04 ucti spcc 08 multiplexing questions

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  • 5/21/2018 04 UCTI SPCC 08 Multiplexing Questions

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    System Programming and Computer Control Page 1 of 7

    Level 2 Asia Pacific University College of Technology and Innovation Tutorial

    Multiplexing

    SECTION A

    Review Questions

    1. What are the three major multiplexing techniques?

    2. How does FDM combine multiple signals into one?3. What is the purpose of a guard band?4. How is one FDM signal separated into its original components?5. Describe the analog hierarchy in which groups of signals are successively multiplexed

    onto higher-bandwidth lines.

    6. How is WDM similar to FDM? How are they different?7. How does TDM combine multiple signals into one?8. How is one TDM signal separated into its original components?9. Discuss the duration of a data unit before and after the TDM process.10. Describe the DS hierarchy.11. How are T lines related to DS service?12. How can T lines be used for analog transmission?13. What is the relationship between the number of slots in a frame and the number of

    input lines for TDM?

    14. Is bit padding a technique for FDM or TDM? Is the framing bit used in FDM orTDM?

    15. What is inverse multiplexing?

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    System Programming and Computer Control Page 2 of 7

    Level 2 Asia Pacific University College of Technology and Innovation Tutorial

    SECTION B

    Multiple Choice Questions

    16. The sharing of a medium and its link by two or more devices is called .a) Modulation

    b) Encodingc) Line disciplined) Multiplexing

    17. Which multiplexing technique transmits analog signals?a) FDM

    b) TDMc) WDMd) and(c)

    18. Which multiplexing technique transmits digital signals?a) FDM

    b) TDMc) WDMd) None of the above

    19. Which multiplexing technique shifts each signal to a different carrier frequency?a) FDM

    b) TDMc) Both (a) and (b)d) None of the above

    20. In TDM, for n signal sources of the same data rate, each frame contains __________ slots.a) n

    b) n+lc) nId) 0 to n

    21. In TDM, the transmission rate of the multiplexed path is usually _________ the sum ofthe transmission rates of the signal sources.

    a) Greater thanb) Less thanc) Equal tod) 1 less than

    22. In AT&T's FDM hierarchy, the bandwidth of each group type can be found bymultiplying __________ and adding extra bandwidth for guard bands.

    a) The number of voice channels by 4000 Hzb) The sampling rate by 4000 Hzc) The number of voice channels by 8 bits/sampled) The sampling rate by 8 bits/sample

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    System Programming and Computer Control Page 3 of 7

    Level 2 Asia Pacific University College of Technology and Innovation Tutorial

    23. DS-1 through DS-4 are ___________ while T-l through T-4 are __________..a) Services; multiplexers

    b) Services; signalsc) Services; linesd) Multiplexers; signals

    24. In a T-l line, _________ interleaving occurs.a) Bit

    b) Bytec) DS-0d) Switch

    25. Guard bands increase the bandwidth for ____________ .a) FDM

    b) TDMc) Both (a) and (b)d) None of the above

    26. Which multiplexing technique involves signals composed of light beams?a) FDM

    b) TDMc) WDMd) None of the above

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    System Programming and Computer Control Page 4 of 7

    Level 2 Asia Pacific University College of Technology and Innovation Tutorial

    SECTION C

    Exercises

    27. Given the following information, find the minimum bandwidth for the path.a) FDM multiplexing

    b) Five lines, each requiring 4000 Hzc) 200-Hz guard separating each band

    28. Given the following information, find the maximum bandwidth for each signal source.a) FDM multiplexing

    b) Total available bandwidth = 7900 Hzc) Three signal sourcesd) A 200-Hz guard band between each signal source

    29.

    Five signal sources are multiplexed using TDM. Each source produces 100 charactersper second. Assume that there is byte interleaving and that each frame requires 1

    bit for synchronization. What is the frame rate? What is the bit rate on the path?

    100 frames/second, each frame contains 5 characters (40 bits) and one extra frame bit,

    for the total of 41 bits per frame. Bit rate is 100 x 41 = 4100 bps or 4.1 Kbps

    30. Draw the TDM frames showing the character data, given the following information:a) Four signal sources

    b) Source 1 message: TEGc) Source 2 message: Ad) Source 3 message:e) Source 4 message: E FIL

    31. What is the time duration for a T-l frame?125 s

    32. The T-2 line offers a 6.312-Mbps service. Why is this number not 4 x 1.544 Mbps?33. In Figure 6.19 the sampling rate is 8000 samples/s. Why?

    Nyquist theorem dictates that the sampling rate must be twice the highest frequency; 2

    4000 Hz or 8000 Hz.

    34. If a single-mode optical fiber can transmit at 2 Gbps, how many telephone channelscan one cable carry?

    35. Calculate the overhead (in bits) per voice channel for each T line. What is the percentage of overhead per voice channel?

    T1 line (1,544,000 24 64000) /24 = 333 bits /channel 0.5% T2 line

    (6,312,0096 64000) /96 = 1750 bits /channel 2.7%

    T3 line (44,736,000 672 64000) /672 = 2571 bits /channel 4.0% T4 line

    (274,176,0004032 64000) /4032 = 4000 bits /channel 6.2%

    36. Three voice-grade lines, each using 4 KHz, are frequency multiplexed together byusing AM and canceling the lower modulated band. Draw the frequency-domain

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    System Programming and Computer Control Page 5 of 7

    Level 2 Asia Pacific University College of Technology and Innovation Tutorial

    representation of the resulting signal if the carrier frequencies are at 4, 10, and

    16 KHz, respectively. What is the bandwidth of the resulting signal?

    37. Show the frequency-domain representation of the resulting signals in each stage inFigure.22. Assume no guard band. Choose appropriate carrier frequencies.

    38. We have multiplexed 100 computers using synchronous TDM. If each computersends data at the rate of 14.4 Kbps, what is the minimum bit rate of the line? Can a T-

    1 line handle this situation?

    39. What is the minimum bit rate of each line in Figure 23 if we are using synchronousTDM? Ignore framing (synchronization) bits.

    2 566 Kbps = 1.132 Mbps

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    System Programming and Computer Control Page 6 of 7

    Level 2 Asia Pacific University College of Technology and Innovation Tutorial

    40. Figure 24 shows a multiplexer. If the slot is only 10 bits long (3 bits taken from eachinput plus 1 framing bit), what is the output bit stream? What is the output bit rate?What is the duration of each bit in the output line? How many slots are sent per

    second? What is the duration of each slot?

    41. Figure 25 shows a demulitplexer. If the input slot is 12 bits long (igonore framingbits), what is the bit stream in each output> What is the bit rate for each output line?

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    System Programming and Computer Control Page 7 of 7

    Level 2 Asia Pacific University College of Technology and Innovation Tutorial

    42. Figure 26 shows an inverse multiplexer. If the input data rate is 15 Mbps, what is therate for each line? Can we use the service of T-1 lines for this purpose? Ignore the

    framing bits.

    43. What is the overhead (number of extra bits per second) in a T-1 line?8 Kbps

    44. If we want to connect two Ethernet LANs with 10-Mbps data rates, how many T-1lines do we need? Do we need multiplexers or inverse multiplexers? Show the

    configuration.