© t madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 )...

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© T Madas

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© T Madas “expand” the following brackets: 3(3b – 4c ) =9b–12c p (p + 6 ) =p 2 +6 x (y + 2 ) =xy+2 v (2 + w ) =2+v w 4t (2 – t ) =8t–4 k (k – h ) =kh–k 3d (3 + d ) =9d+3 x (x 2 – 3 ) = 3 x–3 p x v t 2 2 d 2 x 3e (4 + e ) =12e+3 e 2 3h (4h + k ) =12k+3 hh 2 2b (4a – 5 ) =8b–10 ab x 2 (2x + 1 ) =2 2 +x x 3 3u (2u – 5v ) =6u–15 u 2 v 3y (2x – 7 ) =6y–21 xy t 2 (4t + 3 ) =4 2 +t t 3 p (2p 2 – 5q ) =2p–5 p 3 q 3

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Page 1: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

Page 2: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

3(2a + b ) = 6a + 3b2(4x + 3 ) = 8x + 62(3w + 4 ) = 6w + 83(2x – 3y ) = 6x – 9y4(5p + 3 ) =20p + 123(3f – 2 ) = 9f – 6

2(4 + 3a ) = 8 a+ 65(3c – 7 ) =15c – 35

3(2p – 5q ) = 6p – 15qx (x + 3 ) = x 2 + 3u (v + 5 ) =uv + 5

n (3 + m ) = 3 + nm2x (4 – x ) = 8 x– 2

b (b – c ) = b c– b5r (1 + t ) = 5 r+ 5y (y 2 – 4 ) = 3y – 4

xu

nx 2

2

r ty

Page 3: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

3(3b – 4c ) = 9b – 12cp (p + 6 ) = p2 + 6x (y + 2 ) = xy + 2v (2 + w ) = 2 + vw4t (2 – t ) = 8 t– 4k (k – h ) = k h– k

3d (3 + d ) = 9 d+ 3x (x 2 – 3 ) = 3x – 3

px

vt 2

2

d 2

x

3e (4 + e ) =12 e+ 3e 2

3h (4h + k ) =12 k+ 3h h2

2b (4a – 5 ) = 8 b– 10abx 2 (2x + 1 ) =2 2+ xx 3

3u (2u – 5v ) =6 u– 15u 2 v3y (2x – 7 ) = 6 y– 21xyt 2 (4t + 3 ) =4 2+ tt 3

p (2p 2 – 5q ) = 2 p– 5p 3 q3

Page 4: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

3x (5 + x ) =15 x+ 3x 2

2h (6h + k ) =12 k+ 2h h2

3a (3b – 5 ) = 9 a– 15abz 2 (5z + 1 ) = 5 2+ zz 3

2u (2u – 7v ) =4 u–14u 2 v4y (2x – 8 ) = 8 y– 32xyt 2 (6t + 5 ) =6 2+ tt 3

p (7p 2 – 4q ) = 7 p– 4p 3 q5

2x 2(5 + x 2 ) =10 x+2x 4

2h (6h + k ) =12 k+ 2h h2

3a (3ab – 1 ) =9 a– 3abn 3 (4n + 1) =4 3+ nn 4

2u 3(u – 4v ) =2 u– 8u 4 vc (2c 3 – 8) = 2 c– 8c 4

d 4 (3d + 2) =3 4+ dd 5

x 2(3x 3 – 5) = 3 x– 5x 5 2

2

2

2

3

Page 5: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:1

4 (3y – ) = –y34y 1

22 1

823 (2 + )=a 2

13a +a4

32 2

9a 3

(t + )=3t 13 t +t3 3 t 22

(3 + )=xy 32y +x 2y 2x1

212xy

( – )=a bab14

12

18

18 –a 2b 1

16ab

( – )=q ppq13

12

16 –p 2q 1

3pq

( + )=pu 13

12 +u 3v uv6uv 2 2 3 2 3

Page 6: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

Page 7: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

Page 8: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

Page 9: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

3(2a + b ) = 6a + 3b2(4x + 3 ) = 8x + 62(3w + 4 ) = 6w + 83(2x – 3y ) = 6x – 9y4(5p + 3 ) =20p + 123(3f – 2 ) = 9f – 6

2(4 + 3a ) = 8 a+ 65(3c – 7 ) =15c – 35

3(2p – 5q ) = 6p – 15qx (x + 3 ) = x 2 + 3u (v + 5 ) =uv + 5

n (3 + m ) = 3 + nm2x (4 – x ) = 8 x– 2

b (b – c ) = b c– b5r (1 + t ) = 5 r+ 5y (y 2 – 4 ) = 3y – 4

xu

nx 2

2

r ty

Page 10: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

3(3b – 4c ) = 9b – 12cp (p + 6 ) = p2 + 6x (y + 2 ) = xy + 2v (2 + w ) = 2 + vw4t (2 – t ) = 8 t– 4k (k – h ) = k h– k

3d (3 + d ) = 9 d+ 3x (x 2 – 3 ) = 3x – 3

px

vt 2

2

d 2

x

3e (4 + e ) =12 e+ 3e 2

3h (4h + k ) =12 k+ 3h h2

2b (4a – 5 ) = 8 b– 10abx 2 (2x + 1 ) =2 2+ xx 3

3u (2u – 5v ) =6 u– 15u 2 v3y (2x – 7 ) = 6 y– 21xyt 2 (4t + 3 ) =4 2+ tt 3

p (2p 2 – 5q ) = 2 p– 5p 3 q3

Page 11: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

3x (5 + x ) =15 x+ 3x 2

2h (6h + k ) =12 k+ 2h h2

3a (3b – 5 ) = 9 a– 15abz 2 (5z + 1 ) = 5 2+ zz 3

2u (2u – 7v ) =4 u–14u 2 v4y (2x – 8 ) = 8 y– 32xyt 2 (6t + 5 ) =6 2+ tt 3

p (7p 2 – 4q ) = 7 p– 4p 3 q5

2x 2(5 + x 2 ) =10 x+2x 4

2h (6h + k ) =12 k+ 2h h2

3a (3ab – 1 ) =9 a– 3abn 3 (4n + 1) =4 3+ nn 4

2u 3(u – 4v ) =2 u– 8u 4 vc (2c 3 – 8) = 2 c– 8c 4

d 4 (3d + 2) =3 4+ dd 5

x 2(3x 3 – 5) = 3 x– 5x 5 2

2

2

2

3

Page 12: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:–y3

414 (3y – ) =y 1

22 1

823 (2 + )=a 2

13a +a4

32 2

9a 3

+t3 3 t 2(t + )=3t 13 t2

32 +x 2y 2(3 + )=xy yx1

212xy

( – )=a bab14

12

18

18 –a 2b 1

16ab

( – )=q ppq13

12

16 –p 2q 1

3pq

+u 3v uv( + )=pu 13

126uv 2 2 3 2 3

Page 13: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

Page 14: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas

“expand” the following brackets:

Page 15: © T Madas. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8…

© T Madas