02 introduction to quantum mechanics
TRANSCRIPT
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History of Physics
• Christian Huygens on wave nature of light (~1678)• Newton’s Principia for mechanics (~1687)• Maxwell’s A Dynamic Theory of the Electromagnetic
Fields (~1864)• Electron was discovered in 1897 (J.J. Thomson)• A few strange phenomena had to be resolved, but that
would be a matter of time
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Key points of this chapter
• Where and why did classical mechanics fail?• Photoelectric effect: photons behave as particles• Duality principle of de Broglie• Davisson-Germer experiment• Uncertainty relation of Heisenberg• Schrodinger’s Wave equation• Pauli’s exclusion principle
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h= Planck’s constant
6,625*10-34 Js
Proposed that electromagnetic energy is emitted only in quantized form and is always a multiple of smallest unit E=hѵ, where ѵ is the frequency of emitted radiation.
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In 1900:
Experimental setup for the study of photoelectric effect
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Observations of photoelectric effect
Photoelectric effect The maximum kinetic energy of photoelectrons as a function of incident frequency.
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Observations :
•When monochromatic light is incident on a clean surface of a material photoelectrons are emitted from the surface.
•According to classical physics, if light intensity is high enough to overcome work function, photoelectron should be emitted. But this is not always observed.
•Max kinetic energy (Tmax) of electron
Frequency of incident lightѴ > Ѵ0
•Rate of photoelectron emission
intensity of incident light
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Einstein’s explation
• Light behaves as a particles that transfers its energy to an electron
• The energy of a light particle (photon) is E=hν• The energy in excess of workfunction (2-5 eV) is converted
into kinetic energy of the photoelectrons.
where hѵ0 is the work function of the material
But if a photon can behave as a particle, is it also possible that a particle can behave as a wave?
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Who & where?
Someone was thinking about it…
Can we express momentum in terms
of wavelength?
de Broglie was a telecom engineer who spent most of his time on top of the Eiffel tower thinking about waves !
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Louis Victor Pierre Raymond duc de Broglie
Born: 15 Aug 1892 in Dieppe, France
Died: 19 March 1987 in Paris, France
Louis de Broglie (1892 – 1987)
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Wave-particle duality principle
From Einstein’s special theory of relativity, momentum of a photon is given by -
p=h/λ
de Broglie Hypothesized that wavelength of all particles can also be expressed as –
λ=h/p
This is the duality principle of de Broglie
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Let us look at Bragg's Law first: light interfering with a single crystal
Based on the angle of incidence of light, there is either constructive interference or destructive interference.
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Instead of light, what if we use a particle beam such as electrons?
Experimental arrangement of Davisson- Germer experiment (1927)
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Result similar to Bragg reflection (interference)
Scattered electron flux as a function of scattering
Davisson Germer Experiment
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Werner Heisenberg 1901-1976
Friend of Bohr, who was important for nuclear program of allies
Head of German nuclear war program.
Did he do intentionally miscalculations?
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Heisenberg’s uncertainty principle (1927):
the Heisenberg uncertainty principle states that locating a particle in a small region of space makes the momentum of the particle uncertain; and conversely, that measuring the momentum of a particle precisely makes the position uncertain.
In formula:
≥∆∆≥∆∆
tExp
So we can only express things in terms of probabilities!!!
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Probability
Probability is the likelihood that an event will occur. In our present discussion, probability refers to the likelihood of finding an electron at a certain position
Probability density function (pdf) is a function which gives the probability distribution for all possible locations.
Example : Imagining a one dimensional confinement of electron, if [z0,z4] is the set of all possible locations, then f(z) as shown in figure can be the pdf of the electron location.
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Probability
When the set of all possible locations is a continuous range as in this example, the probability of finding the electron at one particular location is zero.
But the probability of finding the electron in a small range say between z1 and z1+dz is finite and is given by f(z1)dz
Since the electron is confined between z0 and z4,
∫ =4
0
1)(z
z
dzzf
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Schrodinger introduced the wave function for any particle, which was later interpreted as the square-root of probability density function of finding the particle at a particular position.
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SCHRODINGER’S WAVE EQUATION
One-dimensional Schrodinger’s wave equation-
Where Ψ(x,t) is the wave function, V(x) is the potential function experienced by the particle, m is the mass of the particle and ħ=h/2Π
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Potential function
Potential here refers to the potential of the electron (electronic potential).
Example : electronic potential of an atom on an electron
Potential function of an isolated atom
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How to solve the wave equation?
Separation of variables:
= CONSTANT = η
Substituting this form into the Schrodinger’s equation :
Hence we have two differential equations each having one variable only
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ħ ω =η, Comparing with equation E=hѵ, η is the TOTAL energy E of the particle
This is an oscillation with radian frequency η/ ħ ⇒ ω = η/ ħ
tjet
−=Φ
η
)(Time dependent portion of wave function
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The time-independent Schrödinger wave equation (TISE)
From previous slide, η = E
∴
Therefore
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Hypothesis of Born (1926):
|Ψ (x,t)|2dx is the probability that the particle can be found in the
interval [x , x + dx]
The time dependent wave function is -
Physical meaning of the wave function
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Important potential functions
We first apply Schrodinger’s equation to some simple situations, the results of which will be used to analyze more complicated cases later.
a) Electron in free space, b) The step potential function, c) The infinite potential well and d) The barrier potential function
•
(a) (b) (c) (d)
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Boundary Conditions
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“Probability integral” is
infinity
Different probability at the same position
Different probability for left to right
and for right to left.
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Before solving the Schrodinger’s wave equation it is helpful to consider general solutions for-
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•
⇒ Potential energy V = 0
Applications of Schrodinger’s wave equation
Electron in free space
Referring to previous
slide, mEc 2=
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Time dependent wave function is then -
( )tEjet −=)(ϕ
This is the equation for a travelling wave.
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Hence a particle with a well defined energy also has a well defined wavelength and momentum
General expression for a travelling wave is -
From previous solution, mEk 2=
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The Infinite Potential Well
Potential function of the infinite potential well
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TISE ⇒
V(x)∞ and E finite, so Ψ(x)=0 in regions I and III
In region II, where V(x)=0, TISE reduces to -
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To satisfy boundary condition that Ψ(x) is continuous
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= 0 ⇒= 0 ⇒
This results in Ka = n π, or K = n (π/a)
with n = 1, 2,…….
K = 2 π /λ = n (π/a)½λ = a/n with n = 1, 2,…….
A1 = 0A2 sin Ka = 0
⇒ψ (x) = A2 sin{ n x}aπ
½λ
½λ
½λ
½λ
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and
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ψ (x) = A2 sin Kx real function
Since particle can only exist between x=0 and x=a,
∫ =ΨΨa
dxxx0
* 1)()(
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⇒a
ja
A 2,22 ±±=
Any of these values same conclusions
For simplicity we take a
A 22 +=
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Particle in an infinite potential well
a) Four lowest discrete energy levels, b) corresponding wave functions and c) corresponding probability functions
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The Step Potential Function
Energy of incident particle E < V0
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TISE
In region I, V=0
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)(
11 txkj
eA η−
InA given phase moves towards +x as time progresses wave travelling in +x direction
)(
11 txkj
eB η+−
Similarly wave travelling in -x direction
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In region II, V=V0 and we assume E<V0
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∞→Ψ x aseven finiteremain must )(2 x
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Reg I ⇒
Reg II ⇒
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The first derivatives of the wave functions must also be continuous at x=0
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Two equations and three unknowns ! So we cannot solve for all three but we can express two co-efficients in terms of the remaining one.
⇓⇓
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What is the form of ψ1 and ψ2?
Potential barrier Wave function at potential barrier
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The probability density function of the reflected wave is -
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Reflection coefficient = R = flux flux
incidentreflected
Where vi and vr are the velocities of incident and reflected waves.
*11
*11
..
..AAvBBvR
i
r=
Now, and E=1/2mv2 when V=0
Since K1 applies to both incident and reflected waves in x ≤ 0,
vr=vi
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Total reflection at an arbitrary step function V0,
if E<V0
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Transmitted wave co-efficient A2=A1+B1, hence A2 is not equal to 0
pdf |Ψ2(x)|2 of finding the particle in region II is not zero
There is finite probability that incident particle will penetrate the potential barrier and exist in region II.
But since reflection coefficient is 1, all particles in region II will eventually turn around and move back into region I.
Quantum mechanical snooker!!!
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The potential barrier
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Reg.I:
Reg.II:
Reg.III:
( since regions I and III are K3=K1)
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Boundary conditions:ψ3 can have component only in +x direction
At x = 0:
ψ2(a) = ψ3(a);
(0) (0)x x
21 ψ ψ∂ ∂∂ ∂
=
a a)x x
32 ψ ( ) ψ (∂ ∂∂ ∂
=
At x = a:
hence B3 = 0;
ψ1 (0) = ψ2 (0);
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• We can see that T is not zero, a result which cannot be explained from classical physics
•T is exponentially dependent on a. Thinner the barrier, higher is the transmission co-efficient.
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Extension of wave theory to atoms.
• For simplicity potential function of one electron atom or hydrogen atom is considered.
•Schrodinger’s wave equation to be solved in three dimensions.
•Potential function is spherically symmetric so use spherical co-ordinates.
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The spherical co-ordinate system
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CARTESIAN COORDINATES
1D:
3D:
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TISE in spherical co-ordinates
Expanding the laplacian operator the TISE in spherical co-ordinates is -
( ) 0)(2.sin.sin1.
sin1.1
20
22
2
222
2 =Ψ−+
∂Ψ∂
∂∂+
∂Ψ∂+
∂Ψ∂
∂∂ rVEm
rrrr
rr θθ
θθϕθ
{ } 0),,()(),,(2
2
0
2
=−+∇ ϕθψϕθψ rrVErm
∂∂
∂∂+
∂∂+
∂∂
∂∂=∇
θθ
θθϕθsin
sin1
sin11
22
2
222
22
rrrr
rr
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Separation of variables ( ) )()()(,, ϕθϕθ ΦΘ=Ψ rRr
Substituting this form of solution, the TISE is -
( ) 02sin.sin.sin.1.sin2
0222
22
2
=−+
∂Θ∂
∂∂
Θ+
∂Φ∂
Φ+
∂∂
∂∂ VEmr
rRr
rR θ
θθ
θθ
ϕθ
Each term is a function of only one of r, θ and φ. Grouping terms of the same variable and equating to a constant we can get three equations.
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ϕ
ϕjmem =Φ⇒−=
∂Φ∂
Φ .1 2
2
2
The equation for φ can be written as -
Wave function should be single valued m=0,±1, ±2, ±3
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Similarly the equations in r and θ can be solved in terms of constants n and l. The separation of variables constants n, l and m are known as principal, azimuthal (orbital) and magnetic quantum numbers and related by –
n=1,2,3… l=n-1,n-2,n-3,…0 |m|=l,l-1,…,0
Each set of quantum numbers a quantum state which an electron can occupy
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Electron energy can be written as –
( ) 2220
40
24 nemEn π ε
−=
• Energy is negative electron is bound to nucleus
• n is integer Energy can have only discrete values.
• electron being bound in a finite region of space quantized energy
where m0 is the electron mass and n is the principal quantum number.
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For the lowest energy state, n=1, l=m=0 and the wave function is given by -
The value of r for which the probability of finding the electron is maximum is -
Bohr radius
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Radial probability density function for the one-electron atom for a) n=1, l=m=0 and b) n=2, l=m=0.
• Radius of second energy shell > radius of first energy shell• finite (but small) probability that this electron can be at smaller radius.
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One more quantum number !
Every electron has an intrinsic angular momentum or spin. This spin is quantized, designated by spin quantum number s and take values +1/2 or -1/2
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Pauli Exclusion Principle
“no two electrons in any given system (atom, molecule or crystal) can have the same set of quantum numbers”
• This principle not only determines the distribution of electrons in an atom but also among the energy states in a crystal as will be seen later.
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• In 1869 Mendeleev demonstrated that a periodic relationship existed between the properties of an element and its atomic weight.
•But it was only quantum mechanics which provided a satisfactory explanation for the periodic table of elements.
•Each row in the periodic table corresponds to filling up of one quantum shell of electrons.
Periodic Table
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Initial portion of the periodic table
From the concept of quantum numbers and Pauli exclusion principle we can explain the periodic table.
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• Hydrogen single electron in lowest energy state (n=1,l=m=0). However spin can be +1/2 or -1/2
•Helium two electrons in lowest energy state and this shell is full. Valence energy shell (which mainly determines the chemical activity) is full and hence helium is an inert element.
•Lithium three electrons. 3rd electron must go into second energy shell (n=2)
•When n=2, l=0 or 1 and when l=1, m=0,±1. In each case s=±½. So this shell can accommodate 8 electrons.
•Neon has 10 electrons and hence the n=2 shell is also full making neon also an inert element.
•Thus the period table can be built. At higher atomic numbers, the electrons begin to interact and periodic table deviates a little from the simple explanation.
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