1 fourier representation of signals and lti systems. chapter 3 ekt 232
TRANSCRIPT
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Fourier Fourier Representation Representation of Signals and of Signals and LTI Systems.LTI Systems.
CHAPTER CHAPTER 33
EKT 232 EKT 232
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Signals are represented as superposition's of complex sinusoids which leads to a useful expression for the system output and provide a characterization of signals and systems.
Example in music, the orchestra is a superposition of sounds generated by different equipment having different frequency range such as string, base, violin and ect. The same example applied the choir team.
Study of signals and systems using sinusoidal Study of signals and systems using sinusoidal representation is termed as representation is termed as Fourier AnalysisFourier Analysis introduced by Joseph Fourier (1768-1830).introduced by Joseph Fourier (1768-1830).
There are four distinct Fourier representations, each applicable to different class of signals.
3.1 Introduction.3.1 Introduction.
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Fourier Series
Discrete Time Fourier series (DTFS)
0
0
12 / 2 /1
x X X xF
F F
F
n Nj kn N j kn N
Fk N n nF
n k e k n eN
where is the representation time and the notation means
a summation over any range of consecutive ’s exactly in length.F
F k N
F
N
k N
Fourier SeriesNotice that in
2 /x X F
F
j kn NF
k N
n k e
the summation is over exactly one period, a finite summation. This is because of the periodicity of the complex sinusoid,
2 / Fj kn Ne
in harmonic number . That is, if is increased by any integer
multiple of the complex sinusoid does not change. F
k k
N
2 /2 / , ( an integer)F FF j k mN n Nj kn Ne e m
This occurs because discrete time n is always an integer.
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Fourier Series
0 0
0 0
2 / 2 /
0
1x X X xj kn N j kn N
k N n N
n k e k n eN
F S
0
In the very common case in which the representation time is
taken as the fundamental period the DTFS isN
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CT Fourier Series Definition
0 0
The Fourier series representation x t of a signal x( )
over a time isF
F
t
t t t T
2x X Fj kf tF
k
t k e
where X[k] is the , is the
and 1/ . The harmonic function
can be found from the signal asF F
k
f Tharmonic function harmonic
number
0
0
21X x
F
F
t Tj kf t
F t
k t e dtT
The signal and its harmonic function form a
indicated by the notation x X .t k
Fourier series
pair F S
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CTFS Properties
Linearity
x y X Yt t k k F S
0
0
Let a signal x( ) have a fundamental period and let a
signal y( ) have a fundamental period . Let the CTFS
harmonic functions, each using a common period as the
representation time, be X[ ] a
x
y
F
t T
t T
T
k nd Y[ ]. Then the following
properties apply.
k
Dr. Abid Yahya
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CTFS Properties
Time Shifting 0 02
0x Xj kf tt t e k F S
0 00x Xjk tt t e k F S
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CTFS Properties
Frequency Shifting (Harmonic Number
Shifting)
0 020x Xj k f te t k k F S
0 00x Xjk te t k k F S
A shift in frequency (harmonic number) corresponds to multiplication of the time function by a complex exponential.
Time Reversal x Xt k F S
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CTFS Properties
Change of Representation Time
0With , x XF xT T t k F S
X / , / an integerX
0 , otherwisem
k m k mk
(m is any positive integer)
0With , x XF x mT mT t k F S
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CTFS PropertiesChange of Representation Time
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CTFS Properties
Time Differentiation
0
0
x 2 X
x X
dt j kf k
dtd
t jk kdt
F S
F S
F S
F S
04/20/23 . J. Roberts - All Rights Reserved
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Time Integration
Case 1. X 0 0
0
Xx
2
t kd
j kf
F S
0
Xx
t kd
j k
F S
Case 2. X 0 0
xt
d is not periodic
CTFS PropertiesCase 1 Case 2
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CTFS PropertiesMultiplication-Convolution Duality
x y X Yt t k k F S
(The harmonic functions, X[ ] and Y[ ], must be based
on the same representation period .)F
k k
T
0x y X Yt t T k kF S#
0
x y x yT
t t t d #
x t y t xap t y t where xap t is any single period of x t
The symbol indicates .
Periodic convolution is defined mathematically by
periodic convolution#
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Fourier Series(DTFS)
0
0
12 / 2 /1
x X X xF
F F
F
n Nj kn N j kn N
Fk N n nF
n k e k n eN
where is the representation time and the notation means
a summation over any range of consecutive ’s exactly in length.F
F k N
F
N
k N
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Notice that in
2 /x X F
F
j kn NF
k N
n k e
the summation is over exactly one period, a finite summation. This is because of the periodicity of the complex sinusoid,
2 / Fj kn Ne
in harmonic number . That is, if is increased by any integer
multiple of the complex sinusoid does not change. F
k k
N
2 /2 / , ( an integer)F FF j k mN n Nj kn Ne e m
This occurs because discrete time n is always an integer.
Fourier Series(DTFS)
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0 0
0 0
2 / 2 /
0
1x X X xj kn N j kn N
k N n N
n k e k n eN
F S
0
In the very common case in which the representation time is
taken as the fundamental period the DTFS isN
Fourier Series(DTFS)
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DTFS Properties0
0
Let a signal x[ ] have a fundamental period and let a
signal y[ ] have a fundamental period . Let the DTFS
harmonic functions, each using a common period as
the representation time, be X[ ] a
x
y
F
n N
n N
N
k nd Y[ ]. Then the following
properties apply.
k
Linearity
x y X Yt t k k F S
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DTFS Properties
Time Shifting 02 /0x XFj kn Nn n e k F S
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DTFS Properties
x Xn k Time Reversal F S
Frequency Shifting(Harmonic Number
Shifting) 02 /
0x XFj k n Ne n k k F S
* * x Xn k Conjugation F S
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DTFS PropertiesTime Scaling
Let z x , 0n an a If a is not an integer, some values of z[n] are undefinedand no DTFS can be found. If a is an integer (other than1) then z[n] is a decimated version of x[n] with some values missing and there cannot be a unique relationshipbetween their harmonic functions. However, if
x / , / an integerz
0 , otherwise
n m n mn
then
0Z 1/ X , Fk m k N mN
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DTFS Properties
Change of Representation Time
0
0
With , x X
With , x X
F x
F x q
N N n k
N qN n k
F S
F S
(q is any positive integer)
X / , / an integerX
0 , otherwiseq
k q k qk
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DTFS Properties
First Backward Difference
2 /x x 1 1 XFj k Nn n e k F S
Multiplication-Convolution
Duality
0
0
x y Y X Y X
x y Y X
q N
n n k k q k q
n n N k k
F S
F S
#
#
Dr. Abid Yahya
The Fourier Transform
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Extending the CTFS
• The CTFS is a good analysis tool for systems with periodic excitation but the CTFS cannot represent an aperiodic signal for all time
• The continuous-time Fourier transform (CTFT) can represent an aperiodic signal for all time
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Forward Inverse
2X x x j ftf t t e dt
F -1 2x X X j ftt f f e df
F
f form
X x j tj t x t e dt
F -1 1x X X
2j tt j j e d
F
formForward Inverse
Definition of the CTFT
x Xt fF x Xt jFor
Commonly-used notation:
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Some Remarkable Implications of the Fourier Transform
The CTFT expresses a finite-amplitude, real-valued, aperiodic signal which can also, in general, be time-limited, as a summation (an integral) of an infinite continuum of weighted, infinitesimal-amplitude, complex sinusoids, each of which is unlimited in time. (Time limited means “having non-zero values only for a finite time.”)
The Discrete-Time Fourier Transform
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Extending the DTFS
• Analogous to the CTFS, the DTFS is a good analysis tool for systems with periodic excitation but cannot represent an aperiodic signal for all time
• The discrete-time Fourier transform (DTFT) can represent an aperiodic signal for all time
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Definition of the DTFT
2 2
1x X X xj Fn j Fn
n
n F e dF F n e
F
F Form
2
1x X X x
2j j n j j n
n
n e e d e n e
F
Form
ForwardInverse
ForwardInverse
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The Four Fourier Methods
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Relations Among Fourier Methods
Discrete Frequency Continuous Frequency
Continuous Time x y X Y x y X Y
Discrete Time x y Y X x y X Y
t t k k t t f f
n n k k n n F F
F S F
F S F# #
0
0
Discrete Frequency Continuous Frequency
Continuous Time x y X Y x y X Y
Discrete Time x y Y X x y X Y
t t T k k t t f f
n n N k k n n F F
F S F
F S F
#
#
Multiplication-Convolution Duality
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Relations Among Fourier Methods
0 0 0
0 0 0
0 0
0 0
Discrete Frequency Continuous Frequency
Continuous Time x X x X
Discrete Time x X x X
j k t j t
j k n j nj
t t k e t t j e
n n k e n n e e
F S F
F S F
Time and Frequency Shifting
0 0 0
0 0 00
0 0
0
Discrete Frequency Continuous Frequency
Continuous Time x X x X
Discrete Time x X x X
j k t j t
j k n jj n
t e k k t e j
n e k k n e e
F S F
F S F
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Tutorials1. Compute the CTFS:
( ) 4cos(500 )x t t 1/ 50FT
,
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2.2. Find the Find the frequency-domainfrequency-domain representation of the representation of the signal in Figure 3.1 below.signal in Figure 3.1 below.
Figure 3.1: Time Domain Signal.Figure 3.1: Time Domain Signal.
Solution:Solution:Step 1Step 1: Determine N and : Determine N and ..
The signal has period N=5, so =2/5.
Also the signal has odd symmetry, so we sum over n = -2 to n = 2 from equation
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Step 2Step 2: Solve for the frequency-domain, : Solve for the frequency-domain, XX[[kk].].From step 1, we found the fundamental frequency, N
=5, and we sum over n = -2 to n = 2 .
5/45/205/25/4
5/22
2
1
0
210125
1
5
1
1
jkjkjjkjk
njk
n
njkN
n
exexexexex
enxkX
enxN
kX o
Cont’d…Cont’d…
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From the value of x{n} we get,
5/2sin15
1
2
1
2
11
5
1 5/25/2
kj
eekX jkjk
Cont’d…Cont’d…