12 nvla physics ii
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SECOND TERMINAL EXAMINATION-2011
ANSWER KEY- PHYSICS II
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1 a) Statement of coulombs law of electrostatics 1
b) No. The least charge is 1.6 x 10-19 C. Explanation of Quantization
of electric charge ( Q = ne) 1
c)
The forces excerted by the charges 5micro coulomb on C are equal and
is given by NFF BA 09.05
105105109 669=
==
These are resolved by vertical and horizondal components. Vertical are
cancel out.
Total force = NFFF ABA 161.0
5
209.02cos2coscos ===+
along CX 2 4
2 a)
R=10+6.6+10=26.6W 2
b) Total resistance = 1.6 + 3.4 = 5 ohm
I = V/ R = 5 / 5 = 1 A and V = IR = 1 x 1.6 = 1.6 v 2 4
3 a) Statement of Biot - Savart law 1
b) Derivation 2 3
4 a) Declination , dip and horizontal component of earths
magnetic field and its explanation 3
b) Explanation of dia , para and ferromagnetic substances 2
c) Sodium. ( Sodium is Para magnetic and the remaining all are diamagnetic ) 1 6
B(5mc)
B`
A`
Xqq
q q
A(5mc)
5 m
5 m
C2m
10W 10W
10W
10W
10W
10W 10W
10W10W 10W
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5 a) Explanation of eddy current 1
b) In speedometer, a small magnet rotates in an aluminum drum and
produces a magnetic field. Rotating magnet produces eddy current in
the drum, drum turns in the direction of rotating field.
A pointer attached to the drum indicates the speed 1 2
6 a) Explanation of Watt less current 2
b) Phasor diagram of LCR and derivation of power 3
c) E = - L dI / dt = -2 x 10 -3 x -1 / 10 -3 = 2V 1 6
7 Davison Germer experiment wave nature l= h / mv
Twinkling of stars Refraction = sin I / sin r
Alpha particle experiment distance of closest approach Rutherford
Blue colour of the sky Scattering Rayleigh 8 X 1/2
4
8 (a) UV ray (b) microwaves (c) Infrared (d) visible light 4 X 1/2
2
9 a) Ray diagram + Explanation 2
b) Explanation least distance distinct vision 1 3
10 a) Explanation coherent sources 1
b) No. The phase of waves emitted from them will be changing independent
of each other. Hence the phase difference between two independent
sources cannot be constant with time. 1
c) Derivation of band width 2
d) I1 /
I2
= (a1/ a
2)2 = 81 / 1 , a
1: a
2= 9 ; 1
a1= 9a
2
Imax
/ Imin
= (a1
+ a2
)2 /(a1
- a2
)2 = ( 9a2
+ a2
)2 / ( 9a2
- a2
)2 = 25 / 16 2 6
11 a) Diagram + Derivation 3
b) I1= 0 , r
1= 0 n = 1.52 and i
2= 90
n = sin i2/ sinr
2
r2= 4108 and A = r
1+ r
2= 0 + 4108=4108 2 5
ll
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12 a) Statement 4 X 1/2
b) Derivation 2
c) Threshold wavelength = hc / 0
=6.62 x 10-34 x 3 x 108 / 4.4 x 1.6 x 10-19 = 2821A0
The wavelength of light is greater than threshold wavelength and
it cannot eject electrons from copper 2 6
13 a) N / N0= (1/2) t/T
N / N0= (1/2) 25/12.5 = (1/2) 2 = 1/4 2 2
14 a) Postulates 2
b) Explanation + formula 2
c) Energy level diagram 2 6