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YOUR STUDENT NUMBER: (PTO) Year 2 Seminars, 06524, Semester 2, 2009 Heterocyclic Chemistry Test 1. Answer all parts. (a) For each of the following pairs of molecules, predict and explain which is the more basic. N H N H 2 N Me (i) (ii) Cl N Me Basic Non basic no non-bonded (lone) pair of electrons N H 2 H H N Me N Me H more stable conjugate base less basic less stable conjugate base more basic more conjugated less conjugated H H

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  • YOUR STUDENT NUMBER:

    (PTO)

    Year 2 Seminars, 06524, Semester 2, 2009 Heterocyclic Chemistry Test

    1. Answer all parts.

    (a) For each of the following pairs of molecules, predict and explain which is the more basic.

    NH

    NH2

    NMe

    (i)

    (ii)

    Cl

    NMe

    Basic Non basicno non-bonded (lone) pair of electrons

    NH2

    H

    H

    NMe

    NMe

    H

    more stable conjugate baseless basic

    less stable conjugate basemore basic

    more conjugatedless conjugated

    H H

  • (PTO)

    (b) Which of the following molecules are aromatic, anti-aromatic or simply conjugated?

    BH

    OCl

    Na

    Cyclic - YES

    Planar - YES

    Continuous conjugation - YES

    Number of pi-electrons = 6

    AROMATIC (4n+2) n = 1

    Cyclic - YES

    Planar - YES

    Continuous conjugation - YES

    Number of pi-electrons = 6

    AROMATIC (4n+2) n = 1

    Cyclic - YES

    Planar - YES

    Continuous conjugation - YES

    Number of pi-electrons = 6

    AROMATIC (4n+2) n = 1

  • YOUR STUDENT NUMBER:

    (PTO)

    Year 2 Seminars, 06524, Semester 2, 2009 Bifunctional Chemistry Test

    2. Answer all parts.

    (a) Mark on the following diagram all of the acidic hydrogen atoms in compound A and indicate clearly, with a brief explanation, which is the most acidic.

    O

    EtO2CO

    CN

    O H

    H

    Hmost acidic:enolate conjugation extends over C N too.

    A

    (b) Draw a tautomeric form of the compound B.

    NH

    B tautomer

    N

    H

    NH

    less stable: loss of aromaticity

    (c) For each of the following (see overleaf) work out what carbonyl-containing compounds could condense to form the molecules shown. In each case, giving a reason, state whether a synthesis from your two starting materials would be practicable (i.e. the reaction would give you the target molecule as the sole product).

  • (END)

    O

    Br

    Br

    EtO

    OO

    O

    Br

    Br

    (i)

    (ii)

    (iii)

    OO

    Br

    Br OH

    H

    + +

    OBr O

    H

    +

    O

    Br

    Br2 x

    NaOHEtOH

    Only ketone can enolize, aldehyde is more reactive electrophile than ketone: crossed condensation practicable. (This is essentially the same as question 1 tutorial sheet 4, and the dibenzylidene acetone lab experiment).

    OO

    Br

    Br O+ +

    OBr O

    +

    O

    Br

    Br2 x

    NaOHEtOH

    Both ketones can enolize, both have similar reactivity as electrophile: crossed condensation NOT practicable. Mixture of self and crossed condensation products obtained. (This is similar to question 2 tutorial sheet 4)

    EtO

    O

    EtO

    O

    +

    2 xNaOEtEtOHEtO

    O

    EtO

    OO

    CLAISEN condensation comes from 2 moles of the same ester: condensation practicable.(This is essentially the same as question 1 tutorial sheet 6)

    EtO

    O

    EtO

    O

    +

    ALDOL crossedcondensation

    ALDOL crossedcondensation