1 resonance and formal charge. 2 resonance and formal charge: at the conclusion of our time...
TRANSCRIPT
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Resonance and Formal Charge
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Resonance and Formal Resonance and Formal Charge:Charge:
At the conclusion of our time At the conclusion of our time together, you should be able to:together, you should be able to:
1. Define resonance2. Determine resonance structures for a
molecule3. Calculate the formal charge for an
atom4. Determine the resonance structure that
contributes the most to a compound by using formal charge
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SAMPLE PROBLEM: Writing Resonance Structures
PLAN:
SOLUTION:
PROBLEM: Write resonance structures for the nitrate ion, NO3
-.
After Steps 1-4, go to 5 and then see if other structures can be drawn in which the electrons can be delocalized over more than two atoms.
Nitrate has 1(5) + 3(6) + 1 = 24 valence e-
N
O
O O
N
O
O O
N
O
O O
N does not have an octet; a pair of e- will move in to form a double bond.
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N
O
O O
N
O
O O
N
O
O O
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1. Smaller formal charges (either positive or negative) are preferable to larger charges;
2. A more negative formal charge should exist on an atom with a larger EN value.
3. Get unlike charges as close together as possible
4. Avoid like charges (+ + or - - ) on adjacent atoms
Four criteria for choosing the more important resonance structure:
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Resonance and Formal Charge
Formal charge of atom =
# valence e- =
(# unshared electrons +
1/2 the # shared electrons)
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Nitric acidNitric acidNitric acidNitric acid
.... ::
....HH OO
OO
OO
NN
::
::....
....
► We will calculate the formal charge for We will calculate the formal charge for each atom in this Lewis structure.each atom in this Lewis structure.
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Nitric acidNitric acidNitric acidNitric acid
.... ::
....HH OO
OO
OO
NN
::
::....
....
► Hydrogen shares 2 electrons with oxygen.Hydrogen shares 2 electrons with oxygen.► Assign 1 electron to H and 1 to O.Assign 1 electron to H and 1 to O.► A neutral hydrogen atom has 1 electron.A neutral hydrogen atom has 1 electron.► Therefore, the formal charge of H in nitric Therefore, the formal charge of H in nitric
acid is 0.acid is 0.
Formal charge of HFormal charge of H
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Nitric acidNitric acidNitric acidNitric acid
.... ::
....HH OO
OO
OO
NN
::
::....
....
► Oxygen has 4 electrons in covalent bonds.Oxygen has 4 electrons in covalent bonds.► Assign 2 of these 4 electrons to O.Assign 2 of these 4 electrons to O.► Oxygen has 2 unshared pairs. Assign all 4 Oxygen has 2 unshared pairs. Assign all 4
of these electrons to O.of these electrons to O.► Therefore, the total number of electrons Therefore, the total number of electrons
assigned to O is 2 + 4 = 6.assigned to O is 2 + 4 = 6.
Formal charge of OFormal charge of O
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Nitric acidNitric acidNitric acidNitric acid
.... ::
....HH OO
OO
OO
NN
::
::....
....
► Electron count of O is 6.Electron count of O is 6.► A neutral oxygen has 6 electrons.A neutral oxygen has 6 electrons.► Therefore, the formal charge of oxygen Therefore, the formal charge of oxygen
is 0.is 0.
Formal charge of OFormal charge of O
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Nitric acidNitric acidNitric acidNitric acid
.... ::
....HH OO
OO
OO
NN
::
::....
....
► Electron count of O is 6 (4 electrons from Electron count of O is 6 (4 electrons from unshared pairs + half of 4 bonded electrons).unshared pairs + half of 4 bonded electrons).
► A neutral oxygen has 6 electrons.A neutral oxygen has 6 electrons.► Therefore, the formal charge of oxygen is 0.Therefore, the formal charge of oxygen is 0.
Formal charge of OFormal charge of O
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Nitric acidNitric acidNitric acidNitric acid
.... ::
....HH OO
OO
OO
NN
::
::....
....
► Electron count of O is 7 (6 electrons from Electron count of O is 7 (6 electrons from unshared pairs + half of 2 bonded electrons).unshared pairs + half of 2 bonded electrons).
► A neutral oxygen has 6 electrons.A neutral oxygen has 6 electrons.► Therefore, the formal charge of oxygen is -1.Therefore, the formal charge of oxygen is -1.
Formal charge of OFormal charge of O
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Nitric acidNitric acidNitric acidNitric acid
.... ::
....HH OO
OO
OO
NN
::
::....
....
► Electron count of N is 4 (half of 8 Electron count of N is 4 (half of 8 electrons in covalent bonds).electrons in covalent bonds).
► A neutral nitrogen has 5 electrons.A neutral nitrogen has 5 electrons.► Therefore, the formal charge of N is +1.Therefore, the formal charge of N is +1.
Formal charge of NFormal charge of N
––
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Nitric acidNitric acidNitric acidNitric acid
.... ::
....HH OO
OO
OO
NN
::
::....
....
► A Lewis structure is not complete unless A Lewis structure is not complete unless formal charges (if any) are shown.formal charges (if any) are shown.
Formal chargesFormal charges
––
++
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Formal ChargeFormal ChargeFormal ChargeFormal Charge
Formal charge = Formal charge =
Number of Number of
valencevalence
electronselectrons
number ofnumber ofbondsbonds
number ofnumber ofunshared electronsunshared electrons
–– ––
An arithmetic formula for calculating formal charge.An arithmetic formula for calculating formal charge.
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––
"Electron Counts""Electron Counts" and Formal and Formal Charges in NHCharges in NH44
+ + and BFand BF44--
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44
NN
HH
HH HH
HH
++77
44
....
BBFF
FF
FF
FF
....
............:: ::
:: ::
:: ::
....
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Formal Charge: Selecting the Best Resonance Structure
An atom “owns” all of its nonbonding electrons and half of its bonding electrons.
Formal charge of atom =
# valence e-
- # unshared electrons
- 1/2 # shared electrons
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OO O
A
B
CFor OA # valence e- = 6
# nonbonding e- = 4
# bonding e- = 4 X 1/2 = 2
Formal charge = 0
For OB
# valence e- = 6
# nonbonding e- = 2
# bonding e- = 6 X 1/2 = 3
Formal charge = +1For OC
# valence e- = 6
# nonbonding e- = 6
# bonding e- = 2 X 1/2 = 1
Formal charge = -1
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EXAMPLE: NCO- has 3 possible resonance forms -
Resonance and Formal Charge
N C O
A
N C O
B
N C O
C
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N C O N C O N C O
Now Determine Formal Charges
-2 0 +1 -1 0 0 0 0 -1
Forms B and C have smaller formal charges; this makes them more important than form A. (rule 1)
Form C has a negative charge on O which is the more electronegative element, therefore C contributes the most to the resonance hybrid. (rule 2)
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Exceptions to the Octet Rule
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Exceptions to the Octet RuleExceptions to the Octet Rule
► 4b. Expanded Octets – only on period 3 and 4b. Expanded Octets – only on period 3 and higher higher
Expanded octets form when an atom can Expanded octets form when an atom can decrease (or maintain at 0) it’s formal chargedecrease (or maintain at 0) it’s formal charge
Ex: SFEx: SF66, PCl, PCl55, SO, SO22, SO, SO33, SO, SO44
► 5a. Electron deficient – have fewer than 85a. Electron deficient – have fewer than 8 Ex: BeClEx: BeCl22, BF, BF33 may attain an octet by coordinate covalent bondmay attain an octet by coordinate covalent bond
► Odd number of electrons – aka free radicalsOdd number of electrons – aka free radicals Ex: NOEx: NO22 May attain an octet by pairing with another free May attain an octet by pairing with another free
radicalradical
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SAMPLE PROBLEM: Writing Lewis Structures for Exceptions to the Octet Rule.
PLAN:
SOLUTION:
PROBLEM: Write the Lewis structure for BFCl2.
Draw the Lewis structures for the molecule and determine if there is an element which can be an exception to the octet rule.
BFCl2 will have only 1 Lewis structure.
F
BCl Cl
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Resonance and Formal Resonance and Formal Charge:Charge:
Let’s see if you can:Let’s see if you can:
1. Define resonance2. Determine resonance structures for a
molecule3. Calculate the formal charge for an
atom4. Determine the resonance structure that
contributes the most to a compound by using formal charge
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Now determine the formal charges and best structure for the 2 examples at the bottom of page 11.
Your Turn
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Now determine the formal charges and best structure for the middle example on page 12.
Your Turn
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N
O
O O
N
O
O O
N
O
O O
1
-1
0
-1
1 1
-1
-1
00
-1
-1
Is there a better structure??
No!!
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