1-06 even and odd functions notes
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Even and Odd FunctionsStudents will determine if a function is even,
odd, or neither using algebraic methods.
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We can define a function according to its symmetry to the y – axis or to the origin. This symmetry will also correspond with certain Algebraic conditions.
The function can be classified as either even, odd or neither.
Even and Odd Functions
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• A function f is even if the graph of f is symmetric with respect to the y-axis.
Even Functions
f(x) = |x| - 3 f(x) = |x + 6|
Even Not an Even
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• Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f.
• Test Algebraically for f(2) and f(-2)
Using Algebraic Method
f(x) = |x + 6| f(x) = |x| - 3
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• A function f is odd if the graph of f is symmetric with respect to the origin.
Odd Functions
Odd Function Not Odd Function
f(x) = 3x f(x) = 3x + 6
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• Algebraically, f is odd if and only if f(‐x) = ‐f(x) for all x in the domain of f.
• Test Algebraically for f(‐2) and ‐ f(2)
f(x) = 3x f(x) = 3x + 6
Using Algebraic Method
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• Ex. 1 Test this function for symmetry: • f(x) = x5 + x³ + x
• Solution. We must look at f(−x): • f(−x) = (−x)5 + (−x)³ + (−x) = −x5 − x³ − x = −(x5 + x³ + x) = −f(x)• Since f(−x) = −f(x), this function is symmetrical with respect to the origin.
• Remember: A function that is symmetrical with respect to the origin is called an odd function.
Example
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• 1) f(x) = x³ + x² + x + 1Even Odd
• Answer: Neither, because f(−x) ≠ f(x) , and f(−x) ≠ −f(x).
• 2) f(x) = 2x³ − 4x
• Answer: f(x) is odd. It is symmetrical with respect to the origin because f(−x) = −f(x).
• 3) f(x) = 7x² − 11
• Answer: f(x) is even -- it is symmetrical with respect to the y-axis -- because f(−x) = f(x).
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