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1/44 #-Rewriting #-Rewriting Systems Systems Based upon Based upon Brno University of Technology, Czech Republic [email protected] Křivka, Z., Meduna, A., Schönecker, R.: Generation of Languages by Rewriting Systems that Resemble Automata, In: IJFCS Vol. 17, No. 5, 2006 and An Infinite Hierarchy and An Infinite Hierarchy Resulting from Them Resulting from Them

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3/44 #-Rewriting Systems in Formal Language Theory Language-defining models Pure rewriting systems Between automata and grammars: have states but generate languages

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Page 1: 1/44 #-Rewriting Systems Based upon Brno University of Technology, Czech Republic  Křivka, Z., Meduna, A., Schönecker, R.: Generation

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#-Rewriting Systems#-Rewriting Systems

Based uponBased upon

Brno University of Technology, Czech Republic

[email protected]

Křivka, Z., Meduna, A., Schönecker, R.: Generation of Languages by Rewriting Systems that

Resemble Automata, In: IJFCS Vol. 17, No. 5, 2006

and An Infinite Hierarchy Resulting from Themand An Infinite Hierarchy Resulting from Them

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Contents

1. Concepts2. Definition 3. Main Result: An Infinite Hierarchy4. Open Problem Areas

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#-Rewriting Systems in Formal Language Theory

• Language-defining models• Pure rewriting systems• Between automata and grammars: have states but generate languages

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Concept#-Rewriting System is based on the rules of the form

pm# q x0 # x1 … # xn

by which the system makes a computational step as

(p, …#ym-1#ym#ym+1…) (q, …# ym-1x0#x1…#xnym# ym+1…)

mth #

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Definition 1/2#-Rewriting System (#RS) is a quadruple

H = (Q, , s, R), where

• Q finite set of states,• alphabet, # is called a bounder,• s Q start state,• R finite set of rules of the form

pm# qxwhere p, q Q, m is a positive integer, x *.

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Definition 2/2

Computational step: (p, u#v) (q, uxv) [pm# qx R],

where the number of #s in u is m – 1, p, q Q, u, x, v *.

Configuration: (q, x), q Q, x *

Generated language:L(H) = {w ( – #)*: (s, #) * (q, w) in H, q Q}.

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Example: #RS

#RS H:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

H accepts aabbcc:

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Example: #RS

(s, #)

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) [1]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1] [2]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1] (q, a#b#) [2]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1] (q, a#b#) [2] [3]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1] (q, a#b#) [2] (p, a#bc#) [3]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1] (q, a#b#) [2] (p, a#bc#) [3] [4]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1] (q, a#b#) [2] (p, a#bc#) [3] (f, aabbc#) [4]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1] (q, a#b#) [2] (p, a#bc#) [3] (f, aabbc#) [4] [5]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1] (q, a#b#) [2] (p, a#bc#) [3] (f, aabbc#) [4] (f, aabbcc) [5]

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Example: #RS

(s, #) (p, ##) [1] (q, a#b#) [2] (p, a#bc#) [3] (f, aabbc#) [4] (f, aabbcc) [5]

L(H) = {anbncn: n 1}

#RS H: H accepts aabbcc:[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Finite index of #RS#-Rewriting systems of index k:

over configurations with k or fewer #s #RSk – the language family generated by

#RSs of index k

Example: Index k = 2: 1. (p, a#a#b) (q, aa#aa#b) [p1# qa#a R]

OKOK 2. (p, a#a#b) (q, a#aa##bb) [p2# qa##b R]

INCORRECTINCORRECT

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Example: #RS of finite index

(s, #) (p, ##) [1] (q, a#b#) [2] (p, a#bc#) [3] (f, aabbc#) [4] (f, aabbcc) [5]

L(H) = {anbncn: n 1} #RS2

#RS H: H accepts aabbcc:

H is of index 2.

[1]. s 1# p ##[2]. p 1# q a#b[3]. q 2# p #c[4]. p 1# f ab[5]. f 1# f c

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Main Result: An Infinite Hierarchy

Theorem: #RSk #RSk+1, for all k 1.

Proof:makes use of programmed grammars (PG) of index k

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Proof: Programmed GrammarsProgrammed Grammar (PG) is a modification of context-free grammar based on the rules of the form:

r: A x, Wr

• r: A x is a context-free rule labeled by r,• Wrfinite set of rule labels

Derivation step (): after the application of rule r,

a rule from Wr has to be applied

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Proof: Finite index of PG

Programmed grammars of index k: over sentential forms with k or fewer

occurrences of nonterminals.

Pk – the language family defined by programmed grammars of index k

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Example: PG

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S [1]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] [2]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] [3]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] aAbBC [3]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] aAbBC [3] [4]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] aAbBC [3] aAbBcC [4]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] aAbBC [3] aAbBcC [4] [5]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] aAbBC [3] aAbBcC [4] aabBcC [5]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] aAbBC [3] aAbBcC [4] aabBcC [5] [6]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] aAbBC [3] aAbBcC [4] aabBcC [5] aabbcC [6]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] aAbBC [3] aAbBcC [4] aabBcC [5] aabbcC [6] aabbcc [7]

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Example: PG

S ABC [1] aABC [2] aAbBC [3] aAbBcC [4] aabBcC [5] aabbcC [6] aabbcc [7]

L(G) = {anbncn: n 1} P3

PG G:1: S ABC, {2, 5}2: A aA, {3}3: B bB, {4}4: C cC, {2, 5}5: A a, {6}6: B b, {7}7: C c,

G generates aabbcc:

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Proof: Pk = #RSk , k 1

aAbBc G adXYbBc [p: A dXY, {q, o}] G … [q]

as

(AB, p, a#b#c) H (XYB, q, ad##b#c) [AB, p 1# XYB, q d##]

Pk #RSk:Let G be a PG of index k. Construct a #RS H of

index k, so H simulates derivation step

Pk #RSk:

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Proof: #RSk = Pk , k 1

(p, a#b#c) H (q, aa#bb#c) [p1# q a#b]as ap, 1, 2bp, 2, 2c

G aq, 1, 2bp, 2, 2cG aq, 1, 2bq, 2, 2cG aaq, 1, 2bbq, 2, 2cG aaq, 1, 2bbq, 2, 2cG aaq, 1, 2bbq, 2, 2c

1) Renumbering:

2) Rewriting:3) Finalization:

#RSk Pk:Let H be a #RS of index k. Construct a PG G of

index k, so G simulates a computational step

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Proof: #RSk #RSk+1, k 1

Theorem: #RSk #RSk+1, for all k 1.

Recall that:• Pk Pk+1, for all k 1

As Pk = #RSk, for all k 1, we have

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Future Investigation• Determinism• Unlimited index• Other variants:

• Right-linear• Context-sensitive• Parallel

DiscussionDiscussion