1.0 modul super score kertas 1 set 1 (1)
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MODUL SUPER SCORE SBP 2014
©Panel Perunding Mata Pelajaran Matematik Tambahan, Page 1
KERTAS 1 SET 1
NAMA : MARKAH TARIKH :
Answer all questions. Jawab semua soalan.
1. The diagram shows the relation between set X and set Y.
Rajah menunjukkan hubungan di antara set X dan set Y. State /Nyatakan (a) The range of the relation
Julat hubungan itu (b) The value of x
Nilai x [2 marks]
[2 markah] Answer / Jawapan :
2. Given the function g : x → 5−x . Find the values of x if g(x) = 4. [2 marks]
Diberi fungsi g : x → 5−x . Cari nilai-nilai x jika g(x) = 4. [2 markah] Answer / Jawapan :
For examiner’s
use only
2
2
2
1
x g(x)
– 4
x
1
4 6
3
2
– 2
x
Set X Set Y
MODUL SUPER SCORE SBP 2014
©Panel Perunding Mata Pelajaran Matematik Tambahan, Page 2
3. Given the functions f(x) = 4x – m and 169)(1 +=− kxxf , where k and m are constants. Find the
values of k and m. [3 marks]
Diberi fungsi f(x) = 4x – m dan 169)(1 +=− kxxf , dimana k dan m adalah pemalar. Cari nilai-
nilai bagi k dan m. [3 markah]
Answer / Jawapan : 4. Diagram shows a graph of a quadratic function f(x) = ‒2(x + h)2 ‒ 2 where k is a constant.
Rajah menunjukkan graf fungsi kuadratik f(x) = ‒2(x + h)2 ‒ 2 dimana k ialah pemalar.
Find Cari (a) the value of k
nilai k
(b) the value of h nilai h
(c) the equation of axis of symmetry. persamaan bagi paksi simetri.
[3 marks] [3 markah]
Answer / Jawapan :
For examiner’s
use only
3
3
3
4
x 0 (-3, k) •
f(x) = −2(x + h)2 − 2
y
MODUL SUPER SCORE SBP 2014
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5. Find the values of p if the quadratic function f(x) = 2x2 + 2px – (p + 1) has a minimum value of – 5 [3 marks] Cari nilai-nilai bagi p jika fungsi kuadratik f(x) = 2x2 + 2px – (p + 1) mempunyai nilai minimum – 5
[3 markah] Answer / Jawapan :
6. Find the range of values of x for xx 624)4( 2 −<− [2 marks]
Cari julat nilai x bagi xx 624)4( 2 −<− [2 markah]
Answer / Jawapan :
For examiner’s
use only
2
6
3
5
MODUL SUPER SCORE SBP 2014
©Panel Perunding Mata Pelajaran Matematik Tambahan, Page 4
7. One of the roots of the quadratic equation 032 2 =−− kxx is – 4. Find the value of k.
[2 marks] Satu dari punca persamaan kuadratik 032 2 =−− kxx ialah – 4. Cari nilai k. [2 markah]
Answer / Jawapan :
8. One of the roots of the equation 3x2 – 6x + p = 0 is three times the other root , find the possible
values of p. [3 marks] Salah satu punca bagi persamaan 3x2 – 6x + p = 0 adalah tiga kali punca yang satu lagi, cari nilai yang mungkin bagi p. [3 markah] Answer / Jawapan :
3
8
2
7
For examiner’s
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MODUL SUPER SCORE SBP 2014
©Panel Perunding Mata Pelajaran Matematik Tambahan, Page 5
9. Solve the equation 06216 42 =− +− xx . [3 marks] Selesaikan persamaan 06216 42 =− +− xx [3 markah]
Answer / Jawapan :
10. Solve the equation 2x • 5x +2 = 25000. [3 marks] Selesaikan persamaan 2x • 5x +2 = 25000. [3 markah]
Answer / Jawapan :
3
9
3
10
For examiner’s
use only
MODUL SUPER SCORE SBP 2014
©Panel Perunding Mata Pelajaran Matematik Tambahan, Page 6
11. Solve the equation log2 (x – 3) = log2 4x + 1 [3 marks]
Selesaikan persamaan log2 (x – 3) = log2 4x + 1 [3 markah]
Answer / Jawapan : 12. Given that log2 x = m and log2 y = n. Express log4 (xy2) in terms of m and n. [3 marks]
Diberi log2 x = m dan log2 y = n. Nyatakan log4 (xy2) dalam sebutan m dan n. [3 markah]
Answer / Jawapan : lum
3
11
4
12
For examiner’s
use only
MODUL SUPER SCORE SBP 2014
©Panel Perunding Mata Pelajaran Matematik Tambahan, Page 7
13. Find the sum to infinity of the geometric progression 20, 10, 5, ... [2 marks] Cari hasil tambah ketakterhinggaan janjang geometri 20, 10, 5, ... [2 markah]
Answer / Jawapan :
14. Given a geometric progression has the first term and the sum to infinity are 25 and 62.5
respectively. Find the common ratio of the progression. [2 marks] Diberi satu janjang geometri mempunyai sebutan pertama dan hasil tambah hingga ketakterhinggaan adalah 25 dan 62.5 masing-masing. Cari nisbah sepunya bagi janjang tersebut. [2 markah]
Answer / Jawapan :
2
14
2
13
For examiner’s
use only
MODUL SUPER SCORE SBP 2014
©Panel Perunding Mata Pelajaran Matematik Tambahan, Page 8
15. Write 0.01010101... as a single fraction in the lowest terms. [3 marks]
Tulis 0.0101010... sebagai satu pecahan tunggal dalam sebutan terendah. [3 markah]
Answer / Jawapan :
16. The diagram below shows two vectors OP and OQ .
Rajah di bawah menunjukkan dua buah vektor OP dan OQ .
Express Ungkapkan
(a) OP in the form ⎟⎟⎠
⎞⎜⎜⎝
⎛
yx
.
OP dalam bentuk ⎟⎟⎠
⎞⎜⎜⎝
⎛
yx
.
(b) PQ in the form jyix ~~ +
PQ dalam bentuk jyix ~~ + [4 marks]
[4 markah] Answer / Jawapan :
3
15
4
16
For examiner’s
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P(– 2 , 5)
Q(4 , – 3 )
x
y
MODUL SUPER SCORE SBP 2014
©Panel Perunding Mata Pelajaran Matematik Tambahan, Page 9
17. Given ⎟⎟⎠
⎞⎜⎜⎝
⎛
−=
34
h , ⎟⎟⎠
⎞⎜⎜⎝
⎛−=
02
k and ⎟⎟⎠
⎞⎜⎜⎝
⎛=+m
kha6
, find the values of a and m. [3 marks]
Diberi ⎟⎟⎠
⎞⎜⎜⎝
⎛
−=
34
h , ⎟⎟⎠
⎞⎜⎜⎝
⎛−=
02
k dan ⎟⎟⎠
⎞⎜⎜⎝
⎛=+m
kha6
, cari nilai bagi a dan m. [3 markah]
Answer / Jawapan :
18. Points A, B and C are collinear. It is given that 6 4AB a b= −
uuur
% % and 4 (2 )BC a k b= + +
uuur
% %, where k is
a constant. Find Titik A, B dan C adalah segaris. Diberi bahawa 6 4AB a b= −
uuur
% %dan 4 (2 )BC a k b= + +
uuur
% %, dengan
keadaan k adalah pemalar. Cari (a) the value of k
nilai k
(b) the ratio AB : BC nisbah AB : BC
[4 marks] [4 markah]
Answer / Jawapan :
3
17
4
18
For examiner’s
use only
MODUL SUPER SCORE SBP 2014
©Panel Perunding Mata Pelajaran Matematik Tambahan, Page 10
Jawapan/Answer : No Answer
1 (a) {– 2, 2, 3, 6} (b) x = 0
2 x = 1, x = 9
3 k = 41
, m = 49
4 (a) k = – 2 (b) h = 3 (c) x = – 3
5 – 4, 2 6 42 <<− x 7 k = 44
8 21
=α , 49
=p
9 x = 5 10 x = 3
11 x = 73
−
12 2
2 mn +
13 40 14 0.6
15 991
16 (a) ⎟⎟
⎠
⎞⎜⎜⎝
⎛−
52
(b) ~~86 ji−
17 a = 2 , m = – 6
18 (a) k = 3
14−
(b) AB : BC = 3 : 2