1 molecular oxygen from a group theoretical point of view · 2020-05-15 · instead of...
TRANSCRIPT
Physical Chemistry V Exercise V 1 May 2020
1 Molecular oxygen from a group theoretical point of view
In the �rst question of Exercise Set 4 we already looked at the electronic structure of O2. In this
exercise, we will use molecular group theory to obtain the allowed states for the two energetically
lowest-lying electronic con�gurations and their corresponding term symbols. Please note that
you can �nd character tables and direct product tables at http://www.webqc.org or in most
textbooks on spectroscopy.
(a) List all symmetry elements for O2 and determine the corresponding point group.*
(b) Derive the transformation properties of the 2p orbitals of O2. To do so, draw vectors
(x, y, z) on each oxygen atom. Set up matrices which represent the symmetry operations
of the group. Determine the character χ(Ai) of each symmetry operation Ai.��
(c) Through inspection of the character table of the point group, express the reducible rep-
resentation determined in part (b) as a combination of irreducible representations.
(d) With the obtained information construct the orbital diagram for p orbitals (compare with
Exercise 4), �ll in the electrons corresponding to the most stable con�guration and deduce
the term symbols. To obtain the term symbols of the states you have to multiply the
characters of the irreducible representations that represent the partially �lled molecular
orbitals. Then use inspection to reduce this reducible representation into irreducible
representation, which gives you the required term symbols.
(e) Using equation (4.36) from your notes, show why the 3Σ−u ← 3Σ−g transition is electroni-
cally allowed and the 1∆g← 3Σ−g transition is electronically forbidden with light polarized
parallel to the molecular axis (i.e. you only have to look at the parallel component of the
dipole moment).
2 Vibrations of BrF5
Group theory of molecules gives an easy access to the concept of normal modes and a descriptive
picture of molecular vibrations. In this task the normal modes of BrF5 in square pyramidal
geometry will be analysed.
*We use �symmetry element� as used e.g. in Bishop, Group Theory and Chemistry and Bunker, Jensen,Fundamentals of Molecular Symmetry. To quote Bishop: �The symmetry operation is an action, the symmetryelement is a geometrical quantity (a point, a line or a plane) about which an action takes place. A symmetryelement is e.g the C3 rotation axis in NCl3 which has two symmetry operations: clockwise rotation by 2π/3and clockwise rotation by 4π/3. The symmetry operations form the group, but the symmetry elements alreadydetermine the group.
�The character is given by the trace of the matrix, which is the sum of its diagonal elements.�The character for the rotations along the C∞ symmetry element (which you hopefully found) is a function
of the rotation angle ϕ. All members of a class in a character table have the same character for a givenrepresentation. Note that a class is composed of conjugate elements of the group (check what that means). Tofully introduce the confusing terminology, note that the elements of the group are the symmetry operations butthe classes of the group are equivalent to the symmetry elements of the molecule.
1 / 4
Physical Chemistry V Exercise V 1 May 2020
(a) List the seven symmetry elements of BrF5.
(b) What is the point group of BrF5?
(c) How many nuclear degrees of freedom does BrF5 have in total?
(d) Derive the characters of the reducible representation for all degrees of freedom, Γtot
(e) What are the irreducible representations corresponding to rotation and translation?
(f) Derive the representation of all vibrations Γvib. Using the reduction formula below, derive
the irreducible representation (i.e. the symmetry) of all individual vibrational modes,
al =1
h
∑c
g(c)χ(l)(c)∗χ(c), (1)
where al is the multiplicity of irrep l, c is the class index, h is the group order, χ(l)(c)∗ is
the character of class c in irrep l, χ(c) is the character of the reducible representation of
class c and g(c) is the number of symmetry operations in a class c.
(g) Consider the symmetries of vibrational modes you obtained. Which of them are IR active,
and which are Raman active?
3 Hückel MO treatment of Cyclobutadiene
In this task, we will determine the energy levels of cyclobutadiene using the Hückel MO method.
The HMO model represents a simple semiempirical method to calculate the electronic energy
level structure of molecules that exhibit conjugated π molecular orbitals such as polyenes and
aromatic molecules. The model is useful to gain a semi-quantitative description of the π
molecular orbitals and their relative energies and is widely used in physical-organic chemistry.
Instead of diagonalising the Hückel Hamiltonian He� directly, we will build from the relevant
atomic orbitals a set of symmetry-adapted molecular orbitals. This will allow us to build the
molecular orbital diagram of cyclobutadiene and determine the energy levels associated with
the ground state con�gurations along with their symmetry. We consider the π-system which
spans all carbon atoms.
Figure 1: Structure of cyclobutadiene ([4]annulene).
2 / 4
Physical Chemistry V Exercise V 1 May 2020
(a) List all symmetry elements of cyclobutadiene in a square-shaped nuclear con�guration.
Which point group does it belong to?
(b) In a Hückel-MO picture one assumes that the valence orbitals are given by the π-bonding
and -antibonding orbitals. Which orbitals contribute to the π-system of the molecule?
(c) These orbitals form a basis {φi} for the Hückel Hamiltonian
He� =
α β 0 β
β α β 0
0 β α β
β 0 β α
Name and explain the approximations that were used to set up this Hamiltonian.
(d) Determine the reducible representation of the π molecular orbitals (Γπ) by applying the
symmetry operations of the associated point group to this basis set. Decompose the re-
ducible representation into irreducible representations by applying the reduction formula
(Eq. (1)).
(e) Now we construct a new, symmetry-adapted orthonormal basis set {ψr} by applying the
projection operator
P (l) =dlh
∑R
χ(l)(R)∗R (2)
to the appropriate basis functions of the original set of basis functions. Here, h is the
group order, dl is the dimension of the irreducible representation l and χ(l)(R) is the
character of operation R for the irreducible representation l.
Hint: For the derivation of the new set of basis functions you can ignore the prefactors
dl/h since you normalize the functions afterwards.
(f) In the previous task you should have obtained the new orbitals ψj in terms of the old
ones φj . For this task, use the following solution:
ψ1 =1
2(φ1 + φ2 + φ3 + φ4)
ψ2 =1
2(φ1 − φ2 + φ3 − φ4)
ψ3 =1√2
(φ1 − φ3)
ψ4 =1√2
(φ2 − φ4).
3 / 4
Physical Chemistry V Exercise V 1 May 2020
Set up the Hückel Hamiltonian in the new symmetry adapted basis set. To obtain the
elements in the new basis, calculate H ′jk = 〈φj |He�|φk〉. Use the approximation 〈φj |φk〉 =
δjk.�
(g) Calculate the Hückel energies of the orbitals and draw an energy level diagram. For this
purpose, set up the Hückel determinant det(H ′ − εI), where I is a 4× 4 unit matrix, set
it equal to zero, an determine the possible values of ε.
(h) Fill in the electrons and derive the molecular term symbol for the ground state.
(i) Bonus: As one can see, the ground state of the cyclobutadiene molecule is degenerate.
In accordance with the Jahn-Teller theorem, such states are unstable and any non-totally
symmetric distortion that lowers the overall energy of the system (e.g. geometrical dis-
tortion due to vibrational movement of the nuclei) removes the degeneracy. Consider the
rectangular structure of cyclobutadiene. How does decreasing the symmetry a�ect the
basis functions? Compare with the result you obtained for the square conformation of
the molecule. Draw the molecular orbital energy diagram. Derive the molecular term
symbol for
� the most stable electronic con�guration
� the excited con�guration where one electron is transferred to the next higher lying
orbital
Hint: While constructing energy level diagrams, use the fact that orbitals describing
double bonds have a lower energy than orbitals describing single bonds.
�We could include the overlap Sjk = 〈φj |φk〉, which would lead to a generalized eigenvalue equation. Thisis no practical problem for e.g. a computer implementation but it complicates the discussion.
4 / 4