© 2015 pearson education, inc. clicker questions chapter 19 barbara mowery york college

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© 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

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Page 1: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Clicker Questions

Chapter 19

Barbara Mowery

York College

Page 2: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Which process is not spontaneous at 25 degrees Celsius?

a. the melting of an ice cube

b. the sublimation of dry ice

c. the boiling of liquid nitrogen

d. the freezing of ethyl alcohol

Page 3: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Which process is not spontaneous at 25 degrees Celsius?

a. the melting of an ice cube

b. the sublimation of dry ice

c. the boiling of liquid nitrogen

d. the freezing of ethyl alcohol

Page 4: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

All spontaneous processes are

a. reversible.

b. isothermal.

c. irreversible.

d. exothermic.

Page 5: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

All spontaneous processes are

a. reversible.

b. isothermal.

c. irreversible.

d. exothermic.

Page 6: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Entropy is a measurement of the _______ of a system.

a. randomness

b. internal energy

c. temperature

d. polarity

Page 7: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Entropy is a measurement of the _______ of a system.

a. randomness

b. internal energy

c. temperature

d. polarity

Page 8: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Entropy (S) is a state function, so the change in entropy is given by Sfinal _____ Sinitial.

a. +

b. −

c. ×

d. /

Page 9: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Entropy (S) is a state function, so the change in entropy is given by Sfinal _____ Sinitial.

a. +

b. −

c. ×

d. /

Page 10: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The entropy of a sample of CO2 increases upon heating because all three types of molecular motion increase.

a. True

b. False

Page 11: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The entropy of a sample of CO2 increases upon heating because all three types of molecular motion increase.

a. True

b. False

Page 12: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The entropy of a sample of Ne increases upon heating because all three types of molecular motion increase.

a. True

b. False

Page 13: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The entropy of a sample of Ne increases upon heating because all three types of molecular motion increase.

a. True

b. False

Page 14: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The Second Law of Thermodynamics says that the entropy of the universe _______ whenever a spontaneous process occurs.

a. increases b. decreasesc. remains unchangedd. reaches equilibrium

Page 15: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The Second Law of Thermodynamics says that the entropy of the universe _______ whenever a spontaneous process occurs.

a. increases b. decreasesc. remains unchangedd. reaches equilibrium

Page 16: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

An automobile being driven from west to east is experiencing _______ motion.

a. kinetic

b. rotational

c. vibrational

d. translational

Page 17: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

An automobile being driven from west to east is experiencing _______ motion.

a. kinetic

b. rotational

c. vibrational

d. translational

Page 18: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Changes in a molecule’s bond lengths or bond angles are examples of _______ motion.

a. kinetic

b. rotational

c. vibrational

d. translational

Page 19: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Changes in a molecule’s bond lengths or bond angles are examples of _______ motion.

a. kinetic

b. rotational

c. vibrational

d. translational

Page 20: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

When a molecule spins like a top, it is undergoing _______ motion.

a. kinetic

b. vibrational

c. translational

d. rotational

Page 21: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

When a molecule spins like a top, it is undergoing _______ motion.

a. kinetic

b. vibrational

c. translational

d. rotational

Page 22: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

k = Boltzmann constant.W = the number of microstates. S = entropy.Which is true?

a. S = k × W

b. S = k / W

c. S = k ln W

d. S = kW

Page 23: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

k = Boltzmann constant.W = the number of microstates. S = entropy.Which is true?

a. S = k × W

b. S = k / W

c. S = k ln W

d. S = kW

Page 24: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Entropy decreases when

a. a liquid becomes a gas.

b. a solid becomes a liquid.

c. a gas becomes a solid.

d. the number of moles of gas increases.

Page 25: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Entropy decreases when

a. a liquid becomes a gas.

b. a solid becomes a liquid.

c. a gas becomes a solid.

d. the number of moles of gas increases.

Page 26: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Which process does not illustrate a decrease in entropy?

a. Na(s) + Br2(l) 2 NaBr(s)

b. CaCO3(s) CaO(s) + CO2(g)

c. NH3(aq) +H2S(g) (NH4)2S(aq)

d. AgNO3(aq) + KCl(aq)

AgCl(s) + KNO3(aq)

Page 27: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Which process does not illustrate a decrease in entropy?

a. Na(s) + Br2(l) 2 NaBr(s)

b. CaCO3(s) CaO(s) + CO2(g)

c. NH3(aq) +H2S(g) (NH4)2S(aq)

d. AgNO3(aq) + KCl(aq)

AgCl(s) + KNO3(aq)

Page 28: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The Third Law of Thermodynamics says that the entropy of a pure, perfect crystal is _______ at absolute zero (zero Kelvins).

a. increasing b. decreasing

c. infinite d. zero

Page 29: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The Third Law of Thermodynamics says that the entropy of a pure, perfect crystal is _______ at absolute zero (zero Kelvins).

a. increasing b. decreasing

c. infinite d. zero

Page 30: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The notation, pressure, temperature, and units for reporting Standard Molar Entropies are

a. Sstd; 1 atm; 0° C; kJ/mol-°C.

b. S°; 1 atm; 298 K; J/mol-K.

c. ΔS°; 0 atm; 298 K; J/mol-K.

d. ΔS°f; 1 atm; 0° C; kJ/°C.

Page 31: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The notation, pressure, temperature, and units for reporting Standard Molar Entropies are

a. Sstd; 1 atm; 0° C; kJ/mol-°C.

b. S°; 1 atm; 298 K; J/mol-K.

c. ΔS°; 0 atm; 298 K; J/mol-K.

d. ΔS°f; 1 atm; 0° C; kJ/°C.

Page 32: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Which is not a standard condition for reporting Standard Free Energy values?

a. is 0 for pure liquids and solids, regardless of their state.

b. is reported for solutions at 1 M.

c. is reported for gases at 1 atm.

d. is 0 for pure elements in their standard states.

Page 33: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

Which is not a standard condition for reporting Standard Free Energy values?

a. is 0 for pure liquids and solids, regardless of their state.

b. is reported for solutions at 1 M.

c. is reported for gases at 1 atm.

d. is 0 for pure elements in their standard states.

Page 34: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

G = the Gibbs free energy.H = enthalpy. S = entropy.T = the Kelvin temperature.Which is true?

a. G = H + TS

b. G = H − TS

c. G = H × TS

d. G = H / TS

Page 35: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

G = the Gibbs free energy.H = enthalpy. S = entropy.T = the Kelvin temperature.Which is true?

a. G = H + TS

b. G = H − TS

c. G = H × TS

d. G = H / TS

Page 36: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

If the enthalpy change is positive and the entropy change is negative, the reaction is

a. spontaneous at all temperatures.

b. non-spontaneous at all temperatures.

c. spontaneous at low temperatures.

d. spontaneous at high temperatures.

Page 37: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

If the enthalpy change is positive and the entropy change is negative, the reaction is

a. spontaneous at all temperatures.

b. non-spontaneous at all temperatures.

c. spontaneous at low temperatures.

d. spontaneous at high temperatures.

Page 38: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

If the enthalpy change is negative and the entropy change is positive, the reaction is

a. spontaneous at all temperatures.

b. non-spontaneous at all temperatures.

c. spontaneous at low temperatures.

d. spontaneous at high temperatures.

Page 39: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

If the enthalpy change is negative and the entropy change is positive, the reaction is

a. spontaneous at all temperatures.

b. non-spontaneous at all temperatures.

c. spontaneous at low temperatures.

d. spontaneous at high temperatures.

Page 40: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

At equilibrium, the value of the free energy change (“delta G”) is

a. positive.

b. negative.

c. fluctuating.

d. zero.

Page 41: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

At equilibrium, the value of the free energy change (“delta G”) is

a. positive.

b. negative.

c. fluctuating.

d. zero.

Page 42: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The general equation used to calculate ΔGrxn from standard free energies of formation is ΔGrxn =

a. ΔHrxn − T ΔSrxn.

b. Σn(ΔGf)products −Σ n(ΔGf)reactants.

c. Σn(ΔGf)reactants −Σ n(ΔGf)products.

d. ΔGf − RT lnQ.

Page 43: © 2015 Pearson Education, Inc. Clicker Questions Chapter 19 Barbara Mowery York College

© 2015 Pearson Education, Inc.

The general equation used to calculate ΔGrxn from standard free energies of formation is ΔGrxn =

a. ΔHrxn − T ΔSrxn.

b. Σn(ΔGf)products −Σ n(ΔGf)reactants.

c. Σn(ΔGf)reactants −Σ n(ΔGf)products.

d. ΔGf − RT lnQ.