1 kwh

Click here to load reader

Upload: sriram-ram

Post on 26-Oct-2014

199 views

Category:

Documents


1 download

TRANSCRIPT

1 kwh = 1.34 hp 1.kw = 1.25kva 1 hp = 0.74 kw 1 hp = 1.73 amp 0.8 kw =1 kva in british method 1 hp=735.5 kw in metric method 1 hp=746 kw 1 KW =1.340HP

Best Answer - Chosen by AskerThis is the formula: Power (kW) = Power (HP) x 0.7457 Power (HP) = Power (kW) x 1.341 VALUE WATTS (W) KILOWATTS (kW) AMPERES (I) KILOVOLT AMPERES (kVA) FREQUENCY (Hertz or f) RPM (n) NUMBER OF ROTOR POLES (P) POWER FACTOR (PF) HORSEPOWER (HP) AMPERES (when kW is known) AMPERES (when kVA is known) I E

1-PHASE I X E X PF E X L X PF 1000 kW X 1000 E X PF IXE 1000 Rotor Poles X RPM 120 Hertz X 120 Rotor Poles Hertz X 120 RPM Actual Watts IXE I v E X PF 746 X EFF kW X 1000 E X PF kVA X 1000 E

3-PHASE I X E X 1.73 X PF E X I X 1.73 X PF 1000 kW X 1000 E X 1.73 X PF I X E X 1.73 1000 Rotor Poles X RPM 120 Hertz X 120 Rotor Poles Hertz X 120 RPM Actual Watts I X 1.73 X E I X E X 1.73 X PF 746 X EFF kW X 1000 E X 1.73 X PF kVA X 1000 E X 1.73

= current in amperes = voltage in volts

W kW kVA HP RPM (n) ns Rotor Poles (P) Hertz (f) T EFF PF HP

= watts = power in kilowatts = apparent power in kilo-volt-amperes = output power in horsepower = motor speed in revolutions per minute (RPM) = synchronous speed in revolutions per minute (RPM) = number of poles = frequency in cycles per second (CPS) = torque in pound-feet = efficiency as a decimal = power factor as a decimal = horsepower

Energy Measurement with Joules and Dynes

IntroductionYou may need to convert Voltage, A mperage and electrical specifications from equipment into kW, kVA and BTU information that can be used to calculate overall power and HVAC requirements. The following section addresses the process of taking basic electrical values and converting them into other types of electrical values.

The specification nameplates on most pieces of computer, radio or network equipment usually list required electrical power values. These values are usually expressed in volts, amps, kilovolt-amps (kVA), Watts or some combination of all of the above. If you are an architect or engineer using equipment nameplate information to compute power and cooling requirements, you will find that the total power and cooling values will exceed the actual run requirements of the equipment. Reason: the nameplate value is designed to ensure that the equipment will start and run safely. Manufacturers build in a "safety factor" (sometimes called an "engineering cushion") when developing nameplate specifications. Some nameplates specify power requirements that are higher than the equipment will ever need. The most common engineering solution is to utilize only 80% of available capacity and therefore your computed results will overstate the power and cooling equipment requirement by a factor close to 20%. Develop the power and cooling budget using the nameplate specifications inserted into the formulae below and use the resultant documentation as your baseline. Document everything. There will come a day when you will need every amp of power you projected. Power budgets are notoriously consumed in a much shorter time than

predicted. Don't forget to add a "future factor" to your power and cooling budget. Power supplies double in power draw and heat output every two to three years. If you don't include these factors in your budgets, you will consume a 10 year power and cooling budget in three years (this happened to me, I know this is true).

Three Phase PowerYou will notice that all of the equations that refer to three phase power contain the value 1.73 in the formula somewhere. The value 1.73 is the square root of 3. Intuitively, you can see how this value is applied in the formulae. (3 phases therefore 1 phase = square root of 3)

Computing Watts When Volts and Amps are KnownPOWER (WATTS) = Volts x Amps

For example, a small computer has a nameplate that shows 2.5 amps. Given a normal 120 Volt, 60 Hz power source and the ampere reading from equipment, make the following calculation: POWER (WATTS) = 2.5Amps x 120Volts = 300 WATTS

Generally: P=IEP= Power(WATTS) I = Current(Amps) E = Voltage(Volts)

So: I = P/E and E = P/I Therefore: 1 Watt = 1 Ampere x 1 Volt Click here to see my Ohm's Law Pie Chart for complete relationships between power, current and voltage.

Computing Volt-Amps (VA)Same as above. Volt-Amps (VA) = Volts x Amps = 300 VA

Computing Kilovolt-Amps (kVA)kVA stands for "Thousand Volt-Amps". A 2-Pole Single Phase 208-240 power source requires 2 hot wires from 2 different circuits (referred to as poles) from a power distribution panel. SINGLE PHASE KILOVOLT-Amps (kVA) = Volts x Amps / 1000 Using the previous example: 120 x 2.5 = 300 VA 300 Va / 1000 = .3 kVA

208-240 SINGLE-PHASE (2-POLE SINGLE-PHASE)

Example: An enterprise computer bvserver with a 4.7 amp rating and requiring a 208240 power source. Use 220 volts for our calculations. kilovolt-Amps (kVA) = Volts x Amps /1000 220 x 4.7 = 1034 1034 / 1000 = 1.034 kVA

THREE-PHASE

Example: A large disk storage system loaded with disks. The equipment documentation shows a requirement for a 50-amp 208-240 VAC power source. Do not calculate any value for the plug or receptacle. Use 220 volts for the calculation. kilovolt-Amps (kVA) = Volts x Amps x 1.73 / 1000 220 x 50 x 1.73 = 19,030 19,030 / 1000 = 19.030 kVA This would be rounded to 19

Computing KiloWatts

Finding KiloWatts requires using a power factor in the computation. The power factor is a number that adjusts the power calculation to reflect the efficiency of the use of the electricity supplied to the system. This factor can vary widely (usually from 60% to 95%) and is never published on the equipment nameplate and is not often supplied with product information. For purposes of these calculations, we use a power factor of .85. This random number places a slight inaccuracy into the numbers. Its OK and it gets us

very close for the work we need to do. Most UPS equipment will claim a power factor of 1.00. It is common for the power factor to be considered 1.0 for devices less than 3 years old. SINGLE PHASE

Example: We have a medium-sized Intel server that draws 6.0 amps and the power supply has a power factor of .85.

kiloWatt (kW) = Volts x Amps x Power Factor / 1000 120 x 6.0 = 720 VA 720 VA x .85 = 612 612 / 1000 = .612 kW

208-240 SINGLE-PHASE (2-POLE SINGLE-PHASE)

Example: An enterprise computer server has a 4.7 amp rating and requires a 208-240 power source. I'll use 220 volts and a power factor of .85 for our example calculations. kiloWatt (kW) = Volts x Amps x Power Factor x 2 / 1000 220 x 4.7 x 2 = 2068 2068 x .85 = 1757.8 1757.8 / 1000 = 1.76 kW

THREE-PHASE

Example: A large storage system loaded with disks. The equipment documentation shows a requirement for a 50-amp 208 VAC Power source. Do not calculate any value for the plug or receptacle. Use 220 volts for the calculation. kiloWatt (kW) = Volts x Amps x Power Factor x 1.73 1000 220 x 50 x .85 x 1.73 = 16,175.50 16,175.50/1000 = 16.175 kW

To Convert Between kW and kVA

The only difference between kW and kVA is the power factor. The power factor, unless taken from the manufacturer's specifications, is an approximation. For this example, we use a power factor of .95. The kVA value will always be larger than the value for kW. kW to kVA kVA TO kW kW / .95 = kVA kVA x .95 = kW

To Convert Between kW-Hours and kVA

There is NO conversion from kWH to kVA. These are two different measures. kWH is energy and kVA is power (not necessarily dissipated). If you look at kW (power) and kVA (power), then there is a relationship. That relationship is the power factor of the load.

Computing BTUs

Known Standard: 1 kW = 3413 BTUs (or 3.413 kBTUs) If you divide the electrical nameplate BTU value by 3413 you may not get the published kW value. If the BTU information is provided by the manufacturer, use it, otherwise use the above formula.

Shotgun SectionHere are conversions, short and sweet:

To convert kVA to Amps: Multiply kVA by 1000/voltage [ (kVA x 1000) / E ] For 3 Phase power divide by 1.73 [ (kVA x 1000) / E x 1.73 ]

To convert Watts to Volts when amps are known: Voltage = Watts / Amps E=P/I To convert Watts to Amps when volts are known: Amps = Watts / Voltage I=P/E For 3 Phase power divide by 1.73 To convert Amps to Watts when volts are known: Watts = Voltage x Amps P=ExI For 3 Phase power multiply by 1.73 To convert Horsepower to Amps: Horsepower = (E x I x EFF) / 746 Efficiency = (746 x HP) / (V x A) Multiply Horsepower by 746W (1 HP = 746 Watts)

Find Circuit Voltage and Phase Example: 40 HP at 480 (3 Phase) 746 multiplied by 40 = 29,840 29,840 divided by 480 (3 Phase) = 62.2 62.2 divided by 1.73 = 35.95Amps To convert kW to Amps: Multiply kW by 1000/voltage and then by Power Factor [ (kW x 1000) / E x PF ] for 3 Phase power divide by 1.73 [ ( kW x 1000) / E x PF x 1.73 ]

Shotgun Table of FormulaeHOW TO FIND Amps (I) Direct Current When HP, E and EFF are known: HP x 746 / E x EFF

When kW and E are known:

kW x 1000 / E

SINGLE PHASE When P, E and PF are known: P / E x PF

When HP, E, EFF and PF are known:

HP x 746 / E x EFF x PF

When kW, E and PF are known:

kW x 1000 / E x PF

When kVA and E are known:

kVA x 1000 / E

THREE PHASE When P, E and PF are known: P / E x PF x 1.73

When HP, E, EFF and PF are known:

HP x 746 / E x EFF x PF x 1.73

When kW, E and PF are known:

kW x 1000 / E x PF x 1.73

When kVA and E are known:

kVA x 1000 / E x 1.73

(See abbreviations explained below)

HOW TO FIND WATTS (P)

When E and I are known:

IxE

When R and I are known:

R x I2

When E and R are known:

E2 / R

(See abbreviations explained below)

HOW TO FIND KILOWATTS (kW) Direct Current E and I must be known: E x I / 1000

SINGLE PHASE E, I and PF must be known: E x I x PF / 1000

THREE PHASE

E, I and PF must be known:

E x I x PF x 1.73 / 1000

(See abbreviations explained below)

HOW TO FIND KILOVOLT-Amps (kVA) SINGLE PHASE E and I must be known: E x I / 1000

THREE PHASE E and I must be known: E x I x 1.73 / 1000

(See abbreviations explained below)

HOW TO FIND HORSEPOWER (HP) Direct Current E, I and EFF must be known: E x I x EFF / 746

SINGLE PHASE E, I, PF and EFF must be known: E x I x PF x EFF / 746

THREE PHASE E, I, PF and EFF must be known: E x I x PF x EFF x 1.73 / 746

(See abbreviations explained below)

HOW TO FIND KILOWATT-HOUR (KwH) BTU * (2.9307 * 10 -4)

FtLb * (3.7661 * 10 -7) Joule * (2.7777 * 10 -7)

WHERE:

E = VOLTS P = WATTS R = OHMS I = AMPS HP = HORSEPOWER PF = POWER FACTOR kW = KILOWATTS kVA = KILOVOLT-AMPS EFF = EFFICIENCY (decimal)

Basic Horsepower CalculationsHorsepower is work done per unit of time. One HP equals 33,000 ft-lb of work per minute. When work is done by a source of torque (T) to produce (M) rotations about an axis, the work done is: radius x 2 x rpm x lb. or 2 TM When rotation is at the rate N rpm, the HP delivered is: HP = radius x 2 x rpm x lb. / 33,000 = TN / 5,250 For vertical or hoisting motion: HP = W x S / 33,000 x E Where:

W = total weight in lbs. to be raised by motor S = hoisting speed in feet per minute E = overall mechanical efficiency of hoist and gearing. For purposes of estimating E = .65 for eff. of hoist and "connected gear."

Energy measurement with Joules and DynesEnergy is measured in joules (Watt-seconds) or kiloWatt-hours. A power level of one Watt that continues for one second equals one joule. The integrated energy from a 100-Watt light that runs for 60 seconds equals 6000 joules. 4.18 joules equal 1 calorie, which is enough energy to raise the temperature of one gram of water by one degree Celsius (or Centigrade). When it comes to energy density (Watts per liter or Watts per kilogram) it is difficult to beat gasoline. A lead-acid battery is good for about 125 thousand joules per kilogram. Lithium batteries can provide as much as 1.5 million joules per kilogram. Gasoline tends to run about 45 million joules per kilogram. Joules: 1 joule is exactly 107 ergs. 1 joule is approximately equal to:

6.2415 x 1018 eV (Electron Volts) 0.2390 cal (calorie) (small calories, lower case c) 2.3901 x 104 kilocalorie, Calories (food energy, upper case C) 9.4782 x 104 BTU (British thermal unit) 0.7376 ft-lb (foot-pound force)2.7778 x 107 kiloWatt hour 2.7778 x 104 Watt hour

Units defined in terms of the joule include:

1 thermo chemical calorie = 4.184 J 1 International Table calorie = 4.1868 J 1 Watt hour = 3600 J 1 kiloWatt hour = 3.6 x 106 J (or 3.6 MJ) 1 ton TNT = 4.184 GJ

Useful to remember:

1 joule = 1 Newton meter = 1 Watt second

Dynes: In physics, the dyne (symbol "dyn", from Greek (dynamis) meaning power, force) is a unit of force specified in the centimeter-gram-second (CGS) system of units, a predecessor of the modern SI. One dyne is equal to exactly 10 micronewtons. Equivalently, the dyne is defined as "the force required to accelerate a mass of one gram at a rate of one centimeter per second squared": 1 dyn = 1 g x cm/s2 = 10 - 5 kg x m/s2 = 10 N The dyne per centimeter is the unit usually associated with measuring surface tension. For example, the surface tension of distilled water is 72 dyn/cm at 25C (77F).Units of force newton (SI unit) 1N 1 dyn = 1 kg x m/s2 = 10-5 N dyne = 105 dyn = 1 g x cm/s2 = 980665 dyn 444822 dyn kilogram-force, kilopond 0.10197 kp 1.0197 x 10-6 kp = gn x (1 kg) pound-force 0.22481 lbf 2.2481 x 10-6 lbf 2.2046 lbf poundal 7.2330 pdl 7.2330 x 10-5 pdl 70.932 pdl

1 kp

= 9.80665 N

1 lbf 1 pdl

4.448222 N

0.45359 kp

= gn x (1 lb) 0.031081 lbf

32.174 pdl = 1 lb x ft/s2

0.138255 N 13825 dyn 0.014098 kp

The value of gn as used in the official definition of the kilogram-force is used here for all gravitational units.

MechanicalGeneral Approximations - RULES OF THUMB Use these in the field for fast approximations:

At 3600 rpm, a motor develops a 1.5 lb-ft of torque per HP at rated HP output At 1800 rpm, a motor develops a 3 lb-ft of torque per HP at rated HP output At 1200 rpm, a motor develops a 4.5 lb-ft of torque per HP at rated HP output At 900 rpm, a motor develops a 6 lb-ft of torque per HP at rated HP output At 575 volts, a 3-phase motor draws 1 AMP per HP at rated HP output At 460 volts, a 3-phase motor draws 1.25 AMP per HP at rated HP output At 230 volts a 3-phase motor draws 2.5 AMP per HP at rated HP output At 230 volts, a single-phase motor draws 5 AMP per HP at rated HP output At 115 volts, a single-phase motor draws 10 AMP per HP at rated HP output

b-8018 FORID:10

ISO-8859-1

Search

netw o

w w w .google.co.

w w w .csgnetw o

w w w .google.co.

Share on facebookShare on twitterShare on emailShare on printMore Sharing SerHome | Top Free Apps | CALCULATORS and CONVERTERS | Back

onversion Table

nversion table package allows conversion from one set of units to another. It is for manual use and does no calculations. But, t sily printed table for reference. Most of the conversion factors are taken from the public domain information of the U.S. Nationa e of Standards and Technology, NIST.

would like to automatically convert, try using our: Unit Converter

more printable reference: rsion Factors Table

Standard PrefixesPrefix used in code Prefix for written unit Multiplier dahkMGTPEZdekahectokilomegagigaterapetaexazeta10 100 1000 1e6 1e9 1e12 1e15 1e18 1e21

Y-

yotta-

1e24

dcmmunpfazy-

decicentimillimicronanopicofemtoattozeptoyocto-

1e-1 1e-2 1e-3 1e-6 1e-9 1e-12 1e-15 1e-18 1e-21 1e-24

Standard UnitsUnit Symbol Definition Time second sec 1s Comments

minute hour hour hour day shake Hertz

min hr hour h day shake Hz

60 s 60 min 1 hr 1 hr 24 hr 10 ns 1 s^-1 Length or Distance alternate symbol alternate symbol

international foot inch international mile international mile milli-inch Parsec League Astronomical Unit

ft in mile mi mil pc league ua

0.3048 m 1.0/12.0 ft 5280.0 ft 1 mile 0.001 in 3.085678e16 m 3 mile 1.49598e11 m alternate symbol

Astronomical Unit yard Angstrom Angstrom furlong fathom Rod U.S. survey foot U.S. survey mile point pica

AU yd Ang \\AA furlong fathom rd sft smi pt pica

1.49598e11 m 3 ft 1e-10 m 1 Ang 220 yd 6 ft 16.5 ft (1200./3937.) m 5280 sft 1./72. in 1./6. in

alternate symbol

alternate symbol

also called statue mile Typeface Point Typeface Pica Temperature

Celsius Rankine Fahrenheit

C R F

1 K -273.15 5.0/9.0 K 1 R -459.67 Mass

gram gram pound mass Troy pound carat (metric) slug snail Short Ton Long Ton Ounce Grain Pennyweight

g gm lbm lbt carat slug snail ton ton_l oz gr dwt

0.001 kg g 0.45359237 kg 0.3732417 kg 0.2 g 1 lb sec^2/ft 1 lb sec^2/in 2000 lbm 2240 lbm 28.34952 g 64.79891 mg 1.55174 g

This is case sensitive. (alternate symbol) (avoirdupois) (apothecary)

(avoirdupois)

Force or Weight Newton Dyne pound force N dyn lb 1 kg m/s^2 1e-5 N lbm G

pound force poundal kilopound kilogram force

lbf poundal kip kgf

lbm G 1 lbm ft/sec^2 1000 lbf kg G Energy

Joule British Therm. Unit British Therm. Unit British Therm. Unit calorie calorie Calorie electron volt erg Ton of TNT

J BTU Btu BTU_th cal cal_th Cal eV erg TNT

1Nm 1055.056 J 1 BTU 1054.350 J 4.1868 J 4.184 J 4.1868 kJ 1.602177e-19 J 1e-7 J 4.184e9 J Power (International Table) alternate symbol (Thermochemical) (International Table) (Thermochemical) (nutritionists)

Watt Horse Power

W hp

1 J/s 550 ft lb/s Pressure

bar Pascal Pounds per sq. inch Pounds per sq. ft. kilo psi

bar Pa

1e5 N/m^2 1 N/m^2

psi

1 lb/in^2

psf ksi

1 lb/ft^2 1000.0 psi 1.01325e5 N/m^2 3.387 kPa

atmospheres

atm

inches of Mercury millimeters Mercury Torr

inHg

mmHg

0.1333 kPa

torr

1.333224 Pa Volume or Area

Liter gallon

L gal

1/1000.0 m^3 3.785412 L

Pint (U.S. liquid) Quart (U.S. liquid) Pint (U.S. dry) Quart (U.S. dry) Acre Hectare Barrel (petroleum) Fluid Ounce Gill (U.S.) Peck (U.S.) Tablespoon Teaspoon Cup

pint qt dpint dqt acre ha barrel oz_fl gi pk tbl tsp cup

1/8. gal 2 pint 0.5506105 L 2 dpint 1/640.0 smi^2 10000 m^2 158.9873 L 29.57353 mL 0.1182941 L 8.809768 L 1/32. pint 1/3. tbl 16. tbl Electromagnetism

Coulomb Volt

Co V

1As 1 W/A

Electric Charge Electric Potential

Ohm Ohm Faraday Farad Stokes Oersted Webber Tesla Henry Siemens

ohm

1 V/A

Electric Resistance alternate symbol Electric Charge Capacitance

\\Omega 1 V/A faraday farad stokes Oe Wb Tesla H S 96485.31 Co Co/V 1e-4 m^2/s 79.57747 A/m Vs Wb/m^2 Wb/A A/V

Magnetic flux Magnetic flux density Inductance Electrical Conductance Light and Radiation

Lux Lux Lumen Stilb Phot

lux lx lm sb ph

cd/m^2 cd/m^2 cd 10000 cd/m^2 10000 lx

Iluminance

Luminous Flux

Becquerel Gray Sievert

Bq Gy Sv

s^-1 J/kg J/kg

activity Absorbed Dose, kerma Dose equivalent Other Quantities

pound mole poise

lbmole poise

1 mol lbm/g 1 g /sec cm 9.80665 m/sec^2

quantity viscosity

Gravity's accel.

G

Gravity on Earth

Degree

deg

Pi/180

Can be used to convert from degrees to radians for functions.

Percent Knot Miles per Hour Gallon/minute Revolution/minute

% knot mph gpm rpm

0.01 1852 m/hr 1 mi/hr 1. gal/min 360 deg/min Updated: 7/1/11 velocity velocity flow rate

Leave us a question or comment on Facebook

Search or Browse Our Sitepartner-pub-8018 FORID:10 ISO-8859-1Search

Automotive Aviation Business Communications Computer Construction Electronics Everyday Use Financial General Interest Geography Related Health

Home Repair Javascript Lottery Marine Math Help Math Scripts Mechanical Money Science Sports Time Weather

Registered Trademark and Copyright 1973 - 2012 CSG, Computer Support Group, Inc. and CSGNetwork.Com All Rights Reserved

Home | Advertising | Calculators and Converters | Contact Us | Javascript | Sitemap | Glossary | Top Free Apps

Energy in general is defined as the capacity for doing work. Power is the rate of doing work or the rate of using energy:

P=Work/t=Energy/t

, where t is time. Although casually the terms energy and power are often used interchangeably, technically they have different meanings. The SI unit of energy and work (which are numerically the same) is the joule (J). A joule is the work done by a force of one newton for a distance of one meter. This unit is usually used in physics. Energy comes in many forms, such as heat, motion, gravitational, radiated solar power, and electrical. For different types of energy other physical units are also used. For example, the British Thermal Unit (Btu) is often used to measure the heat energy or compare fuels. One Btu is what's needed to heat one pound of water one degree F. The SI derived unit of power is watt (W). Watt is power required to produce or use of one joule of energy per second. This unit and its multiple kilowatt are usually used in ratings of various electric loads and sources of electricity, such as generators for homes.

How do we get an expression for electrical power from its general definition as work per unit time? By definition, work done by a constant force F when it moves an object by distance L in the direction of force is:Work=FL

. We know that in an uniform electric field with voltage V over distance L, the force acting on a charge Q is equal to F=V/LQ. (Particularly, in the field of 1 volt/meter, force of 1 newton is acting on one coulomb charge). Substituting this into the above general expression of work gives the equation for P required to move a charge Q in an electric field: P = FL/t = VQ/t. The rate of charge flow Q/t is called electric current I. Replacing Q/t with I in the above formula yields a familiar expression for instantaneous value of electrical power: P=VI. In AC circuits voltage and current are often shifted in phase and are not sinusoidal. You can use the tools below to make instant online conversion between various SI, CGS, imperial and other energy and power units.

POWER UNIT CONVERSION CALCULATOR

ENERGY UNIT CONVERSION CALCULATOR

watt [W]: kilowatt [kW]: megawatt [MW]: gigawatt [GW]: terawatt [TW]: milliwatt [mW]: volt ampere [V*A]: newton meter/second: joule/second [J/s]: pound-foot/second: erg/second [erg/s]: ton (refrigeration): kilocalorie (IT)/hour: calorie (IT)/second: Btu (IT)/hour [Btu/h]: Btu (th)/hour: Btu (IT)/second: horsepower [hp]: horsepower (metric): horsepower (boiler):

1

joule [J]: kilojoule [kJ]: electron-volt [eV]: [MeV]:

1

0.001

0.001

0.000001

6.241506363e

0.000000001 megaelectron-volt

6.241506363e

1e-12

erg: watt-hour [W*h]: kilowatt-hour [kW*h]: watt-second [W*s]: newton meter [N*m]: hour [hp*h]:

10000000

1000

0.000277778

1

0.000000278

1

1

1

1

0.737562149 horsepower10000000

0.000000373

horsepower (metric) hour: (IT) [kcal (IT), kcal]: (th) [kcal (th)]:

0.000000378

0.000284345 kilocalorie

0.000238846

0.859845228 kilocalorie 0.238845897 calorie

0.000239006

(IT) [cal (IT), cal]:

0.238845897

3.412141633

calorie (th) [cal (th)]: calorie (nutritional): Btu (IT): Btu (th): (refrigeration) [ton*h]:

0.239005736

3.41442595

0.000238846

0.000947817

0.000947817

0.001341022

0.000948452

0.001359622 ton-hour 0.000101942oil fuel

0.000000079

equivalent @barrel (US):

1.566639868e

horsepower (electric):

0.001340483

ton (explosives):

2.390057361e

dyne centimeter [dyn*cm]: gram-force centimeter [gf*cm]: kilogram-force meter [kgf*m]:

10000000

power and energy conversion factors are provided by unitconversion.org

10197.162130

0.101971621

NOTESfoot-pound force [ft*lbf]: : IT- International Table th- thermochemical unit inch-pound force [in*lbf]: inch-ounce [in*ozf]: poundal foot [pdl*ft]: therm: therm (US): Hartree energy: Rydberg constant:0.737562149 8.850745792

141.61193266

23.730360457

0.000000009

0.000000009

2.293710449e

4.587420897e