3472-1 skema mt trial sbp spm 2013
TRANSCRIPT
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3472/1
Matematik
Tambahan
Kertas 1
2 jamOgos 2013
BAHAGIAN PENGURUSAN
SEKOLAH BERASRAMA PENUH DAN SEKOLAH KECEMERLANGAN
KEMENTERIAN PENDIDIKAN MALAYSIA
PENTAKSIRAN DIAGNOSTIK AKADEMIK SBP 2013
PERCUBAAN SIJIL PELAJARAN MALAYSIA
ADDITIONAL MATHEMATICS
Paper 1
Skema Pemarkahan ini mengandungi 6 halaman bercetak
MARKING SCHEME
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PERATURAN PEMARKAHAN- KERTAS 1
No. Solution and Mark SchemeSub
Marks
Total
Marks
1(a) 4
( )2xf x
1
1
2
2 3
4n
3 3
B2 :3 1 2
7
nn
OR 7 2 3 1n n
B1 : 12
( )7
xg x
OR ( ) 3 1g n n
3 7 18p and q B2 : 7 18p or q
B1 : ( 3) 3p px
3 3
4
2
1and 10
5
1B2: or 10
5
2 1B1: 2 or 2 OR 5(2) ( 1)(2) 2 0
5 5
m n
m n
nm m n
2OR 5 5(2 ) 10 0x m x m
3 3
5
4
9q
B2: 0)3)(3(4)3( 2 q
B1: 23 3 3 0x x q
3 3
3
29
B1 : 25 7 (0 3)m
(3,7)
1
2
1
4
(b)
(b)
(c)
6(a)
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7 2
2 : 35 (5 100) 1x OR1
525
x
1 : 35 5 1 100(5 )x x
3 3
8 9
4x
B3 : 22
9 18 3x
x x ORx
B2 :3 3 3
2log 9( 2) log log 2
xx x OR
x
B1 : 3
3
log(accept any base)
log 9
x
4 4
9 4
B2 : 6m
B1 : (2 1) ( 3) ( 3) ( 1)m m m m or equivalent
3 3
1or 0.2
5r
B2 : (5 1)(5 6) 0r r
B1 : 26
25ar ar a or equivalent
25or 12.5
2
3 4
11 19,23,27,31
B3 : 8n or 11n OR 19 or 31
B2 : 1 2 3 100n n n nT T T T OR
1 2 3 100n n n nT T T T
B1 : 4d
4 4
(b)
10(a)
1
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4
12
2
5 and 4
B2 : 5 or 4
B1 : 8
s t
s t
yx
x
3 3
13 (a) 52
(b) 3 6 or equivalent2
y x
B1 :3
2ABm
1
2
3
14 7 and 13p p
B2 : 7 OR 13p p
B1 : 2 6 20 or 2 6 20p p
3 3
15
(a) 7, 6C
B1 : 4 1
2 OR 2 4 2 22 2
OC OC i j i j
(b) 85 or 9.220
2 3
16 2 and 6p q
B2 : 2 or 6p q
B1 : 2 0 or 4 0p p q
3 3
17(a) 1.117 rad
2.728 cm2
B2 : 2 2 21 1 1
5 1.117 sin 64 OR 5 1.117 5 sin 642 2 2
B1 : 2 21 1
5 1.117 or 5 sin 642 2
1 4
1
3(b)
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5
18 0 ,60 ,180
B2 : sin 2cos 1 0x x
B1 : 2sin cos sinx x x
3 3
19 (2,1)
B2 : 2 5 2 2 4x
B1 : 1 22 5 2 2 or 4 (use 1)x m m m
33
20 3
B2 : 1 13 m
B1 :1
or or 3 3
dy du dy mm
du dx dx
3 3
21 3
B2 :5
1[ ] 10 2mx
B1 :5 5
1 1
( ) 2 10m dx k x dx or
3 3
22(a)
(b)
315
B1 :2
29 (6)7
x
2 3
23(a)
(b)
252
48
B1 : 4! 2!
1
2
3
81 1
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24(a)
(b)
2
9
B1 :1 20
3 30
2
5
B1 :2 13 1 10
or3 30 3 30
2 4
25 6
B2 :
0
0
1 1 1
2 2 64
n
nC
B1 : 1 ( 0)P x
3 3
2