e is always constant, but ke and pe can change if pe and ke change, they must change in such a way...

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E is always constant, but KE and PE can change If PE and KE change, they must change in such a way as to keep E constant Example Consider the 1D free-fall of an object of mass m from a height of y 0 =h PE KE E y m y 0 =h, t 0 =0, v 0 =0 y<h, t, v>0 The initial energy of the system defines the total energy mgh PE KE E KE mgh PE 0 , 0 0 system

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Page 1: E is always constant, but KE and PE can change  If PE and KE change, they must change in such a way as to keep E constant Example Consider the 1D free-fall

E is always constant, but KE and PE can change

If PE and KE change, they must change in such a way as to keep E constant

Example

Consider the 1D free-fall of an object of mass m from a height of y0=h

PEKEE

y m y0=h, t0=0, v0=0y<h, t, v>0

The initial energy of the system defines the total energy

mghPEKEE

KEmghPE

0 , 00

system

Page 2: E is always constant, but KE and PE can change  If PE and KE change, they must change in such a way as to keep E constant Example Consider the 1D free-fall

System – the collection of objects being study to the exclusion of all other objects in the surroundings, in this example, we consider the object of mass m only

Some time later, KE and PE have changed, but E has not

)(

v221

yhmg

mgymghKE

mgymmgh

PEKEE

Energy

y0h

E

PE=mgy

KE

What is KE, PE, and v when y=h/2?

2)

2( ,

2

hmg

hhmgKE

hmgmgyPE

Page 3: E is always constant, but KE and PE can change  If PE and KE change, they must change in such a way as to keep E constant Example Consider the 1D free-fall

J 90.422

J 9.80m) 00.1)( kg)(9.80 00.1( 13.3m) 00.1)(80.9(v

v2

2

2

sm

sm

sm

221

EhmgKEPE

mghEgh

mh

mgKE

For y=0 (just before the object hits the ground)?

sm

sm

221

43.4m) 00.1)(80.9(22vv

J 80.9 ,0

2

ghmghm

mghKEEmgyPE

Note: we have neglected air resistance and what happens when the object hits the ground.

Page 4: E is always constant, but KE and PE can change  If PE and KE change, they must change in such a way as to keep E constant Example Consider the 1D free-fall

Example

A hockey puck slides across the ice. Its speed slows from 45.00 m/s to 44.67 m/s after traveling a distance of 16.0 m. Determine the coefficient of kinetic friction between the ice and the puck.

Solution:

Given: v0=45.00 m/s, vf=44.67 m/s, x=16.0 m=s

Method: Use work-energy theorem

FN

fk

mg

s

mgssfsfsFW

mgFfmafF

mgFmgFF

kkk

kNkkxkx

NNy

180cos cos

,

0

Page 5: E is always constant, but KE and PE can change  If PE and KE change, they must change in such a way as to keep E constant Example Consider the 1D free-fall

094.0)0.16)(80.9(2

)00.4567.44(

2

)v(v

2vv

vv

2220

2

20

2

202

1221

0

gs

gs

mgsmm

KEKEW

fk

kf

kf

f

Conservative and Non-conservative Forces

Conservative Force: a force for which the work it does on an object does not depend on the path. Gravity is an example.

Page 6: E is always constant, but KE and PE can change  If PE and KE change, they must change in such a way as to keep E constant Example Consider the 1D free-fall

h

y m

A B C

A

mg s

mghW

mghh

mgsmgW

mghsFW

sin)sin()sin(

cos

mg mg

s s

B

C

Non-conservative Force - a force for which the work done depends on the path

- friction- air resistance

Page 7: E is always constant, but KE and PE can change  If PE and KE change, they must change in such a way as to keep E constant Example Consider the 1D free-fall

If both conservative and non-conservative forces act on an object, the work-energy theorem is modified

CfNC

fNCCtotal

WKEKEWKEKEWWW

0

0

For the case of gravity

)()(

)()(

00

00

00

00

0

PEKEPEKEPEPEKEKE

PEKEWmgymgyKEKEWyymgKEKEW

yymgWW

ff

ff

NC

ffNC

ffNC

fCg