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Organic Chemistry III - Reactions II C hem F actsheet April 2001 Number 17 1 To succeed with this topic you need to Be able to name and draw organic molecules (Factsheet 15) Know the reactions of alkanes, alkenes and halogenoalkanes (Factsheet 16) After working through this Factsheet you will Know the reactions of alcohols Know some of the reactions of aldehydes, ketones and carboxylic acids Know the ways in which the organic compounds of this Factsheet and Factsheet 16 can be converted from one to another (i.e. synthetic pathways) Important The question at the end of this Factsheet test not only the information in it, but also the information in Factsheet 16. Factsheets 16 and 17 make up the complete work on organic reactions. Exam Hint - The secret to answering questions on organic chemistry is not to be put off by the unfamiliar compounds used in the question. Always look for the functional groups / families of the compounds Functional groups always react in the same way! Alcohols Alcohols have the general formula, C n H 2n + 1 OH, and the functional group is –OH. The ending of the name in –ol shows the presence of the –OH group. If two –OH groups are present it is called a diol. The position of the –OH group on the carbon chain of a molecule affects its properties, so you need to be able to identify the three types of alcohols: Primary H H C OH Secondary C H OH C C Tertiary C OH C C C -OH on the end of the carbon chain 2 carbon atoms attached to the OH- carrying C atom 3 carbon atoms attached to the OH- carrying C atom Reactions 1. Halogenation Primay, secondary, tertiary alcohols behave the same way. The – OH groups is replaced by Cl , Br or I. e.g. PCl 5 in dry conditions. C 2 H 5 OH + PCl 5 C 2 H 5 Cl + HCl + POCl 3 reaction type: substitution mechanism: nucleophilic e.g. Solid NaBr with concentrated H 2 SO 4 are used to produce HBr, C 2 H 5 OH + HBr C 2 H 5 Br + H 2 O reaction type: substitution mechanism: nucleophilic e.g. Solid P with solid I 2 to make PI 3 , 3C 2 H 5 OH + PI 3 3C 2 H 5 I + H 3 PO 3 reaction type: substitution mechanism: nucleophilic Alcohol Halogenalkane halogenating agent Exam Hint - test for alcohols (i.e. the – OH group). Add solid PCl 5 in dry conditions. It is an alcohol if white ‘steamy’ fumes (of HCl) are seen. This is a very important test and, like the bromine water test for a alkene, is a common examination question 2. Dehydration (i.e. the removal of H 2 O) Add concentrated H 2 SO 4 and heat to 170 0 C, e.g. H OH C C H H H H + H 2 O H C C H H H conc. H 2 SO 4 heat to 170 o C Alcohol Alkene dehydrating agent 3. Oxidation (only primary and secondary not tertiary) Potassium dichromate(VI), K 2 Cr 2 O 7 , in dilute H 2 SO 4 with heating. This is the oxidising agent and it is orange in colour, but changes to green as it is reduced. N.B. remember this colour change ! (i) Primary alcohols e.g. C 2 H 5 OH + [O] Then – if left, the aldehyde is oxidised further to the carboxylic acid , e.g. Cr 2 O 7 2- / H + C CH 3 O H + H 2 O C CH 3 O H + [O] C CH 3 O OH Alcohol Aldehyde [O] Aldehyde [O] Carboxylic acid

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Page 1: 17 Organ

Organic Chemistry III - Reactions II

ChemFactsheetApril 2001 Number 17

1

To succeed with this topic you need to••••• Be able to name and draw organic molecules (Factsheet 15)••••• Know the reactions of alkanes, alkenes and halogenoalkanes

(Factsheet 16)

After working through this Factsheet you will

••••• Know the reactions of alcohols••••• Know some of the reactions of aldehydes, ketones and carboxylic

acids••••• Know the ways in which the organic compounds of this Factsheet

and Factsheet 16 can be converted from one to another (i.e.synthetic pathways)

ImportantThe question at the end of this Factsheet test not only the information init, but also the information in Factsheet 16. Factsheets 16 and 17 make upthe complete work on organic reactions.

Exam Hint - The secret to answering questions on organic chemistryis not to be put off by the unfamiliar compounds used in the question.Always look for the functional groups / families of the compoundsFunctional groups always react in the same way!

AlcoholsAlcohols have the general formula, C

n H

2n + 1OH, and the functional group

is –OH. The ending of the name in –ol shows the presence of the –OHgroup. If two –OH groups are present it is called a diol. The position of the–OH group on the carbon chain of a molecule affects its properties, so youneed to be able to identify the three types of alcohols:

Primary

H

H

C OH

Secondary

C

H

OH

CC

Tertiary

C

OH

CC

C

-OH on theend of thecarbon chain

2 carbon atomsattached to theOH- carrying C atom

3 carbon atomsattached to theOH- carrying C atom

Reactions1. HalogenationPrimay, secondary, tertiary alcohols behave the same way. The – OHgroups is replaced by Cl , Br or I.

e.g. PCl5 in dry conditions.

C2H

5OH + PCl

5 → C

2H

5Cl + HCl + POCl

3

reaction type: substitutionmechanism: nucleophilic

e.g. Solid NaBr with concentrated H2SO

4 are used to produce HBr,

C2H

5OH + HBr → C

2H

5Br + H

2O

reaction type:substitutionmechanism: nucleophilic

e.g. Solid P with solid I2 to make PI

3 ,

3C2H

5OH + PI

3 → 3C

2H

5I + H

3PO

3

reaction type:substitutionmechanism: nucleophilic

Alcohol Halogenalkanehalogenatingagent

Exam Hint - test for alcohols (i.e. the – OH group).Add solid PCl5 in dry conditions . It is an alcohol if white ‘steamy’fumes (of HCl) are seen. This is a very important test and, like thebromine water test for a alkene, is a common examination question

2. Dehydration (i.e. the removal of H2O)

Add concentrated H2SO

4 and heat to 170 0C,

e.g.

H

OH

CC

H

H H

H

+ H2O

H

CC

H

H Hconc. H

2SO

4

heat to 170oC

Alcohol Alkenedehydratingagent

3. Oxidation (only primary and secondary not tertiary)Potassium dichromate(VI), K

2Cr

2O

7, in dilute H

2SO

4 with heating. This is

the oxidising agent and it is orange in colour, but changes to green as it isreduced. N.B. remember this colour change !

(i) Primary alcohols

e.g. C

2H

5OH + [O]

Then – if left, the aldehyde is oxidised further to the carboxylic acid ,

e.g.

Cr2O

72-/

H+ CCH3

O

H

+ H2O

CCH3

O

H

+ [O] CCH3

O

OH

Alcohol Aldehyde[O]

Aldehyde[O]

Carboxylic acid

Page 2: 17 Organ

Chem Factsheet

2

Organic chemistry III - reactions II

N.B. In the A2 course these oxidation processes are shown to becapable of being reversed by a reduction process,

i.e. Carboxylicacid

[H]Aldehyde

[H] Primaryalcohol

Ketone[H] Secondary

alcohol

(ii) Secondary alcohols

e.g.

+ [O]

H

OH

C CH3

CH3

O

C CH3

CH3

+ H2O

Synthetic PathwaysSummary Of Reactions From Factsheet 16 & 17

PrimaryHalogenalkanes

KOH(aq)

H+

PrimaryAlcohol

K2Cr

2O

7Aldehyde

H+

K2Cr

2O

7 CarboxylicAcid

KOH / ethanol HX

AlkeneX

2 DihalogenoAlkanes

KOH(aq)Diol

KOH / ethanol HX

SecondaryHalogenalkanes

KOH(aq) SecondaryAlcohol H+

K2Cr

2O

7

Ketone

Practice Questions1. The molecule contains the – OH group in various positions:

C

H

H

CC C C

H OH H H

H

HOH

HO

HCH OH

H

1 2 3 4 5

6

Is the –OH in a primary, secondary or tertiary position in the carbonatom numbered 1, 3, 4 and 6?

2. Propan -1– ol is reacted with the following reagents under the conditionsshown. In each case give:(i) The balanced chemical equation.(ii) The systematic name of the organic product.

(a) Solid NaBr and concentrated sulphuric acid.(b) Heating to 170 oC with concentrated sulphuric acid.(c) Heating with potassium dichromate (VI) in dilute sulphuric acid.

3. An unknown liquid gives the following test results:(a) Produces white steaming fumes with dry PCl

5

(b) changes potassium dichromate(VI) in dilute sulphuric acid fromyellow to green when heated.

What family could the liquid belong to?

4. For each of the steps A – D give the regents and the conditions necessaryto bring about the conversion:

H

OH

C CH3

CH3

step AC CH

3CH2

H

Br

C CH3

CH3

step B

H

H

OH

C CH3

CH3

step C

step D

O

C CH3

CH3

Secondary alcohol Ketone[O]

Ketones cannot be oxidised further.

Page 3: 17 Organ

Chem Factsheet

3

5. Compound A (C4H

10O) is oxidised to compound B (C

4H

8O

2) by

heating it with K2Cr

2O

7 and dilute H

2SO

4. A produces compound C

with P and I2 at room temperature. C is converted into D by reacting it

with ethanolic KOH.

Identify the compounds A, B, C and D by giving their structuralformulas and systematic names.

6. An unknown compound gives the following test results:(a) decolourises bromine water(b) produces a yellow precipitate when reacted with dilute nitric acid

followed by silver nitrate solution.What functional groups does the compound contain?

Answers1. C� - primary, C� - tertiary, C� - secondary, C� - primary

2. (a) C3H

7OH + HBr → C

3H

7Br + H

2O

1-bromopropane

(b) C3H

7OH → C

3H

6 + H

2O

propene

(c) C3H

7OH + [O] → C

2H

5CHO + H

2O

propanal

Or 2C

3H

7OH + 3[O] → 2C

2H

5 COOH + H

2O

propanoic acid

3. Primary or secondary alcohol (both need to be named)

4. A – conc. H2SO

4 at 170 oC

B – HBr (from conc. H2SO

4 / NaBr)

C – KOH(aq)D – K

2 Cr

2 O

7 / dil. H

2 SO

4 + heat

5. A

B

C

D

6. (a) alkene,

(b) iodide, -I

Organic chemistry III - reactions II

C

H

H

CC C

H H H

OH

H

H

H H

butan-1-ol

C

H

H

CC C

H H

H

H H

OH

Obutanoic acid

C

H

H

CC C

H H H

I

H

H

H H

1-iodobutane

C

H

H

CC C

H

H

H

H

H H

but-1-ene

C C

Acknowledgements:This Factsheet was researched and written by Sam Goodman & Kieron HeathCurriculum Press, Unit 305B, The Big Peg, 120 Vyse Street, Birmingham, B18 6NFChemistryFactsheets may be copied free of charge by teaching staff or students,provided that their school is a registered subscriber.No part of these Factsheets may be reproduced, stored in a retrieval system, ortransmitted, in any other form or by any other means, without the priorpermission of the publisher. ISSN 1351-5136