2011 mm f1 p2 skema

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matematikform 1paper 2skema jawapan2011

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NoMarking SchemeMarks

19.(a) 8 cm x 4 cm = 32 cm

(b) i) perimeter = 20 cm + 14cm + 10 cm + 34 cm + 30 cm

= 108 cm

ii) area = 20 x 14 + x 30 x 16

= 280 + 240

= 520 cm N1N1

K1

N14

20. = 16 x 3 x 3 x 3

x =

= 9 cm K1K1

N13

PEJABAT PELAJARAN DAERAH KULAIJAYA

MARKING SCHEME MATHEMATICS FORM 1

PAPER 2 2011NoMarking SchemeMarks1.a ) 465 312 = 465 000 ( to the nearest thousand)

b) EMBED Equation.3 8216 + 699

8216

+ 699

8915

EMBED Equation.3

N1

K1

N1

32.149 18 x 7 EMBED Equation.3 14

= 149 126 EMBED Equation.3 14

= 149 9

= 140

K1

K1

N1

33.Common Multiples of 4 and 6

Multiples of 4 : 4, 8, 12, 16, 20,24,28, 32,36

Multiples of 6: 6,12,18, 24,30,36

Therefore the first three common multiples of 4 and 6 are 12, 24, 36

K1

K1

N1

34.Factors of 36 : 1,2,3,4, 6,9,12,18, 36

Factors of 48: 1,2,3,4,6,8,12,16,24,48

Therefore the HCF of 36 and 48 is 12

K1

K1

N1

35

EMBED Equation.3 = EMBED Equation.3

= EMBED Equation.3

K1

N1

2

NoMarking SchemeMarks6

EMBED Equation.3 = EMBED Equation.3

= EMBED Equation.3

= EMBED Equation.3

K1

K1

N1

37..27.3 0.24 EMBED Equation.3 ( 11.94) = 27.3 0.24 EMBED Equation.3 1.6 = 27.3- 0.15

= 27.15

K1

K1

N1

38.If 12% of x is 360, determine the value of x

QUOTE = 360

12 QUOTE = 360 X 100 =

x = 36000

12

x = 3000

K1

N1

29.Objective question = 20 X 2 = 40

Subjective question = 8 X 3 = 24

total = 64

QUOTE 100

= 80%

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K1

K1

N1

4

NoMarking SchemeMarks10.X = -8 Y = -4

= (-8) + (-4)

= - 8 4

= -12

K1

N1

211.3y 12 x + 10 y 4x

-3y + 10 y -12 x 4 x

= -7 y 16 x

Area GEFH = 5 x 3 y = 15 xy

Shaded Area= 2x xy = 2xy

Total = 13 xy

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K1

N1

412.18 kg 303 g X 5

= 90kg 1515g

+ 1kg - 1000g

91 kg 515g

= 9.515 kg

K1

K1

N1

313.4 hours 20 mt

+ 15 mt

4 hours 35 mt

+ 2 hours 25 mt

7 hours 60 mt = 7 hours

Time Departed = 13.15

+ 7.00

21.15 or 9.15 pm.

K1

K1

N1

314.x = 90 EMBED Equation.3 - 37 EMBED Equation.3

= 53 EMBED Equation.3

49 EMBED Equation.3 + 55 EMBED Equation.3 + y = 180 EMBED Equation.3

y = 180 EMBED Equation.3 - 49 EMBED Equation.3 - 55 EMBED Equation.3

= 76 EMBED Equation.3

K1

K1

N1

31

NoMarking SchemeMarks15.(a) Reflex angle

(b) P = 46 EMBED Equation.3 (vertically opposite angle)

2q + 90 EMBED Equation.3 + 46 = 180 EMBED Equation.3

2q = 180 EMBED Equation.3 - 90 EMBED Equation.3 -46 EMBED Equation.3

2q = 44 EMBED Equation.3

q = 22 EMBED Equation.3 P1

K1

K1

N1

416.

P2

217.a) y = 180 EMBED Equation.3 - 63 EMBED Equation.3

= 117 EMBED Equation.3

b) EMBED Equation.3 DBC = (180 EMBED Equation.3 - 68 EMBED Equation.3 ) EMBED Equation.3 2

= 56 EMBED Equation.3

x = 60 EMBED Equation.3 + 56 EMBED Equation.3

= 116 EMBED Equation.3

N1

K1

N1

318.Perimeter = (5 cm x 3) + 12cm + (7cm x 2) + 13 cm

= 15 cm + 12 cm + 14 cm + 13 cm

= 54 cm K1

K1

N1

3

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