11.6 –areas of regular polygons
DESCRIPTION
11.6 –Areas of Regular Polygons. Center of a polygon:. Point equidistant to the vertices of the of the polygon. P. Radius of a polygon:. Length from the center to the vertex of a polygon. Apothem of the polygon:. Length from the center to the side of a polygon. - PowerPoint PPT PresentationTRANSCRIPT
![Page 1: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/1.jpg)
11.6 –Areas of Regular Polygons
![Page 2: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/2.jpg)
Center of a polygon:
Point equidistant to the vertices of the of the polygon
P
![Page 3: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/3.jpg)
Radius of a polygon:
Length from the center to the vertex of a polygon
PM
PN
![Page 4: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/4.jpg)
Apothem of the polygon:
Length from the center to the side of a polygon
PQ
![Page 5: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/5.jpg)
Central angle of a regular polygon:
Angle formed by two radii in a polygon
MPN360
n
![Page 6: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/6.jpg)
1. Find the measure of a central angle of a regular polygon with the given number of sides. Round answers to the nearest tenth of a degree if necessary.
6 sides
360
n3606
60°
60°
![Page 7: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/7.jpg)
1. Find the measure of a central angle of a regular polygon with the given number of sides. Round answers to the nearest tenth of a degree if necessary.
12 sides
360
n 36012
30°
![Page 8: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/8.jpg)
1. Find the measure of a central angle of a regular polygon with the given number of sides. Round answers to the nearest tenth of a degree if necessary.
40 sides
360
n360
40 9°
![Page 9: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/9.jpg)
1. Find the measure of a central angle of a regular polygon with the given number of sides. Round answers to the nearest tenth of a degree if necessary.
21 sides
360
n360
21 17.1°
![Page 10: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/10.jpg)
2. Find the given angle measure for the regular hexagon shown.
Each central angle =
360
n360
6 60°
mEGF = 60°
60°
mEGD = 60°
![Page 11: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/11.jpg)
2. Find the given angle measure for the regular hexagon shown.
mEGH = 30°
60°30°
![Page 12: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/12.jpg)
2. Find the given angle measure for the regular hexagon shown.
mDGH = 30°
60°30°30°
![Page 13: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/13.jpg)
2. Find the given angle measure for the regular hexagon shown.
mGHD = 90°
![Page 14: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/14.jpg)
1
2A san
Area of a regular polygon:
s = side length
a = apothem length
n = number of sides
![Page 15: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/15.jpg)
3. A regular pentagon has a side length of 8in and an apothem length of 5.5in. Find the area.
1
2A san
1(8)(5.5)(5)2
A
(4)(27.5)A
2110A in
![Page 16: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/16.jpg)
4. Find the area of the polygon.
42 = a2 + 22
16 = a2 + 412 = a2
2 3 a 2 3
1
2A san
1(4)(2 3)(6)2
A
(2)(12 3)A
224 3A in Apothem = _____________
A = ____________________
2 3in224 3in
![Page 17: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/17.jpg)
5. Find the area of the polygon.
c2 = a2 + b2
6.82 = a2 + 42
30.24 = a2
1
2A san
1(8)(5.5)(5)2
A
(4)(27.5)A
2110A in
5.5 = a
5.5
Apothem = _____________
A = ____________________2110in
5.5in
46.24 = a2 + 16
![Page 18: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/18.jpg)
mACB = _______
12cm 12cm
360
n360
3120°
120°
60°60°
24cm
Apothem = ___________
A = __________________
6. Find the area of the polygon.
30°
![Page 19: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/19.jpg)
6. Find the area of the polygon.
30° 60° 90°
1 3
12
3a
3 12a
a 12 H
3
3
12 3
3
2
12cm 12cm
4 3
4 3
mACB = _______120°
Apothem = ___________
A = __________________
30°
4 3cm
![Page 20: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/20.jpg)
1
2A san
1(24)(4 3)(3)2
A
(12)(12 3)A
2144 3A cm
6. Find the area of the polygon.
4 3
12cm 12cm
mACB = _______120°
Apothem = ___________
A = __________________
4 3cm
2144 3cm
![Page 21: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/21.jpg)
360
n360
6 60°
30°
5m
7. Find the area of the polygon.
5m
mACB = _______60°
Apothem = ___________
A = __________________
60°
![Page 22: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/22.jpg)
7. Find the area of the polygon.
30° 60° 90°
1 3
5 3a
5 a H
230°
5m5m
5 3
5 3mmACB = _______60°
Apothem = ___________
A = __________________
60°
![Page 23: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/23.jpg)
1
2A san
1(10)(5 3)(6)2
A
(5)(30 3)A
260 3A m
7. Find the area of the polygon.
30°
5m5m
5 3
5 3mmACB = _______60°
Apothem = ___________
A = __________________260 3m
![Page 24: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/24.jpg)
360
n360
5 72°
36°
8. Find the area of the polygon.
mACB = _______72°
Side Length = ________
A = __________________
![Page 25: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/25.jpg)
36°
SOH – CAH – TOA
tan 3622
x
1
22 tan36 x
= x 15.98 15.9815.98O
AH
8. Find the area of the polygon.
mACB = _______72°
Side Length = ________
A = __________________
31.96cm
![Page 26: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/26.jpg)
1
2A san
1(31.96)(22)(5)2
A
21757.8A cm
36°
15.9815.98O
AH
8. Find the area of the polygon.
mACB = _______72°
Side Length = ________
A = __________________
31.96cm
21757.8cm
![Page 27: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/27.jpg)
360
n360
8 45°
45°
22.5°
9. Find the area of the polygon.
mACB = __________
Apothem = __________
Side Length = ________
A = __________________
![Page 28: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/28.jpg)
22.5°
SOH – CAH – TOA
cos 22.56
a
1
6cos 22.5 a
= a 5.545.54
O
AH
sin 22.56
x
1
6sin 22.5 x
= x 2.3
9. Find the area of the polygon.
mACB = __________
Apothem = __________
Side Length = ________
A = __________________
45°5.54in
4.6in
2.3 2.3
![Page 29: 11.6 –Areas of Regular Polygons](https://reader036.vdocuments.us/reader036/viewer/2022062809/5681573e550346895dc4e352/html5/thumbnails/29.jpg)
1
2A san
1(4.6)(5.54)(8)2
A
2101.94A in
22.5°
5.54
O
AH
2.3 2.3
9. Find the area of the polygon.
mACB = __________
Apothem = __________
Side Length = ________
A = __________________
45°5.54in
4.6in2101.94in