2011 mm f1 p2 skema
DESCRIPTION
matematikform 1paper 2skema jawapan2011TRANSCRIPT
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NoMarking SchemeMarks
19.(a) 8 cm x 4 cm = 32 cm
(b) i) perimeter = 20 cm + 14cm + 10 cm + 34 cm + 30 cm
= 108 cm
ii) area = 20 x 14 + x 30 x 16
= 280 + 240
= 520 cm N1N1
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N14
20. = 16 x 3 x 3 x 3
x =
= 9 cm K1K1
N13
PEJABAT PELAJARAN DAERAH KULAIJAYA
MARKING SCHEME MATHEMATICS FORM 1
PAPER 2 2011NoMarking SchemeMarks1.a ) 465 312 = 465 000 ( to the nearest thousand)
b) EMBED Equation.3 8216 + 699
8216
+ 699
8915
EMBED Equation.3
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32.149 18 x 7 EMBED Equation.3 14
= 149 126 EMBED Equation.3 14
= 149 9
= 140
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33.Common Multiples of 4 and 6
Multiples of 4 : 4, 8, 12, 16, 20,24,28, 32,36
Multiples of 6: 6,12,18, 24,30,36
Therefore the first three common multiples of 4 and 6 are 12, 24, 36
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34.Factors of 36 : 1,2,3,4, 6,9,12,18, 36
Factors of 48: 1,2,3,4,6,8,12,16,24,48
Therefore the HCF of 36 and 48 is 12
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35
EMBED Equation.3 = EMBED Equation.3
= EMBED Equation.3
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2
NoMarking SchemeMarks6
EMBED Equation.3 = EMBED Equation.3
= EMBED Equation.3
= EMBED Equation.3
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37..27.3 0.24 EMBED Equation.3 ( 11.94) = 27.3 0.24 EMBED Equation.3 1.6 = 27.3- 0.15
= 27.15
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38.If 12% of x is 360, determine the value of x
QUOTE = 360
12 QUOTE = 360 X 100 =
x = 36000
12
x = 3000
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29.Objective question = 20 X 2 = 40
Subjective question = 8 X 3 = 24
total = 64
QUOTE 100
= 80%
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4
NoMarking SchemeMarks10.X = -8 Y = -4
= (-8) + (-4)
= - 8 4
= -12
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211.3y 12 x + 10 y 4x
-3y + 10 y -12 x 4 x
= -7 y 16 x
Area GEFH = 5 x 3 y = 15 xy
Shaded Area= 2x xy = 2xy
Total = 13 xy
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412.18 kg 303 g X 5
= 90kg 1515g
+ 1kg - 1000g
91 kg 515g
= 9.515 kg
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313.4 hours 20 mt
+ 15 mt
4 hours 35 mt
+ 2 hours 25 mt
7 hours 60 mt = 7 hours
Time Departed = 13.15
+ 7.00
21.15 or 9.15 pm.
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314.x = 90 EMBED Equation.3 - 37 EMBED Equation.3
= 53 EMBED Equation.3
49 EMBED Equation.3 + 55 EMBED Equation.3 + y = 180 EMBED Equation.3
y = 180 EMBED Equation.3 - 49 EMBED Equation.3 - 55 EMBED Equation.3
= 76 EMBED Equation.3
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31
NoMarking SchemeMarks15.(a) Reflex angle
(b) P = 46 EMBED Equation.3 (vertically opposite angle)
2q + 90 EMBED Equation.3 + 46 = 180 EMBED Equation.3
2q = 180 EMBED Equation.3 - 90 EMBED Equation.3 -46 EMBED Equation.3
2q = 44 EMBED Equation.3
q = 22 EMBED Equation.3 P1
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416.
P2
217.a) y = 180 EMBED Equation.3 - 63 EMBED Equation.3
= 117 EMBED Equation.3
b) EMBED Equation.3 DBC = (180 EMBED Equation.3 - 68 EMBED Equation.3 ) EMBED Equation.3 2
= 56 EMBED Equation.3
x = 60 EMBED Equation.3 + 56 EMBED Equation.3
= 116 EMBED Equation.3
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318.Perimeter = (5 cm x 3) + 12cm + (7cm x 2) + 13 cm
= 15 cm + 12 cm + 14 cm + 13 cm
= 54 cm K1
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3
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