12.4 – standard deviation

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12.4 – Standard Deviation

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12.4 – Standard Deviation. Measures of Variation. The range of a set of data is the difference between the greatest and least values. The interquartile range is the difference between the third and first quartiles. median Find the median. - PowerPoint PPT Presentation

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Page 1: 12.4 – Standard Deviation

12.4 – Standard Deviation

Page 2: 12.4 – Standard Deviation

Measures of Variation

The range of a set of data is the difference between the greatest and least values.

The interquartile range is the difference between the third and first quartiles

Page 3: 12.4 – Standard Deviation

There are 9 members of the Community Youth Leadership Board.

Find the range and interquartile range of their ages: 22, 16, 24, 17,

16, 25, 20, 19, 26.

greatest value – least value = 26 – 16 Find the range.

= 10

Q3 – Q1 = 24.5 – 16.5 Find the interquartile range.= 8

The range is 10 years. The interquartile range is 8 years.

median Find the median.

16 16 17 19 20 22 24 25 26

Q1 = = 16.5     Q3 = = 24.5 Find Q1 and Q3.(16 + 17)

2(24 + 25)

2

Example

Page 4: 12.4 – Standard Deviation

More Measures of Variation

Standard deviation is a measure of how each value in a data set varies or deviates from the mean

Page 5: 12.4 – Standard Deviation

2. Find the difference between each value and the mean:

3. Square the difference:

5. Take the square root to find the standard deviation

4. Find the average (mean) of these squares:

1. Find the mean of the set of data:

Steps to Finding Standard Deviation

x

xx 2)( xx

n

xx 2)(

n

xx 2)(

Page 6: 12.4 – Standard Deviation

Standard Deviation

Find the mean and the standard deviation for the values 78.2, 90.5,

98.1, 93.7, 94.5.

The mean is 91, and the standard deviation is about 6.8.

234.045

= 6.8

= = 91   Find the mean.(78.2 + 90.5 + 98.1 +93.7 +94.5)5

x

= Find the standard deviation.

(x – x)2

n

Organize the nextsteps in a table.78.2 91 –12.8 163.84

90.5 91 –0.5 .2598.1 91 7.1 50.4193.7 91 2.7 7.2994.5 91 3.5 12.25

x

x

x – x

(x – x)2

Page 7: 12.4 – Standard Deviation

Let’s Try One – No Calculator!

Find the mean and the standard deviation for the values 9, 4, 5, 6

  Find the mean. x

= Find the standard deviation.

(x – x)2

n

Organize the nextsteps in a table.

x

x

x – x

(x – x)2

Page 8: 12.4 – Standard Deviation

Let’s Try One – No Calculator

Find the mean and the standard deviation for the values 9, 4, 5, 6

The mean is 6, and the standard deviation is about 1.87.

= = 6  Find the mean.(9+4+5+6)4

x

= Find the standard deviation.

(x – x)2

n

Organize the nextsteps in a table.9 6 3 9

4 6 -2 45 6 -1 16 6 0 0

sum 14

x

x

x – x

(x – x)2

87.12

14

4

56

4

4

4

14

Page 9: 12.4 – Standard Deviation

More Measures of Variation

Z-Score: The Z-Score is the number of standard deviations that a value is from the mean.

Page 10: 12.4 – Standard Deviation

A set of values has a mean of 22 and a standard deviation of 3. Find the

z-score for a value of 24.

Z-Score

= 0.6

= Simplify.23

= Substitute.24 – 22

3

z-score = value – mean standard deviation

Page 11: 12.4 – Standard Deviation

A set of values has a mean of 34 and a standard deviation of 4. Find the

z-score for a value of 26.

Z-Score

= -2

= Simplify.-84

= Substitute.26 – 34

4

z-score = value – mean standard deviation

Page 12: 12.4 – Standard Deviation

Standard DeviationUse the data to find the mean and standard deviation for daily

energy demands on the weekends only.

Step 1: Use the STAT feature to enter the data as L1.

S M T W Th F S53 52 47 47 50 39

33 40 41 44 47 49 4339 47 49 54 53 46 3633 45 45 42 43 39 3333 40 40 41 42

Step 2: Use the CALC menu of STAT to access the 1-Var Stats option.

The mean is about 36.1 MWh;

The mean is x.

the standard deviation is about 3.6 MWh.

The standarddeviation is x.