03 drilling equipment
TRANSCRIPT
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PETE 411Well Drilling
Lesson 3
The Rig - Drilling Equipment
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Contents
� Rig Pumps� Solids Control Equipment� Air Drilling� The Rotary System� The Swivel� The Well Control System� The Well Monitoring System� Offshore Drilling
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Assignments:
READ: ADE Ch. 1, to p.30
HW #1: ADE 1.1, 1.2, 1.3Due Monday, Sept. 9, 2002at the beginning of class
NOTE: Answers in book are not always correct...
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Schematic of Rig
Circulating System for
liquiddrilling fluid
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Example 1.3
Compute the pump factor in units of barrels per stroke for a double-acting duplex pump having:
6.5-inch liners (dL)2.5 inch rods (dr)18-inch strokes (LS)and a volumetric efficiency of 90%. (EV)
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Solution:
The pump factor for a duplex pump can be determined using Equation 1.10
( )
( )( ) ( ) ( )[ ]stroke/in 1991
5.25.629.0182
dd2EL2
F
3
22
2r
2LVSp
=
−π=
−π=
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Recall:There are 231 in.3 in an U. S. gallon and 42 U.S. gallons in a U.S. barrel. Thus converting to the desired field units yields:
1991 in.3/stroke * gal/231 in.3 * bbl/42 gal.= 0.2052 bbl/stroke.
Thus: Pump Factor = 0.2052 bbl/stroke
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Pump Factor = 3 * π/4 dL2 LS EV/(231 * 42)
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Example:
Pump Factor for Triplex Pump
( )( )
bbl/stroke 09442.0
.in42231
bblstroke
in90.01264
3
ELd 4
3
32
VS 2
L
=∗
π=
∗
π∗=
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Example: Pump Rate
= Pump Factor * Strokes/min
= 0.09442
= 7.554 bbl/min= 317.3 gal/min
minstks80
stkbbl ∗
Pump Rate = 317 gal/min
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Hydrocyclone• desander• desilter
* No moving parts* Low cost* Pressure drop
* Diameter
13Decanting Centrifuge Use?
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l
l
Use?
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Fig. 1.33Schematic of Rotary System
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Fig. 1.34Cutaway View of Swivel
ROTATING* Seals* Bearings
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Fig. 1.38Cutaway View and
Dimensions for Example Tool Joint
PINBOX
TJShoulder
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Fig. 1.39Stabilizer
* Keeps pipe in center of hole* Aids in drilling straight hole* Prolongs bit life
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Fig. 1.41Kick Detection During
Drilling Operations
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2
3
KICK
GAIN IN PITVOLUME EQUAL
TO KICK VOLUME
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Fig. 1.46Remote Control
Panel for operating Blowout
Preventers CHOKE
What to do if KICK occurs?
21Fig. 1.44 Annular Blowout Preventer
DPTJDCOH
Press
22Ram Blowout Preventer
23Ram Blowout Preventer - cont’d
SHEAR / BLINDRAM ASSEMBLY
24Fig. 1.48 Rotating Blowout Preventer
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Fig. 1.51High-
Pressure Circulating System for
Well Control
Operations
Keep BHP const.
Kick
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Fig. 1.56Subsurface
Well Monitoring
System
MWD
27Fig. 1.57 Spread Mooring Systems
OFFSHORE DRILLING
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Fig. 1.58Schematic of Equipment for Marine
Drilling
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Fig. 1.59 Operation of aHeave Compensator
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Fig. 1.60Subsea
BOP Stack
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Fig. 1.63 Subsea Equipment Installation Procedure
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Typical Casing Strings
Water Level
DepthSeafloor Below ML
Conductor pile 36” 30” 200’
Conductor Casing 26” 20” 1000’
Surface Casing 17 1/2” 13 3/8” 4000’
Hole Csg. Depth
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Some Typical Casing Strings
DepthBelow ML
Conductor pile 36” 30” 200’
Conductor Casing 26” 20” 1000’
Surface Casing 17 1/2” 13 3/8” 4000’
Hole Csg. Depth
34Capacity = Area * Length
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What is the capacity of 10,000 ft of 5” OD, 19.50 lb/ft drillpipe?
Capacity = Area * Length
Area = π/4 d2 = π/4 * 4.2762 = 14.36 in2
Length = 10,000 ft = 120,000 in
Capacity = 14.36 *120,000 in3 /(231*42 in3 /bbl)
Capacity = 177.6 bbls
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What is the displacement of 10,000 ft of 5” OD, 19.50 lb/ft drillpipe?
Capacity = Area * Length
Area = π /4 (od2 - id2 ) = π /4 * (52 - 4.2762)
= 5.275 in2
Length = 10,000 ft = 120,000 in
Displ. = 5.276 * 120,000 in3 /(231 * 42 in3 /bbl)
Displacement = ? Bbls