Consider NaCl structure (see Table 1), where each Na+ cation is surrounded- .
15
-
8/2/2019 407 Class Notes
16/114
R = ionic radius of anion Cl-
RC = ionic radius of cation (Na+)
AACA R22R8)RR(2 ==+
[ ] 2A2
A2
CA )R2()R2()RR(2 +=+
AC R12R =
414.012RC ==A
16
-
8/2/2019 407 Class Notes
17/114
This is the smallest value of RC/RA for which all 6 anions touch the cation,
called the critical radius ratio.-- larger values allowed
-- smaller values not allowed
Figure 4 Stable and unstable anion-cation coordination
represent cations.
CN = 4
Consider ZnS structure (see Table 1), where each Zn2+ cation (0.83) issurrounded by four S2- anions (1.74) at the bond distance.
2RR CA =+2R2 A =
17
-
8/2/2019 407 Class Notes
18/114
Table 1. The critical (r/R) ratio foreach coordination number.
( )23 =
CR
== 0.2250.22516RC =2RA
Note that for crystals havingequal numbers of anions
,of 2, 3, 4, 6, 8 and 12 satisfysymmetry requirements.
18
-
8/2/2019 407 Class Notes
19/114
Crystal Structures
We have examined the forces responsible for aggregation of atoms ormolecules. Now we will consider how they are organized or distributed in
Periodic arrays crystalline materialsRandom arrays amorphous materials
Crystal lattice is defined as an array of points, infinite in extent, in whichevery po n as en ca surroun ngs.
Unit cell is the smallest re ion that com letel defines the cr stal lattice
-- vertices of unit cell are known as lattice points-- lengths of unit cell are known as lattice parameters
19
-
8/2/2019 407 Class Notes
20/114
Figure 5 Possible unit cells for a 2-D space lattice: (a)
square, (b) rectangle, and (c) parallelogram.
There are 14 possible arrangements for 3-D lattices, which areknown as Bravais lattices. These can be grouped into 7 crystalsystems, based on edge lengths of unit cell (unit vectors) and theangles between them.
20
-
8/2/2019 407 Class Notes
21/114
Figure 6 The 14 Bravais lattices grouped into the 7 crystal systems. Therestrictions on the lattice parameters a, b, and c and the angles between
the edges of the unit cell, , andare listed for each unit cell. 21
-
8/2/2019 407 Class Notes
22/114
Miller Indices
os common conven on use o eno e po n s, rec ons, an p anesin crystal lattices
PointsRight-hand Cartesian coordinate
points, e.g. 1,0,0.
Directions
Specific directions denoted bysquare brackets, e.g. [111].Families of directions denotedby angle brackets, e.g.
22
-
8/2/2019 407 Class Notes
23/114
Angle between directions [h1k1l1] and [h2k2l2] is given by:
)kh()kh(
)kkhh(cos
222222
212121
ll
ll
++++
++=
Planes
Defined as the reciprocals of the intercepts on coordinate axes
23
-
8/2/2019 407 Class Notes
24/114
, . . ., . . .
Families of planes denoted byFamilies of planes denoted by bracesbraces, e.g. {111}., e.g. {111}.24
-
8/2/2019 407 Class Notes
25/114
Structures of MetalsThree main types:
-- body centered cubic (bcc)
-- face centered cubic (fcc)
-- hexa onal close acked hc
25
-
8/2/2019 407 Class Notes
26/114
cc an cp s ruc ures orme y eren s ac ng sequences o c ose-pac eplanes.
ABABABA.hcp Both have
.
Figure 7 Close packed stacking sequence (ABCABCA) for fcc structure26
-
8/2/2019 407 Class Notes
27/114
Figure 8 Close packed stacking sequence (ABABABA) for
hc structure.
Density=
26.98; a = 4.04 x 10-8 cm; A0 = 6.02 x 1023 mol-1
27
-
8/2/2019 407 Class Notes
28/114
23
24cm/g72.2
10x94.65.
v===
c ua measure ens y s . g cm
Calculate packing factor (PF) for bcc, fcc and hcp structures.
(PF = volume of atoms/volume of unit cell)
bcc structure
28
-
8/2/2019 407 Class Notes
29/114
3
0
3
34
2a
r
PFbcc
=
3
Sinceao =3
r
0.68== 8
bcc
fcc structure
29
-
8/2/2019 407 Class Notes
30/114
3
3
fcca
r3
4
4PF
=
2
r4Since a0 =
=
=23
PF fcc 0.74
hc structure
Same as for fcc, since both structures are ideally close-packed, withCN = 12.
PF hcp = 0.74
30
-
8/2/2019 407 Class Notes
31/114
Interstitial Sites
The locations of the largest holes in bcc, fcc and hcp structures areknown as interstitial sites
fcc structure
Largest hole in an fcc structure is located at the center of the unit cell.-- known as an octahedral site, since the polyhedron connecting
nearest neighbor atoms has 8 sides-- there are 12 equivalent octahedral sites located at edge
centers of the unit cell-- each edge site is shared by four unit cells, hence there are 4 =
[(12 x ) + (1 x 1)] octahedral sites per unit cell-- if hole radius is k, then the radius ratio k/r = 0.414-- hence atoms about 40% of the size of the host atoms can fit
into octahedral sites
The fcc structure also contains tetrahedral sites, located at , , -type
-- there are 8 equivalent tetrahedral sites that lie completelywithin the unit cell
31
-
8/2/2019 407 Class Notes
32/114
-- the radius ratio, k/r, for a tetrahedral site is 0.225
-- ence, a oms a ou o e s ze o e os a oms can n otetrahedral sites
Thus, there are twice as many tetrahedral sites as octahedral sites, andeac e ra e ra s e s a ou one- a e ame er o an oc a e ra s e.
bcc structure
This structure also contains both octahedral and tetrahedral sites-- octahedral sites are located at face centers and edge centers of
the unit cell, giving a total of 6 sites per unit cell and k/r = 0.155.-- e ra e ra s es are oca e a , , ype pos ons, g v ng atotal of 12 tetrahedral sites per unit cell and k/r = 0.291.
Thus, there are twice as many tetrahedral sites as octahedral sites, and
each tetrahedral site is about twice the diameter of an octahedral site.
hcp structure
Similar to fcc, as indicated in Table 2.
32
-
8/2/2019 407 Class Notes
33/114
Table 2. The size and number of tetrahedral and octahedral interstitial
sites in the BCC, FCC, and HCP crystal structures. The sizes of the
interstitial sties are given in terms of the radius ratio (k/r) where k is the
radius of the largest atom that can fit into the interstitial position and ris the radius of the host atoms. The number of interstitial sites is given in
number of sites per host atom.
Structure
tetrahedralsites
octahedralsites
tetrahedral sitesper unit cell (perhost atom)
octahedral sitesper unit cell (perhost atom)
BCCFCCHCP
k/r = 0.291k/r = 0.225k/r = 0.225
k/r = 0.155k/r = 0.414k/r = 0.414
12 (6)8 (2)12 (2)
6 (3)4 (1)6 (1)
33
-
8/2/2019 407 Class Notes
34/114
Figure 9 The locations of the interstitial sites in the common crystal
octahedral sites in BCC, (d) tetrahedral sites in BCC, (e) octahedralsites in HCP, and (f) tetrahedral sites in HCP.
34
St t f C i
-
8/2/2019 407 Class Notes
35/114
Structures of Ceramics
The structures of many ceramic crystals can be visualized in terms ofstacking of close-packed planes of anions, with interstitial sites occupiedby the cations.
Two types of interstitial sites:---- octahedral (CN=6)
Crystal structures determined by:-- stacking sequence (fcc vs. hcp)-- manner in which interstitial sites are occupied
Figure 10 -- The stacking of one
lane of close- acked s heres(anions) on top of another:
tetrahedral and octahedral
positions between the planes
,
respectively
Example NaCl structure-- fcc arra of close- acked anions of the 111 t e-- cations reside in octahedral sites, each with 6 nearest neighbor anions-- all octahedral sites are occupied
35
-
8/2/2019 407 Class Notes
36/114
crystal structure from which a corner
has been removed. The exposed plane
of anions (dark spheres inside the
triangle) is a {111}-type plane: the
cations (light spheres) occupy theinterstitial octahedral positions.Density
*Other ionic structures can be understood in similar manner.
( )Ac AAn +=
Density
Acn = number of formula units within unit cellAc = sum of at. wt. of cationsAA = sum of at. wt. of anionsVc = volume of unit cell
NA = Av. number 36
-
8/2/2019 407 Class Notes
37/114
Calculate the density of NaCl.n =4
C Na .AA = ACl = 35.45 g/moleVC = a3
+ += r2r2a
( )3ClNa
3c r2r2aV + +==
81.1rCl
=
.Na +
( )[ ] 23388 10023.61081.11002.12..
+=
3cm/.g14.2=
37The experimental value is 2.16 g/cm3
-
8/2/2019 407 Class Notes
38/114
AX-Type Crystal Structures
Equal numbers of cations and anions, known as AX compounds.
NaCl(CN = 6)
ZnS(CN = 4)
38
-
8/2/2019 407 Class Notes
39/114
39
-
8/2/2019 407 Class Notes
40/114
AmXP-Type Crystal Structures
When charges on cations and anions are not the same, a compound with
the formula AmXP can exist, e.g. CaF2
RC/RA = 0.8, so that CN = 8
half of center positions only are occupiedby Ca2+ ions
A B X -Type Crystal Structures
Compounds that have more than one type of
BaTiO3 (perovskite structure).
40
Silicate Ceramics
-
8/2/2019 407 Class Notes
41/114
Silicate Ceramics
The basic building block of all silicate ceramics (amorphous and crystalline)
is the tetrahedron.
-- each silicon atom is tetrahedrally bonded to four oxygen atoms
-- since each oxygen atom requires an extra electron to achieve a stable
electronic structure, a charge of 4 is associated with every tetrahedron.
Figure 12 A silicon-oxygen (SiO4)4-tetrahedron.
Si4+ = 0.39 Hence r Si (ion)/rO (ion) = 0.3
O2-
= 1.32 41
Thi l i ithi th t bilit 0 225 /R < 0 414 (T bl 3) f
-
8/2/2019 407 Class Notes
42/114
This value is within the stability range 0.225 r/R < 0.414 (Table 3) fortetrahedral coordination (CN=4). Since the Si-O bond is mixed ionic andcovalent about 50:50 the tetrahedron satisfies the bondinrequirements of both ionic radius ratio and covalent directionality.
Various silicate ceramics arise from the different ways in which the-
4 -, -, - .Because of the high charge on the Si4+ ion, the tetrahedral units areseldom joined edge to edge and never face to face, but almost alwaysshare corners, with no more than two tetrahedra sharing a corner.
Figure 13 Effect of corner edge, and face sharing on cation-cation
separa on. e s ances 1: 2: 3 are n e ra o : . : . ; a s,
cation-cation repulsion increases on going from left to right, which
tends to destabilize the structure. 42
-
8/2/2019 407 Class Notes
43/114
43
Silica
-
8/2/2019 407 Class Notes
44/114
Silicon dioxide or silica SiO has a three-dimensional structure such thatevery corner oxygen atom in each tetrahedron is shared by adjacenttetrahedra.
-- most common crystalline forms are quartz, cristobalite and tridymite.-- relatively open structures of low density
-- high melting points, due to strength of Si-O bonds
Figure 14Figure 14 22--D representations of (a) silica glass, (b) crystalline silica.D representations of (a) silica glass, (b) crystalline silica.44
Sili l
-
8/2/2019 407 Class Notes
45/114
Silica glass
Also known as vitreous silica, silica glass has a highly disorderedstructure, i.e. it lacks the long-range order characteristic of crystallinesilica, Fig. 14.
---- Oxides, such as BOxides, such as B22OO33 and GeOand GeO22, which readily form glassy, which readily form glassystructures, are referred asstructures, are referred as network formersnetwork formers. When added to a. When added to as ca g ass, ey su s u e or e s ca es ca g ass, ey su s u e or e s ca e e ra e rae ra e ra, so a e, so a elonglong--range order is retained.range order is retained.
45
-
8/2/2019 407 Class Notes
46/114
-- Oxides, such as Na2O and K2O, which are incapable of forming glassystructures, are referred as network modifiers. When added to a silica
glass, they break-up the tetrahedral network and create a moredisordered structure.
-- x es, suc as 2 an 2 3, n w c e ca ons su s u e or silicon and help to stabilize the network, are called intermediates.
viscosity of the glass, making it easier to form into useful shapes. Thus,glass containers and windows are made from low melting point soda-lime-
silica glasses, while furnace tubes are made from high melting point vitreoussilica.
Pyrex, a glass composition containing the network formers SiO2 and B2O3,an e ne wor mo ers a2 an a , as proper es n erme a e
between those of soda-lime-silicate glass and vitreous silica, e.g. it has aboutthree times the thermal shock resistance of silica glass, but does not requirethe hi h rocessin tem erature of vitreous silica.
46
Layered silicates
-
8/2/2019 407 Class Notes
47/114
y
-a planar array of tetrahedra.
-- formula unit is (Si2O5)2-
-- a negative charge is associated with the unbonded oxygen
atoms projecting out of the plane.
Figure 15Figure 15 SchematicSchematic
representation of the tworepresentation of the two--
structure having a repeat unitstructure having a repeat unit
formula of (Siformula of (Si22OO55))22--..
Such a negatively charged sheet can bond with an equivalent positivelySuch a negatively charged sheet can bond with an equivalent positivelychar ed sheet to form an electricall neutral structure.char ed sheet to form an electricall neutral structure.
---- sheet or layered silicate structures are characteristic of clayssheet or layered silicate structures are characteristic of clays
and other mineralsand other minerals 47
-
8/2/2019 407 Class Notes
48/114
-- bonding within a two-layered sheet is strong (ionic-covalent),
der Waals).
Clays
Aluminosilicates that contain chemically bound water.
-- crystal structures are relatively complicated
,hydroplasticity
-- can be fired at relatively low temperature to form a dense and
strong ceramic
Kaolinite
Compound is formed by bonding between Al2(OH)42+ and (Si2O5)2- layers.
-- formula unit is Al2(OH)4 Si2O5-- crystalline kaolinite is composed of many such double layers,
stacked one upon the other
-- additive to paper products
48
-
8/2/2019 407 Class Notes
49/114
Figure 16 The structure ofkaolinite clay.
Compound comprises 1 sheet of MgCompound comprises 1 sheet of Mg33(OH)(OH)224+4+ + 2 sheets of (Si+ 2 sheets of (Si22OO55))22--
---- formula unit is Mgformula unit is Mg33(OH)(OH)22 (Si(Si22OO55))22---- slips easily, like graphiteslips easily, like graphite
---- absorbs waterabsorbs water49
-
8/2/2019 407 Class Notes
50/114
Glass Properties
Glass transition temperature
For an amorphous or non-crystalline material, the glass transitiontem erature T is the critical tem erature that se arates lassbehavior from rubbery behavior, in the time scale of the experiment.
-- most easil detected via measurements of chan es inspecific volume (1/ = v/unit mass) associated with heatingor cooling a material
-- upon heating, the material undergoes a transition fromthe glassy state to the supercooled liquid state, and thento the fully liquid state.
50
-
8/2/2019 407 Class Notes
51/114
Figure 17 Specific volume as a function of temperature for a series of
. .
discontinuous change in volume occurs at the melting temperature Tm. (b)The liquid-to-glass transformation (the liquid-to-crystal curve is shown for
reference). The temperature range in which the slope of the liquid-glass
curve changes is the glass transition temperature Tg. (c) Specific volume
versus temperature for a semicrystalline material. The discontinuous
change in volume occurs at Tm, and a change in slope occurs at Tg. 51
-
8/2/2019 407 Class Notes
52/114
Viscosity-temperature behavior
The temperature dependence of the viscosity of a glassy material is thekey to proper selection of processing parameters.
-- melting point (viscosity 100 P) is the temperature where the glass isfluid enough to be considered a liquid.
-- working point (viscosity 104 P) is the temperature where the glass iseasily deformed.
-- softening point (viscosity 4 x 107
P) is the maximum temperaturew ere g ass can e an e w ou s or on.
-- annealing point (viscosity 1013 P) is the temperature were anyresidual stress in the glass can be eliminated.
-- strain point (viscosity 3 x 1014 P) is the temperature where fractureoccurs before plastic deformation.
Most glass-forming operations are carried out in the working range,which is between the working and softening temperature.
52
-
8/2/2019 407 Class Notes
53/114
Figure 18 Logarithm of viscosity versus temperature for fused
silica and several silica glasses. 53
Structures of Polymers
-
8/2/2019 407 Class Notes
54/114
y
Hydrocarbon moleculesMost polymers are derived from hydrocarbon precursors. It is instructive,therefore, to consider the structures of some typical hydrocarbonmolecules.
All four valence electrons in carbon participate in bonding. Moreover,hybridization of s and p orbitals of the valence electrons gives directionalbonding.
-- 4 equivalent sp3 orbitals, as in methane and ethane-- 3 equivalent sp2 orbitals, as in ethylene-- 2 equivalent sp1 orbitals, as in acetylene
54
-
8/2/2019 407 Class Notes
55/114
single bond -- formed by overlapping sp3 orbitals with the orbitals of
double bond -- formed by overlapping sp2 orbitals with the orbitals of twodifferent carbon atoms
triple bond -- formed by overlapping sp1 orbitals with the orbitals of two
Saturated hydrocarbons
sp3 orbitals of both CH4 and C2H6 directed towards the corners of a
regular tetrahedron 55
U t t d h d b
-
8/2/2019 407 Class Notes
56/114
Unsaturated hydrocarbons
56
Polymer molecules
-
8/2/2019 407 Class Notes
57/114
Polymer molecules
-- Activator (catalyst) is needed to start process of polymerization. For
Directional nature of covalent bonds enables carbon atoms to form long-chainmolecules.
example, ethylene gas can be transformed into polyethylene solid byheating under pressure in the presence of a catalyst.
-- Polymerization process begins when an active mer is formed byreaction of an ethylene gas molecule with a catalyst species (R).Polymer chain is then formed by the sequential addition ofpolyethylene monomer units. In so doing, the active site is
transferred to each end-unit monomer as it is linked to the growingchain.
57
Activator (catalyst) is needed to start process of polymerization. Forexample, ethylene gas can be transformed into polyethylene solid byh ti d i th f t l t
-
8/2/2019 407 Class Notes
58/114
p , y g p y y yheating under pressure in the presence of a catalyst.
The polymerization process begins when an active mer is formed byreaction of an ethylene gas molecule with a catalyst species (R). Thepolymer chain is then formed by the sequential addition of polyethylenemonomer units. In so doing, the active site is transferred to each end-
.
, ,is a long chain polyethylene molecule. Carbon atoms form a zig-zagbackbone in the molecule, with an angle of 109 between the bonds; theC-C bond length is 0.154 nm. 58
-
8/2/2019 407 Class Notes
59/114
Figure 19 For polyethylene, (a) a schematic representation of mer and
chain structures, and (b) a perspective of the molecule, indicating thezigzag backbone structure.
Hence, the formula unit for a polyethylene molecule may be
HH ||
represen e as o ows, w ere n s e num er o e y ene mo ecu esw ere n s e num er o e y ene mo ecu es
(monomers) that bond together to form the long chain molecule.(monomers) that bond together to form the long chain molecule.
n
HH
CC
||
59
-
8/2/2019 407 Class Notes
60/114
-
8/2/2019 407 Class Notes
61/114
The molecular structures of PTFE, PVC and PP are shown in Figure 21. In
PTFE, all the hydrogen atoms in polyethylene have been replaced byfluorine atoms, whereas in PVC and PP every fourth hydrogen atom alongthe chain has been replaced by Cl or CH3 (methyl group).
Figure 20 Mer and chain structures for
a po y e ra- uoroe y ene, po yv ny
chloride, and (c) polypropylene.
61
Molecular shape
-
8/2/2019 407 Class Notes
62/114
p
Long chain molecules are capable of rotation and bending in threedimensions. This is because any carbon atom in a chain can lie at anypoint on the cone of revolution (109 angle) with the bond of thepreceding carbon atom, Figure 22. Thus, a long chain molecule typicallyhas a very complex shape, involving many bends, twists and kinks.
Figure 21 Schematic representations of how polymer chain shape is
influenced by the positioning of backbone carbon atoms (solid circles).For (a), the rightmost atom may lie anywhere on the dashed circle and
Straight and twisted chain segments are shown in (b) and (c),
respectively.
62
Polymer crystallinity
-
8/2/2019 407 Class Notes
63/114
The crystalline state of a polymer is more complex than that of ametal or ceramic, because of the difficulty of aligning the long chainmolecules in a regular close-packed structure. However, it does occurreadily in molecules, such as PE and PTFE, where the atoms are arrangedsymme r ca y a ong e car on ac one. o ye y ene can ecrystallized with the orthorhombic structure, Figure 23, which represents
the closest packing of the long chain molecules.
Figure 22 Arrangement of
molecular chains in a unit
.
63
-- degree of crystallinity may range from completely amorphous up toabout 95% crystalline
-
8/2/2019 407 Class Notes
64/114
--counterpart because of the closer packing of molecules in thecrystalline state
-- degree of crystallinity achieved by a polymer depends on the coolingra e rom e qu s a e
-- many bulk polymers that are crystallized from the melt formspherulites, Fig. 24, which are considered to be the polymer
Figure 23 A transmission photo-
micrograph (using cross-polarized
light) showing the spherulite
structure of ol eth lene. Linear
boundaries form between adjacentspherulites, and within each
spherulite appears a Maltese
cross. .
64
Polymer characteristics
-
8/2/2019 407 Class Notes
65/114
1. Side groups-- clusters of atoms that are attached to the carbon backbone
2. Degree of polymerization
-- defines average chain size of a polymer
3. Cross linking
-- joining of two chains together by an atom, group of atoms or another
chain
4. Elastomers
-- polyisoprene experiences large elongations under load, and returns to itsoriginal shape upon unloading
-- trans-poly on opposite sides (rigid solid)
-- cis- ol on same side steric hindrance causes kinkin i.e. chains tocoil.
65
5.Vulcanization-- cross-linking process in elastomers; non-reversible reaction at
-
8/2/2019 407 Class Notes
66/114
cross linking process in elastomers; non reversible reaction at
-- automobile tires have 3-5% S and are elastic-- battery cells have more S and are more rigid
6.Stereoisomerism
-- same composition but different structureisotactic all on one side
atactic randomly on opposite sides
7.Thermo lastic ol mer-- softens when heated and hardens when cooled (reversible process),as in polyethylene
-- due to breaking and reforming of weak secondary bonds between
8.Thermosetting resin-- decom ose before the soften because of extensive cross linkin , as
in epoxy resin
66
9. Conformation-- this refers to the outline or shape of the long chain molecule
-
8/2/2019 407 Class Notes
67/114
--
10. Configuration-- this refers to the arrangement of atoms positions along the chain-- can be altered only by breaking and reforming primary bonds
Melting and crystallization
Carbon backbone of a long chain polymer is strong, since it is composed ofa c a n o - pr mary on s. n e crys a ze s a e, e c ose-pac esegments of the long chain molecules are held together by weak secondarybonds
It follows that when a cr stalline ol mer is heated thermal ener caneasily disrupt the regular periodicity of the crystalline domains, therebyforming a disordered network of long chain molecules. As in ceramics,melting and solidification occurs over a temperature range, T = Tm Tg.
.state, leading to a glassy solid (fast), semi-crystalline solid (intermediate),and crystalline solid (slow)
67
-
8/2/2019 407 Class Notes
68/114
Figure 24 Specific volume
versus temperature, upon
,
totally amorphous (curve A),
semicrystalline (curve B), andcrystalline (curve C) polymers
Polyethylene readily crystallizes by slow cooling from the melt, whereaspolystyrene does not, due to the presence of bulky side groups (benzenerings)
-- abrupt changes in elastic stiffness, heat capacity and thermal expansiocoefficient occur at Tg
--temperature range T = Tm Tg, where the material is in its softened,rubber-like state.
68
-
8/2/2019 407 Class Notes
69/114
In addition, graphite has high resistance to thermal shock, high absorptionof gases, and good machinability. Applications include heating elements,rocket nozzles electrical contacts batter electrodes and air urification
-
8/2/2019 407 Class Notes
70/114
rocket nozzles electrical contacts batter electrodes and air urification
devices.
Diamond
A metastable form of carbon, diamond is composed entirely of strongcovalently-bonded carbon atoms, with tetrahedral coordination. The
properties of diamond are exceptional in many respects.-- hardest known material
-- very low electrical conductivity
-- unusually high thermal conductivity
-- optically transparent in the visible and infrared
-- high index of refraction
Synthetic diamonds are produced commercially by a high pressure-high
temperature process. Industrial grade diamond grits are used for grindingand cutting operations, and polycrystalline diamond compacts are used forrock drill bits and machine tools.
ThinThin filmsfilms of of diamonddiamond areare alsoalso manufacturedmanufactured byby aa ChemicalChemical VaporVaporDepositionDeposition (CVD)(CVD) processprocess.. SuchSuch filmsfilms areare usedused asas wearwear resistantresistant coatingscoatings
onon drills,drills, bearings,bearings, dies,dies, andand lenseslenses.. 70
Fullerenes
-
8/2/2019 407 Class Notes
71/114
Discovered in 1985, C60 fullerene is a molecular form of carbon thatconsists of a hollow spherical cluster of sixty carbon atoms.
-- same symmetry as that of a soccer ball
-- composed of 20 hexagons and 12 pentagons, such that no two
pentagons share a common side,
each C60 molecule is a molecular analogue of such a dome.
-- other molecular forms with larger numbers of carbon atoms
have been found-- properties of these fullerene molecules are being investigated
Recently, methods have been found to produce nanoscale tubular andpo y e ra s ruc ures. ar on nano u es sp ay very g spec c
strengths.Many structural applications for this new class of superstrong carbon
.
71
-
8/2/2019 407 Class Notes
72/114
72
Polymer characteristics
-
8/2/2019 407 Class Notes
73/114
.-- clusters of atoms that are attached to the carbon backbone
2. Degree of polymerization--
3. Cross linking-- joining of two chains together by an atom, group of atoms or another
4. Elastomers-- polyisoprene experiences large elongations under load, and returns to its
-- trans-poly on opposite sides (rigid solid)-- cis-poly on same side (steric hindrance) causes kinking, i.e. chains to
coil.
5. Vulcanization-- cross-linking process in elastomers; non-reversible reaction at
elevated temperatures using sulfur compounds-- automobile tires have 3-5% S and are elastic-- battery cells have more S and are more rigid
1
ElastomersPolyisoprene experiences large elongations under load, and returns toits ori inal sha e u on unloadin
-
8/2/2019 407 Class Notes
74/114
its ori inal sha e u on unloadin
trans-poly on opposite sides(rigid solid)
cis-poly on same side (sterichindrance) causes kinking, i.e.
Vulcanization
- -temperatures using sulfur compounds
2
6.Stereoisomerism-- same com osition but different structure
-
8/2/2019 407 Class Notes
75/114
isotactic all on one sidesyndiotactic alternating side groupsatactic randomly on opposite sides
7.Thermoplastic polymer
-- softens when heated and hardens when cooled (reversible process),as in polyethylene
--chains
8.Thermosetting resin
-- ,in epoxy resin
9. Conformation--
-- can be modified by a simple bond rotation10. Configuration
---- can be altered only by breaking and reforming primary bonds
3
Stereoisomerism
-
8/2/2019 407 Class Notes
76/114
ame compos on u eren a om c arrangemen :
Isotactic R groups all on oneside
alternating on opposite sides
Atactic R groups randomly onopposite sides
4
Binary Phase Diagrams
Relevant terms
-
8/2/2019 407 Class Notes
77/114
-- component is a pure element (e.g. Fe, Si, or B) or stoichiometriccompound (e.g. NaCl, Al2O3, or Si3N4), i.e. a component is achemically distinct substance.
-- system is the volume occupied by a substance or series ofalloys (e.g. Fe-C, Al2O3-Cr2O3, or ice-water).
-- phase is a chemically and structurally homogeneous regionof a material.
-- homogeneous region is a region (or volume) in which theproperties of a system are uniform.
-- phase diagram is a map of the regions in which the different
phases exist when the system is in equilibrium.
-- solid solution describes the substitution of solute in solventwithout a phase change.
Examples
-- pure fcc-Cu is a single component (Cu) single phase (fcc) system
-
8/2/2019 407 Class Notes
78/114
pure fcc Cu is a single component (Cu), single phase (fcc) system.
-- a mixture of ice and water is a single component (H2O) systemcomposed of two phases.
-- a mixture of bcc-Fe (ferrite) and fcc-Fe (austenite) is a singlecomponent system composed of two phases.
-- solid solution of Cu-Ni (or NiO-MgO) is a two-component, single-phase system.
One-component system
Simplified case, where phase relationships may be represented on apressure-temperature diagram.
-
8/2/2019 407 Class Notes
79/114
Fig. 25 - The equilibrium
temperature-pressure diagramfor iron.
Fig. 26 Pressure-temperature
phase diagram for SiO2.
Phase equilibria can be described by the Gibbs phase rule
F = C P + 2
which relates number of degrees of freedom, F, at equilibrium to numberof components, C, in the system, number of phases in equilibrium, P, andthe two state variables temperature and pressure.
In a one-component system, such as Fe or SiO2
- if 3 phases are in equilibrium, then F = 1 3 + 2 = 0. This meansthat there is no freedom in specifying variables, so that the 3phases can exist only at a point - triple point.
-
8/2/2019 407 Class Notes
80/114
p y p p p
-- if 2 phases are in equilibrium, then F = 1 2 + 2 = 1. Thismeans that if one variable is changed (T) then the other isautomatically fixed (P), so that the 2 phases can exist along aline - phase boundary line.
Two-component systemMost practical materials are composed of two components, and, since
pressure is usually fixed at 1 atmosphere, the important variables aretemperature and composition. In such cases, the appropriate expressionfor the phase rule is
F = C P + 1
When pressure is eliminated as a variable, a two-dimensional phasediagram can be constructed, showing the regions of composition andtemperature where the different phases are in equilibrium.
Specifying composition
In many practical situations, compositions are specified as weightpercentages (wt.%) or weight fractions of components. Alternatively,compositions may be specified in terms of atomic percentages (at.%)or atomic fractions.
-
8/2/2019 407 Class Notes
81/114
100
B.wt.at
B.%wt
A.wt.at
A.%wt
A.wt.at
A.%wt
A.%at
+
=
Similarly
100
B.wt.at
B.%at
A.wt.at
A.%at
A.wt.at
A.%at
A.%wt
+
=
Example
Calculate the atomic percentage of C in Fe for a two-component alloycontaining 0.8 wt.% C.
80
-
8/2/2019 407 Class Notes
82/114
100
85.55
2.99
12
8.0
12
8.0
C.%at
+
=
= 3.63 at.% C
In ceramic systems, compositions are usually expressed as molefractions. If mole fraction of component A is NA, then
)nn(nN
BA
AA
+=
where nA and nB are the numbers of moles of components A and B,respectively.
Isomorphous systemThis is the simplest two-component phase diagram.
-- displays complete solubility in both liquid andsolid states over the entire composition range.
-- for any mixture of the two components,
-
8/2/2019 407 Class Notes
83/114
solidification occurs over a temperature range,rather than at a specific temperature, as is thecase for a pure component.
-- liquidus curve separates single-phase liquidregion from two-phase (solid + liquid) region.
--solidus curve separates two-phase (solid +
liquid) region from single-phase solid region.
Fig. 27 - An idealized binary(A-B) phase diagram withassociated definitions.
Hume-Rothery rulesIn order to form a substitutional solid solution over a wide range of
compositions, the following conditions must be met:
-- crystal structures of the two components (A and B) must be the same
-- size difference between components must not differ by more than ~
-
8/2/2019 407 Class Notes
84/114
15%.
-- valences of the two components must be similar
-- electronegativities of the two components must be comparable
These conditions are satisfied for
many metallic and ceramicsystems, e.g. Cu-Ni, Ag-Au, NiO-MgO, Al2O3-Cr2O3.
Fig. 28 Binary isomorphoussystems Cu-Ni and NiO-MgO
Lever ruleThe relative amounts of two phases in the semi-solid (solid + liquid) region
can be determined by the lever rule.
Amount of liquid of comp.
( )osL
CCpC
==
-
8/2/2019 407 Class Notes
85/114
Amount of solid of comp.
( )Ls CC()qp( +
( )( )Ls
Los
CC(
CC
)qp(
qC
=
+=
where Co is the composition of the mixture.
A CL C0 CS B
wt.% B
T
Cooling curvesExperimentally, liquidus and solidus curves can be determined by
taking cooling curves at different compositions.
-- for pure components, there is a sharp break in the coolingcurve (thermal arrest) due to heat of transformation
-
8/2/2019 407 Class Notes
86/114
(crystallization).-- for two-component mixtures, heat is released over a range of
temperaturesT = (TL TS), so that there is a change in slopeof the cooling curve.
Fig. 29 (a) A binary isomorphous phase diagram showing cooling
curves for (b) pure component A, and (c) alloy 1.
Solidification and microstructure
Under equilibrium conditions, all
i i i i h
-
8/2/2019 407 Class Notes
87/114
compositions in an isomorphoussystem solidify in a similar manner.
Figure 30 Equilibrium solidification ofalloy 1 (composition 0.6 B); (a) thecooling path and sketches showing thedevelopment of the microstructure, and(b) an expanded section of part (a)showing the compositions of the
liquidus and solidus boundaries in therange of 1010C to 1060C.
-- at T1 the alloy begins to solidify, and the first solid crystallites toform have a composition given by the intersection of the horizontal
T1 isotherm (tie line) with the solidus curve (xB = 0.70).
-- when the temperature is reduced to T2, the compositions of bothliquid and solid phases are given by the intersection of the tie line
ith th li id d lid ( 0 68 0 57)
-
8/2/2019 407 Class Notes
88/114
with the liquidus and solidus curves (xS = 0.68; xL = 0.57).
-- similarly for T3, T4, and T5, until at T5 solidification is complete.-- the final result of solidification is a polycrystalline (many-grained)
material.
-- at all temperatures, the amounts of liquid and solid phases are given
by the Lever rule.
Example
What are the mass fractions of solid and liquid phases in equilibrium at T2?
( )( )
73.057.068.060.068.0
)qp(pCL =
=
+=
( )( )
27.057.068.0
57.060.0
)qp(
q)C1(C Ls =
=
+==
-
8/2/2019 407 Class Notes
89/114
Eutectic system
-
8/2/2019 407 Class Notes
90/114
Figure 31 A binary eutectic phase diagram and the associatedterms used to describe regions of a eutectic system.
As in the isomorphous system, the boundaries separating the liquid andsolid phase fields and the two-phase fields are called liquidus and solidusboundaries, respectively.
-- the two liquidus curves converge at an eutectic point, E, which is
the lowest melting point in the system
-
8/2/2019 407 Class Notes
91/114
the lowest melting point in the system
-- at the eutectic point, the temperature and compositions of the twosolid phases ( and ) are fixed. The invariant reaction may berepresented as
L + where and are the terminal solid solutions of B in A (x1) and Ain B (x2) at the eutectic temperature.
Not present in an isomorphous system, solvus boundaries appear atboth ends of the eutectic phase diagram, representing the temperaturedependence of the solid solubility of each component.
Solidification and microstructure
1. Eutectic composition
-
8/2/2019 407 Class Notes
92/114
Fig. 32Schematic of theequilibrium microstructures
for a Pb-Sn alloy of eutecticcomposition C3above andbelow the eutectictemperature.
-
8/2/2019 407 Class Notes
93/114
Fig. 33 - Photomicrographshowing the microstructure ofa Pb-Sn alloy of eutectic
composition. 375 x.
Fig. 34 - Schematic representationof the formation of the eutecticmicrostructure in the Pb-Sn system.
Eutectic microstructure consists of alternating layers (lamellae) of (dark) and (light) phases, where and are solid solutions ofSn in Pb and Pb in Sn, respectively
-- microstructure is formed by counter-diffusion of Sn and Pbatoms just ahead of the advancing solid-liquid interfaceduring solidification.
-- scale of the eutectic microstructure decreases withincreasing cooling rate from the liquid state.
The weight fractions of andphases at the eutectic point are given bythe Lever rule.
45.0)3.188.97(
)9.618.97(
)qp(
pC =
=
+=
55.0)C1(C ==
-
8/2/2019 407 Class Notes
94/114
55.0)C1(C
2. Off-eutectic composition
Fig. 35 Schematic representations of the equilibriummicrostructures for a Pb-Sn alloy of composition C4as it iscooled from the liquid-phase region.
-
8/2/2019 407 Class Notes
95/114
Cooling curves
Cooling curves can be used to determine the locations of eutecticpoint, liquidus curve, and solidus curve
-
8/2/2019 407 Class Notes
96/114
Fig.37 The use of
cooling curves toestablish the liquidusand solidus in a binaryeutectic alloy underequilibrium conditions.
Alloy 3 (eutectic composition) experiences a sharp break in the coolingcurve, due to isothermal transformation of the liquid phase into two
solid phases (+).
-
8/2/2019 407 Class Notes
97/114
p ( )
Alloys 2 and 4 experience heat release over a range of temperatures T= (TL - TS), prior to isothermal solidification at the eutectic temperature,TE.
Alloys 1 and 5 behave like regular solid solution alloys, in that there is achange in slope of the cooling curve at TL and TS.
Complex systems
Most practical phase diagrams are more complex than the relatively
simple isomorphous and eutectic systems considered so far. Figure 38shows a binary phase diagram that comprises:
-
8/2/2019 407 Class Notes
98/114
shows a binary phase diagram that comprises:
-- two eutectic reactions (L + ; L + ), a peritecticreaction (L + ), and an intermediate phase reaction (L).
-- phase melts congruently, i.e. the compositions of liquid andsolid phases are the same.
-- phase melts incongruently, i.e. it decomposes into twophases (L + ), such that composition of the liquid phase isdifferent from that of the solid phase.
-
8/2/2019 407 Class Notes
99/114
Fig. 38 (a) Complex phase diagram containing a peritectic and two
eutectic reactions, and (b) invariant reactions in (a) emphasizedalong with their symbolic representations.
Eutectoid system
An eutectoid reaction is a solid-state reaction, involving the decompositionof a single solid phase () into two solid phases ( + ) having differentcompositions.
-- decomposition occurs by solute redistribution in the phase just
-
8/2/2019 407 Class Notes
100/114
p y p jin front of the two phase ( + ) region.
-- solid-state reaction is slower than liquid-state reaction, due tomuch slower diffusion rate in the solid state.
-- most important commercial system that exhibits an eutectoidreaction is the Fe-Fe3C system
Fe-Fe3C system
Upon heating, pure Fe experiences two solid state reactions:
912C 1394C-ferrite -austenite -ferrite(bcc) (fcc) (bcc
-
8/2/2019 407 Class Notes
101/114
Fig. 39 The Fe-C phase diagram.
With the addition of C, these polymorphic transformations are drasticallymodified
-- the solubility of C in -austenite is large; maximum of 2.14 wt.% at 1147C.-- the solubility of C in -ferrite is small; maximum of 0.022 wt.% at 727C.-- when the solubility of C in and phases is exceeded, an intermediate
phase Fe3C, known as cementite, makes its appearance.
Upon cooling from the fully austenitic state, an alloy of composition 0.76wt.%C, the following eutectoid reaction occurs:
+ Fe3C
-
8/2/2019 407 Class Notes
102/114
(austenite) (ferrite) (cementite)
pearlite
Pearlite is the product of -austenite decomposition, and consists ofalternating layers (lamellae) of -ferrite and Fe3C-cementite.
-- pearlite is nucleated at the prior austenite grain boundaries, andpropagates by a diffusion controlled mechanism
-- C atoms diffuse away from the -ferrite regions into the adjacentFe3C cementite regions.
-
8/2/2019 407 Class Notes
103/114
Fig. 40 Schematics ofmicrostructures for an Fe-C alloy
of eutectoid composition (0.76wt.% C) above and below theeutectoid temperature.
Fig. 41 Photomicrograph of aneutectoid steel showing the
pearlite microstructure, whichconsists of alternating layers of-ferrite (light phase) and Fe3C-cementite (dark phase). 500x
-
8/2/2019 407 Class Notes
104/114
Fig. 42 Schematic representation of the formation ofpearlite from austenite; direction of carbon diffusionindicated by arrows.
The wt. fractions of the constituent and Fe3C phases in pearlitecan be determined using the Lever rule.
89.0)022.07.6(
)76.07.6(fraction.wt =
=
wt. fraction Fe3C = 0.11
Off-eutectoid composition
Alloy compositions to the left and right of the eutectoid (0.76 wt.% C) aretermed hypoeutectoid and hypereutectoid, respectively.
-- cooling a hypoeutectoid alloy from the fully austenitic region gives
-
8/2/2019 407 Class Notes
105/114
g yp y y g grise first to pro-eutectoid -ferrite (along the prior austenite grainboundaries) and then pearlite.
-- similarly for hypereutectoid alloys, except that the pro-eutectoid
phase is cementite.
-- the weight fractions of pro-eutectoid ferrite and total ferrite (pro-eutectoid + eutectoid ferrite) can be determined using the Lever rule.
Hypoeutectoid alloys comprise most of the commercially important steels,
since they combine high strength (due to pearlite) and good fracture toughness(due to pro-eutectoid ferrite).
-
8/2/2019 407 Class Notes
106/114
Fig. 43 Schematic of themicrostructures for an Fe-Calloy of hypoeutectoidcomposition C0(< 0.76 wt.%
C), as it is cooled fromwithin the austenite phaseregion to below theeutectoid temperature.
Fig. 44 - Photomicrographof a 0.38 wt.% C steelhaving a microstructureconsisting of pearlite and
pro-eutectoid ferrite. 635x.
Effect of cooling rate
Slow cooling from the fully austenitic region gives pearlite (diffusion-controlled transformation).
(fcc) (bcc) + Fe3C (orthorhombic)(austenite) (ferrite) (cementite)
-
8/2/2019 407 Class Notes
107/114
-- composed of alternating layers of ferrite () and cementite (Fe3C),Fig. 41.
-- formed by redistribution of C in the phase just ahead of theadvancing two-phase ( + Fe3C) interface, Fig. 42.
-- pearlite is strong and tough.
Fast cooling from the fully austenitic region gives martensite (diffusion-
less transformation).
(fcc) (bct)(austenite) (martensite)
-- martensite has a needle-like morphology and is hard and brittle.
pearlite
-
8/2/2019 407 Class Notes
108/114
When heated, Fe3C begins to form as fine precipitates within the martensiteneedles.
-- this has the effect of reducing hardness and increasing toughness,called tempering.
When heated just below the eutectoid temperature for a long time (~10 hours),a relatively uniform distribution of coarse Fe3C particles is formed in an -ferrite matrix.
-- such a microstructure, called spheroidite, possesses moderatestrength and good ductility.
Fig. 45 Progress of athermal martensitic transformation in an Fe-1.8wt.% C alloy after cooling to (a) 24C, (b) -60C, and (c) -100C.
-
8/2/2019 407 Class Notes
109/114
Fig. 46 Microstructure of a tempered martensite (spheroidite)in a steel with 0.7 wt.% C.
Isothermal transformation diagram
The pearlite transformation is both temperature and time dependent,whereas the martensite transformation depends solely on temperature,not time. This difference in behavior can be represented convenientlyon an isothermal transformation (IT) diagram.
-
8/2/2019 407 Class Notes
110/114
Fig. 47 Schematic of an isothermal transformation(IT) diagram for a eutectoid steel.
Curve A slow cooling gives 100% pearlite
Curve B fast cooling (quenching) gives 100% martensite
Curve C slow cooling to point X, followed by quenching, gives50% pearlite + 50% martensite
MartemperingThis is a commercially important quench-and-temper process:
-- quench to a temperature just above Ms and hold to minimizethermal gradients that can lead to surface cracking
-- quench again to ambient temperature to form 100% martensite
-- reheat to tempering temperature to develop fine-scale Fe3Cparticles
-
8/2/2019 407 Class Notes
111/114
particles
-- resulting tempered martensite has high strength and moderateductility
Fig. 48 Schematic showing thecooling curve superimposed onIT diagram for martempering, or
indirect quench process (with atemper step).
-
8/2/2019 407 Class Notes
112/114
Fig. 47 Schematic of an isothermal transformation(IT) diagram for a eutectoid steel.
Indicates microstructural consequences of changing cooling ratefrom the fully austenitic region
-- s ow coo ng orms pear te
-- fast cooling forms martensite
-
8/2/2019 407 Class Notes
113/114
Incubation period is characteristic of pearlitic transformation, since it
occurs via a diffusion-controlled mechanism
--
boundaries
Martempering
This is a commercially important quench-and-temper process:
-- quench to a temperature just above Ms and hold to minimizethermal gradients that can lead to surface cracking
-
8/2/2019 407 Class Notes
114/114
-- quench again to ambient temperature to form 100% martensite
-- reheat to tempering temperature to develop fine-scale Fe3Cparticles
-- ductility
Fig. 48 Schematic showing thecooling curve superimposed on
IT diagram for martempering, or
indirect quench process (with atemper step).