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© Cambridge International Examinations 2013
CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/11 Paper 1 (Core), maximum raw mark 56
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
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Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 11
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only
cso correct solution only
dep dependent
ft follow through after error
isw ignore subsequent working
oe or equivalent
SC Special Case
www without wrong working
Qu. Part Answers Mark Part Marks
1 121 042
1
2 250
1
3
86.7 or 86.74 to 86.75 1
4 (a)
(b)
42 000
10 381 cao
1
1
5 (a)
(b)
2
Both lines drawn
1
1
6 (a)
(b)
(4, 1)
Point plotted at (–1, 3)
1
1
7 3a – 4b
Final Answer
2 B1 for answer 3a ± jb or ka – 4b
or SC1 for answer reached in working then spoilt
8
5.293 cao 2 B1 for 5.29 or 5.292 to 5.2927
9
125 2 B1 for 55 or 125 in any other correct position on
diagram
or M1 for 180 – 55
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 11
© Cambridge International Examinations 2013
10
7.7
2 M1 for 44 × 100
17.5 oe
11 (a)
(b)
6561 cao
1
1
1
12
4.8 oe 2 M1 for 5 + 19 = 3x + 2x oe or better
or B1 24 – 2x = 3x oe
or 5 = 5x – 19 oe
13 [Other angle could be] 84 2 M1 for 180 – (48 + 48)
or SC1 shows that two angles of 66 are needed to make
an isosceles triangle
14
(a)
(b)
6
2 oe
200 Final answer
1
1FT
FT 600 × their (a) providing their (a) is a probability
15
435, 445 cao 2 B1 for one value in correct place
or SC1 for both values correct but reversed
16 (a)
(b)
4
7 nfww
1
2
M1 for a correctly ordered list of at least 8 numbers
17
944 cao
3 M1 for 800 × 6 ×100
3 oe
A1 for 144
A1 FT Dependent on M1 scored
for their 144 + 800 evaluated
18
(a)
(b)
Ruled perpendicular line
through P
Correct ruled line drawn
with 2 correct sets of arcs
1
2
± 2°
B1 for correct line without correct arcs
or for 2 sets of correct arcs with no line
19
6.6 cao
3 M1 for sin 56 = 8
hoe or better
A1 for 6.63......
A1 FT Dependent on M1 scored
for their answer correctly rounded to 2sf
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 11
© Cambridge International Examinations 2013
20
(a)
(b)
12
16
−
5
3
2
2
B1 for each correct component
B1 for each correct component
21
(a)
12
9 –
12
1 oe
[=] 12
8 oe [=]
3
2
M1
M1
Must be shown.
Both fractions must be shown
(b) 2
5 ×
25
4 oe
Cancelling shown
or 50
20oe [=]
5
2
M1
M1
Must be shown
Dependent and cancelling shown
or a fraction and then 5
2 must be shown
22 (a)
(b)
6b( a – 4c)
Final answer
n (j + k) or nj + nk oe
Final answer
2
2
B1 for answer 6( ab – 4bc ) or 3b( 2a – 8c )
or 2b( 3a – 12c ) or b( 6a – 24c )
M1 for one correct step of a two-step method
or SC1 for [m] = k + jn or [m] = j+ kn
23 (a)
(b)
(c)
(i) 11
(ii) subtract 4 oe
2, 6, 10 cao
3n – 4 oe
1
1
1
2
B1 for answer 3n ± k, where k is an integer
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/12 Paper 1 (Core), maximum raw mark 56
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
![Page 6: 0580 MATHEMATICS - Max Papersmaxpapers.com/wp-content/uploads/2012/11/0580_w13_ms_all.pdf · CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education](https://reader030.vdocuments.us/reader030/viewer/2022021418/5a9e49a37f8b9a6a218d3844/html5/thumbnails/6.jpg)
Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 12
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only cso correct solution only dep dependent ft follow through after error isw ignore subsequent working oe or equivalent SC Special Case www without wrong working
Qu. Answer Mark Part Marks
1 3 + 5 × (4 – 2) 1
2
2
2
1
3 12 final answer 1
4 (a) 3.5 symbols in hot chocolate row 1
(b) 7 1
5 19% 0.7195 √0.038 sin 11.4 1/5 2 B1 for decimals [0.19], [0.2], 0.194…, 0.197…, 0.192… seen Or for four in correct order
6 (a) −447 1
(b) 2 1
7 15.7 or 15.70 to 15.71 2 M1 for 2 × π × 2.5
8
160
2 M1 for 18
8 × 360
9 (a) 1
(b) or or
1
Many other answers
10 8.54[4....] 2 M1 for 7.22 + 4.62 or better
11 10.1[0] Final answer 3 M1 for 1.3199 and 1.3401 seen
and M1 for 500 × 1.3199 or 500 × 1.3401 or for 500 × (their highest – their lowest) oe
12 10[.00] 3 M2 for 1.90 and 2.90 and 5.20 only or M1 for two of 1.90, 2.90, 5.20 in a list of three or two values from the table
or SC1 for 1.90, 2.90, 4.30 [from 2
20.540.3 +
]
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 12
© Cambridge International Examinations 2013
13 (a) 5 cao 1
(b) 196 cao 1
(c) 97 cao 1
14 (a) (0, 5) 1
(b) –2 1
(c) y = –2x + k 1 k ≠ 5
15 (a) 26 1
(b)
10
3−c or
10
3
−
− c
oe final answer
2
M1 for one correct step of a two step method.
16 74.1 or 74.137 to 74.140 3 M1 for 10 × 6 and M1 for 0.5 × π × 32
17 [x =] 3, [y =] 4 3 M1 for correctly eliminating one variable A1 for [x =] 3 A1 for [y =] 4 If zero scored, SC1 for correct substitution and evaluation to find the other variable.
18 (a) x7 1
(b) 5y6 2 B1 for 5ym or ky6 in answer m ≠ 0, k ≠ 0
19 (a) Ruled line from (0, 0) to (5, 22.5) 2 B1 for (5, 22.5) or (0, 0) at the ends of the ruled line.
(b) (i) 17.5 to 18.5 1FT FT their straight line
(ii) 3.3 to 3.4 1FT FT their straight line
20 (a) Net completed 2 With one 2 by 5, one 3 by 5 and two 2 by 3 rectangles correctly positioned B1 for 2 correct rectangles correctly positioned
(b) 30 cm3
2
1
M1 for 3 × 2 × 5 Independent mark
21 (a) Angle bisector with correct arcs 2 B1 for correct line, with incorrect or no arcs or
correct arcs with incorrect or no line
(b) Perpendicular bisector with two correct pairs of arcs
2 B1 for correct line, with incorrect or no arcs or
correct arcs with incorrect or no line
(c) Arc centre C, radius 7cm Correct region shaded
1
1FT
FT their arc centre C
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/13 Paper 1 (Core), maximum raw mark 56
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
![Page 9: 0580 MATHEMATICS - Max Papersmaxpapers.com/wp-content/uploads/2012/11/0580_w13_ms_all.pdf · CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education](https://reader030.vdocuments.us/reader030/viewer/2022021418/5a9e49a37f8b9a6a218d3844/html5/thumbnails/9.jpg)
Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 13
© Cambridge International Examinations 2013
Qu. Answers Mark Part Marks
1 84 1
2 a(2a − 5) final answer 1
3 29 1
4 39 2 M1 for 52 × 45 ÷ 60 oe
5 (a) 2600 1
(b) [0].058 1
6 (a) 11
6
1
(b) Arrow to right of 0.5 1 Reasonable accuracy
7 Any two of (20, 8) (–4, 0) (12, 24) 2 B1 for one correct
8 (a) 9[h] 35[min] 1
(b) 19 25 1
9 (a) 3 1
(b) 3 1
10 22
9 , 0.41, 7
3 , 43%, 7
π
2
B1 for decimals [0.41] 0.429,
0.409. 0.449 [0.43], or for 4
in correct order
11 (a)
− 7
6
1
(b)
−
21
18
1FT
‘Their (a)’ × −3
12 (a) Negative 1
(b) Positive 1
13 [AB =] 5.3 to 5.7 cm
[Bearing] 130° to 134°
1
1
SC1 for correct length line and
bearing but starting at base of
North line
14 [x =] 1.75 or 14
3 or 4
7
2
M1 for first correct step 4x = 7,
x + 4
3 = 4
10 ,
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 13
© Cambridge International Examinations 2013
15 7
22 − 5
7
35
225 their× oe − 35
77 their× oe or
35
77225 theirtheir ×−× oe
35
61 or 135
26 cao
B1
M1
A1
16
160
3 M1 for sin 15 = 628
][oe or better
A1 for 162.5[3…] or 163
or 162.54
B1 FT correct rounding
17 30.9 or 30.88 to 30.91 3 M2 for 12 × 12 − π × 6 × 6 or
4( 6 × 6 − 4
1π × 6 × 6)
M1 for 12 × 12 or π × 6 × 6 or
( 6 × 6 − 4
1π × 6 × 6)
18 (x =) 3, (y =) −2 3 M1 for correctly eliminating
one variable
A1 for [x = ]3
A1 for [y =] −2
If zero scored, SC1 for correct
substitution and evaluation to
find the other variable
19 (a)
7.5 × 10–2
2 M1 for 0.075 or 3/40 80
6
0.75 × 10–1 or 75 × 10–3 oe
(b) 9.3 × 107 2 M1 for 93 000 000 or 93 × 106
or 0.93 × 108 oe
20 (a) Circle, radius 3 cm, centre A, not inside the
rectangle
2 M1 for arc or full circle centre
A radius 3 cm
or for an incorrect size circle at
A outside rectangle
(b) One line of symmetry with correct arcs
E.g.
2
B1 for correct ruled line (must
reach or cross two sides)
B1 for 2 pairs of correct
intersecting arcs
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 13
© Cambridge International Examinations 2013
21 (a) 11x − 7y final answer 2 B1 for 11x ± my or nx − 7y
(b) 3a − 2b final answer 2 B1 for 8a −12b or −5a + 10b
or 3a ± pb or qa −2b
22 (a) (i) 1000 [m] 1
(ii) 80 [m/min] 2 M1 for 1600 ÷ 20
(iii) 20 [min] 1
(b) (i) Ruled line from (11 10, 1600) to (11 35, 0) 2 M1 for 1600 ÷ 64 soi
(ii) 11 35 1FT their line at the axis if on the
grid and not before 11 10.
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/21 Paper 2 (Extended), maximum raw mark 70
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
![Page 13: 0580 MATHEMATICS - Max Papersmaxpapers.com/wp-content/uploads/2012/11/0580_w13_ms_all.pdf · CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education](https://reader030.vdocuments.us/reader030/viewer/2022021418/5a9e49a37f8b9a6a218d3844/html5/thumbnails/13.jpg)
Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 21
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only
cso correct solution only
dep dependent
ft follow through after error
isw ignore subsequent working
oe or equivalent
SC Special Case
www without wrong working
Qu. Answers Mark Part Marks
1 86.7 or 86.74 to 86.75 1
2 5.293 cao 2 B1 for 5.29 or 5.292 to 5.2927
3 125 2 B1 for 55 or 125 in any other correct position
on diagram or M1 for 180–55
4 7.7 2 M1 for 44 ×
100
5.17 oe
5 4.8 oe 2 M1 for 5 + 19 = 3x + 2x oe or better
or B1 for 24 – 2x = 3x oe
or 5 = 5x – 19 oe
6 (a) 6
2 oe
1
(b) 200 1FT FT 600 × their (a) providing their (a) is a
probability
7 435, 445 cao 2 B1 for one value in the correct place
or SC1 for both values correct but reversed
8
134
3 M2 for 53
1001.20
×
×
oe
or M1 for 1.20100
53=
××x
or 3% = 4.02 oe
If 0 scored SC1 for answer of figs 134
9 (a) 2+n
n
oe final answer
1
(b) n2–1 oe final answer 2 B1 for any quadratic in final answer
10 [±]22
ac − oe final answer
3
M1 for correct square
M1 for correct re-arrangement
M1 for correct square root
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 21
© Cambridge International Examinations 2013
11 150 3 M1 for m3 to cm3 or cm3 to m3
12 (a) 110 1
(b) 79 2 B1 for DAC = 42 or ACB = 79 or ACD = 28
13 (a) 4
5 oe
1
(b) 4y6 2 B1 for ky6 or y6 or 4yk or 4 as final answer
14 1
52
−
−
t
t final answer
3 B1 for 1
)1(3
−
−
t
t or better
B1 for 3(t – 1) – (t + 2) oe or better
15 (a) 12
1
12
9− oe
[=]12
8oe [=]
3
2
M1
M1
Must be shown
Both fractions must be shown
(b) 25
4
2
5× oe
Cancelling shown or 50
20oe [=]
5
2
M1
M1
Must be shown
Dependent and cancelling shown or a
fraction and then 5
2must be shown
16 (a)
6
9
1
(b) 10.8 or 10.81 to 10.82
2FT M1 for 22 )6()9( theirtheir +
A1 for 10.8 or FT correctly evaluated
(c) (17, 13) 1FT FT their 9 and 6.
(8 + their 9, 7 + their 6) correctly evaluated
17 (a) (a + b)(1 + t) 2 B1 for 1(a + b) + t(a + b)
or a(1 + t) + b(1 + t)
(b) (x – 6)(x + 4) 2 SC1 for answer of (x + a)(x + b) where
ab = –24 or a + b = –2
18
486 cao
4
M1 for πππ 243422
2
1=+× rr or better
A1 for [r =] 9
M1 for ( )33
4
2
1 their][ rπ×
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 21
© Cambridge International Examinations 2013
19
(a) 40
2 M1 for 6060
1000144
×
×
oe
(b) 3.5
2FT FT 140 ÷ their (a)
M1 for dist ÷ their (a)
or dist ÷ 40
or dist ×1000144
6060
×
×
or B1 for 140 seen
20 (a) (i) Accurate bisector of angle B with
correct arcs
2
B1 for correct line or correct arcs
(ii) Accurate perpendicular bisector of
BC with correct arcs
2
B1 for correct line or correct arcs
(b) correct region shaded 1
21
(a) 73.7 or 73.73 to 73.74
3 M1 for 223
20×
+
or B1 for BX = 8
M1 for tan [ ] = 8
6
their or better
(b) 120
2 M1 for 12202
1××
oe
22
(a) (i) 50
5 oe
1
(ii)
50
11 oe
1
(b) 16
11 oe
1
(c) 2450
380 oe
2 M1 for 49
19
50
20×
(d)
1
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/22 Paper 2 (Extended), maximum raw mark 70
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
![Page 17: 0580 MATHEMATICS - Max Papersmaxpapers.com/wp-content/uploads/2012/11/0580_w13_ms_all.pdf · CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education](https://reader030.vdocuments.us/reader030/viewer/2022021418/5a9e49a37f8b9a6a218d3844/html5/thumbnails/17.jpg)
Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 22
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only
cso correct solution only
dep dependent
ft follow through after error
isw ignore subsequent working
oe or equivalent
SC Special Case
www without wrong working
soi seen or implied
Qu. Answers Mark Part Marks
1 19% 0.7195 038.0 sin 11.4 1/5 2 B1 for decimals [0.19], [0.2], 0.194…, 0.197…,
0.192… seen
Or for four in correct order
2 (a) –447 1
(b) 2 1
3 15.7 or 15.70 to 15.71 2 M1 for 2 × π × 2.5
4
160
2 M1 for 36018
8× oe
5 (a) 1
(b) Some possible answers:
1
6 [±] 4−y final answer 2 M1 for first move completed correctly
M1 for second move completed correctly on answer
line
7
170
2 M1 for 10)2212(2
1×+× oe
8
3619 to 3620
2 M1 for 312×π××
3
4
2
1or better
9 decagon 3 M1 for 360 ÷ 36 oe
A1 for 10
10 10.1[0] 3 M1 for 1.3199 and 1.3401 seen
and M1 for 500 × 1.3199 or 500 × 1.3401
or for 500 × (their highest – their lowest) oe
11
120
3 M1 for d
kv =
A1 for k = 600
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 22
© Cambridge International Examinations 2013
12 p = 71.4025 cao
q = 73.1025 cao
3 B1 for 8.45 and 8.55 seen
M1 for their LB2 [π] or their UB2 [π]
If 0 scored, SC1 for one correct.
13 10[.00] 3 M2 for 1.90 and 2.90 and 5.20 only
or M1 for two of 1.90, 2.90, 5.20 in a list of three or
two values from the table
or SC1 FOR 1.90, 2.90, 4.30
+
2
20.540.3from
14 52 3 B2 for AOB = 104
or B1 for OAB or OBA = 38
15 (8, 2) 3 M1 for correctly eliminating one variable
A1 for x = 8
A1 for y = 2
If 0 scored, SC2 for correct substitution and correct
evaluation to find the other value.
16 x <6.8 4 B3 for 6.8 with wrong inequality or equal as answer.
Or
M1 for first move completed correctly
and M1 for second move completed correctly
and M1 for third move completed correctly
17 (a)
3026
511
2
SC1 for one correct row or column
(b)
−
−
24
16
8
1 oe
2 B1 for
−
−
24
16k
or B1 for
dc
ba
8
1
18 (a) (1.5, 12.5) oe 2 B1 for either coordinate
(b) y = 3x + 8 oe 3 B2 for y = mx + 8 or y = 3x + c or 3x + 8
or B1 for gradient (or m) = 3 and B1 for c = 8
If 0 scored, SC1 for 23 = their m × 5 + c
or for 2 = their m × –2 + c
or for 12.5 = their m × 1.5 + c
(c) Most common methods:
Correctly substituting P (3, 17) into
y = 3x + 8
Showing the gradient of AP or BP = 3
Other methods possible.
1
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 22
© Cambridge International Examinations 2013
19 (a) –2a – 2c oe 2 M1 for BO = –a – c or for any correct route or correct
unsimplified expression
(b) 2a + c 2 M1 for any correct route or correct unsimplified
expression
(c) –a – c oe 2FT FT their (a) or correct answer
Or M1 for a correct non direct route from O to E or for
correct unsimplified expression or for correct FT
unsimplified
20 (a) 4.05 to 4.2 1
(b) 2.6 to 2.75 2 B1 for 9.6 seen
(c) 2.05 to 2.25 2 B1 for [UQ] 5.0 to 5.1 and [LQ] 2.85 to 2.95 seen
(d)
48
5
2
M1 for 5
21
(a) 37.2 or 37.17 to 37.19
3 M2 for sin[ ] = 6
65sin4×
or M1 for 65sin
6
sin[]
4= oe
(b) 11.7 or 11.72 to 11.74 3 M1 for [B =] 160 – 65 – their (a)
M1 for 2
1 × 4 × 6 × sin their 77.8
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/23 Paper 2 (Extended), maximum raw mark 70
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
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Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 23
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only
cso correct solution only
dep dependent
ft follow through after error
isw ignore subsequent working
oe or equivalent
SC Special Case
www without wrong working
Qu. Answers Mark Part Marks
1 39 2 M1 for 52 × 45 ÷ 60 oe
2 Any two of (20, 8) (–4, 0) (12, 24) 2 B1 for one correct
3
–8
2 M1 for 2x = –16 or 5.72
1−=+ x oe or better
4 tan 100, cos 100, 1/100, 100–0.1 2 B1 for decimals –0.1[[7..], –5.[67..], [0.01],
0.6[3..] or for three in the correct order
5 (a) 600 000 1
(b) 79.2 2 M1 for 22 × 60 × 60 ÷ 1000 oe
6
25[.00]
3 M2 for 30 × 120
100oe
or M1 for 30 associated with 120%
e.g. 1.2x = 30
7 5 3 M2 for (x – 5)(x – 1)
or
M1 for evidence of a factorisation which gives
the correct coefficient of x or positive prime
constant term e.g. (x – 7)(x + 1), (x – 4)(x – 2),
(x – 3)(x – 1)
8 1.6 oe 3 M1 for m = kx3
A1 for k = 25
9 (a) a2 + 2ab + b2 2 B1 for a2 [+] ab [+] ab [+] b2 or better seen
(b) 22 1
10
160
3 M1 for sin 15 = 628
[]oe or better
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 23
© Cambridge International Examinations 2013
11 (a)
−
24
13
1
(b)
− 24
12
10
1oe
2 B1 for
dc
ba
10
1or B1 for
− 34
12k
12
(a) 7.5 × 10–2
2 M1 for 0.075 or 40
3or
80
6or 0.75 × 10–1 oe
(b) 9.3 × 107 2 M1 for 93 000 000 or 93 × 106 or 0.93 ×108 oe
13 (a) 24 2 M1 for MOC = 48
(b) 24 2 M1 for ACM = 66
or
B1 for 48 – their (a)
14 (a) 8q–1 or q
8
2
B1 for 8qk or kq–1
(b) 1/5 or 0.2
2 M1 for 5–2,2
5
1or [0].04 seen oe
15 (a) Circle, radius 3 cm, centre A, not
inside the rectangle
2 M1 for arc or full circle centre A radius 3 cm
or for an incorrect size circle at A outside
rectangle
(b) One line of symmetry with correct
arcs. E.g.:
2 B1 for correct ruled line (must reach or cross two
sides)
B1 for 2 pairs of intersecting arcs
16
(a) 8.61 or 8.609 to 8.6102
4 M1 for 120sin32
1 2×π××
M1 for [ ]23360
30 2××π×
M1 for area of triangle + 2 sectors
(b) 430 or 431 or 430.4 to 430.41 1FT FT their (a) × 50
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 23
© Cambridge International Examinations 2013
17 (a) triangle at (0, 3) (2, 3) and (2, 4) 3 B1 for each correct vertex
If 0 scored then M1 for correct reflection in the
y axis or correct translation of their first stage 3
right 2 up
(b) reflection in y axis 2 B1 for reflection
B1 for y axis or x = 0
18 (a) 19–19.1 1
(b) 3 2 M1 for 47 seen
(c) 4.9 to 5.7 2 B1 for [UQ] 21.7 to 22.2 and [LQ] 16.5 to 16.8
(d)
50
45 oe
2 B1 for 45 seen or
SC1 for 50
5isw
19 (a) 75 2 B1 for [g(6) =] 36
(b) 3.5 –6.5 3 M1 for (2x + 3)2 = 100
M1 for 2x + 3 = [±]10
If 0 scored, SC1 for one correct value as answer
(c)
2
3−x oe final answer
2 M1 for x = 2y + 3 or y – 3 = 2x or 2
3
2+= x
y
or better
(d) 5 1
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/31 Paper 3 – Core maximum raw mark 104
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
![Page 25: 0580 MATHEMATICS - Max Papersmaxpapers.com/wp-content/uploads/2012/11/0580_w13_ms_all.pdf · CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education](https://reader030.vdocuments.us/reader030/viewer/2022021418/5a9e49a37f8b9a6a218d3844/html5/thumbnails/25.jpg)
Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 31
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only
cso correct solution only
dep dependent
ft follow through after error
isw ignore subsequent working
oe or equivalent
SC Special Case
www without wrong working
Qu. Answers Mark Part Marks
1 (a) (i)
(ii)
(iii)
(iv)
(b)
(c) (i)
(ii)
36 cao
5, 2, 3, 4, 3, 8, 1, 4
fully correct bar chart
26 – 30 cao
7 (hours) 25 ( minutes) cao
238.48
75
1
2
3FT
1
1
2
2
B1 for 6 or 7 frequencies correct
or 8 correct tallies if frequency column
blank
or 8 correct frequencies in tally column
B1 for a correct linear scaled frequency
axis
B2FT for correct height and equal width
of bars
or
B1FT for correct height of at least 5 bars
or all bars correct height but unequal
widths or gaps
SC2 for a fully correct bar chart but linear
scale not marked
M1 for 167 × 1.428 soi by 238.47(6) or
238.5 or 238
M1 for 107.1 ÷ 1.428
2 (a) (i)
(ii)
(b) (i)
(ii)
(iii)
(c) (i)
2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30,
40, 60.
60
60
49
2
Any correct example
1
2
1
1
1
1
Award mark for any one from list.
B1 for any common factor on answer line,
1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30
Calculation and correct answer must be
seen
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 31
© Cambridge International Examinations 2013
(ii)
(d) (i)
(ii)
(iii)
Any correct example
>
>
<
1
1
1
1
Calculation and correct answer must be
seen
3 (a) (i)
(ii)
(b) (i)
44 – 46
231 – 235
Fully correct drawing with arcs
52250 to 60500 nfww
1
1
3
3FT
B2 for correct triangle without arcs
B1 for 1 correct length side
Or arc of 6cm or 8cm
M2 for 2
1 × 550 ×
(their correct height × 50)
Or 2
1 × 11 × their correct height in cm
or
B1 for their correct height in cm
or their correct height × 50 seen
If 0 scored then SC1 for 2
1 × 550 ×
(50 × k)
4 (a) (i)
(ii)
(b) (i)
(ii)
Translation
−
−
8
7
Enlargement
[Scale factor] 0.5
[Centre] (0, 0)
D at ( –2, 4) (–4 , 4) (–3 , 6)
E at ( –4, 2) ( –4 , 4) ( –6 ,3)
1
1
1
1
1
1
2
Accept 7 left and 8 down
B1 for correct orientation, incorrect centre
or 90° rotation clockwise about (0,0).
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 31
© Cambridge International Examinations 2013
5 (a) (i)
(ii)
(b) (i)
(ii)
(iii)
(c)
230
252
9
3.5
4
x = 1.5 or 3/2
y = –5
2
2
1
2
3
4
M1 for 130 + 4 × 25 or better
M1 for 4n = 1138 – 130 or better
Or (1138 – 130) / 4 or better
M1 for 8y = 24 + 4 or better
Or y – 4/8 = 24/8 or better
M1 for first correct step
M1FT for second correct step
M1 for correctly equating one set of
coefficients.
M1 for correct method to eliminate one
variable.
A1 for x = 1.5
A1 for y = –5
6 (a)
(b) (i)
(ii)
(c)
(d) (i)
(ii)
252.56
510
170
102
136
34.5
63.6 or 63.61 – 63.63
127 or 127.2…
2
2
3
3
2
1FT
M1 for (30 + 30 + 17) × 3.28 or better oe
M1 for 30 × 17
M2 for 2 correct areas clearly identified
or M1 for 408 ÷ (5 + 3 + 4) soi by 34 or
one correct area clearly identified
SC2 for three correct answers in incorrect
places
M2 for 221730 + soi by 1189
or M1 for 302 + 172 soi by 1189
M1 for 4.52 × π or 20.25 π
FT for their (d)(i) × 2
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Page 5 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 31
© Cambridge International Examinations 2013
7 (a)
(b)
(c)
(d) (i)
(ii)
14, 4, 2, 8, 14
8 points correctly plotted
Smooth and correct curve through all
correct points
x = 0.5 or x = 2
1
y = 9 ruled
–2.15 to –2.25
3.15 to 3.25
3
P3FT
C1
1
1
1FT
1FT
B2 for 4 correct
B1 for 2 or 3 correct
P2FT for 6 or 7 points correctly plotted
P1FT for 4 or 5 points correctly plotted
8 (a) (i)
(ii)
(iii)
(b) (i)
(ii)
(c)
(d) (i)
(ii)
July or Jul
10.9
– 9.6
150 ÷ 360
90 oe
250
11682
4.48 × 106 cao
9.82
1
1
1
1
3
3
1
3
Accept 150 × 90
360, 150 × 4
M1 for their 150/360 × 600 or their
150 × 150/90
and B1 for 150 seen as angle
M2 for 885 × 15 × 0.88 oe
M1 for 885 × 0.88 oe
or 885 × 15 × 0.12 oe
M2 for 4480000
44800004920000− × 100 oe
or
−1
4480000
4920000× 100 oe
or
B1 for 440000 or 0.44 or 1.098(….)
or 109.8(…..)
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Page 6 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 31
© Cambridge International Examinations 2013
9 (a) (i)
(ii)
(iii)
(b) (i)
(ii)
(c)
Chord
Radius
12
Tangent [meets] radius [at] 90 [°]
66
Angles [in] triangle 180 or
Angle [in a] semi–circle [= 90]
Octagon
360 ÷ 8 [= 45]
(180 – their 45) ÷ 2
67.5
15
1
1
1
1
2
1
1
M1
M1FT
A1
2
M1 for BCD identified as 90
or 180–24–90
alternative method
M1 for (8–2) × 180 [=1080]
or 6 × 180 [=1080]
M1FT for (their 1080 ÷ 8) ÷ 2
or their 1080 ÷ 16
A1 for 67.5
M1 for 360 / 24
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/32 Paper 3 (Core), maximum raw mark 104
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
![Page 31: 0580 MATHEMATICS - Max Papersmaxpapers.com/wp-content/uploads/2012/11/0580_w13_ms_all.pdf · CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education](https://reader030.vdocuments.us/reader030/viewer/2022021418/5a9e49a37f8b9a6a218d3844/html5/thumbnails/31.jpg)
Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 32
© Cambridge International Examinations 2013
Abbreviations cao correct answer only cso correct solution only dep dependent ft follow through after error isw ignore subsequent working oe or equivalent SC Special Case www without wrong working
Question. Answers Mark Part Marks
1 (a) Scalene [triangle]
(b) Congruent
(c) (i) translation
−
2
6
(ii) rotation
180°
[Centre] ( 0,0 )
(d) Image (1, –2), (4, –2), (2, –3)
(e) Image (2, 4), (8, 4), (4, 6)
(f) 6
1
1
1
1
1
1
1
1
2
2FT
Accept 6 left and 2 up.
SC1, 1, 1 for
Enlargement, [SF=] –1,(0,0)
B1 for 2 times enlargement, incorrect centre
M1 for 0.5 × their base × their height
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 32
© Cambridge International Examinations 2013
2 (a) (i) 9
5
(ii) 60
(b) 1080
(c) 0.85 × 3450
Or 3450 – 0.15 × 3450
(d) 32
2
2
3
2
3
B1 for 144
80 or better or 0.556 or 0.555… or
answer 9
4
M1 for 144 ÷ (6+5+1) or 144÷12
M1 for 2 ÷ 5 × 5200 soi by 2080
And M1 for
their 2080 + 24×175 – 5200 or better
B1 for 0.85 or for 0.15 × 3450
M2 for 1002500
25003300×
−
oe
or ( 2500
3300 – 1 ) × 100 oe
Or
B1 for 800 or 2500
25003300− or
2500
3300 or
1.32 or 132 or 0.32
3 (a) (i) 4n + 21, final answer
(ii) 5n + 3 = 3n + 27
[n =] 12
(iii) 126
(b) (i) yellow
(ii) arrow pointing at 0.5
(iii) 20
4 o.e. or 0.2 or 20%
(iv) 20
16 o.e. or 0.8 or 80%
1
1
2
1FT
1
1
1
1FT
M1 for 5n – 3n = 27 – 3 or better
SC1 for 4 out of 20 and 16 out of 20
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 32
© Cambridge International Examinations 2013
4 (a) (i) 370 to 380
(ii) [0]36 to [0]40
(iii) Intersecting arcs:
Arc centre A radius 10.5 cm
Arc centre B radius 7 cm
(iv) 300 to 310
(b) 11 25
(c) 4200
(d) 13.1
(e) 8515
2
1
2
1FT
3
1
2
1
B1 for 7.4 to 7.6 seen
B1 for one correct arc
or C correct with no arcs
M2 for 525 ÷ 700 × 60 or better soi
Or M1 for 525 ÷ 700 soi by 0.75
B1 for 13 100 or 13.107 or 13.100
Or B1FT their conversion to 4 or more sig
figs seen and then correctly rounded to 3 sig
figs
5 (a) –1 –1.25 2.5 1
(b) 10 correctly plotted points
Two correct smooth curves through
all correct points and not across
y-axis
(c) 1.15 to 1.35
(d) (i) Line x = –3.5 ruled
(ii) (5, –3) plotted
(iii) line y = –3 ruled
2
P3FT
C1
1FT
1
1
1FT
B1 for two correct
P2FT for 8 or 9 correctly plotted
P1FT for 6 or 7 correctly plotted
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Page 5 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 32
© Cambridge International Examinations 2013
6 (a) (i) 26
(ii) 16
(iii) 17 –3
(b) (i) 9 17
(ii) odd
(c) (i) 23
(ii) 5n + 3 oe final answer
(iii) 19
1
1
2
2
1
1
2
2
B1 for each
B1 for one correct in correct position
or FT for fourth term
B1 for 5n + k , jn + 3 j ≠ 0
Or 5n + 3 oe not as final answer
M1FT for their (c)(ii) = 98 if linear soi
7 (a) 23
(b) [Affected by an] extreme value oe
(c) 40.9
(d) (i) 6 points correctly plotted
(ii) positive
(iii) line of best fit ruled and
continuous
(iv) No, [estimate unreliable as]
outside range [of data]
2
1
2
P2
1
1
1
M1 for clear attempt to find middle
If zero scored then SC1 for 40
M1 for
(36+38+42+36+45+42+32+40+40+46+56+38)
÷ 12 implied by 491 ÷ 12
If zero scored then SC1 for 26.25 or 26.3
P1 for 4 or 5 correctly plotted
dep on at least 11 points on graph
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Page 6 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 32
© Cambridge International Examinations 2013
8 (a) 7
Pentagon
(b) (i) trapezium
(ii) 125°
(iii) 32°
(c) (i) 90°
angle [in a] semicircle [=90°]
(ii) 55°
(iii) 93°
1
1
1
1
2
1
1
1
3
M1FT for 180 – 125 – 23 or better
or 180 – their 125 – 23 or better
M2 for 90 – 52 or 180 – 90 – 52 or 38
If M0 then B1 for angle CAD = 90° indicated
9 (a) (i) 7
(ii) –32
(iii) –11
(b) (i) 1.05 × 107
(ii) 4 580 000
(iii) Kaliningrad
(iv) 2.7 × 105
1
1
1
1
1
1
2
Allow –7
B1 for figs 27
10 (a) 3.5
(b) 2n – 18 or 2 ( n – 9 ) final answer
(c) 5p2(2 + p) final answer
2
2
2
M1 for 6x – 12 = 9 or better
or x – 2 = 6
9 or better
B1 for 8n – 8 or –6n –10 or 2n or –18
M1 for any correct incomplete factorisation
or 5p2(2 + p) seen in working
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/33 Paper 3 – Core, maximum raw mark 104
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
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Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 33
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only
cso correct solution only
dep dependent
ft follow through after error
isw ignore subsequent working
oe or equivalent
SC Special Case
www without wrong working
Qu. Part Answers Mark Part Marks
1 (a)
(b)
(c)
(d)
240 900
[Total] 1640
(i) 600 ÷ 5 × 17
(ii) 30
43.1
261.36 cao
1,1
1FT
M2
2
2
3
500 + their 2 costs
M1 for 600 ÷ 5 or 17 ÷ 5
M1 for 2040 ÷ 17 × 3
Or 120 × 3, soi by 360
M1 for 1002040
20402920×
−
oe
or 100)12040
2920( ×− oe
or 1001002040
2920−× oe
M1 for 1500 × 1.0553 oe
M1FT for their 1761.36 – 1500
If only 1 scored SC1 for correctly rounding to
2 decimal places from at least 3 decimal places
SC2 if only 1761.36 seen
2 (a)
(b)
Kite
(i) Rotation
90° clockwise (or 270° anti-
clockwise) oe
[centre] origin oe
(ii) Translation
−
−
10
2
1
1
1
1
1
1
Accept 2 left and 10 down oe
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 33
© Cambridge International Examinations 2013
(c)
(iii) Enlargement
[Scale Factor] –3
[centre] (–3, 4)
(i) [x2 =] 32 + 12
[x =] 2213 + or [x = 19 +
or 10 and = 3.162…
(ii) 9.15
(iii) 27.45 to 27.5
1
1
1
M1
M1dep
3
1FT
M1 for 32 + 12 or better
Needs a value to 3 or more decimal places
B1 for 2 or 1.41 or better seen
M1 for 2 x 3.16 + 2 x their 1.41...
soi by 9.14
If zero scored SC1 if answer in range 8.6 to 9.6
their (c)(ii) ×3
3 (a)
(b)
(i) 28
(ii) 25 or 49 or 9 or 1
(iii) 2
(iv) 19 or 29
(i) 5
(ii) 27
1
1
1
1
1
2
B1 for 8
1 or 216 seen
4 (a)
(b)
(c)
(i) 40
(ii) 140
(i) [w =] 90
(ii) [x =] 24
(iii) [y =] 66
[z =] 66
[Angle between] tangent [and]
diameter/radius [=] 90°
2
1FT
1
1
1FT
1FT
1
M1 for 360 ÷ 9
180 – their (a)(i)
180 – (their w + their x)
(90 – their x) or their y
5 (a)
(i) 1, 7, 1
(ii) 8 points correctly plotted
Correct smooth curve through all 8
correct points
1, 1, 1
P3FT
C1
P2FT for 6 or 7 correct
P1FT for 4 or 5 correct
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 33
© Cambridge International Examinations 2013
(b)
(c)
(d)
–1.1 to –1.3 and 4.1 to 4.3
(i) Line x = 1.5 drawn
(ii) x = 1.5 oe
(i) Ruled continuous line drawn
(ii) 1
(iii) [y =] x + 2
1FT,
1FT
1
1FT
1
2
1FT
Equation of their line in (c)(i)
M1 for run
rise for their line
their (d)(ii) + their 2
6 (a)
(b)
(c)
(d)
(i) 18
(ii) 7
(iii) 25
Alison with reference to [higher] mean
and
Bethan with reference to [higher] median
(i) [Frequencies] 3, 2, 1
[Angles] 72°, 48°, 24°
(ii) Two correct sectors on pie chart
3 ‘correct’ labels
5
2
2
1
2
1FT
1FT
1
2
2FT
1
2
M1 for evidence of ordering
M1 for sum of 15 items ÷ 15 soi
Strict FT
Strict FT
B1 for 1 correct or
M1 for one frequency ÷ 15 × 360
or × 24
B1FT for 1 correct sector
Only ft if (c)(i) angles total 144
Independent
B1 for 0.4 or 40% or 15
6 or any equivalent
fraction
7 (a)
(b)
(c)
[Angle DCE =] 36.9 or 36.8699 to 36.9
1.875 or 1.88
3.75
3
2
1FT
B1 for [DE =] 0.75 soi
M1 for than DCE = 0.1
DEtheir
M1 for 0.5 × (1.5 + 2.25) × 1.0 oe
their (b) × 2
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Page 5 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 33
© Cambridge International Examinations 2013
(d)
3 rectangles and 1 trapezium correctly
placed on the grid with correct scale and
size.
4
B1 for rectangle to right 6 by 8 squares
B1 for an accurate and correctly placed
trapezium
B1 for a rectangle to left 9 by 8 squares
B1 for rectangle 5 by 8 squares and further to
the left
8 (a)
(b)
(c)
(d)
(e)
Octagon
[Pattern 3] 20 and 22
[Pattern 4] 26, 29
[Pattern 7] 44, 50
(i) 6n + 2 oe final answer
(ii) 140 oe
7n + 1 oe final answer
n – 1 final answer
1
1
1, 1
1, 1
2
1FT
2
2FT
B1 for 6n + a or bn + 2 b ≠ 0
ft linear expression in (c)(i)
B1 for 7n + c or dn + 1 d ≠ 0
B1FT for n + j or kn 1 k ≠ 0
9
(a)
(b)
(c)
(i) [r =] h
V
π
3
(ii) [r =] 15
1413
x
x
π
[r =] 2.99…
18.9 or 18.8 or 18.849 to 18.852
1.9 [cents] cao
2
M1FT
A1
2
3
B1 for [r2 =] h
Vor
V 33
π
seen or better
their formula
M1 for 2 × π × 3 oe
M1 for 2,15 (or 215) ÷ 113
A1 for 0.019 (0…) or 1.9 (0…) soi
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/41 Paper 4 (Extended), maximum raw mark 130
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
![Page 42: 0580 MATHEMATICS - Max Papersmaxpapers.com/wp-content/uploads/2012/11/0580_w13_ms_all.pdf · CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education](https://reader030.vdocuments.us/reader030/viewer/2022021418/5a9e49a37f8b9a6a218d3844/html5/thumbnails/42.jpg)
Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 41
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only
cso correct solution only
dep dependent
ft follow through after error
isw ignore subsequent working
oe or equivalent
SC Special Case
www without wrong working
art anything rounding to
soi seen or implied
Qu Answers Mark Part Marks
1 (a) (i)
5
2 cao
1
(ii) 3 : 2 cao 1
(b) (i) 1.22
2
M1 for 86.38 – 28 × 1.56
(ii) 1.3 [0] nfww 3 M2 for 1.56 ÷ 1.2 oe
or M1 for 1.56 = 120% soi
(c) 33.6[0] 2 M1 for (667 – 314.2) ÷ 10.5 oe
2 (a) 3 correct lines on grid
(0, 0) to (40, 5)
(40, 5) to (100, 5)
(100, 5) to (120, 0)
2 Allow good freehand
SC1FT for 2 lines correct, FT from an incorrect
line
(b)
40
5 oe
1
(c) 3.75 4 M2 for 0.5 × 40 × 5 + 60 × 5 + 0.5 × 20 × 5 oe
[450]
or M1 for evidence of a relevant area = distance
and M1dep their area (or distance) ÷ 120
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 41
© Cambridge International Examinations 2013
Qu Answers Mark Part Marks
3 (a) (i) 204 or 204.2 to 204.23 2 M1 for 135××π implied by answer in range
204.1 to 204.3
(ii) 12 cao
3 M2 for 22513 − or states 5, 12, 13 triangle
or M1 for 132 = 52 + h2 or better
(iii) 314 or 314.1 to 314.2
2 M1 for ×××2
53
1π their (a) (ii) implied by
answer in range 314 to 314.3
(iv) 3.14 × 10–4 or 3.141 to
3.142 × 10–4
2FT FT their (a) (iii) ÷ 1003 correctly evaluated and
given in standard form to 3 sig figs or better
or M1 FT for their (a) (iii) ÷ 1003
or SC1 for conversion of their m3 into standard
form only if negative power
(b) 138 or 138.3 to 138.5
4 M3 for 36026
10×
π
π
oe or
36013
135
2×
×
××
π
π (i)(a)or their oe
or M2 for a correct fraction without × 360
or M1 for 132××π oe [81.6 to 81.8] seen
or 2
13×π oe [530.6 to 531.2] seen
4 (a) 45.[0] or 45.01 to 45.02 nfww 4 M2 for 552 + 702 – 2.55.70 cos 40
or M1 for correct implicit equation
A1 for 2026. ….
(b) 84.9 or 84.90 to 84.92 4 B1 for angle BDC = 40 soi
M2 for 32sin
)40(sin70 their
or M1 for correct implicit equation
(c) (i) 4060 or 4063 to 4064 nfww
3
M2 for 2
1 ( )40sin 70 × 55 + 2
1
( ))3240180(sin)(70 −−× theirbtheir oe
or M1 for correct method for one of the triangle
areas
(ii) 1020 or 1015 to 1016
2FT
FT their (c) (i) ÷ 4 oe correctly evaluated
or M1 their (c) (i) ÷ figs 4 oe
(d) 35.4 or 35.35… nfww
2 M1 for sin 40 = 55
distance or better
or for 2
1 (55 × 70 sin 40) = (70 × distance) ÷ 2
or better
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 41
© Cambridge International Examinations 2013
Qu Answers Mark Part Marks
5 (a) (i) Correct reflection to (4, 8)
(2, 9) (4, 9)
2
SC1 for reflection in line x = 5
or reflection in y = k
Ignore additional triangles
(ii) Correct rotation to (4, 2), (4, 3)
(6, 3)
2
SC1 for rotation 180˚ with incorrect centre
Ignore additional triangles
(iii) Shear, x-axis oe invariant,
[factor] 2
3 B1 each (independent)
(iv)
10
21
2FT
FT their shear factor
B1FT for one correct column or row in 2 by 2
matrix but not identity matrix
or SC1FT for
12
01
(b) (i) p + 2s final answer
2 M1 for recognising OQ as position vector soi
(ii) s +
2
1p final answer
2 B1 for s + kp or ks + 2
1p
or correct route (k ≠ 0)
(c) parallel and OQ = 2SR oe 1
6 (a) (i) 1.4 to 1.6 1
(ii) 1.15 to 1.25 1
(iii) – 1 1
(iv) – 2.25 to – 2.1
– 0.9 to – 0.75
2.2 to 2.35
3 B2 for 2 correct or B1 for one correct
or B1 for y = x drawn ruled to cut curve 3 times
(b) (i) – 15 2 B1 for [h(3) =] 8 seen
or M1 for 1 – 2(x2 – 1) or better
(ii)
2
1 x−
or 22
1 x
− oe final answer
2
M1 for2 x = 1 – y or x = 1–2y or better
(iii) – 2, 2
3 M1 for x2 – 1 = 3 or better
B1 for one answer
(iv)
8
1 oe nfww
3 M2 for 8x = 1 or 8x – 1 = 0
or M1 for 1 – 2(3x) [= 2x]
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Page 5 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 41
© Cambridge International Examinations 2013
Qu Answers Mark Part Marks
7 (a) 24.7 or 24.66 to 24.67 4 M1 for midpoints soi
(condone 1 error or omission)
(5, 15, 25, 35, 45, 55)
and
M1 for use of ∑fx with x in correct interval
including both boundaries (condone 1 further
error or omission)
and
M1 (dependent on second M) for ∑fx ÷ 120
(b) (i) 50, 90, 114 2 B1 for 2 correct
(ii) Correct curve
or ruled polygon
3 Ignore section to left of t = 10
B1 for 6 correct horizontal plots
and B1FT for 6 correct vertical plots
If 0 scored SC1 for 5 out of 6 correct plots
and
B1FT for curve or polygon through at least 5 of
their points dep on an increasing curve/polygon
that reaches 120 vertically
(iii) 21.5 to 23
15 to 16.5
24 to 26
4
B1
B1
B2 or B1 for 72 or 72.6 seen
(c) (i) 50, 30 2 B1 each
(ii) Correct histogram
3FT B1 for blocks of widths 0 – 20, 30 – 60 (no
gaps)
B1FT for block of height 2.5 or their 50 ÷ 20
and B1FT for block of height 1 or their 30 ÷ 30
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Page 6 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 41
© Cambridge International Examinations 2013
Qu Answers Mark Part Marks
8
(a) ( ) ( )( )1184112
−−− or better
p = –(– 11), r = 2(8) or better
– 0.67, 2.05 final answers
B1
B1
B1B1
Seen anywhere or for
2
16
11
−x
Must be in the form r
qp + or
r
qp −
or B1 for 16
11
16
11
8
112
+
+
SC1 for – 0.7 or – 0.672 to – 0.671 and 2.0 or
2.046 to 2.047
or answers 0.67 and – 2.05
(b) 132
3 M1 for xky = oe or kyx = oe
A1 for k = 6 oe or better or for k = 0.1666 to
0.167
[k = 6 implies M1A1] oe
(c) 20 with supporting algebraic working
6 B2 for 195.0
5.14
5.2=
−+xx
oe
or B1 for 5.2
x
or 5.
5.14−x
M1dep on B2 for first completed correct move
to clear both fractions
M1 for second completed correct move to
collect terms in x to a single term
M1 for third completed correct move to collect
numeric term[s] leading to ax = b
SC1 for 20 with no algebraic working
9 (a) y = 2 oe
y = 2x oe
y = – 2
1 x + 5 oe
1
2
2
M1 for y = kx, 0≠k or gradient 2 soi
M1 for gradient – ½ soi or y = kx + 5oe
or x + 2y = k 0≠k oe
If L2 and L3
both correct but interchanged then
SC3
(b) y ≥ 2 oe
y ≤ 2x oe
y ≤ – 2
1 x + 5 oe
3
B1 for each correct inequality, allow in any
order
After 0 scored, SC1 for all inequalities reversed
(c) (i) 4 [bushes], 3 [trees]
2
M1 for any correct trial using integer
coordinates in region
or 30x + 200y = 720 seen
(ii) 2 [bushes], 4 [trees]
860
2
1
M1 for any correct trial using integer
coordinates in region
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Page 7 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 41
© Cambridge International Examinations 2013
Qu Answers Mark Part Marks
10 (a) (i) 1 + 2 + 3 + 4 + 5 = 15 1
(ii) Correct substitution equating to
sum
e.g. ( )
3122
=+
kand k = 2 stated
with no errors seen
2 M1 for using a value of n in ( )k
nn 1+
e.g. ( )
3122
=+
k
or for a verification using k = 2
e.g. ( )
32
122=
+
(iii) 1830 1
(iv) 30
2 M1 for ( )2
1+nn
= 465 or better
(v) n – 8 1
(b) (i) 225, 15 2 B1 either
(ii)
( )4
122
+nn
oe
1
(iii) 36100
2 M1 for ( )4
1191922
+ oe or 1902
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/42 Paper 4 (Extended), maximum raw mark 130
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
![Page 49: 0580 MATHEMATICS - Max Papersmaxpapers.com/wp-content/uploads/2012/11/0580_w13_ms_all.pdf · CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education](https://reader030.vdocuments.us/reader030/viewer/2022021418/5a9e49a37f8b9a6a218d3844/html5/thumbnails/49.jpg)
Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 42
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only
cso correct solution only
dep dependent
ft follow through after error
isw ignore subsequent working
oe or equivalent
SC Special Case
www without wrong working
art anything rounding to
soi seen or implied
Correct answer Mark Part marks
1 (a) (i) 3216 Final answer 2 M1 for (18900 – 5500) × 0.24 oe
(ii) 1307 Final answer 2FT FT (18900 – their (a)(i)) ÷ 12 correctly
evaluated
M1 for (18900 – their (a)(i)) ÷ 12
(b) 4.5[%] nfww
2 M1 for 10018900
]18900[50.19750×
−
or 18900
1890050.19750 −
(c) A by 31.05…
or 31.04 to 31.05
or 31.[0]
31.1[0]
5 M1 for 1500 × 4.1/100 × 3 [+ 1500] oe
M1 for 1500 × 1.0333 [– 1500] oe
A1 for 1684.5 or 184.5 or 1653[.45..] or
153[.45..]
and M1dep for subtraction of their amounts or
their interests
2 (a) 36.9° or 36.86 to 36.87 2 M1 for tan[DBC] = 1.8/2.4 oe
(b) (i) 1.8² + 2.4² leading to 9
2
M1 for 1.8² + 2.4² or better
(ii) [cosABD) =]
346.62
6.8346.6222
××
−+
127 or 126.8…
M2
A2
M1 for correct cos rule but implicit version
A1 for –0.599…
After 0 scored, SC2 nfww for answer 127 or
126.8 to 126.96 from other methods or no
working shown
(c) 39.6 or 39.7 or 39.59 to 39.68 3 M2 for ½ (2.4 + 8.6) × 1.8 × 4 oe
Or M1 for )6.84.2(2
8.1+ oe soi by 9.9 to
9.92
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 42
© Cambridge International Examinations 2013
3 (a) 10
74 −x
final answer nfww
3 M2 for 52
)13(2)12(5
×
+−− xx
or 25
)12(5
×
−x–
25
)13(2
×
+x
or M1 for attempt to convert to common
denominator of 10 or multiple of 10 with one
error in numerator
(b) x² + 9 final answer nfww 4 B3 for 4x² – 6x – 6x + 9 – 3x² +12x or correct
answer given and
then spoilt
or B1 for 4x² – 6x – 6x + 9 seen and B1 for
– 3x² +12x or – (3x² – 12x) seen
(c) (i) (2x – 1)(x + 3) isw solving 2 M1 for (2x + a)(x + b) where ab = –3 or
2b + a = 5 with integers a and b
(ii)
)3(2
12
−
−
x
x
or 62
12
−
−
x
x
final answer nfww
3
M2 for 2(x + 3)(x – 3) or (2x – 6)(x + 3) or
(2x + 6)(x – 3) seen
or M1 for 2(x² – 9) seen
4 (a) (i) 90 ÷ (42/360 × π × 82) o.e.
3.836 to 3.837
M3
A1
M2 for 42/360 × π × 82 × h = 90
or M1 for 42/360 × π × 82
(ii) 131 or 130.75 to 130.9 nfww 5 M2 for 42/360 × π × 2 × 8 × 3.84 oe
[22.48 to 22.53]
or M1 for 42/360 × π × 2 × 8 oe soi
[5.86 to 5.87]
and M1 for 2 × (8 × 3.84)
[61.37 to 61.44]
and M1 for 2 × (42/360 × π × 82)
[46.88 to 47]
(b) 2.42 or 2.416 to 2.419
3 M2 for 3.84 × 390
5.22oe or h = 3
3
90
5.2284.3 ×
or M1 for 390
5.22oe or 3
5.22
90oe seen
or 3
384.3
h =
5.22
90oe
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 42
© Cambridge International Examinations 2013
5 (a) 7, 11.5, 4.5 1,1,1
(b) Correct curve cao
5
B3FT for 10 correct plots, on correct vertical
grid line and within correct 2 mm square
vertically
Or B2FT for 8 or 9 correct plots
Or B1FT for 6 or 7 correct plots
and B1 indep for two separate branches on
either side of y-axis
(c) (i) 0.69 < x < 0.81 1
(ii) –2.3 < x < –2.2
–0.8 < x < –0.6
0.35 < x < 0.5
3
B1 for each correct
After 0 scored, allow SC1 for drawing line
y = 7.5 long enough to cross curve at least once
(d) (i) y = 10 – 3x ruled correctly
–0.55 < x < –0.45
0.35 < x < 0.45
B2
B1dep
B1dep
long enough to cross curve twice.
B1 for ruled line gradient –3 or y intercept at
10 but not y = 10
Or B1 for ‘correct’ but freehand
Dependent on at least B1 scored for line
After 0 scored, SC2 for –0.5 and 0.4 [from
solving equation]
(ii) 10 1 –2
or –10 –1 2
3 B2 for 2 – x – 10x2 [= 0] oe
Or B1 for 01012
2=−−
xx
oe Correctly
eliminating – 3x
Or B1 for 2 – x – 3x3 = 10x2 – 3x3 oe Correctly
clearing fractions
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Page 5 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 42
© Cambridge International Examinations 2013
6 (a) (i) 110
1 oe
2 M1 for 10
1
11
1×
(ii)
110
6 oe
55
3
2 M1 for 10
2
11
3×
(iii)
110
8 oe
55
4
2FT FT their (a)(ii) + 10
1
11
2× correctly evaluated
or M1 their (a)(ii) + 10
1
11
2×
(b) (i)
990
6 oe
165
1
2 M1 for 9
1
10
2
11
3××
(ii)
990
336 oe
165
56
2 M1 for 9
6
10
7
11
8××
(iii)
990
198 oe
5
1
5 M4 for
××+
××
9
9
10
1
11
23
9
8
10
2
11
33 oe
or M3 for
××
××
9
9
10
1
11
23
9
8
10
2
11
33 or
oe
Or
M1 for 9
8
10
2
11
3×× oe seen and M1 for
××9
9
10
1
11
2 oe seen
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Page 6 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 42
© Cambridge International Examinations 2013
7 (a) 14 10 or 2 10 pm final answer 2 M1 for (0)8 10 oe or answer 14 hours and
10 minutes or answer 2 10 [am]
(b) 5 hours 45 minutes cao 2 M1 for 345 [mins] seen or for 805 /7 × 3 oe or
5.75 seen
(c) (i) 798 or 798.2 to 798.4….
2 M1 for 10712 / 60
2513 or 10712 ÷ 13.4…
(ii) 1.82 × 105
or 1.815 × 105 to 1.816 × 105
4 B3 for 182000 or 181500 to 181600 seen
or M2 for 10712000/59 oe
or M1 for figs 10712/figs 59 soi by figs 182 or
figs 1815 to 1816
and B1 FT for their number of litres correctly
converted to standard form rounded to 3sf or
better
(d) 8600 3 M2 for 10148 ÷ 1.18 oe
or M1 for 10148 associated with 118[%]
8 (a) (i) –6 1
(ii) 2.75 oe 2 M1 for [g(x) =] 0.5 or 7/14
Or
++
+ 1
75
1
72
xx
oe
(b)
4
3−x or
4
x
– 4
3 Final answer
2
M1 for y – 3 = 4x or better or x = 4y + 3 or
better
or 4
y=
4
3 + x or flowchart with – 3 then ÷ 4
(c) (i) 5
2 M1 for 4x = 23 – 3 or x + 4
3 =
4
23 or better
(ii) x² + 5x – 7 = 0
)1(2
)7)(1(455 2−−±−
oe
1.14 and –6.14 final answers
B1
B1
B1
B1
B1
May be implied by correct values in formula
B1 for )7)(1(452 −− or better [53]
If in form r
qp +
orr
qp −
, B1 for –5 and
2(1) or better
No recovery of full line unless seen
Or SC1 for 1.1 or 1.140…. and –6.1
or – 6.140 …
Or answers –1.14 and 6.14
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Page 7 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 42
© Cambridge International Examinations 2013
9 (a) (i) Reflection
x = –2 oe
2
B1 for either
(ii) Translation
−
2
7 oe
2
B1 for either
(iii) Stretch
x-axis oe invariant
[factor] 3
3
B1 for each
(b) (i) Triangle with coords at (8, 2)
(7, 3) and (7, 5)
2 B1 for rotation about (6, 0) but 90°
anticlockwise
Or for rotation 90° clockwise around any point
(ii) Triangle with coords at
(–2, –5) (–6, –5) and (–8, –7)
2 B1 for 2 correct points or for enlargement of
SF –2 any centre
(iii) Triangle with coords at (1, –1)
(4, –6) and (3, –5)
2 B1 for 2 correct points or coordinates of
2 points shown
(c)
− 12
01
2
B1 for one row or one column correct but not
identity matrix.
Or SC1 for
−
10
21
10 (a) 48 and 57, 9n + 3 oe
(b) 56 and 50, 86 – 6n oe
(c) 125 and 216, n3 oe
(d) 130 and 222 n3 + n oe
1 2
1 2
1 1
1 1FT
B1 for 9n + k oe
B1 for k – 6n oe
FT their (c) + n dep on expression in n in (c)
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CAMBRIDGE INTERNATIONAL EXAMINATIONS
International General Certificate of Secondary Education
MARK SCHEME for the October/November 2013 series
0580 MATHEMATICS
0580/43 Paper 4 (Extended), maximum raw mark 130
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
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Page 2 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 43
© Cambridge International Examinations 2013
Abbreviations
cao correct answer only
cso correct solution only
dep dependent
ft follow through after error
isw ignore subsequent working
oe or equivalent
SC Special Case
www without wrong working
art anything rounding to
soi seen or implied
Qu. Answers Mark Part Marks
1 (a) (i) 45 2 M1 for 5 × 63 ÷ 7
(ii) 20 2 M1 for 5 × 56 ÷ 14
(iii)
23.4 or 23.38 to 23.41
3 M2 for 1009.413
8.48–9.413×
×
×
or 1009.4
138.48–9.4×
÷
Or
M1 for 9.413
8.48–9.413
×
×
or 1009.413
8.48×
×
or 76.6[…]
(b) 128 4 Using fractions (percentages / decimals):
M1 for 8
3
4
3×
=
32
9 or 5.37
100
75× [= 28.125%]
A1 for 32
9 or 28.125[%]
M1 for 36 ÷ 32
9 oe
or 36 × 125.28
100 oe
Partial percentages
M1 for (Remaining) 5.37
36100 ×
[= 96]
A1 for 96
M1 for 96 ÷ 100
75 oe
SC1 for 288
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Page 3 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 43
© Cambridge International Examinations 2013
2 (a)
119.94[…] nfww
3 M2 for 26sin
122sin62×
or M1 for 122sin
AC =
26sin
62 oe
SC2 for correct answer from alternative methods
(b) 109 or 108.7 to 108.8 nfww 4 M2 for 119.9..2 + 552 – 2 × 119.9.. × 55cos65
A1 for 11827[·…] or 11834 to 11835[·…]
or M1 for implicit version
(c) 1970 or 1969 to 1970.4 2 M1 for ½ × 119.9.. × 62 × sin 32
(d) 22300 or 22310 to 22320 3 M2 for (their (c) + 0.5 × 55 × 119.9.. × sin65) × 4.5
or
M1 for their (c) + 0.5 × 55 × 119.9.. × sin65
3 (a) 9 – 2x, 7 – 2x oe 2 B1 for each, accept in any order
(b) x(9 – 2x)(7 – 2x)
4x3 – 32x2 + 63x
M1FT
A1
Correct expansion and simplification with no errors
(c) 24 20 2 B1 for each correct value
(d) Correct curve 3 B2FT for 5 correct plots
or
B1FT for 3 or 4 correct plots
(e) 0.65 to 0.75 ≤ x ≤ 2 oe 2 B1 for 0.65 to 0.75 seen
(f) (i) 36 to 37 1
(ii) 1.2 to 1.4 1
4 (a) 48 and 84
66 and 66
2 B1 for each pair
(b) 540 2 M1 for 3 × 180 or (2 × 5 – 4) × 90
or 5 × (180 – 360 ÷ 5) oe
(c) 1620 2 M1 for 7 × 360 – their 540 – 360
(d) (i) 2x + 5 + 3y – 20 + 4x – 5 + x + y –
10 = 360 oe
1 Allow partial simplification but not 7x + 4y – 30 = 360
(ii) 2x + 5 + 3y – 20 = 180 1
(iii) [x =] 30, [y =] 45 nfww 4 M1 for correct multiplication
M1 for correct elimination
A1 x = 30 or y = 45
If 0 scored SC1 for correct substitution to find the
other variable
(iv) 65, 115, 115, 65 1 Accept in any order
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Page 4 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 43
© Cambridge International Examinations 2013
5 (a) (i) 3.81 or 3.812 to 3.813 or
3h 49min nfww
4 M1 for midpoints soi (condone 1 error or omission
and
M1 for use of ∑fx with x in correct interval including
both boundaries (condone 1 further error or omission)
and
M1 (dep on 2nd M1) for ∑fx ÷ 80 (305 ÷ 80)
(ii) Correct histogram 4 B1 for each correct block
and
B1 for correct widths
(b) (i) 5
2 ,
4
1 ,
4
3 ,
4
1 oe
2 B1 for 5
2 or both
4
1s in correct place
(ii) 20
18 nfww
10
9
3 M2 FT for 1 – their 5
2 × their
4
1
or 5
3 ×
4
3 +
5
3 × their
4
1 + their
5
2 ×
4
3 oe
or
M1 FT for their 5
2 × their
4
1
or 5
3 × their
4
1 + their
5
2 ×
4
3 oe
(iii) 125
27 [0.216]
2 M1 for 5
3 ×
5
3 ×
5
3
6 (a) 329.7 to 330 3 M2 for ½π(122 + 8.752 – 3.252) oe
or M1 for ½π122 or ½π8.752 or ½π3.252
SC2 for answer 1318 to 1320
(b) 2970 or 2967 to 2969.[…] 4 M3 for ½π(24 + 17.5 + 6.5) × 35 + their (a)
or
M2 for ½π(24 + 17.5 + 6.5) × 35
or
M1 for ½π × 24 or ½π × 17.5 or ½π × 6.5
SC3 for 3955 to 3960 dep on SC2 in (a)
(c) 11.5 or 11.6 or 11.53 to 11.55 3FT M1 for their (a) × 35
A1 for 11500 or 11530 to 11550
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Page 5 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 43
© Cambridge International Examinations 2013
(d) (i) 40
20=
h
r or
4020
hr=
1 Accept 20 : 40 = r : h leading to 40r = 20h [r = h/2]
40
20 =
2
1 and
2
1=
h
r
(ii)
35.3 or 35.31 to 35.34
3 M2 for 31211545
π
×their oe or 2 × their r
or
M1 for their 11545 = hh
×
×π×
2
23
1 oe
or their 11545 = rr 23
1 2××π× oe
7 (a) (i) 2
3 or 1.5
2
M1 for )4(8
)4(14
−−
−−
oe
(ii) y = 2
3x + 2 oe
2 B1 for y = their 2
3x + c o.e.
or y = mx + 2, m ≠ 0
SC1 for 2
3x + 2
(iii)
18
12
1
(iv) 21.6 or 21.63[…] 2 M1 FT for their 122 + their 182 oe
(b) (i) (a) 3b – 4a 1
(b)
5
1(6b – 8a) oe simplified
2 M1 for 5
1(12a + 6b) – 4a or AR = AO + OR
(c) 6a + 3b oe simplified 1
(ii)
OR is parallel to OT
1 Dep on OT correct
(iii) 4
9 or 2.25
2 M1 for
2
2
3
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Page 6 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 43
© Cambridge International Examinations 2013
8 (a) ( )
2
–2
t
uts oe nfww
3
M1 for a correct rearrangement to isolate the a term
and
M1 for a correct multiplication by 2
and
M1 for a correct division by t2
(b) 36.75 cao 3 M2 for 15.5 + 2.5 × 8.5
B1 for two of 15.5, 2.5, 8.5 seen
(c) (i) 5
16 or better [3.2]
1
(ii) 11.2 4 M2 for ½(25 + 10)16 (= 280)
or M1 for appreciation of distance from area
and M1 for their 280 ÷ 25 (dep on M1)
9 (a) 15 18 3n + 3 or 3(n + 1)
6 10
25 36 (n + 1)2
9 B2 for 15, 6, 25
or B1 for two correct values
B3 for 18, 10, 36
or B1 for each correct value
B2 for 3n + 3 oe
or M1 for 3n + k, for any k
B2 for (n + 1)2 oe
or M1 for a quadratic expression
(b) 14 2 M1 for (n + 1)(n + 2) = 240 or better
or 15 × 16 = 240
(c) (i) ½ + p + q = 9 1
(ii) [p = ] 3
[q = ] 2
11
5 B2 for 4p + 2q = 23
or B1 for ½ × 23 + p × 22 + q × 2 oe
M1 for correct multiplication and subtraction of their
equations
A1 for [p = ] 3 or [q = ] 2
11
If 0 scored then SC1 for either correct
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Page 7 Mark Scheme Syllabus Paper
IGCSE – October/November 2013 0580 43
© Cambridge International Examinations 2013
10 (a) 3+x
x
cao
3
B1 for (x + 3)(x – 3)
B1 for x(x – 3)
(b) 2
3 and –5
7
M2 for 15(x + 1) – 20x = 2x(x + 1)
or M1 for multiplication by one denominator only
or )1(
20)1(15
+
−+
xx
xx
and B2 for 2x2 + 7x – 15 [= 0]
or B1 for 15x + 15 – 20x or 2x2 + 2x
and M2 for (2x – 3)(x + 5) or their correct factors or
formula
or M1 for (2x + a)(x + b)
where ab = –15 or a + 2b = 7
A1 for x = 2
3 and –5