1. if needed, solve one of the equations for y (slope ... · replace this expression with the value...

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7 7.2 - Solving Systems of Equations by Substitution. DAY 2 (Distributive Property) 1. If needed, solve one of the equations for y (slope intercept form) 2. Put parentheses around the expression you are substituting in to the other equation 3. Replace this expression with the value of y for the other equation. 4. Solve for x. 5. Write answer as an ordered pair (x, y). This is the solution to the system 6. Check your solution by substituting the coordinates into each equations 1. 2. y = x + 12 10 + 3y = 19 4x + 2y = 36 y = 2x + 5 3. 4. y = 3x + 8 x = y – 12 8x + 4y = 12 4x + 2y = 6 5. 6. y = 2x – 3 y = 2x + 1 x + y = 18 -2x + 3y = -9

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Page 1: 1. If needed, solve one of the equations for y (slope ... · Replace this expression with the value of y for the other equation. 4. ... 4x + 2y = 36 y = 2x + 5 ... 6. y = 2x – 3

7

7.2 - Solving Systems of Equations by Substitution. DAY 2 (Distributive Property)

1. If needed, solve one of the equations for y (slope intercept form)

2. Put parentheses around the expression you are substituting in to the other equation 3. Replace this expression with the value of y for the other equation. 4. Solve for x. 5. Write answer as an ordered pair (x, y). This is the solution to the system

6. Check your solution by substituting the coordinates into each equations

1. 2.

y = x + 12 10 + 3y = 19

4x + 2y = 36 y = 2x + 5

3. 4.

y = 3x + 8 x = y – 12

8x + 4y = 12 4x + 2y = 6

5. 6.

y = 2x – 3 y = 2x + 1

x + y = 18 -2x + 3y = -9

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