3 percent copper mm - creighton...
TRANSCRIPT
Experiment310September2019
PercentCopperandMolarMassofaCopperCompoundSo,let’ssayIstartedwithabout1.0billiongramsofunknownthatisonly40%copper…
...thatwouldbe…400thousandkgofcopper
…at$6/kg…
…or$2.4million.Boom.
Wearegoingtoneedabiggerscale.
Objectives:Todeterminepercentcopperandmolarmassofanunknowncoppersalt.
Overview:1. Overviewformulas,molarmassand%Cu2. ProcedureOverview3. Calculations4. Procedure5. Yourlabreport
So,wearemakingcoppertoday?
Well,yeah...butthat’snotthepoint.Wewillfigureouthowmuchcopperisinanunknowncoppersaltandthemolarmassoftheunknown.And
that’sprettyawesome!
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Remember,beforecomingtolab,youshouldwriteanintroductionthatincludestheobjectivefromthisslideandincludesimportantequationsandconceptsfromthefollowing
slidesthataremarkedwiththissign.
InfoforIntroduction
1.Overview,formulas,molarmass,%Cu
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Cu2+Cu2+
Cu2+
Cu2+
Cl-
Theunknownmaybeahydrate–asaltthatincludeswaterinitsformula.Ornot.
Forexample,copper(II)
chlorideexistsasanhydrous(nowatersofhydration)orasadihydrate(2watersof
hydration).
Todaywewillanalyzeapuresaltofcopper(II)–maybeit’scopper(II)nitrate,orcopper(II)acetate,orcopper(II)chloride,
andsoon.Wejustdon’tknow.It’sanunknown!
Examplesofsolidcopper(II)chloride:
Asadihydrate:CuCl2.2H2O(s)Orasananydroussolid:CuCl2(s)
Eitherway,insolutionit’sjustions:
Cl-Cl-
Cl-
Cl- Cl-
Cl-Cl-
CuSO4(s)?Cu(NO3)2(s)?
Cu(C2H3O2)2(s)?
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Continuingwithcopper(II)chlorideasanexample,theanhydrousversionandthedihydrateversionhave
differentmolarmassesandpercentscopper.
Anydrouscopper(II)chloride:CuCl2(s):
MM=1x63.55(Cu)+2x35.45(Cl)=134.45g/mol%Cu=100%x
=47.27%Cu
1x63.55134.45
Asadihydrate:CuCl2.2H2O(s):
MM=1x63.55(Cu)+2x35.45(Cl)+4x1.008(H)+2x15.999(O)=170.48g/mol
%Cu=100%x
=37.28%Cu
1x63.55170.48
1.Overview,formulas,molarmass,%Cu
2.ProcedureOverview(page21)
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Mg2+
Mg2+Mg2+
Mg2+
X-
Weuseexcessmagnesiumtomakesurewereduceallof
theCu2+iontoCumetal
Westicktothelabmanual’sproceduretoday.Wewilldissolveourunknowncoppersaltinwaterandreducethecopper(II)iontocoppermetalwith
magnesium.Hereisthenetionicequation.ThespectatorionsareunknowntousandareshownasX-inthebeakers.TheymightevenbeX2-.
Cu2+(aq)+Mg(s)àCu(s)+Mg2+(aq)
X-X-
X-
X- X-X-X-
InfoforIntroduction
Cu2+
Cu2+ Cu2+Cu2+
X- X-X-
X-
X- X-X-X-
Mg Mg MgMgMg Cu CuCuCuMg
Stir
Cu2+istheL.R.Justsayin’…
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Mg2+
Mg2+Mg2+
Mg2+
X- X-X-
X-
X- X-X-X-
InfoforIntroduction
Cu2+
Cu2+ Cu2+Cu2+
X- X-X-
X-
X- X-X-X-
Mg Mg MgMgMg Cu CuCuCuMg
Stir
Cu2+(aq)+Mg(s)àCu(s)+Mg2+(aq)
Youcantellwhenthereactionisover–alloftheblueCu2+isgoneandthesolutioniscolorless.Youshouldseeorangecoppermetal.
NextwehavetogetridofexcesssolidMgoritwilladdtotheweightofthesolidcopperandmessup
ourresults.
2.ProcedureOverview(page21)
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Mg2+
Mg2+Mg2+
Mg2+
X- X-X-
X-
X- X-X-X-
InfoforIntroduction
Cu CuCuCuMg
H3O+
AcidoxidizesMgtoaqueousMg2+.Weaddacidandstiruntilthebubblesstop.
Mg2+
Mg2+Mg2+
Mg2+
X- X-X-
X-
X-X-X-X-
Cu CuCuCu
Mg(s)+H3O+(aq)àMg2+(aq)+H2(g)+H2O(l)
Mg2+
Afterthesolidmagnesiumisgone(nomorebubbles),wecanfilterthesolutionandcollectthecoppermetal.
Stir
2.ProcedureOverview(page21)
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2.Procedurefromlabmanual
Nowit’stimeforyoutodotheexperiment Followingthe
procedureinthelabmanual
Whenyouaredonewiththeprocedure,comebacktothe
nextslide
…forthecalculations!
3.Calculations
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Fromthemassofcopperwecangetmolesofcopperandbecausetheunknownhasonlyonecopperatom,themoles
ofunknownequalsthemolesofcopper!Easypeasy.
%Cu=100%x
mCunCununknownPercentcopperandmolarmassareeasy
formulastouse.Watchoutforsignificantfiguresandunits.
MM=mCu
munknown
munknown
nunknownInfofor
calculations
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Soweendupwithtwoimportantmeasurementstoday–themassoftheunknownandthemassofcopperintheunknown.
%Cu=100%x
Gettingthemassofcopperrightisthetrick.Ifyoulose
someCuduringfiltration,your%Cuwillbetoolow.IftheCuiswet,themasswillbetoohighandsowillthe%Cu
mCu
munknown
Infoforcalculations
Notsoeasytomessupthemassofthe
unknown…
3.Calculations
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Soifourmassofcopperistoolow,ourpercentCuwillalsobetoolow.Butwhataboutthemolarmass?
InfoforSourcesofError
mCunCununknown
Rememberhowmassofcoppergivesusmolesofcopperandthatgivesus
molesofunknown?Yeah.Soerrorswiththemassof
copperwillcauseerrorswiththemolarmassaswell.
MM=munknownnunknown
3.Calculations
%Cu=100%xmCu
munknown
SO4
Hmmm...IfIgetthemassofthecopperright,Ishouldbegood.
Thisisthefirstexperimentinwhichwearebeinggradedfor
accuracy!
…andsigfigs
…andunits
3.Calculations
12Yourcopperisworthabout0.72cents
SO4
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Herearesomecompoundsofcopper.Ourunknownis
oneofthese.
Infoforcalculations
CuBr2 MM=223.4g/molCu(C2H3O2)2.H2O MM=199.6g/molCuCl2.2H2O MM=170.5g/molCuCO3 MM=123.6g/molCuSO4
.5H2O MM=249.7g/mol
Whichoneisit?Andwhatisthepercenterrorformolar
mass?
%Error=100%xdifferenceactual
Sometimesyoucan’tdecidebetweentwo.Concludeitmaybeeither–don’tjustpickone–that’snotgoodscience.BTW,Ihavealuncheonrightafterthis.
Hencethetux.
3.Calculations
4.Procedurefortoday(pg.21)
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I. Wearyoursafetyglassestoday.Andweneedtodressforamesstoday.
II. Wefollowthemanualcarefully.
III. Useananalyticalbalanceformeasuringmassesofcopperunknownandcoppertoday.Usethelittlescaleatyourstationtomeasurethemagnesium.
IV. Recordobservationsanddetailsascarefullyaspossible.
V. Conclusions.We’lllearnmoreonthenextslide.
VI. InsteadofStep11,turninyourcopperinaweighingdish.Makealabelwithyournamesandlabstationandsection.
Intheconclusionwecansummarizewhatwe’velearned.Whydidwedothisexperiment?ReviewtheObjectivesfromSlide2andseeifwedidwhatwesetouttodo.Wereadyourconclusionscarefully.Besuretowriteitinyourownwordsandnotcopyitfromanyone.
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Conclusion.In this experiment we determined the percent copper in an unknown salt
of copper(II). To do this we needed the mass of the unknown salt and the mass of the copper it contained. In our case, we used 2.514 g unknown and ended up with 1.250 g copper metal, which is 0.1967 mol Cu. That works out to 49.72% copper using the formula %Cu = 100% X mass Cu/mass unknown.
We also determined the molar mass of the unknown using the formula MM = mass unknown/moles unknown. The moles of unknown is the same as the moles of copper. We got 2.514 g/0.01967 moles = 127.8 g/mol, which is most similar to CuCO3 from the list of choices. If that is actually the identity of the unknown, we are off by just 3.4%. None of the other choices were even close, so we are confident about the identity of our unknown.
5.Yourlabreport.
Wealsoaddresssourcesoferrors.Sometimestherearen’tanyobviousonesandothertimesthereareplenty.Weneedtoonlyworryaboutthemoreplausibleones.Lookingoverthecontinuumofpossibleerrorsfor
thisexperiment,wewillstickwiththereasonableonesonly.
Reasonable UnreasonableNottoolikelyCopperwaswetor
SomecopperwaslostUsedthebalanceincorrectly
SamplewasimpureLawsofphysicssuspended.
SabotagedbyTAs
5.Yourlabreport.
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Sources of error.In the context of our good results, errors probably were not
significant for us. However, we can see how maybe some copper could have been lost during the filtering. If that had happened, the percent copper would be too low and the molar mass too high. On the other hand, if the copper were a bit wet or had some magnesium in it, the percent copper would calculate to be too high and the molar mass too low. We feel that no major errors were encountered.
5.Yourlabreport:EnteringOn-lineresults.
Todayisthefirstexperimentinwhichweenterourresultson-line.ClickthelinkattheChm204websitewhereitsaysSubmiton-lineresults(forExperiment3).Besupercarefultonotmakecareless
mistakes.Thevaluesyouenterwillbeusedtocheckyourcalculations.Thestuffyouenterisworth15pointsthisweek.Youandyourlabpartnernormallyentervaluestogether.Referbackto
theorientationpresentationifyouhaveanyquestions.
NumbersmustbeenteredinMicrosoft’sExcelformatonlyifyouareusing
exponentials.Thatformatlookslike1.234E-5or6.789E10.Thereareno
spacesoneithersideoftheE.Numberscanalsobeenteredasdecimalswithouttheexponentialnotation–like0.001234,
forexample.
Don’tmessup.
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5.Yourlabreport:EnteringOn-lineresults.
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CanIenter1.234x10^5?
Howabout1.234E^5?
Isthisok:1.234E5?
Whatabout…
No.
No.
No.
No.
Only1.234E5works.That’sthewayitis.
5.Yourlabreport.
① First,thecoverpagewithTAinitials.② Next,thetrimmedcopypagesfromyourlabnotebook
stapledtogether.③ Enteron-linedatabeforeyouleavelab.Yourcalculations
willbecheckedaswellascorrectuseofunitsandsignificantfigures.Latesubmissionsarenotgraded–seethesyllabus.
④ Turnedinlabreporttodayorbeforethestartofclasstomorrow.Latelabsmaynotbegraded–seethesyllabus.
StickpeopleinspiredbyxkcdcartoonsbyRandallMunroe 19
Ourworkhereisdone
Let’sgo!
ChemLabwiththeStickPeopleandBirdwascreatedandproducedbyDr.BruceMattson,CreightonChemistry.Enjoyitandshareitifyouwish.