01100_freqresp
DESCRIPTION
goodTRANSCRIPT
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11: Frequency Responses
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 1 / 12
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Frequency Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 2 / 12
Ifx(t)is a sine wave, theny(t)will also be asine wave but with a different amplitude and
phase shift.Xis an input phasor andY is theoutput phasor.
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Frequency Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 2 / 12
Ifx(t)is a sine wave, theny(t)will also be asine wave but with a different amplitude and
phase shift.Xis an input phasor andY is theoutput phasor.
Thegainof the circuit is YX = 1/jCR+1/jC =
1jRC+1
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Frequency Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 2 / 12
Ifx(t)is a sine wave, theny(t)will also be asine wave but with a different amplitude and
phase shift.Xis an input phasor andY is theoutput phasor.
Thegainof the circuit is YX = 1/jCR+1/jC =
1jRC+1
This is a complex function of so we plot separate graphs for:
-
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Frequency Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 2 / 12
Ifx(t)is a sine wave, theny(t)will also be asine wave but with a different amplitude and
phase shift.Xis an input phasor andY is theoutput phasor.
Thegainof the circuit is YX = 1/jCR+1/jC =
1jRC+1
This is a complex function of so we plot separate graphs for:
Magnitude: YX=
1|jRC+1| =
1
1+(RC)2
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Frequency Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 2 / 12
Ifx(t)is a sine wave, theny(t)will also be asine wave but with a different amplitude and
phase shift.Xis an input phasor andY is theoutput phasor.
Thegainof the circuit is YX = 1/jCR+1/jC =
1jRC+1
This is a complex function of so we plot separate graphs for:
Magnitude: YX=
1|jRC+1| =
1
1+(RC)2
0 1 2 3 4 50
0.5
1
RC
Magnitude Response
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Frequency Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 2 / 12
Ifx(t)is a sine wave, theny(t)will also be asine wave but with a different amplitude and
phase shift.Xis an input phasor andY is theoutput phasor.
Thegainof the circuit is YX = 1/jCR+1/jC =
1jRC+1
This is a complex function of so we plot separate graphs for:
Magnitude: YX=
1|jRC+1| =
1
1+(RC)2Phase Shift:
YX
= (jRC+ 1) = arctan RC1
0 1 2 3 4 50
0.5
1
RC
Magnitude Response
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Frequency Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 2 / 12
Ifx(t)is a sine wave, theny(t)will also be asine wave but with a different amplitude and
phase shift.Xis an input phasor andY is theoutput phasor.
Thegainof the circuit is YX = 1/jCR+1/jC =
1jRC+1
This is a complex function of so we plot separate graphs for:
Magnitude: YX=
1|jRC+1| =
1
1+(RC)2Phase Shift:
YX
= (jRC+ 1) = arctan RC1
0 1 2 3 4 50
0.5
1
RC
Magnitude Response
0 1 2 3 4 5
-0.4
-0.2
0
RC
Phase Response
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase()
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
0 0.5 1
-0.4
-0.2
0 X
YX-Y
=50
Real
Imag
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase()
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
0 0.5 1
-0.4
-0.2
0 X
YX-Y
=50
Real
Imag
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72 0 20 40 60 80 100 120-1-0.5
0
0.5
1
x
y
time (ms)
x=blue,y=red
w = 50 rad/s, Gain = 0.89, Phase = -27
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase()
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase()
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
0 0.5 1
-0.4
-0.2
0 X
YX-Y
=100
Real
Imag
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase()
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
0 0.5 1
-0.4
-0.2
0 X
YX-Y
=100
Real
Imag
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72 0 20 40 60 80 100 120-1
-0.5
0
0.5
1
x
y
time (ms)
x=blue,y=red
w = 100 rad/s, Gain = 0.71, Phase = -45
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase()
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase(
)
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
0 0.5 1
-0.4
-0.2
0 X
YX-Y
=300
Real
Imag
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase(
)
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
0 0.5 1
-0.4
-0.2
0 X
YX-Y
=300
Real
Imag
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72 0 20 40 60 80 100 120-1
-0.5
0
0.5
1
x
y
time (ms)
x=blue,y=red
w = 300 rad/s, Gain = 0.32, Phase = -72
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase(
)
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Sine Wave Response
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 3 / 12
RC= 10 ms
YX =
1jRC+1 =
10.01j+1
0 0.5 1
-0.4
-0.2
0 X
YX-Y
=300
Real
Imag
= 50 YX = 0.89 27
= 100 YX = 0.71 45
= 300 YX = 0.32 72 0 20 40 60 80 100 120-1
-0.5
0
0.5
1
x
y
time (ms)
x=blue,y=red
w = 300 rad/s, Gain = 0.32, Phase = -72
0 100 200 300 400 5000
0.5
1
(rad/s)
|Y/X|
0 100 200 300 400 500
-80
-60
-40
-20
0
(rad/s)
Phase(
)
The output,y(t),lagsthe input,x(t), by up to90.
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Logarathmic axes
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 4 / 12
We usually use logarithmic axes for frequency and gain (but not phase)
because % differences are more significant than absolute differences.
E.g.5 kHz versus5.005 kHz is less significant than10 Hz versus15 Hzeven though both differences equal5 Hz.
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Logarathmic axes
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 4 / 12
We usually use logarithmic axes for frequency and gain (but not phase)
because % differences are more significant than absolute differences.
E.g.5 kHz versus5.005 kHz is less significant than10 Hz versus15 Hzeven though both differences equal5 Hz.
0.1 1 10
-0.4
-0.2
0
RC
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Logarathmic axes
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 4 / 12
We usually use logarithmic axes for frequency and gain (but not phase)
because % differences are more significant than absolute differences.
E.g.5 kHz versus5.005 kHz is less significant than10 Hz versus15 Hzeven though both differences equal5 Hz.
0.1 1 10-30
-20
-10
0
RC0.1 1 10
-0.4
-0.2
0
RC
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Logarathmic axes
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 4 / 12
We usually use logarithmic axes for frequency and gain (but not phase)
because % differences are more significant than absolute differences.
E.g.5 kHz versus5.005 kHz is less significant than10 Hz versus15 Hzeven though both differences equal5 Hz.
Logarithmic voltage ratios are specified in decibels (dB)=20 log10|V2||V1| .
0.1 1 10-30
-20
-10
0
RC0.1 1 10
-0.4
-0.2
0
RC
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Logarathmic axes
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 4 / 12
We usually use logarithmic axes for frequency and gain (but not phase)
because % differences are more significant than absolute differences.
E.g.5 kHz versus5.005 kHz is less significant than10 Hz versus15 Hzeven though both differences equal5 Hz.
Logarithmic voltage ratios are specified in decibels (dB)=20 log10|V2||V1| .
Common ratios:1 0 dB,
0.1 1 10-30
-20
-10
0
RC0.1 1 10
-0.4
-0.2
0
RC
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Logarathmic axes
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 4 / 12
We usually use logarithmic axes for frequency and gain (but not phase)
because % differences are more significant than absolute differences.
E.g.5 kHz versus5.005 kHz is less significant than10 Hz versus15 Hzeven though both differences equal5 Hz.
Logarithmic voltage ratios are specified in decibels (dB)=20 log10|V2||V1| .
Common ratios:1 0 dB,10 20 dB, 0.1 20 dB, 100 40 dB,
0.1 1 10-30
-20
-10
0
RC0.1 1 10
-0.4
-0.2
0
RC
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Logarathmic axes
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 4 / 12
We usually use logarithmic axes for frequency and gain (but not phase)
because % differences are more significant than absolute differences.
E.g.5 kHz versus5.005 kHz is less significant than10 Hz versus15 Hzeven though both differences equal5 Hz.
Logarithmic voltage ratios are specified in decibels (dB)=20 log10|V2||V1| .
Common ratios:1 0 dB,10 20 dB, 0.1 20 dB, 100 40 dB,2 6 dB, 0.5 6 dB,
0.1 1 10-30
-20
-10
0
RC0.1 1 10
-0.4
-0.2
0
RC
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Logarathmic axes
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 4 / 12
We usually use logarithmic axes for frequency and gain (but not phase)
because % differences are more significant than absolute differences.
E.g.5 kHz versus5.005 kHz is less significant than10 Hz versus15 Hzeven though both differences equal5 Hz.
Logarithmic voltage ratios are specified in decibels (dB)=20 log10|V2||V1| .
Common ratios:1 0 dB,10 20 dB, 0.1 20 dB, 100 40 dB,2 6 dB, 0.5 6 dB,
2 = 1.41 3 dB, 12
= 0.707 3 dB.
0.1 1 10-30
-20
-10
0
RC0.1 1 10
-0.4
-0.2
0
RC
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Logarathmic axes
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 4 / 12
We usually use logarithmic axes for frequency and gain (but not phase)
because % differences are more significant than absolute differences.
E.g.5 kHz versus5.005 kHz is less significant than10 Hz versus15 Hzeven though both differences equal5 Hz.
Logarithmic voltage ratios are specified in decibels (dB)=20 log10|V2||V1| .
Common ratios:1 0 dB,10 20 dB, 0.1 20 dB, 100 40 dB,2 6 dB, 0.5 6 dB,
2 = 1.41 3 dB, 12
= 0.707 3 dB.
0.1 1 10-30
-20
-10
0
RC0.1 1 10
-0.4
-0.2
0
RC
Note:P V2
decibel power ratios:10log10P2P1
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log
1 10 1001
10
100
2
(rad/s)
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.
1 10 1001
10
100
2
(rad/s)
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.
1 10 1001
10
100
2
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.
1 10 1001
10
100
2
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.
1 10 1001
10
100
2
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc
-
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36/118
Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.
1 10 1001
10
100
2
0.22
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.conly affects the lines vertical position.
1 10 1001
10
100
2
0.22
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.conly affects the lines vertical position.
1 10 1001
10
100
2
0.22
80
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.conly affects the lines vertical position.
1 10 1001
10
100
2
0.22
80
65-1
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.conly affects the lines vertical position.
1 10 1001
10
100
2
0.22
80
65-1
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc 0, phase =90 magnitude slope.
1 10 100-1
-0.5
0
0.5
1
2 0.22
80
65-1
(rad/s)
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.conly affects the lines vertical position.
If |H| is measured in decibels, a slope ofris called6r dB/octaveor20r dB/decade.
1 10 1001
10
100
2
0.22
80
65-1
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc 0, phase =90 magnitude slope.
1 10 100-1
-0.5
0
0.5
1
2 0.22
80
65-1
(rad/s)
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.conly affects the lines vertical position.
If |H| is measured in decibels, a slope ofris called6r dB/octaveor20r dB/decade.
1 10 1001
10
100
2
0.22
80
65-1
-9-1
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc 0, phase =90 magnitude slope.Negativec adds180 to the phase.
1 10 100-1
-0.5
0
0.5
1
2 0.22
80
65-1
-9-1
(rad/s)
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
Suppose we plot the magnitude and phase ofH=c (j)r
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.conly affects the lines vertical position.
If |H| is measured in decibels, a slope ofris called6r dB/octaveor20r dB/decade.
1 10 1001
10
100
2
0.22
80
65-1
-9-1
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc 0, phase =90 magnitude slope.Negativec adds180 to the phase.
Note:Phase angles are modulo360, i.e.450
90. 1 10 100
-1
-0.5
0
0.5
1
2 0.22
80
65-1
-9-1
(rad/s)
-
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Logs of Powers
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 5 / 12
H=c (j)r has a straight-line magnitude graph and a constant phase.
Magnitude (log-log graph):
|H| =cr log |H| = log |c|+r log This is a straight line with a slope ofr.conly affects the lines vertical position.
If |H| is measured in decibels, a slope ofris called6r dB/octaveor20r dB/decade.
1 10 1001
10
100
2
0.22
80
65-1
-9-1
(rad/s)
Phase (log-lin graph):
H= jr + c=r 2 (+ifc 0, phase =90 magnitude slope.Negativec adds180 to the phase.
Note:Phase angles are modulo360, i.e.450
90. 1 10 100
-1
-0.5
0
0.5
1
2 0.22
80
65-1
-9-1
(rad/s)
-
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Straight Line Approximations
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
-
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Straight Line Approximations
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
-
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Straight Line Approximations
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1
0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
-
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Straight Line Approximations
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1High frequencies ( 1RC):H(j) 1jRC
0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
-
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Straight Line Approximations
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1High frequencies ( 1RC):H(j) 1jRCApproximate the magnitude response
as two straight lines
0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
-
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Straight Line Approximations
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1 |H(j)| 1High frequencies ( 1RC):H(j) 1jRCApproximate the magnitude response
as two straight lines
0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
-
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Straight Line Approximations
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1 |H(j)| 1High frequencies ( 1RC):H(j) 1jRC |H(j)| 1RC1
Approximate the magnitude response
as two straight lines
0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
-
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Straight Line Approximations
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1 |H(j)| 1High frequencies ( 1RC):H(j) 1jRC |H(j)| 1RC1
Approximate the magnitude response
as two straight lines
0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
-
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Straight Line Approximations
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1 |H(j)| 1High frequencies ( 1RC):H(j) 1jRC |H(j)| 1RC1
Approximate the magnitude response
as two straight lines intersecting at the
corner frequency, c = 1RC.
0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
-
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Straight Line Approximations
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1 |H(j)| 1High frequencies ( 1RC):H(j) 1jRC |H(j)| 1RC1
Approximate the magnitude response
as two straight lines intersecting at the
corner frequency, c = 1RC.
At the corner frequency: 0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
(a)the gradient changes by 1(= 6 dB/octave= 20 dB/decade).
-
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Straight Line Approximations
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1 |H(j)| 1High frequencies ( 1RC):H(j) 1jRC |H(j)| 1RC1
Approximate the magnitude response
as two straight lines intersecting at the
corner frequency, c = 1RC.
At the corner frequency: 0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
(a)the gradient changes by 1(= 6 dB/octave= 20 dB/decade).(b) |H(jc)| =
11+j
= 1
2= 3 dB (worst-case error).
-
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Straight Line Approximations
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 6 / 12
Key idea:(aj+ b)
aj for |a| |b|b for |a| |b|
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1 |H(j)| 1High frequencies ( 1RC):H(j) 1jRC |H(j)| 1RC1
Approximate the magnitude response
as two straight lines intersecting at the
corner frequency, c = 1RC.
At the corner frequency: 0.1/RC 1/RC 10/RC-30
-20
-10
0
(rad/s)
|Gain|(dB)
(a)the gradient changes by 1(= 6 dB/octave= 20 dB/decade).(b) |H(jc)| =
11+j
= 1
2= 3 dB (worst-case error).
A linear factor(aj+ b)has a corner frequency ofc = ba .
-
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600
0.1 1 10 100 1000
-40
-20
0
(rad/s)
-
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
0.1 1 10 100 1000
-40
-20
0
(rad/s)
-
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Sort corner freqs:1, 4, 12, 50
0.1 1 10 100 1000
-40
-20
0
(rad/s)
-
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Sort corner freqs:1, 4, 12, 50Step 3:For
-
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Sort corner freqs:1, 4, 12, 50Step 3:For
-
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Sort corner freqs:1, 4, 12, 50Step 3:For
-
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Sort corner freqs:1, 4, 12, 50Step 3:For
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Sort corner freqs:1, 4, 12, 50Step 3:For
-
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Sort corner freqs:1, 4, 12, 50Step 3:For
-
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Plot Magnitude Response
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 7 / 12
The gain of a linear circuit is always arational polynomial inj and iscalled thetransfer functionof the circuit. For example:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Sort corner freqs:1, 4, 12, 50Step 3:For
-
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Low and High Frequency Asymptotes
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 8 / 12
You can find the low and high frequency asymptotes without factorizing:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
L d Hi h F A t t
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Low and High Frequency Asymptotes
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 8 / 12
You can find the low and high frequency asymptotes without factorizing:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
0.1 1 10 100 1000
-40
-20
0
(rad/s)0.1 1 10 100 1000
-0.5
0
0.5
(rad/s)
Low and High Frequency Asymptotes
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Low and High Frequency Asymptotes
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 8 / 12
You can find the low and high frequency asymptotes without factorizing:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
0.1 1 10 100 1000
-40
-20
0
(rad/s)0.1 1 10 100 1000
-0.5
0
0.5
(rad/s)
Low Frequency Asymptote:
Low and High Frequency Asymptotes
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Low and High Frequency Asymptotes
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 8 / 12
You can find the low and high frequency asymptotes without factorizing:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
0.1 1 10 100 1000
-40
-20
0
(rad/s)0.1 1 10 100 1000
-0.5
0
0.5
(rad/s)
Low Frequency Asymptote:From factors:HLF(j) =
20j(12)(1)(4)(50) = 1.2j
Low and High Frequency Asymptotes
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Low and High Frequency Asymptotes
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 8 / 12
You can find the low and high frequency asymptotes without factorizing:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
0.1 1 10 100 1000
-40
-20
0
(rad/s)0.1 1 10 100 1000
-0.5
0
0.5
(rad/s)
Low Frequency Asymptote:From factors:HLF(j) =
20j(12)(1)(4)(50) = 1.2j
Lowestpower ofj on top and bottom:H(j) 720(j)600 = 1.2j
Low and High Frequency Asymptotes
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Low and High Frequency Asymptotes
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 8 / 12
You can find the low and high frequency asymptotes without factorizing:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
0.1 1 10 100 1000
-40
-20
0
(rad/s)0.1 1 10 100 1000
-0.5
0
0.5
(rad/s)
Low Frequency Asymptote:From factors:HLF(j) =
20j(12)(1)(4)(50) = 1.2j
Lowestpower ofj on top and bottom:H(j) 720(j)600 = 1.2jHigh Frequency Asymptote:
Low and High Frequency Asymptotes
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Low and High Frequency Asymptotes
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 8 / 12
You can find the low and high frequency asymptotes without factorizing:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
0.1 1 10 100 1000
-40
-20
0
(rad/s)0.1 1 10 100 1000
-0.5
0
0.5
(rad/s)
Low Frequency Asymptote:From factors:HLF(j) =
20j(12)(1)(4)(50) = 1.2j
Lowestpower ofj on top and bottom:H(j) 720(j)600 = 1.2jHigh Frequency Asymptote:
From factors:HHF(j) = 20j(j)(j)(j)(j) = 20 (j)
1
Low and High Frequency Asymptotes
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Low and High Frequency Asymptotes
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 8 / 12
You can find the low and high frequency asymptotes without factorizing:
H(j) = 60(j)2+720(j)
3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
0.1 1 10 100 1000
-40
-20
0
(rad/s)0.1 1 10 100 1000
-0.5
0
0.5
(rad/s)
Low Frequency Asymptote:From factors:HLF(j) =
20j(12)(1)(4)(50) = 1.2j
Lowestpower ofj on top and bottom:H(j) 720(j)600 = 1.2jHigh Frequency Asymptote:
From factors:HHF(j) = 20j(j)(j)(j)(j) = 20 (j)
1
Highestpower ofj on top and bottom:H(j) 60(j)23(j)3
= 20(j)1
Phase Approximation
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Phase Approximation
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Phase Approximation
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Phase Approximation
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j)
1
0.1/RC 1/RC 10/RC
-0.4
-0.2
0
(rad/s)
Phas
e/
Phase Approximation
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Phase Approximation
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j)
1
1 = 0
0.1/RC 1/RC 10/RC
-0.4
-0.2
0
(rad/s)
Phas
e/
Phase Approximation
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Phase Approximation
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j)
1
1 = 0
High frequencies ( 1RC):H(j) 1jRC
0.1/RC 1/RC 10/RC
-0.4
-0.2
0
(rad/s)
Phas
e/
Phase Approximation
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Phase Approximation
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j)
1
1 = 0
High frequencies ( 1RC):H(j) 1jRC j1 = 2
0.1/RC 1/RC 10/RC
-0.4
-0.2
0
(rad/s)
Phas
e/
Phase Approximation
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Phase Approximation
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j)
1
1 = 0
High frequencies ( 1RC):H(j) 1jRC j1 = 2Approximate the phase response as
three straight lines.
0.1/RC 1/RC 10/RC
-0.4
-0.2
0
(rad/s)
Phas
e/
Phase Approximation
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Phase Approximation
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High Frequency
Asymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j)
1
1 = 0
High frequencies ( 1RC):H(j) 1jRC j1 = 2Approximate the phase response as
three straight lines.
By chance, they intersect close to
0.1c and10c wherec= 1RC. 0.1/RC 1/RC 10/RC
-0.4
-0.2
0
(rad/s)
Phas
e/
Phase Approximation
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Phase Approximation
11: Frequency Responses Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j)
1
1 = 0
High frequencies ( 1RC):H(j) 1jRC j1 = 2Approximate the phase response as
three straight lines.
By chance, they intersect close to
0.1c and10c wherec= 1RC. 0.1/RC 1/RC 10/RC
-0.4
-0.2
0
(rad/s)
Phas
e/
Between0.1c and10c the phase changes by
2over two decades.
This gives a gradient = 4 radians/decade.
Phase Approximation
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ase pp o at o
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j)
1
1 = 0
High frequencies ( 1RC):H(j) 1jRC j1 = 2Approximate the phase response as
three straight lines.
By chance, they intersect close to
0.1c and10c wherec= 1RC. 0.1/RC 1/RC 10/RC
-0.4
-0.2
0
(rad/s)
Phas
e/
Between0.1c and10c the phase changes by
2over two decades.
This gives a gradient = 4 radians/decade.(aj+ b)in denominator gradient= 4 /decade at
= 101ba .
Phase Approximation
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pp
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 9 / 12
Gain:H(j) = 1jRC+1
Low frequencies ( 1RC):H(j) 1 1 = 0
High frequencies ( 1RC):H(j) 1jRC j1 = 2Approximate the phase response as
three straight lines.
By chance, they intersect close to
0.1c and10c wherec= 1RC. 0.1/RC 1/RC 10/RC
-0.4
-0.2
0
(rad/s)
Phas
e/
Between0.1c and10c the phase changes by
2over two decades.
This gives a gradient = 4 radians/decade.(aj+ b)in denominator gradient= 4 /decade at
= 101ba .
The sign ofgradient is reversed for (a) numerator factors and (b) ba
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p
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Plot Phase Response
-
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p
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Plot Phase Response
-
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p
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Plot Phase Response
-
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p
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3)10+
(.6)40+
(.48) 120 (.62) 500+
.
Plot Phase Response
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11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3)10+
(.6)40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .
Plot Phase Response
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11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3)10+
(.6)40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .
Plot Phase Response
-
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11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3)10+
(.6)40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .Step 5:At = 0.1gradient becomes 4 .is still 2 .
Plot Phase Response
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11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3)10+
(.6)40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .Step 5:At = 0.1gradient becomes 4 .is still 2 .Step 6:At = 0.4,= 2 0.64 = 0.35. New gradient is 2 .
Plot Phase Response
-
5/19/2018 01100_Freqresp
93/118
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48) 1.2+
(.62)5 (.3)10+
(.6)40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .Step 5:At = 0.1gradient becomes 4 .is still 2 .Step 6:At = 0.4,= 2 0.64 = 0.35. New gradient is 2 .Step 7:At
= 1.2,= 0.35 0.48
2 = 0.11. New gradient is
4.
Plot Phase Response
-
5/19/2018 01100_Freqresp
94/118
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62) 5 (.3)10+
(.6)40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .Step 5:At = 0.1gradient becomes 4 .is still 2 .Step 6:At = 0.4,= 2 0.64 = 0.35. New gradient is 2 .Step 7:At
= 1.2,= 0.35 0.48
2 = 0.11. New gradient is
4.
Steps 8-12:Repeat for each gradient change.
Plot Phase Response
-
5/19/2018 01100_Freqresp
95/118
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3) 10+
(.6)40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .Step 5:At = 0.1gradient becomes 4 .is still 2 .Step 6:At = 0.4,= 2 0.64 = 0.35. New gradient is 2 .Step 7:At
= 1.2,= 0.35 0.48
2 = 0.11. New gradient is
4.
Steps 8-12:Repeat for each gradient change.
Plot Phase Response
-
5/19/2018 01100_Freqresp
96/118
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 =
20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3)10+
(.6) 40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .Step 5:At = 0.1gradient becomes 4 .is still 2 .Step 6:At = 0.4,= 2 0.64 = 0.35. New gradient is 2 .Step 7:At = 1.2,= 0.35
0.48
2 = 0.11. New gradient is
4.
Steps 8-12:Repeat for each gradient change.
Plot Phase Response
-
5/19/2018 01100_Freqresp
97/118
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 = 20
j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3)10+
(.6)40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .Step 5:At = 0.1gradient becomes 4 .is still 2 .Step 6:At = 0.4,= 2 0.64 = 0.35. New gradient is 2 .Step 7:At = 1.2,= 0.35
0.48
2 = 0.11. New gradient is
4.
Steps 8-12:Repeat for each gradient change.
Plot Phase Response
-
5/19/2018 01100_Freqresp
98/118
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3)10+
(.6)40+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .Step 5:At = 0.1gradient becomes 4 .is still 2 .Step 6:At = 0.4,= 2 0.64 = 0.35. New gradient is 2 .Step 7:At = 1.2,= 0.35
0.48
2 = 0.11. New gradient is
4.
Steps 8-12:Repeat for each gradient change. Final gradient is always 0.
Plot Phase Response
-
5/19/2018 01100_Freqresp
99/118
11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers
Straight Line
Approximations
Plot Magnitude Response
Low and High FrequencyAsymptotes
Phase Approximation
Plot Phase Response
RCR Circuit
Summary
E1.1 Analysis of Circuits (2014-5225) Frequency Responses: 11 10 / 12
H(j) = 60(j)2
+720(j)3(j)3+165(j)2+762(j)+600 = 20j(j+12)(j+1)(j+4)(j+50)
Step 1:Factorize the polynomials
Step 2:Gradient changes at101c.
Sign depends on num/den and sgnba
:.1, 10+; .4, 40+; 1.2+, 120; 5, 500+
0.1 1 10 100 1000-0.5
0
0.5
(rad/s)
Step 3:Put in ascending order and calculate gaps aslog1012
decades:
.1 (.6) .4 (.48)1.2+
(.62)5 (.3)10+
(.6)40
+
(.48) 120 (.62) 500+
.Step 4:Find phase of LF asymptote: 1.2j= +2 .Step 5:At = 0.1gradient becomes 4 .is still 2 .Step 6:At = 0.4,= 2 0.64 = 0.35. New gradient is 2 .Step 7:At = 1.2,= 0.35
0.48
2 = 0.11. New gradient is
4.
Steps 8-12:Repeat for each gradient change. Final gradient is always 0.
At 0.1 and 10 times each corner frequency, the graph is continuous but its
gradient changes abruptly by 4 rad/decade.
RCR Circuit
-
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11: Frequency Responses
Frequency Response
Sine Wave Response
Logarathmic axes
Logs of Powers