006 friction
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Friction
Pages 23-26 in text
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What is Friction Friction is a force
A frictional force arises when two
substances contact each other.
The molecules of each surface interact
according to Newtons Laws of Motion.
Friction always opposes motion, i.e., it is
opposite to the direction of velocity.
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Types of Friction
Dry FrictionOccurs between the non-lubricated
surfaces of solid objects
Fluid FrictionOccurs with fluids,or
lubricated surfaces
Dynamic FrictionWhen dry friction acts
between two surfaces that are
moving relative to each other
>Static FrictionWhen dry friction acts between
two surfaces that are not
moving relative to each other
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Contact Force
Force that occurs between objects that are in
contact with each other.
Contact forces can be resolved into
components that are perpendicular and
parallel to the surfaces in contact.
The perpendicular component is called the
normal force.
The parallel component is called friction.
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Contact Force in Running
Normal ForceFriction Force
During the push off phase in running, the normal force actsupward on the runner, while the friction force acts forward on
the runner. The frictional force is the only force capable of
moving the runner horizontally down the track. The normal
force can only accelerate the runner upwards.
Resultant force on runner
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Friction and the Normal Force
The maximum frictional force is
proportional to the normal contact force.
An increase in the normal force results in anincrease in the maximum friction.
This is because the molecules on the two
surfaces are pushed together more, thusincreasing their interactions.
d i h d
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Increased Weight, Increased
Normal Force, Increased Friction
5 kg10 kg
Surfaces are more compressed together and there
are more interactions between molecules
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Friction and Surface Area
Friction is not affected by the size of thesurface area in contact.
If the normal force remains constant, but the
contacting surface area is increased, thenthe normal force is spread out over moremolecules, thus the force on each moleculeis reduced.
Amontons (1699)
What about race car tires?
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Calculating Friction
Ff_max = FN
Ff_max is the maximum force of friction
(Mu) is the coefficient of friction
FN is the normal force
Friction can range in value from -Ff_max to +Ff_max
depends on the types of surfaces that are interacting.It would be low for rubber on ice, but high for rubber
on asphalt. It also depends on whether the surfaces are
moving relative to each other ( static ordynamic )
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Friction Example
A 5 kg block of wood rests on a ceramic counter. If the
coefficient of static friction between the block and the counteris 0.4, what horizontal force is necessary to move the block.
5 kgFh
Normal force = FN = mg = 5 x 9.81 = 49 N
FN
mg
Ff
FhFree body
diagram
Fx = maxFhFf= max = 0
Fh = Ff
Fy = mayFNmg = may = 0
FN = mg
Fh= Friction force = FN = 0.4 x 49 = 19.6 N
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Horse Pulling Cart
According to Newtons 3rd Law, these forces are equal and
opposite. So, if the horse pulls forward on the cart with thesame force as the cart pulls back on the horse, how will the
horse ever move the cart?
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SolutionFriction acts on the horses feet but very little acts on the wheels of the
cart. Drawing a free body diagram reveals the answer. The horse and
cart are one system so the forces in between them are internal and
cannot produce a change in motion of the system.
mg
Friction force
resulting from the
horse pulling back
on the ground
Force of friction on
the wheel which
opposes the motion of
the horse-cart system
FN
FN
FF FF
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Tug of War
Fat Bastard vs. Phil PfisterFat Bastard
Pull Force = 3000 N
Mass = 210 kg
Height = 1.8 m
Pfister
Pull Force = 3000 N
Mass = 120 kg
Height = 1.8 m
Both competitors are wearing the same footwear which
has a coefficient of friction of 1.5 with the rubber floorthey are competing on. If both men employ the same
technique, who wins?
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Two Free Body Diagrams
Fat Bastard Pfister
3000 N 3000 N
2060 N
Ff= FN= 1.5 x 2060
= 3090 N
2060 N
1180 N
1180 N
Ff= FN
= 1.5 x 1180
= 1770 N
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Fat Bastard Wins Both competitors have a force of 3000 N
pulling on them from the rope.
Fat Bastards extra mass gives him apotential friction force (3090 N) which isgreater than the force of the rope, so hedoesnt move.
Pfisters maximum friction force (1170 N)is less than the force of rope, so he is pulledtoward Fat Bastard.
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Would it be better to pull up or down
on the rope?
Suppose competitor A was taller than
competitor B.
A would be pulling on an upward angle,
while B would be pulling on a downward
angle.
Who has the advantage?
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Pulling Up On The Rope
mg
FN
Fx1
rope
Fx2
Fy1
This component
increases N
Fy = mayFNFy1mg = may = 0
FN = mg + Fy1
Friction force = Fx1 = FN
Bigger N, means larger
friction force
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Pulling Down On The Rope
mg
FNFx1
rope
Fx2
Fy1
This component
decreases N
Fy = mayFN + Fy1mg = may = 0
FN = mgFy1
Friction force = Fx1 = FN
Smaller N, means less
friction force
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Midterm Example Question
40
y
x
Fx1
A 5 kg box is being pushed up a 40
incline with anacceleration of -2 m/s/s. If the coefficient of dynamic
friction between the incline and box is 0.2, then what
is the value ofFx1? Remember thatfriction alwaysopposes the direction of motion.